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5Chapter Overview
Overview
Thermodynamics studies heat, work, energy changes and the direction of chemical or physical processes. In chemistry, it helps predict whether a reaction releases heat, absorbs heat, or can occur spontaneously. The chapter begins with thermodynamic terms such as system, surroundings, state functions, path functions, heat, work and different processes. The first law connects heat, work and internal energy through conservation of energy. Enthalpy makes heat changes easier to study at constant pressure, especially using calorimetry. Hess Law allows calculation of reaction enthalpy through alternative paths, including bond enthalpy, lattice enthalpy and Born-Haber cycles. Finally, entropy and Gibbs energy decide spontaneity and equilibrium. For NEET, sign conventions, formula application and conceptual comparisons are extremely important.
- 1Energy is conserved but can be transferred as heat or work.
- 2Internal energy and enthalpy are state functions; heat and work are path functions.
- 3Expansion work is negative for a system because the system loses energy by doing work.
- 4Exothermic processes have negative ΔH, while endothermic processes have positive ΔH.
- 5Entropy generally increases during melting, vaporization, expansion and formation of more gaseous moles.
- 6A process is spontaneous at constant temperature and pressure when ΔG is negative.
- 7NEET frequently asks ΔH-ΔU relation, work sign, Hess Law calculations and ΔG sign conditions.
Thermodynamics Flow
Terms first, First Law next, heat measurement by calorimetry, path shortcut by Hess Law, and final decision by Gibbs energy.
Three Big Symbols
U means internal energy, H means heat content at constant pressure, G means go/no-go for spontaneity.
Burning Fuel
Combustion of petrol releases heat, so ΔH is negative. Thermodynamics helps calculate heat released and predict feasibility.
Ice Melting
Ice melting absorbs heat, but entropy increases. At temperatures above 0°C, the TΔS term makes melting spontaneous.
Mixing Physics and Chemistry Work Signs
In chemistry, work done on the system is positive and expansion work done by the system is negative.
Using Celsius in Gibbs Equation
Always use kelvin in ΔG = ΔH - TΔS. Also convert entropy from J to kJ if enthalpy is in kJ.
Change in internal energy equals heat supplied to the system plus work done on the system.
Variables
ΔU=change in internal energy of the system
q=heat absorbed by the system
w=work done on the system
Enthalpy is a state function useful for heat changes at constant pressure.
Variables
H=enthalpy
U=internal energy
pV=pressure-volume term
Thermodynamic Terms & Processes
Overview
Thermodynamic terms define the language of the chapter. A system is the part of the universe chosen for study, while surroundings include everything outside it. Systems may be open, closed or isolated depending on whether matter and energy can be exchanged. Properties such as pressure, volume, temperature and internal energy describe the state of a system. State functions depend only on initial and final states, whereas path functions such as heat and work depend on how the change occurs. Internal energy is the total microscopic energy stored in a system. Heat is energy transfer due to temperature difference, while work is energy transfer by force-displacement or pressure-volume change. Processes may be isothermal, adiabatic, isochoric or isobaric.
- 1The universe in thermodynamics is system plus surroundings.
- 2A boundary may be real or imaginary, fixed or movable, conducting or insulating.
- 3State of a system is fixed when state variables such as p, V, T and composition are fixed.
- 4Heat and work are not stored in a system; they are modes of energy transfer.
- 5Internal energy changes due to heat and work exchange.
- 6For ideal gas isothermal process, internal energy change is zero because internal energy depends only on temperature.
- 7For adiabatic process, q = 0; for isochoric process, work due to volume change is zero.
Open Closed Isolated
Open shares both matter and energy, Closed closes matter only, Isolated is alone and shares nothing.
Process Name Trick
Iso means same: isothermal same temperature, isochoric same volume, isobaric same pressure. Adiabatic means heat absent.
State Function Shortcut
State functions are like altitude: only start and end matter. Path functions are like distance walked: route matters.
Open System
Hot tea in an open cup exchanges heat with air and also loses water vapour, so it is an open system.
Isochoric Process
Heating gas in a rigid sealed steel container increases pressure and temperature, but volume is constant, so PV work is zero.
Adiabatic Process
Rapid compression in a bicycle pump is approximately adiabatic; temperature rises because work is done on the gas.
Calling heat a state function
Heat is not contained in a system. It is energy in transit due to temperature difference, so q is a path function.
Confusing isolated and closed systems
A closed system can exchange energy but not matter. An isolated system exchanges neither matter nor energy.
