NEET Chemistry · NCERT Class 11

Structure of Atom notes

Discovery of Subatomic Particles, Atomic Models, Bohr Model of Atom, Quantum Mechanical Model, Atomic Orbitals & Quantum Numbers and Electronic Configuration — explained topic by topic with key points, formulas, memory tricks and common mistakes.

  • 7 topics
  • 61 min read
  • 27 formulas
  • 27 PYQs
1

Chapter Overview

6 min

Structure of Atom explains how scientists moved from the idea of an indivisible atom to the modern quantum mechanical picture. The chapter begins with the discovery of electrons, protons and neutrons through discharge tube, canal ray and neutron experiments. It then compares Thomson’s plum pudding model, Rutherford’s nuclear model and their limitations. Bohr’s model introduces fixed orbits, quantized energy and hydrogen spectrum calculations. The quantum mechanical model replaces definite paths with probability-based orbitals and includes de Broglie waves, Heisenberg uncertainty and Schrödinger’s equation. Quantum numbers describe each electron completely, while Aufbau principle, Pauli exclusion principle and Hund’s rule explain electronic configuration. For NEET, this chapter is highly important because it combines conceptual theory, spectra, formulas and configuration-based MCQs.

Key points7

  • The chapter develops from experimental discoveries to mathematical atomic structure.
  • Bohr model works well only for one-electron systems such as H, He⁺ and Li²⁺.
  • Quantum numbers define shell, subshell, orbital orientation and spin.
  • Maximum electrons in a shell = 2n² and in a subshell = 2(2l + 1).
  • Half-filled and fully-filled subshells are unusually stable due to symmetry and exchange energy.
  • Atomic spectra provide evidence for quantized energy levels.
  • NEET frequently asks numerical questions from Bohr radius, energy, wavelength and uncertainty.

Memory tricks2

Chapter Order: Remember: Particles → Models → Bohr → Quantum → Orbitals → Configuration. First discover what is inside atom, then learn how electrons are arranged.

Most Asked Areas: For NEET, focus on Bohr formulas, quantum numbers, orbital shapes, electronic configuration and exceptions like Cr and Cu.

Examples1

Big Picture Example

Hydrogen spectrum cannot be explained by Rutherford model because accelerating electrons should radiate continuously. Bohr explained it by saying electrons jump between fixed energy levels and emit photons of definite frequencies.

Common mistakes3

Mixing Orbit and Orbital

Orbit is Bohr’s fixed circular path; orbital is a three-dimensional probability region from quantum mechanics.

Using Bohr Model for All Atoms

Bohr formulae are valid for hydrogen and hydrogen-like one-electron species only.

Wrong Configuration Order

Filling order follows increasing n + l value, not simply shell number.

Reference tables2

Quick revision8

Formulas3

de Broglie Wavelength
λ=h/mvλ = h / mv

Relates wavelength of a moving particle to its momentum.

λ
de Broglie wavelength
h
Planck constant
m
mass of particle
v
velocity of particle
Bohr Energy
En=−13.6Z2/n2eVE_n = -13.6 Z² / n² eV

Energy of electron in nth orbit of a hydrogen-like species.

E_n
energy of nth orbit
Z
atomic number
n
principal quantum number
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Diagrams3

2

Discovery of Subatomic Particles

8 min

The discovery of subatomic particles proved that atoms are divisible. Cathode ray discharge tube experiments showed that negatively charged rays travel from cathode to anode, move in straight lines, produce fluorescence and get deflected by electric and magnetic fields. J. J. Thomson identified these rays as electrons and measured the charge-to-mass ratio, e/m. Millikan’s oil drop experiment later helped determine electron charge, allowing calculation of electron mass. Canal rays, observed in modified discharge tubes, were positively charged and led to the identification of the proton. James Chadwick discovered the neutron by bombarding beryllium with alpha particles and observing neutral radiation. These discoveries formed the basis of atomic structure, nuclear charge, isotopes and mass number.

Key points7

  • Cathode ray properties are independent of electrode material and gas, proving electrons are universal particles.
  • Canal rays depend on gas present because positive ions are formed from gas atoms.
  • The lightest positive particle is the proton, obtained from hydrogen.
  • Thomson’s e/m value showed electron has extremely small mass compared with atoms.
  • Millikan’s charge value plus Thomson’s e/m value gives mass of electron.
  • Neutron explains isotopes and missing nuclear mass.
  • Atomic number equals number of protons; mass number equals protons plus neutrons.

