NEET Chemistry · NCERT Class 11

Hydrocarbons notes

Alkanes, Alkenes, Alkynes, Aromatic Hydrocarbons and Reactions & Applications — explained topic by topic with key points, formulas, memory tricks and common mistakes.

  • 6 topics
  • 57 min read
  • 24 formulas
  • 62 PYQs
1

Chapter Overview

7 min

Hydrocarbons are organic compounds made only of carbon and hydrogen. NCERT classifies them mainly as aliphatic hydrocarbons, which include alkanes, alkenes and alkynes, and aromatic hydrocarbons, mainly benzene and its derivatives. Alkanes are saturated and generally undergo substitution, alkenes and alkynes are unsaturated and mainly undergo addition, while benzene is resonance-stabilized and prefers electrophilic substitution. This chapter connects structure, hybridisation, nomenclature, preparation, physical properties, reactions, mechanisms, industrial uses and environmental effects. For NEET, the most important ideas are homologous series, IUPAC naming, Markovnikov rule, peroxide effect, acidity of alkynes, benzene resonance, electrophilic substitution, directive influence, combustion and pollution.

Key points7

  • The type of C-C bond decides hybridisation, geometry and reactivity.
  • Unsaturation is tested by decolourisation of bromine water or alkaline KMnO4.
  • Alkanes are less reactive because C-C and C-H sigma bonds are strong and non-polar.
  • Alkenes and alkynes react with electrophiles because π electrons are loosely held.
  • Benzene is unusually stable due to resonance and delocalisation.
  • Reaction mechanism questions often test carbocation stability and directive effects.
  • Hydrocarbon combustion has direct links with air pollution, global warming and health hazards.

Memory tricks2

Reaction Personality Trick: Single bond is shy, double and triple bonds are friendly, benzene is royal. So alkanes react slowly, alkenes/alkynes add easily, and benzene protects aromaticity by substitution.

Formula Ladder: Alkane has maximum H: CnH2n+2. Remove 2 H for one double bond: alkene CnH2n. Remove 4 H for one triple bond: alkyne CnH2n−2.

Examples2

Daily-Life Hydrocarbons

LPG contains propane and butane; natural gas is mainly methane; petrol and diesel are mixtures of hydrocarbons; acetylene is used in oxy-acetylene welding.

NEET Concept Example

If a compound decolourises bromine water, it is likely unsaturated. Ethene and ethyne do this, but ethane does not under ordinary conditions.

Common mistakes2

Confusing Aromatic with Fragrant

In organic chemistry, aromatic means cyclic, planar, conjugated and Huckel-stabilised. It does not simply mean pleasant smell.

Assuming Benzene Gives Addition Easily

Benzene generally prefers substitution because addition would destroy aromatic resonance energy.

Reference tables2

Quick revision8

Formulas4

General Formula of Alkanes
CnH2n+2CnH2n+2

Used for open-chain saturated hydrocarbons containing only single bonds.

n
Number of carbon atoms
General Formula of Alkenes
CnH2nCnH2n

Used for open-chain hydrocarbons containing one carbon-carbon double bond.

n
Number of carbon atoms
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Diagrams3

2

Alkanes

10 min

Alkanes are saturated hydrocarbons containing only carbon-carbon and carbon-hydrogen single sigma bonds. Their general formula is CnH2n+2 for open-chain members, and every carbon is sp3 hybridised with tetrahedral geometry. They form a homologous series in which successive members differ by -CH2-. Alkanes are relatively unreactive because their sigma bonds are strong and nearly non-polar, so they are also called paraffins. NCERT expects students to know classification, IUPAC nomenclature, preparation by hydrogenation, reduction, Wurtz reaction, decarboxylation and Kolbe electrolysis, physical properties, conformations of ethane, and reactions such as halogenation, combustion and pyrolysis. NEET often asks stability of conformers, selectivity in halogenation and product prediction.