Using wrong sign for expansion
For expansion, ΔV is positive, so w = -pextΔV is negative. The system does work on surroundings.
Thermodynamic analysis divides the universe into the part studied and everything outside it.
Variables
system=part selected for thermodynamic study
surroundings=everything outside the system
Work done during expansion or compression against constant external pressure.
Variables
w=work done on the system
pext=external pressure
ΔV=change in volume of system
First Law of Thermodynamics
Overview
The First Law of Thermodynamics is the law of conservation of energy applied to thermodynamic systems. It states that energy can neither be created nor destroyed; it can only be converted from one form to another. For a chemical system, the change in internal energy equals heat supplied to the system plus work done on the system: ΔU = q + w. If heat is absorbed, q is positive; if heat is released, q is negative. If work is done on the system, w is positive; if the system expands and does work, w is negative. Enthalpy is defined as H = U + pV and becomes especially useful for constant-pressure reactions. For ideal gases, ΔH and ΔU differ by ΔngRT.
- 1Internal energy is a state function, but heat and work are path functions.
- 2For cyclic processes, ΔU = 0 because final state equals initial state.
- 3For isochoric processes, ΔV = 0, so PV work is zero and qv = ΔU.
- 4For isobaric processes, heat at constant pressure equals enthalpy change.
- 5Δng includes only gaseous moles: moles of gaseous products minus moles of gaseous reactants.
- 6In numerical problems, always keep units consistent: L atm, J or kJ must be converted properly.
Chemistry Work Sign
Expansion: system spends energy, so w is negative. Compression: system receives work, so w is positive.
ΔH and ΔU Trick
ΔH differs from ΔU only when gaseous moles change significantly: remember the gas term ΔngRT.
Numerical Example: Expansion Work
A gas expands from 2 L to 5 L against 1 atm. w = -pextΔV = -1 × 3 = -3 L atm = -303.9 J.
Numerical Example: First Law
If a system absorbs 500 J heat and does 200 J work, q = +500 J and w = -200 J, so ΔU = +300 J.
ΔH and ΔU Example
For N2(g) + 3H2(g) → 2NH3(g), Δng = 2 - 4 = -2, so ΔH = ΔU - 2RT.
Counting solids and liquids in Δng
In ΔH = ΔU + ΔngRT, count only gaseous reactants and gaseous products.
Using system pressure instead of external pressure
For irreversible expansion work against constant pressure, use external pressure: w = -pextΔV.
Forgetting unit conversion
1 L atm = 101.3 J. Convert work to J or kJ before adding to heat.
Relates internal energy change to heat and work using chemistry sign convention.
Variables
ΔU=change in internal energy
q=heat absorbed by system
w=work done on system
Work done when a gas expands or compresses against constant external pressure.
Variables
pext=external pressure
V1=initial volume
V2=final volume
ΔV=change in volume
Defines enthalpy as internal energy plus pressure-volume energy.
Variables
H=enthalpy
U=internal energy
pV=pressure-volume term
Calorimetry & Enthalpy
Overview
Calorimetry is the experimental measurement of heat exchanged during physical or chemical changes. The basic equation q = mcΔT connects heat with mass, specific heat capacity and temperature change. Heat capacity is the heat required to raise the temperature of a body by 1 K, while specific heat capacity is for unit mass. In chemistry, enthalpy change is the heat exchanged at constant pressure. Standard enthalpy changes are measured under standard conditions, usually 1 bar and specified temperature, commonly 298 K. Standard enthalpy of formation is the enthalpy change when one mole of a compound forms from elements in their standard states. Enthalpies of combustion, neutralization and solution are important reaction enthalpies frequently tested in NEET numericals.
- 1A calorimeter is designed to isolate heat exchange between reaction and measured surroundings.
- 2In coffee-cup calorimetry, pressure is usually constant, so measured heat relates to ΔH.
- 3In bomb calorimetry, volume is constant, so measured heat relates to ΔU.
- 4The heat lost by hot body equals heat gained by cold body if no heat is lost to surroundings.
- 5Standard enthalpy values depend on physical states of reactants and products.
- 6Enthalpy of solution may be positive or negative depending on lattice breaking and hydration energy.
Calorimetry Formula
q = mcΔT: mass carries heat capacity through temperature change.
Formation Enthalpy Rule
Elements in their standard states have ΔfH° = 0. Oxygen gas, graphite carbon and hydrogen gas are common examples.
Combustion Sign
Combustion means burning and heat release, so enthalpy of combustion is usually negative.