Memory tricks3

Cathode Ray Charge: Cathode rays go toward the positive plate, so they must be negative. Remember: Opposites attract.

Particle Order: Electron first, proton next, neutron last: EPN sounds like 'Experimental Particles Named'.

Canal Rays Depend on Gas: Canal rays are gas ions, so changing gas changes the positive ion.

Examples2

Electron Mass Calculation

If e = 1.602 × 10⁻¹⁹ C and e/m = 1.76 × 10¹¹ C kg⁻¹, then m = e/(e/m) ≈ 9.1 × 10⁻³¹ kg.

Mass Number Example

For sodium, Z = 11 and A = 23. Number of neutrons = A − Z = 23 − 11 = 12.

Common mistakes3

Thinking Canal Rays Are Always Protons

Canal rays are positive ions. Only hydrogen gas gives the lightest positive ion related to the proton.

Confusing e/m with m/e

Thomson measured charge-to-mass ratio e/m, not mass-to-charge ratio.

Putting Neutrons Outside Nucleus

Neutrons are nuclear particles along with protons; electrons occupy the extranuclear region.

Reference tables3

Quick revision8

Formulas3

Charge-to-Mass Ratio
e/m=1.758820×1011Ckg−1e/m = 1.758820 × 10¹¹ C kg⁻¹

Thomson determined this ratio for electron using deflection in electric and magnetic fields.

e
magnitude of electron charge
m
mass of electron
Mass of Electron
m=e/(e/m)m = e / (e/m)

Electron mass is calculated using charge from oil drop experiment and e/m from Thomson experiment.

m
mass of electron
e
charge of electron
e/m
charge-to-mass ratio
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Diagrams4

3

Atomic Models

8 min

Atomic models developed as experimental evidence improved. Thomson proposed the plum pudding model, where negatively charged electrons were embedded in a uniform positively charged sphere, making the atom neutral. Rutherford tested this model using alpha particles directed at a thin gold foil. Most alpha particles passed straight through, some deflected slightly and very few bounced back. This proved that most of the atom is empty space and almost all positive charge and mass are concentrated in a tiny nucleus. Rutherford’s nuclear model placed electrons around the nucleus, but it could not explain atomic stability because revolving electrons should continuously lose energy and fall into the nucleus. It also failed to explain line spectra. Atomic spectra later supported quantized energy levels.

Key points7

  • Alpha particles are positively charged helium nuclei.
  • Large deflection occurs only when alpha particles come close to the positive nucleus.
  • Nucleus is much smaller than the atom but contains nearly all its mass.
  • Thomson model could not explain strong back scattering.
  • Rutherford model was a major step but classical physics made it unstable.
  • Continuous spectrum contains all wavelengths; line spectrum contains selected wavelengths.
  • Emission spectrum is produced when excited electrons return to lower energy states.

Memory tricks2

Rutherford Results: Most pass = mostly empty; few deflect = positive centre; very few return = tiny dense nucleus.

Spectrum Clue: Line spectrum means limited allowed energies; continuous spectrum means all wavelengths.

Examples2

Scattering Analogy

If you throw marbles at a huge empty stadium with one tiny heavy pillar, most marbles pass through; only those near the pillar deflect. This is like Rutherford scattering.

Spectrum Example

A neon sign glows with specific colours because excited neon atoms emit light at definite wavelengths, forming a line spectrum.

Common mistakes3

Assuming Rutherford Explained Stability

Rutherford explained the nucleus but failed to explain why orbiting electrons do not fall into it.

Forgetting Alpha Particle Charge

Alpha particles are positively charged, so they are repelled by the positive nucleus.

Confusing Atomic and Nuclear Size

The nucleus is extremely small compared with the atom, but contains almost all mass.

Reference tables3

Quick revision8

Formulas3

Photon Energy
E=hνE = hν

Energy of radiation emitted or absorbed in atomic spectra.

