ChemistryNCERT Class 11
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Thermodynamics Notes

Study Notes

5 Topics28 Formulas42 PYQs39 Key Points

Topics

5
1

Chapter Overview

Overview

Thermodynamics studies heat, work, energy changes and the direction of chemical or physical processes. In chemistry, it helps predict whether a reaction releases heat, absorbs heat, or can occur spontaneously. The chapter begins with thermodynamic terms such as system, surroundings, state functions, path functions, heat, work and different processes. The first law connects heat, work and internal energy through conservation of energy. Enthalpy makes heat changes easier to study at constant pressure, especially using calorimetry. Hess Law allows calculation of reaction enthalpy through alternative paths, including bond enthalpy, lattice enthalpy and Born-Haber cycles. Finally, entropy and Gibbs energy decide spontaneity and equilibrium. For NEET, sign conventions, formula application and conceptual comparisons are extremely important.

Key Points7
  • 1Energy is conserved but can be transferred as heat or work.
  • 2Internal energy and enthalpy are state functions; heat and work are path functions.
  • 3Expansion work is negative for a system because the system loses energy by doing work.
  • 4Exothermic processes have negative ΔH, while endothermic processes have positive ΔH.
  • 5Entropy generally increases during melting, vaporization, expansion and formation of more gaseous moles.
  • 6A process is spontaneous at constant temperature and pressure when ΔG is negative.
  • 7NEET frequently asks ΔH-ΔU relation, work sign, Hess Law calculations and ΔG sign conditions.
Memory Tricks2

Thermodynamics Flow

Terms first, First Law next, heat measurement by calorimetry, path shortcut by Hess Law, and final decision by Gibbs energy.

Three Big Symbols

U means internal energy, H means heat content at constant pressure, G means go/no-go for spontaneity.

Examples2

Burning Fuel

Combustion of petrol releases heat, so ΔH is negative. Thermodynamics helps calculate heat released and predict feasibility.

Ice Melting

Ice melting absorbs heat, but entropy increases. At temperatures above 0°C, the TΔS term makes melting spontaneous.

Reference Tables2
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Common Mistakes2

Mixing Physics and Chemistry Work Signs

In chemistry, work done on the system is positive and expansion work done by the system is negative.

Using Celsius in Gibbs Equation

Always use kelvin in ΔG = ΔH - TΔS. Also convert entropy from J to kJ if enthalpy is in kJ.

Formula Cards4
First Law of Thermodynamics

Change in internal energy equals heat supplied to the system plus work done on the system.

Variables

ΔU=

change in internal energy of the system

q=

heat absorbed by the system

w=

work done on the system

Enthalpy

Enthalpy is a state function useful for heat changes at constant pressure.

Variables

H=

enthalpy

U=

internal energy

pV=

pressure-volume term

Diagrams3
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2

Thermodynamic Terms & Processes

Overview

Thermodynamic terms define the language of the chapter. A system is the part of the universe chosen for study, while surroundings include everything outside it. Systems may be open, closed or isolated depending on whether matter and energy can be exchanged. Properties such as pressure, volume, temperature and internal energy describe the state of a system. State functions depend only on initial and final states, whereas path functions such as heat and work depend on how the change occurs. Internal energy is the total microscopic energy stored in a system. Heat is energy transfer due to temperature difference, while work is energy transfer by force-displacement or pressure-volume change. Processes may be isothermal, adiabatic, isochoric or isobaric.

Key Points7
  • 1The universe in thermodynamics is system plus surroundings.
  • 2A boundary may be real or imaginary, fixed or movable, conducting or insulating.
  • 3State of a system is fixed when state variables such as p, V, T and composition are fixed.
  • 4Heat and work are not stored in a system; they are modes of energy transfer.
  • 5Internal energy changes due to heat and work exchange.
  • 6For ideal gas isothermal process, internal energy change is zero because internal energy depends only on temperature.
  • 7For adiabatic process, q = 0; for isochoric process, work due to volume change is zero.
Memory Tricks3

Open Closed Isolated

Open shares both matter and energy, Closed closes matter only, Isolated is alone and shares nothing.