Solved Example: Heating Water
50 g water is heated by 10 K. Using c = 4.18 J g−1 K−1, q = 50 × 4.18 × 10 = 2090 J.
Solved Example: Neutralization
If neutralization releases 2.85 kJ for 0.05 mol water formed, ΔH = -2.85/0.05 = -57 kJ mol−1.
Standard Formation Example
Formation of CO2: C(graphite) + O2(g) → CO2(g). The enthalpy change is ΔfH° of CO2.
Forgetting the negative sign for reaction heat
If solution gains heat, reaction loses heat. Therefore qreaction = -qsolution.
Using mass in kg with c in J g−1 K−1
Keep units consistent. If c is in J g−1 K−1, mass must be in grams.
Not converting heat to per mole
Calorimeter gives total heat for the sample used. Enthalpy is usually reported in kJ mol−1.
Heat capacity is heat required to raise temperature of a body by one kelvin.
Variables
C=heat capacity
q=heat supplied
ΔT=temperature change
Specific heat capacity is heat required to raise temperature of unit mass by one kelvin.
Variables
c=specific heat capacity
m=mass
ΔT=temperature change
Used to calculate heat gained or lost by a substance from temperature change.
Variables
q=heat exchanged
m=mass of substance
c=specific heat capacity
ΔT=final temperature minus initial temperature
Hess Law & Reaction Enthalpies
Overview
Hess Law states that the enthalpy change of a reaction is the same whether the reaction occurs in one step or many steps, provided the initial and final states are the same. This works because enthalpy is a state function. Therefore, difficult reaction enthalpies can be calculated by adding, reversing or multiplying known thermochemical equations. Reaction enthalpy can also be calculated using standard enthalpies of formation or average bond enthalpies. Enthalpy of bond dissociation measures energy needed to break one mole of bonds in gaseous molecules. Enthalpy of atomization forms gaseous atoms from an element. Lattice enthalpy measures energy change during ionic crystal formation or separation. Born-Haber cycle applies Hess Law to ionic solids and connects sublimation, ionization, dissociation, electron gain and lattice enthalpy.
- 1Thermochemical equations must be balanced exactly before using enthalpy values.
- 2Physical states matter because enthalpy depends on state of substances.
- 3Average bond enthalpy gives approximate values because bond strength depends on molecular environment.
- 4Atomization enthalpy produces gaseous atoms and is always endothermic.
- 5Lattice enthalpy increases with higher ionic charges and smaller ionic radii.
- 6Born-Haber cycles are useful for calculating unknown lattice enthalpy or checking ionic solid stability.
Hess Law Shortcut
Reverse reaction, reverse sign. Multiply reaction, multiply heat. Add reactions, add heats.
Bond Enthalpy Trick
Broken bonds cost energy; formed bonds pay back energy. So ΔH = broken minus formed.
Lattice Enthalpy Trend
Small ions and high charges make a tight lattice, so lattice enthalpy magnitude becomes large.
Formation Enthalpy Calculation
For CH4 + 2O2 → CO2 + 2H2O, ΔrH° = [ΔfH°CO2 + 2ΔfH°H2O] - [ΔfH°CH4 + 2ΔfH°O2]. Since O2 is an element in standard state, its ΔfH° is zero.
Bond Enthalpy Calculation
For H2 + Cl2 → 2HCl, ΔH ≈ BE(H-H) + BE(Cl-Cl) - 2BE(H-Cl).
Born-Haber Use
If all steps except lattice enthalpy are known for NaCl formation, Hess Law allows the unknown lattice enthalpy to be calculated.
Forgetting to change sign on reversing equation
If the thermochemical equation is reversed, ΔH must change sign.
Using bond enthalpy for solids or liquids directly
Bond enthalpies are usually gas-phase average values; they give approximate reaction enthalpies.
Ignoring physical states
H2O(l) and H2O(g) have different enthalpies. Always include physical states in Hess Law calculations.
Overall reaction enthalpy equals the sum of enthalpy changes of individual steps.
Variables
ΔHtotal=enthalpy change of overall reaction
ΔH1, ΔH2=enthalpy changes of individual steps
Calculates standard reaction enthalpy using standard enthalpies of formation.