E
energy of photon
h
Planck constant
ν
frequency of radiation
Wave Relation
c=νλc = νλ

Connects speed, frequency and wavelength of electromagnetic radiation.

c
speed of light
ν
frequency
λ
wavelength
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Diagrams4

4

Bohr Model of Atom

10 min

Bohr model corrected Rutherford’s instability problem for hydrogen-like atoms by introducing quantization. Bohr proposed that electrons revolve only in certain permitted circular orbits called stationary states without radiating energy. Angular momentum is quantized as mvr = nh/2π. Radiation is emitted or absorbed only when an electron jumps between two energy levels, with energy difference ΔE = hν. For hydrogen-like species, orbit radius increases as n²/Z, velocity varies as Z/n and energy is negative, proportional to −Z²/n². The model successfully explains the line spectrum of hydrogen and spectral series such as Lyman, Balmer and Paschen. However, it fails for multi-electron atoms, fine structure, Zeeman effect and the wave nature of electrons.

Key points7

  • Energy levels are negative because electron is bound to the nucleus.
  • Higher n means larger orbit, higher energy and lower magnitude of negative energy.
  • Energy gap decreases as n increases, so spectral lines converge.
  • Emission occurs when electron falls from higher to lower level.
  • Absorption occurs when electron jumps from lower to higher level.
  • For hydrogen-like species, replace Z according to nuclear charge.
  • Bohr model cannot describe exact electron arrangement in multi-electron atoms.

Memory tricks2

Series Order: Lyman, Balmer, Paschen, Brackett, Pfund have final levels 1, 2, 3, 4, 5. Remember: Little Boys Prefer Bright Places.

Bohr Dependence: Radius goes with n square; energy becomes less negative as n goes higher.

Examples3

Energy of Second Orbit of Hydrogen

For H, Z = 1 and n = 2. E₂ = −13.6/4 = −3.4 eV.

Radius of First Orbit of He⁺

For He⁺, Z = 2 and n = 1. r₁ = 0.529 × 1²/2 = 0.2645 Å.

Ionisation Energy of Hydrogen

Ground state energy of hydrogen is −13.6 eV, so energy needed to remove the electron to infinity is +13.6 eV.

Common mistakes3

Wrong Sign of Energy

Bohr energy is negative for bound electrons. Zero energy corresponds to electron at infinity.

Applying to Multi-Electron Atoms

Bohr’s exact formulas work for hydrogen-like species only, not general multi-electron atoms.

Confusing Emission and Absorption

Higher to lower level emits energy; lower to higher level absorbs energy.

Reference tables2

Quick revision8

Formulas5

Angular Momentum Quantization
mvr=nh/2πmvr = nh / 2π

Only those orbits are allowed for which electron angular momentum is an integral multiple of h/2π.

m
mass of electron
v
velocity of electron
r
radius of orbit
n
orbit number
h
Planck constant
Radius of Orbit
rn=0.529n2/ZA˚r_n = 0.529 n²/Z Å

Radius of nth Bohr orbit for hydrogen-like species.

r_n
radius of nth orbit
n
principal quantum number
Z
atomic number
Velocity of Electron
vn=2.18×106Z/nms−1v_n = 2.18 × 10⁶ Z/n m s⁻¹

Speed of electron in nth Bohr orbit of hydrogen-like atom.

v_n
velocity in nth orbit
Z
atomic number
n
orbit number
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Diagrams3

5

Quantum Mechanical Model

9 min

The quantum mechanical model replaces Bohr’s fixed circular orbits with orbitals, which are regions of high probability of finding electrons. It is based on the dual nature of matter, de Broglie’s hypothesis and Heisenberg’s uncertainty principle. de Broglie proposed that moving particles have wavelength λ = h/mv, explaining why electrons show wave character. Heisenberg stated that position and momentum of a microscopic particle cannot both be measured exactly at the same time. Schrödinger developed a wave equation whose solutions are wave functions, ψ. The square of the wave function, ψ², gives probability density of finding an electron. Thus, modern atomic structure does not describe exact paths but predicts allowed energies, orbitals and electron distribution around the nucleus.

Key points7

  • Wave nature is significant for microscopic particles like electrons, not ordinary macroscopic objects.
  • Greater certainty in position causes greater uncertainty in momentum.
  • Exact electron trajectory is not meaningful in quantum mechanics.
  • Orbitals are obtained from acceptable solutions of Schrödinger equation.
  • Probability of finding electron is high where electron cloud density is high.
  • Nodes are regions where probability of finding electron is zero.
  • Quantum model explains multi-electron atoms better than Bohr model.