Process Name Trick

Iso means same: isothermal same temperature, isochoric same volume, isobaric same pressure. Adiabatic means heat absent.

State Function Shortcut

State functions are like altitude: only start and end matter. Path functions are like distance walked: route matters.

Examples3

Open System

Hot tea in an open cup exchanges heat with air and also loses water vapour, so it is an open system.

Isochoric Process

Heating gas in a rigid sealed steel container increases pressure and temperature, but volume is constant, so PV work is zero.

Adiabatic Process

Rapid compression in a bicycle pump is approximately adiabatic; temperature rises because work is done on the gas.

Reference Tables4
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Common Mistakes3

Calling heat a state function

Heat is not contained in a system. It is energy in transit due to temperature difference, so q is a path function.

Confusing isolated and closed systems

A closed system can exchange energy but not matter. An isolated system exchanges neither matter nor energy.

Using wrong sign for expansion

For expansion, ΔV is positive, so w = -pextΔV is negative. The system does work on surroundings.

Formula Cards4
Universe Relation

Thermodynamic analysis divides the universe into the part studied and everything outside it.

Variables

system=

part selected for thermodynamic study

surroundings=

everything outside the system

PV Work

Work done during expansion or compression against constant external pressure.

Variables

w=

work done on the system

pext=

external pressure

ΔV=

change in volume of system

Diagrams3
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3

First Law of Thermodynamics

Overview

The First Law of Thermodynamics is the law of conservation of energy applied to thermodynamic systems. It states that energy can neither be created nor destroyed; it can only be converted from one form to another. For a chemical system, the change in internal energy equals heat supplied to the system plus work done on the system: ΔU = q + w. If heat is absorbed, q is positive; if heat is released, q is negative. If work is done on the system, w is positive; if the system expands and does work, w is negative. Enthalpy is defined as H = U + pV and becomes especially useful for constant-pressure reactions. For ideal gases, ΔH and ΔU differ by ΔngRT.

Key Points6
  • 1Internal energy is a state function, but heat and work are path functions.
  • 2For cyclic processes, ΔU = 0 because final state equals initial state.
  • 3For isochoric processes, ΔV = 0, so PV work is zero and qv = ΔU.
  • 4For isobaric processes, heat at constant pressure equals enthalpy change.
  • 5Δng includes only gaseous moles: moles of gaseous products minus moles of gaseous reactants.
  • 6In numerical problems, always keep units consistent: L atm, J or kJ must be converted properly.
Memory Tricks2

Chemistry Work Sign

Expansion: system spends energy, so w is negative. Compression: system receives work, so w is positive.

ΔH and ΔU Trick

ΔH differs from ΔU only when gaseous moles change significantly: remember the gas term ΔngRT.

Examples3

Numerical Example: Expansion Work

A gas expands from 2 L to 5 L against 1 atm. w = -pextΔV = -1 × 3 = -3 L atm = -303.9 J.

Numerical Example: First Law

If a system absorbs 500 J heat and does 200 J work, q = +500 J and w = -200 J, so ΔU = +300 J.

ΔH and ΔU Example

For N2(g) + 3H2(g) → 2NH3(g), Δng = 2 - 4 = -2, so ΔH = ΔU - 2RT.

Reference Tables3
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Common Mistakes3

Counting solids and liquids in Δng

In ΔH = ΔU + ΔngRT, count only gaseous reactants and gaseous products.

Using system pressure instead of external pressure

For irreversible expansion work against constant pressure, use external pressure: w = -pextΔV.

Forgetting unit conversion

1 L atm = 101.3 J. Convert work to J or kJ before adding to heat.

Formula Cards6
First Law

Relates internal energy change to heat and work using chemistry sign convention.

Variables

ΔU=

change in internal energy

q=

heat absorbed by system

w=

work done on system

Expansion or Compression Work

Work done when a gas expands or compresses against constant external pressure.