Key points7

  • Classification of hydrocarbons begins with saturated alkanes and unsaturated alkenes/alkynes.
  • A homologous series has same functional group/general formula and similar chemical properties.
  • IUPAC naming requires longest chain, lowest locants and alphabetical order of substituents.
  • Alkanes are non-polar, insoluble in water and soluble in non-polar solvents.
  • Free radical halogenation has initiation, propagation and termination steps.
  • Chlorination is less selective while bromination is more selective.
  • Pyrolysis or cracking is industrially important for petrol and alkene production.

Memory tricks2

Alkane Name Trick: Meth, eth, prop, but, pent, hex, hept, oct, non, dec can be remembered as: 'Monkey Eats Proper Bananas; People Hate Old Nasty Dates'.

Conformation Trick: Staggered is stable because groups stay away; eclipsed is energetic because groups cover each other like an eclipse.

Examples2

LPG Example

LPG mainly contains propane and butane, both alkanes. Their easy combustion makes them useful domestic fuels.

Solved Concept

Sodium acetate on heating with soda lime gives methane because decarboxylation removes the carboxyl carbon: CH3COONa + NaOH → CH4 + Na2CO3.

Common mistakes3

Wrong Longest Chain

In IUPAC naming, always select the longest continuous carbon chain first, not the chain that appears straight on paper.

Wurtz with Two Different Halides

Using two different alkyl halides in Wurtz reaction gives a mixture, so it is not a good method for unsymmetrical alkanes.

Ignoring Radical Stability

Major halogenation product often comes from the more stable radical: tertiary > secondary > primary > methyl.

Reference tables3

Quick revision8

Formulas4

Alkane General Formula
CnH2n+2CnH2n+2

Formula for acyclic saturated hydrocarbons.

n
Number of carbon atoms in the alkane
Complete Combustion of Alkane
CnH2n+2+(3n+1)/2O2→nCO2+(n+1)H2OCnH2n+2 + (3n+1)/2 O2 → nCO2 + (n+1)H2O

Balanced general combustion equation for alkanes.

n
Number of carbon atoms
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Diagrams4

3

Alkenes

10 min

Alkenes are unsaturated hydrocarbons containing at least one carbon-carbon double bond. For open-chain monoalkenes, the formula is CnH2n. Each double-bonded carbon is sp2 hybridised, trigonal planar and has one sigma and one pi bond. The pi bond is electron-rich and weaker than a sigma bond, making alkenes more reactive than alkanes. NCERT focuses on IUPAC naming, geometrical isomerism, preparation by dehydration of alcohols and dehydrohalogenation of alkyl halides, physical properties, electrophilic addition, Markovnikov's rule, peroxide effect, oxidation and polymerisation. For NEET, the key is to predict major products using carbocation stability, understand anti-Markovnikov addition only for HBr with peroxide, and remember oxidation products.

Key points7

  • The π bond is the reactive site because it is exposed above and below the molecular plane.
  • Geometrical isomerism arises due to restricted rotation around C=C.
  • Dehydration of alcohols follows Saytzeff rule in many cases: more substituted alkene is major.
  • Electrophilic addition often proceeds through carbocation intermediate.
  • Carbocation stability controls regioselectivity and rearrangements.
  • Bromine water and Baeyer's reagent are tests for unsaturation.
  • Polymerisation converts many small alkene molecules into useful polymers.

Memory tricks2

Markovnikov Memory: Rich get richer: the carbon already having more H gets another H during normal HX addition.

Peroxide Effect Memory: Only HBr says 'BRO' to peroxide. HCl and HI do not show peroxide effect in NCERT/NEET.

Examples2

Polymer Example

Ethene polymerises to polythene, used in plastic bags, bottles and insulation materials.

Solved Concept

Propene plus HBr without peroxide gives 2-bromopropane by Markovnikov addition. With peroxide, it gives 1-bromopropane.