Memory tricks3

ψ and ψ²: Psi is a mathematical wave function; psi square is the physical probability. Remember: Square makes it real.

Uncertainty: Pin down position tightly, momentum becomes fuzzy. Quantum particles do not allow perfect tracking.

de Broglie: More momentum means shorter wavelength: fast heavy objects have negligible matter waves.

Examples2

de Broglie Concept Example

An electron accelerated to high velocity has measurable wavelength, so it can show diffraction. A cricket ball also has wavelength but it is immeasurably small due to large mass.

Uncertainty Example

If the position of an electron is known very accurately inside a tiny region, its velocity becomes highly uncertain, so a fixed Bohr-like path is impossible.

Common mistakes3

Thinking Uncertainty Is Instrument Error

Heisenberg uncertainty is not due to poor instruments; it is a fundamental limitation for microscopic particles.

Treating Orbitals as Fixed Paths

Orbitals are probability regions, not circular tracks followed by electrons.

Using de Broglie Significantly for Large Objects

All matter has wavelength, but for macroscopic objects it is too small to observe.

Reference tables2

Quick revision8

Formulas4

de Broglie Hypothesis
λ=h/mv=h/pλ = h / mv = h / p

Every moving particle has an associated wavelength.

λ
wavelength associated with particle
h
Planck constant
m
mass of particle
v
velocity of particle
p
momentum of particle
Heisenberg Uncertainty Principle
ΔxΔp≥h/4πΔx Δp ≥ h / 4π

There is a fundamental limit to simultaneous precision of position and momentum.

Δx
uncertainty in position
Δp
uncertainty in momentum
h
Planck constant
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Diagrams4

6

Atomic Orbitals & Quantum Numbers

10 min

Atomic orbitals are three-dimensional regions around the nucleus where the probability of finding an electron is high. Each electron in an atom is described by four quantum numbers. The principal quantum number, n, gives shell, size and energy level. The azimuthal quantum number, l, gives subshell and orbital shape; l = 0, 1, 2, 3 correspond to s, p, d and f. The magnetic quantum number, m, describes orbital orientation and has values from −l to +l. The spin quantum number, s, describes electron spin as +1/2 or −1/2. Orbital shapes include spherical s orbitals, dumbbell-shaped p orbitals, cloverleaf d orbitals and complex f orbitals. Nodes are zero-probability regions and are important for orbital structure.

Key points8

  • No two electrons in an atom can have the same set of four quantum numbers.
  • An orbital can hold maximum two electrons with opposite spins.
  • For n = 3, possible subshells are 3s, 3p and 3d.
  • p subshell has three orbitals: p_x, p_y and p_z.
  • d subshell has five orbitals and f subshell has seven orbitals.
  • s orbitals are spherical and non-directional.
  • Number of orbitals in a shell = n²; maximum electrons in shell = 2n².
  • Nodes increase with shell number and affect orbital energy and size.

Memory tricks3

Quantum Numbers: n = Nest, l = Look or shape, m = Magnetic orientation, s = Spin.

Subshell Order: s p d f corresponds to l = 0, 1, 2, 3. Remember: Some People Do Forget.

Nodes: Total nodes are one less than n. Angular nodes equal l. Whatever remains is radial nodes.

Examples2

Allowed Quantum Numbers Example

For a 3p electron: n = 3, l = 1, m can be −1, 0 or +1, and s can be +1/2 or −1/2.

Nodes Example

For 3p orbital, n = 3 and l = 1. Total nodes = 2, angular nodes = 1 and radial nodes = 1.

Common mistakes3

Using l = n

For a given n, l values go only from 0 to n − 1. If n = 3, l cannot be 3.

Wrong m Range

For l = 2, m values are −2, −1, 0, +1, +2, giving five d orbitals.

Ignoring Opposite Spins

Two electrons in the same orbital must have opposite spins, not the same spin.