Variables

pext=

external pressure

V1=

initial volume

V2=

final volume

ΔV=

change in volume

Enthalpy Definition

Defines enthalpy as internal energy plus pressure-volume energy.

Variables

H=

enthalpy

U=

internal energy

pV=

pressure-volume term

Diagrams3
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4

Calorimetry & Enthalpy

Overview

Calorimetry is the experimental measurement of heat exchanged during physical or chemical changes. The basic equation q = mcΔT connects heat with mass, specific heat capacity and temperature change. Heat capacity is the heat required to raise the temperature of a body by 1 K, while specific heat capacity is for unit mass. In chemistry, enthalpy change is the heat exchanged at constant pressure. Standard enthalpy changes are measured under standard conditions, usually 1 bar and specified temperature, commonly 298 K. Standard enthalpy of formation is the enthalpy change when one mole of a compound forms from elements in their standard states. Enthalpies of combustion, neutralization and solution are important reaction enthalpies frequently tested in NEET numericals.

Key Points6
  • 1A calorimeter is designed to isolate heat exchange between reaction and measured surroundings.
  • 2In coffee-cup calorimetry, pressure is usually constant, so measured heat relates to ΔH.
  • 3In bomb calorimetry, volume is constant, so measured heat relates to ΔU.
  • 4The heat lost by hot body equals heat gained by cold body if no heat is lost to surroundings.
  • 5Standard enthalpy values depend on physical states of reactants and products.
  • 6Enthalpy of solution may be positive or negative depending on lattice breaking and hydration energy.
Memory Tricks3

Calorimetry Formula

q = mcΔT: mass carries heat capacity through temperature change.

Formation Enthalpy Rule

Elements in their standard states have ΔfH° = 0. Oxygen gas, graphite carbon and hydrogen gas are common examples.

Combustion Sign

Combustion means burning and heat release, so enthalpy of combustion is usually negative.

Examples3

Solved Example: Heating Water

50 g water is heated by 10 K. Using c = 4.18 J g−1 K−1, q = 50 × 4.18 × 10 = 2090 J.

Solved Example: Neutralization

If neutralization releases 2.85 kJ for 0.05 mol water formed, ΔH = -2.85/0.05 = -57 kJ mol−1.

Standard Formation Example

Formation of CO2: C(graphite) + O2(g) → CO2(g). The enthalpy change is ΔfH° of CO2.

Reference Tables3
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Common Mistakes3

Forgetting the negative sign for reaction heat

If solution gains heat, reaction loses heat. Therefore qreaction = -qsolution.

Using mass in kg with c in J g−1 K−1

Keep units consistent. If c is in J g−1 K−1, mass must be in grams.

Not converting heat to per mole

Calorimeter gives total heat for the sample used. Enthalpy is usually reported in kJ mol−1.

Formula Cards5
Heat Capacity

Heat capacity is heat required to raise temperature of a body by one kelvin.

Variables

C=

heat capacity

q=

heat supplied

ΔT=

temperature change

Specific Heat Capacity

Specific heat capacity is heat required to raise temperature of unit mass by one kelvin.

Variables

c=

specific heat capacity

m=

mass

ΔT=

temperature change

Calorimetry Equation

Used to calculate heat gained or lost by a substance from temperature change.

Variables

q=

heat exchanged

m=

mass of substance

c=

specific heat capacity

ΔT=

final temperature minus initial temperature

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5

Hess Law & Reaction Enthalpies

Overview

Hess Law states that the enthalpy change of a reaction is the same whether the reaction occurs in one step or many steps, provided the initial and final states are the same. This works because enthalpy is a state function. Therefore, difficult reaction enthalpies can be calculated by adding, reversing or multiplying known thermochemical equations. Reaction enthalpy can also be calculated using standard enthalpies of formation or average bond enthalpies. Enthalpy of bond dissociation measures energy needed to break one mole of bonds in gaseous molecules. Enthalpy of atomization forms gaseous atoms from an element. Lattice enthalpy measures energy change during ionic crystal formation or separation. Born-Haber cycle applies Hess Law to ionic solids and connects sublimation, ionization, dissociation, electron gain and lattice enthalpy.