Common mistakes3

Applying Peroxide Effect to HCl or HI

Anti-Markovnikov addition with peroxide is important only for HBr, not for HCl or HI.

Forgetting Carbocation Rearrangement

If a more stable carbocation can form by hydride or methyl shift, rearranged products may appear.

Confusing Addition and Substitution

Alkenes usually undergo addition across C=C, not substitution like alkanes or benzene.

Reference tables3

Quick revision8

Formulas4

Alkene General Formula
CnH2nCnH2n

Formula for open-chain hydrocarbons with one double bond.

n
Number of carbon atoms
Hydrogenation of Alkene
RCH=CHR′+H2→RCH2−CH2R′RCH=CHR' + H2 → RCH2-CH2R'

Alkene adds hydrogen in presence of Ni, Pt or Pd to give alkane.

R, R'
Hydrogen or alkyl groups attached to double-bonded carbons
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Diagrams4

4

Alkynes

9 min

Alkynes are unsaturated hydrocarbons containing at least one carbon-carbon triple bond. Open-chain monoalkynes have the formula CnH2n−2. Each triply bonded carbon is sp hybridised and linear with a bond angle of 180°. The triple bond has one sigma and two pi bonds, so alkynes undergo addition reactions like alkenes, but often in two steps. A unique NCERT feature is the acidic nature of terminal alkynes because sp carbon has 50% s-character and holds electrons more tightly, stabilising the acetylide ion. Alkynes are prepared by double dehydrohalogenation of dihalides and from calcium carbide. NEET commonly tests acidity order, metal acetylide formation, addition reactions, oxidation and conversion of ethyne to benzene.

Key points7

  • The carbon-carbon triple bond is shorter and stronger than double and single bonds.
  • Terminal alkynes form acetylides with sodium, ammoniacal AgNO3 and ammoniacal Cu2Cl2.
  • Hydration of ethyne gives acetaldehyde through unstable enol intermediate.
  • Partial hydrogenation with Lindlar catalyst gives cis-alkene.
  • Reduction with sodium in liquid ammonia gives trans-alkene.
  • Alkynes can decolourise bromine water and alkaline KMnO4.
  • Ethyne is industrially important in welding and organic synthesis.

Memory tricks2

Acidity Trick: More s means more acidic: sp has 50% s-character, so terminal alkynes are the most acidic among simple hydrocarbons.

Triple Bond Addition Trick: Triple bond has two π bonds, so think 'two tickets available' for addition reactions.

Examples2

Welding Example

Ethyne burns with oxygen to produce a very hot oxy-acetylene flame used for welding and cutting metals.

Solved Concept

Propyne reacts with ammoniacal AgNO3 to give a precipitate, but 2-butyne does not because 2-butyne has no terminal acidic hydrogen.

Common mistakes3

Calling All Alkynes Acidic

Only terminal alkynes with -C≡C-H show acidic hydrogen and form metal acetylides.

Forgetting Hydration Tautomerism

Hydration first gives an enol, which rearranges to aldehyde or ketone. Ethyne gives acetaldehyde.

Wrong Stereochemistry in Reduction

Lindlar catalyst gives cis-alkene, while Na/liquid NH3 gives trans-alkene.

Reference tables3

Quick revision8

Formulas4

Alkyne General Formula
CnH2n−2CnH2n−2

Formula for open-chain hydrocarbons with one triple bond.

n
Number of carbon atoms
Calcium Carbide Method
CaC2+2H2O→C2H2+Ca(OH)2CaC2 + 2H2O → C2H2 + Ca(OH)2

Laboratory and industrial method for preparing ethyne.