Variables
ΔrH°=standard reaction enthalpy
ν=stoichiometric coefficient
ΔfH°=standard enthalpy of formation
Spontaneity & Gibbs Energy
Overview
Spontaneity tells whether a process can occur on its own under given conditions, but it does not tell how fast it occurs. A spontaneous process may be fast, like acid-base neutralization, or slow, like rusting. Entropy measures randomness or dispersal of energy; it generally increases during expansion, mixing, melting, vaporization and formation of more gaseous particles. Total entropy of the universe increases for a spontaneous process. For chemical reactions at constant temperature and pressure, Gibbs free energy is the most useful criterion: ΔG = ΔH - TΔS. If ΔG is negative, the process is spontaneous; if positive, non-spontaneous; if zero, equilibrium. Gibbs energy is also related to equilibrium by ΔG° = -RT ln K, linking thermodynamics with chemical equilibrium.
- 1Spontaneity depends on both enthalpy and entropy, not enthalpy alone.
- 2Exothermic reactions are often spontaneous but not always.
- 3Endothermic reactions can be spontaneous if entropy increase is large and temperature is high.
- 4Temperature must be in kelvin in Gibbs equation.
- 5Entropy unit is commonly J mol−1 K−1, while enthalpy is often kJ mol−1, so unit conversion is essential.
- 6At equilibrium, ΔG = 0 but ΔG° may not be zero unless K = 1.
- 7A catalyst cannot change ΔG; it only changes the rate of reaching equilibrium.
Gibbs Spontaneity
Negative G means Go. Positive G means No. Zero G means equilibrium.
Temperature Cases
H negative, S positive: always yes. H positive, S negative: always no. Same signs depend on temperature.
Entropy Direction
Entropy likes gases, mixing, spreading, heating and more particles.
Melting of Ice
Melting is endothermic, so ΔH is positive, but entropy increases. Above 273 K, TΔS becomes large enough to make ΔG negative.
Combustion
Combustion often has negative ΔH and may have favorable ΔG, but it still needs ignition because spontaneity does not remove activation energy.
Equilibrium Example
If K is greater than 1, ΔG° = -RT ln K is negative, meaning products are favored under standard-state comparison.
Equating spontaneity with speed
Spontaneous does not mean fast. Diamond converting to graphite is thermodynamically favored but extremely slow.
Forgetting unit conversion in ΔG
If ΔH is in kJ mol−1 and ΔS is in J mol−1 K−1, convert ΔS to kJ mol−1 K−1 before using ΔG = ΔH - TΔS.
Thinking catalyst changes ΔG
A catalyst lowers activation energy and changes rate, but it does not change ΔG, ΔH, ΔS or equilibrium constant.
Confusing ΔG and ΔG°
ΔG depends on actual conditions through Q, while ΔG° refers to standard conditions and relates to K.
Main equation for deciding spontaneity at constant temperature and pressure.
Variables
ΔG=Gibbs energy change
ΔH=enthalpy change
T=absolute temperature in kelvin
ΔS=entropy change
A process is spontaneous when total entropy of the universe increases.
Variables
ΔSuniverse=total entropy change of system plus surroundings
ΔSsystem=entropy change of system
ΔSsurroundings=entropy change of surroundings
Relates standard Gibbs energy change to equilibrium constant.
Variables
ΔG°=standard Gibbs energy change
R=gas constant
T=absolute temperature
K=equilibrium constant
Formula Sheet
10Change in internal energy equals heat supplied to the system plus work done on the system.
Variables
ΔU=change in internal energy of the system
q=heat absorbed by the system
w=work done on the system
Enthalpy is a state function useful for heat changes at constant pressure.
Variables
H=enthalpy
U=internal energy
pV=pressure-volume term
Predicts spontaneity at constant temperature and pressure.
Variables
ΔG=change in Gibbs free energy
ΔH=enthalpy change
T=temperature in kelvin
ΔS=entropy change
Heat exchanged by a substance is calculated from mass, specific heat capacity and temperature change.
Variables
q=heat exchanged
m=mass of substance
c=specific heat capacity
ΔT=change in temperature
Thermodynamic analysis divides the universe into the part studied and everything outside it.
Variables
system=part selected for thermodynamic study
surroundings=everything outside the system
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NEET PYQs — Thermodynamics
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At a certain temperature T(K), during a process, 500 J is absorbed by the system and work of 200 J is done by the system. Then change in internal energy of the system is:
Consider the following reaction: 2A(g) + B(g) → 2D(g) ΔU° = −10 kJ mol⁻¹ and ΔS° = −44 J K⁻¹ at 298 K Identify the correct option with ΔG° for the reaction and spontaneity of the reaction at 298 K. (Given: R = 8.31 J mol⁻¹ K⁻¹)
An electric heater supplies heat to a system at a rate of 100 W. If the system performs work at a rate of 75 J/s, then the rate at which internal energy increases will be:
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