Key Points6
  • 1Thermochemical equations must be balanced exactly before using enthalpy values.
  • 2Physical states matter because enthalpy depends on state of substances.
  • 3Average bond enthalpy gives approximate values because bond strength depends on molecular environment.
  • 4Atomization enthalpy produces gaseous atoms and is always endothermic.
  • 5Lattice enthalpy increases with higher ionic charges and smaller ionic radii.
  • 6Born-Haber cycles are useful for calculating unknown lattice enthalpy or checking ionic solid stability.
Memory Tricks3

Hess Law Shortcut

Reverse reaction, reverse sign. Multiply reaction, multiply heat. Add reactions, add heats.

Bond Enthalpy Trick

Broken bonds cost energy; formed bonds pay back energy. So ΔH = broken minus formed.

Lattice Enthalpy Trend

Small ions and high charges make a tight lattice, so lattice enthalpy magnitude becomes large.

Examples3

Formation Enthalpy Calculation

For CH4 + 2O2 → CO2 + 2H2O, ΔrH° = [ΔfH°CO2 + 2ΔfH°H2O] - [ΔfH°CH4 + 2ΔfH°O2]. Since O2 is an element in standard state, its ΔfH° is zero.

Bond Enthalpy Calculation

For H2 + Cl2 → 2HCl, ΔH ≈ BE(H-H) + BE(Cl-Cl) - 2BE(H-Cl).

Born-Haber Use

If all steps except lattice enthalpy are known for NaCl formation, Hess Law allows the unknown lattice enthalpy to be calculated.

Reference Tables3
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Common Mistakes3

Forgetting to change sign on reversing equation

If the thermochemical equation is reversed, ΔH must change sign.

Using bond enthalpy for solids or liquids directly

Bond enthalpies are usually gas-phase average values; they give approximate reaction enthalpies.

Ignoring physical states

H2O(l) and H2O(g) have different enthalpies. Always include physical states in Hess Law calculations.

Formula Cards4
Hess Law

Overall reaction enthalpy equals the sum of enthalpy changes of individual steps.

Variables

ΔHtotal=

enthalpy change of overall reaction

ΔH1, ΔH2=

enthalpy changes of individual steps

Reaction Enthalpy from Formation Enthalpies

Calculates standard reaction enthalpy using standard enthalpies of formation.

Variables

ΔrH°=

standard reaction enthalpy

ν=

stoichiometric coefficient

ΔfH°=

standard enthalpy of formation

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6

Spontaneity & Gibbs Energy

Overview

Spontaneity tells whether a process can occur on its own under given conditions, but it does not tell how fast it occurs. A spontaneous process may be fast, like acid-base neutralization, or slow, like rusting. Entropy measures randomness or dispersal of energy; it generally increases during expansion, mixing, melting, vaporization and formation of more gaseous particles. Total entropy of the universe increases for a spontaneous process. For chemical reactions at constant temperature and pressure, Gibbs free energy is the most useful criterion: ΔG = ΔH - TΔS. If ΔG is negative, the process is spontaneous; if positive, non-spontaneous; if zero, equilibrium. Gibbs energy is also related to equilibrium by ΔG° = -RT ln K, linking thermodynamics with chemical equilibrium.

Key Points7
  • 1Spontaneity depends on both enthalpy and entropy, not enthalpy alone.
  • 2Exothermic reactions are often spontaneous but not always.
  • 3Endothermic reactions can be spontaneous if entropy increase is large and temperature is high.
  • 4Temperature must be in kelvin in Gibbs equation.
  • 5Entropy unit is commonly J mol−1 K−1, while enthalpy is often kJ mol−1, so unit conversion is essential.
  • 6At equilibrium, ΔG = 0 but ΔG° may not be zero unless K = 1.
  • 7A catalyst cannot change ΔG; it only changes the rate of reaching equilibrium.
Memory Tricks3

Gibbs Spontaneity

Negative G means Go. Positive G means No. Zero G means equilibrium.