CaC2
Calcium carbide
C2H2
Ethyne or acetylene
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Diagrams4

5

Aromatic Hydrocarbons

12 min

Aromatic hydrocarbons contain benzene-like cyclic, planar and conjugated π systems with special stability. Benzene, C6H6, has six sp2 carbons in a hexagonal ring; all C-C bonds are equal because π electrons are delocalised. It obeys Huckel's 4n+2 rule with six π electrons, making it aromatic. Because addition reactions would destroy aromaticity, benzene mainly undergoes electrophilic substitution reactions such as nitration, halogenation, sulphonation, Friedel-Crafts alkylation and Friedel-Crafts acylation. The mechanism involves generation of electrophile, attack on benzene to form sigma complex, and loss of proton to restore aromaticity. NEET also tests directive influence: activating groups usually direct ortho/para, while deactivating groups usually direct meta, with halogens as exceptions.

Key points8

  • Benzene resonance explains equal bond lengths and extra stability.
  • Electrophilic aromatic substitution restores aromaticity in the final step.
  • The sigma complex or arenium ion is resonance-stabilised but non-aromatic.
  • Activating groups increase ring reactivity by donating electron density.
  • Deactivating groups reduce ring reactivity by withdrawing electron density.
  • Ortho/para directors stabilise sigma complex at ortho and para positions.
  • Meta directors make ortho/para sigma complexes highly unstable.
  • Friedel-Crafts reactions fail with strongly deactivated rings and aniline-like Lewis base complexes.

Memory tricks3

Aromaticity Checklist: Remember PPC-H: Planar, cyclic, conjugated, Huckel 4n+2.

Meta Directors: Most groups with multiple bonds to electronegative atoms are meta directors: -NO2, -CN, -CHO, -COOH, -SO3H.

Halogen Exception: Halogens are 'slow but guiding': they deactivate the ring but guide incoming electrophile to ortho and para positions.

Examples2

Nitration Example

Benzene treated with concentrated HNO3 and concentrated H2SO4 forms nitrobenzene through electrophile NO2+.

Directive Influence Example

Toluene gives mainly ortho- and para-nitrotoluene on nitration because the methyl group is activating and ortho/para directing.

Common mistakes4

Treating Benzene Like Cyclohexatriene

Benzene does not have alternating short and long bonds; all C-C bonds are equal due to resonance.

Forgetting Catalyst in Halogenation

Benzene needs Lewis acid catalyst like FeCl3 or FeBr3 for halogenation.

Wrong Directive Effect of Halogens

Halogens are deactivating but ortho/para directing due to resonance donation.

Assuming Friedel-Crafts Always Works

Friedel-Crafts reactions do not work well with strongly deactivated rings and may fail with groups that complex with AlCl3.

Reference tables3

Quick revision8

Formulas4

Benzene Formula
C6H6C6H6

Molecular formula of benzene, the parent aromatic hydrocarbon.

C
Carbon atom
H
Hydrogen atom
Huckel Rule
π electrons =4n+2π\text{ electrons }= 4n + 2

Criterion for aromaticity in cyclic, planar, fully conjugated systems.

n
0, 1, 2, 3... integer
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Diagrams4

6

Reactions & Applications

9 min

Hydrocarbons are not only reaction types in organic chemistry but also major fuels and industrial raw materials. Their important reactions include combustion, substitution, addition, oxidation, cracking, reforming, polymerisation and electrophilic aromatic substitution. Complete combustion produces carbon dioxide, water and heat, making hydrocarbons useful fuels; incomplete combustion produces carbon monoxide and soot, which are harmful. Petroleum and natural gas are natural mixtures of hydrocarbons separated and processed for petrol, diesel, kerosene, LPG, CNG and petrochemicals. Alkenes are key monomers for plastics, alkynes are useful in welding and synthesis, and aromatic hydrocarbons are used in dyes, drugs and polymers. NEET also asks environmental effects: greenhouse gases, photochemical smog, carcinogenic polynuclear aromatic hydrocarbons and toxicity.