Reference tables3

Quick revision8

Formulas5

Allowed l Values
l=0l = 0
11
22
......
n−1n − 1

Azimuthal quantum number values available for a given principal quantum number.

l
azimuthal quantum number
n
principal quantum number
Allowed m Values
m=−lto+lm = −l to +l

Magnetic quantum number values representing orientations of orbitals.

m
magnetic quantum number
l
azimuthal quantum number
Number of Orbitals in a Subshell
Number of orbitals =2l+1\text{Number of orbitals }= 2l + 1

Calculates the number of orientations in a subshell.

l
azimuthal quantum number
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Diagrams4

7

Electronic Configuration

10 min

Electronic configuration describes the distribution of electrons among orbitals of an atom or ion. Aufbau principle states that electrons fill lower-energy orbitals before higher-energy orbitals, generally guided by the n + l rule. Pauli exclusion principle states that an orbital can contain maximum two electrons and they must have opposite spins. Hund’s rule states that electrons occupy degenerate orbitals singly with parallel spins before pairing. The filling order explains configurations such as 1s² 2s² 2p⁶. Some atoms, especially chromium and copper, show exceptions because half-filled and fully-filled subshells are extra stable due to symmetry and exchange energy. Ions are formed by adding or removing electrons; for transition metal cations, electrons are removed from ns before (n − 1)d.

Key points7

  • Electronic configuration must conserve total number of electrons.
  • Orbital filling order is not simply 1, 2, 3, 4 shells; 4s fills before 3d.
  • Degenerate orbitals are orbitals of the same subshell with equal energy.
  • Half-filled and fully-filled configurations have greater stability.
  • For cations, remove electrons from the outermost shell first, not necessarily the last filled subshell.
  • Noble gas shorthand saves time and reduces mistakes.
  • Hund’s rule maximizes unpaired electrons before pairing begins.

Memory tricks4

Aufbau Order: Use the diagonal rule or remember: 1s 2s 2p 3s 3p 4s 3d 4p 5s.

Pauli Principle: One orbital is like a two-seat bench: only two electrons, and they must sit with opposite spins.

Hund's Rule: Empty bus seats first: electrons occupy separate equal-energy orbitals before pairing.

Cr and Cu: Chromium wants d⁵, copper wants d¹⁰. Half-filled and fully-filled d subshells are extra stable.

Examples3

Configuration of Calcium

Calcium has Z = 20. Configuration = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² or [Ar] 4s².

Configuration of Fe²⁺

Fe is [Ar] 3d⁶ 4s². For Fe²⁺, remove two 4s electrons first, so Fe²⁺ = [Ar] 3d⁶.

Configuration of Copper

Copper, Z = 29, has actual configuration [Ar] 3d¹⁰ 4s¹ because a completely filled d subshell is more stable.

Common mistakes4

Removing 3d Before 4s in Ions

Although 4s fills before 3d, transition metal cations lose 4s electrons before 3d electrons.

Pairing Too Early

In p, d and f subshells, electrons remain unpaired with parallel spins as far as possible before pairing.

Ignoring Exceptions

Cr and Cu do not follow the simple expected configuration because d⁵ and d¹⁰ are more stable.

Wrong Electron Count in Ions

Always adjust electron count first: cation loses electrons, anion gains electrons.

Reference tables4

Quick revision8

Formulas4

n + l Rule
Lower value of (n+l) fills first; if equal\text{Lower value of }(n + l)\text{ fills first};\text{ if equal}
lower n fills first\text{lower }n\text{ fills first}

Predicts relative order of orbital filling in Aufbau principle.

n
principal quantum number
l
azimuthal quantum number
Subshell Capacity
Maximum electrons in subshell =2(2l+1)\text{Maximum electrons in subshell }= 2(2l + 1)

Gives the maximum number of electrons in a subshell.

l
azimuthal quantum number
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Diagrams4

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NEET PYQs from Structure of Atom

The latest 3 of 27 previous-year questions from this chapter.

  1. NEET 2026Set 50MediumQ1

    Consider the following schematic plots of orbital wavefunction ($\psi_r$) against distance ($r$) from the nucleus. The figure representing two radial nodes in the orbital is

    • AA
    • BB
    • CC
    • DD
  2. NEET 2026Set 11EasyQ2

    Match List I with List II: Choose the correct answer from the options given below.

    • AA–IV, B–II, C–III, D–I
    • BA–II, B–III, C–I, D–IV
    • CA–II, B–III, C–IV, D–I
    • DA–I, B–II, C–III, D–IV
  3. NEET 2025Set 45MediumQ3

    The ratio of the wavelengths of the light absorbed by a Hydrogen atom when it undergoes n = 2 → n = 3 and n = 4 → n = 6 transitions, respectively, is

    • A1/36
    • B1/16
    • C1/9
    • D1/4

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