Temperature Cases

H negative, S positive: always yes. H positive, S negative: always no. Same signs depend on temperature.

Entropy Direction

Entropy likes gases, mixing, spreading, heating and more particles.

Examples3

Melting of Ice

Melting is endothermic, so ΔH is positive, but entropy increases. Above 273 K, TΔS becomes large enough to make ΔG negative.

Combustion

Combustion often has negative ΔH and may have favorable ΔG, but it still needs ignition because spontaneity does not remove activation energy.

Equilibrium Example

If K is greater than 1, ΔG° = -RT ln K is negative, meaning products are favored under standard-state comparison.

Reference Tables4
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Common Mistakes4

Equating spontaneity with speed

Spontaneous does not mean fast. Diamond converting to graphite is thermodynamically favored but extremely slow.

Forgetting unit conversion in ΔG

If ΔH is in kJ mol−1 and ΔS is in J mol−1 K−1, convert ΔS to kJ mol−1 K−1 before using ΔG = ΔH - TΔS.

Thinking catalyst changes ΔG

A catalyst lowers activation energy and changes rate, but it does not change ΔG, ΔH, ΔS or equilibrium constant.

Confusing ΔG and ΔG°

ΔG depends on actual conditions through Q, while ΔG° refers to standard conditions and relates to K.

Formula Cards5
Gibbs Free Energy Equation

Main equation for deciding spontaneity at constant temperature and pressure.

Variables

ΔG=

Gibbs energy change

ΔH=

enthalpy change

T=

absolute temperature in kelvin

ΔS=

entropy change

Entropy of Universe Criterion

A process is spontaneous when total entropy of the universe increases.

Variables

ΔSuniverse=

total entropy change of system plus surroundings

ΔSsystem=

entropy change of system

ΔSsurroundings=

entropy change of surroundings

Equilibrium Relation

Relates standard Gibbs energy change to equilibrium constant.

Variables

ΔG°=

standard Gibbs energy change

R=

gas constant

T=

absolute temperature

K=

equilibrium constant

Diagrams4
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Formula Sheet

10
First Law of Thermodynamics

Change in internal energy equals heat supplied to the system plus work done on the system.

Variables

ΔU=

change in internal energy of the system

q=

heat absorbed by the system

w=

work done on the system

Enthalpy

Enthalpy is a state function useful for heat changes at constant pressure.

Variables

H=

enthalpy

U=

internal energy

pV=

pressure-volume term

Gibbs Energy

Predicts spontaneity at constant temperature and pressure.

Variables

ΔG=

change in Gibbs free energy

ΔH=

enthalpy change

T=

temperature in kelvin

ΔS=

entropy change

Calorimetry Equation

Heat exchanged by a substance is calculated from mass, specific heat capacity and temperature change.

Variables

q=

heat exchanged

m=

mass of substance

c=

specific heat capacity

ΔT=

change in temperature

Universe Relation

Thermodynamic analysis divides the universe into the part studied and everything outside it.

Variables

system=

part selected for thermodynamic study

surroundings=

everything outside the system

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NEET PYQs — Thermodynamics

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NEET 2026Set 11EasyQ1

At a certain temperature T(K), during a process, 500 J is absorbed by the system and work of 200 J is done by the system. Then change in internal energy of the system is:

NEET 2026Set 11MediumQ2

Consider the following reaction: 2A(g) + B(g) → 2D(g) ΔU° = −10 kJ mol⁻¹ and ΔS° = −44 J K⁻¹ at 298 K Identify the correct option with ΔG° for the reaction and spontaneity of the reaction at 298 K. (Given: R = 8.31 J mol⁻¹ K⁻¹)

NEET 2026Set 11EasyQ3

An electric heater supplies heat to a system at a rate of 100 W. If the system performs work at a rate of 75 J/s, then the rate at which internal energy increases will be:

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