Key points7

  • Reaction choice depends on saturation and aromaticity.
  • Alkanes: combustion, halogenation and pyrolysis are most important.
  • Alkenes/alkynes: addition, oxidation and polymerisation dominate.
  • Benzene: electrophilic substitution dominates to preserve aromaticity.
  • Petroleum refining includes fractional distillation, cracking and reforming.
  • Incomplete combustion is dangerous because carbon monoxide binds haemoglobin strongly.
  • Hydrocarbon pollution contributes to smog, global warming and respiratory illness.

Memory tricks3

Combustion Products: Complete combustion is clean in equation: hydrocarbon + enough oxygen gives only CO2, H2O and heat.

Petroleum Column Trick: Light fractions fly higher; heavy fractions stay lower. So gases exit top, bitumen remains bottom.

Reaction Family Shortcut: Alkane substitutes, alkene adds, alkyne adds twice, benzene substitutes to save aromaticity.

Examples3

CNG Example

Compressed natural gas is mainly methane. It burns more cleanly than petrol or diesel and is used as vehicle fuel.

Plastic Example

Ethene and propene form polythene and polypropylene, which are common packaging and household plastic materials.

Health Example

Carbon monoxide from incomplete combustion is dangerous because it forms carboxyhaemoglobin and reduces oxygen transport in blood.

Common mistakes4

Ignoring Oxygen Supply

Combustion products depend on oxygen. Limited oxygen produces CO or carbon soot, not only CO2.

Confusing Cracking with Combustion

Cracking breaks large hydrocarbons into smaller hydrocarbons; combustion oxidises hydrocarbons to CO2/H2O.

Calling All Aromatics Safe

Many aromatic hydrocarbons, especially polynuclear aromatic hydrocarbons, are toxic or carcinogenic.

Forgetting Industrial Role of Alkenes

Alkenes are not mainly fuels in NEET questions; they are especially important as polymer monomers and synthetic intermediates.

Reference tables3

Quick revision8

Formulas4

Combustion of Methane
CH4+2O2→CO2+2H2O+ heatCH4 + 2O2 → CO2 + 2H2O +\text{ heat}

Complete combustion of methane, the main component of natural gas.

CH4
Methane
O2
Oxygen
Incomplete Combustion
2CH4+3O2→2CO+4H2O2CH4 + 3O2 → 2CO + 4H2O

Limited oxygen supply can form poisonous carbon monoxide.

CO
Carbon monoxide, a toxic gas
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Diagrams4

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NEET PYQs from Hydrocarbons

The latest 3 of 62 previous-year questions from this chapter.

  1. NEET 2026Set 11MediumQ1

    The number of chlorine atoms present in the organic products X and Y of the following reactions, respectively, are:

    • A3 and 3
    • B6 and 3
    • C6 and 6
    • D3 and 6
  2. NEET 2026Set 50HardQ2

    Given below are two statements : Statement I : trans-But-2-ene upon treatment with $\mathrm{Br_2}$ in $\mathrm{CCl_4}$ gives the following product. Statement II : cis-But-2-ene upon treatment with alkaline $\mathrm{KMnO_4}$ gives the following product. In the light of the above statements, choose the most appropriate answer from the options given below.

    • ABoth Statement I and Statement II are correct
    • BBoth Statement I and Statement II are incorrect
    • CStatement I is correct but Statement II is incorrect
    • DStatement I is incorrect but Statement II is correct
  3. NEET 2026Set 50MediumQ3

    Consider the following reaction sequences and choose the correct option. $\mathrm{L} \xleftarrow{\mathrm{Na/liq.\ NH_3}} \mathrm{Ph{-}C{\equiv}C{-}Me} \xrightarrow[\text{(Lindlar's Catalyst)}]{\mathrm{H_2,\ Pd/C}} \mathrm{K}$ $\mathrm{L} \xrightarrow{\text{HBr, benzoyl peroxide}} \mathrm{N}$ ; $\mathrm{K} \xrightarrow{\mathrm{HBr}} \mathrm{M}$

    • AK and L are geometrical isomers
    • BK and L are enantiomers
    • CM and N are geometrical isomers
    • DM and N are stereoisomers

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