NEET Chemistry · NCERT Class 12

Solutions notes

Solution Basics and Types of Solutions, Concentration Terms, Solubility of Solids and Gases, Vapour Pressure and Raoult's Law, Ideal, Non-Ideal Solutions and Azeotropes, Colligative Properties: Vapour Pressure, Boiling and Freezing, Osmosis and Osmotic Pressure, Abnormal Molar Mass and Van't Hoff Factor, NEET Numerical Strategy and Formula Sheet and Complete Chapter Mind Map and Quick Revision — explained topic by topic with key points, formulas, memory tricks and common mistakes.

  • 10 topics
  • 72 min read
  • 32 formulas
  • 43 PYQs
1

Solution Basics and Types of Solutions

6 min

A solution is a homogeneous mixture of two or more substances whose composition is uniform throughout. The component present in smaller amount is generally called solute, while the component present in larger amount is solvent. Solutions may be solid, liquid or gaseous depending on the physical state of solvent and solute. NEET questions often test classification, saturation, and the difference between true solutions, suspensions and colloids. A saturated solution contains maximum solute at a given temperature, an unsaturated solution can dissolve more solute, and a supersaturated solution contains more solute than normally possible and is unstable. Understanding these basics is essential before learning concentration, vapour pressure and colligative properties.

Key points5

  • The terms solute and solvent are relative; in aqueous solutions, water is usually the solvent.
  • A true solution has uniform composition and particles cannot be separated by ordinary filtration.
  • Saturation depends strongly on temperature and pressure.
  • Supersaturation is a metastable condition useful in crystallization.
  • NEET frequently asks examples of solid-solid, gas-liquid and liquid-liquid solutions.

Memory tricks2

Solvent Sets the State: Remember: the solvent usually decides whether the solution is solid, liquid or gas.

Saturation Ladder: Unsaturated = wants more, saturated = full, supersaturated = overfull and unstable.

Examples2

Daily Life Solution

Salt water is a solid-in-liquid solution where sodium chloride is solute and water is solvent.

Alloy Example

Brass is a solid solution of zinc in copper.

Common mistakes2

Confusing solute with smaller volume only

Solute is usually smaller in amount, but in aqueous chemistry water is often called solvent even if quantities are comparable.

Ignoring temperature in saturation

A solution saturated at one temperature may become unsaturated or supersaturated at another temperature.

Reference tables2

Quick revision6

Formulas1

Basic Representation of a Solution
Solution = Solute + Solvent\text{Solution }=\text{ Solute }+\text{ Solvent}

A symbolic way to remember that a solution is formed when solute particles disperse uniformly in a solvent.

Solute
Component dissolved, usually present in smaller amount
Solvent
Component that dissolves the solute, usually present in larger amount

Diagrams3

2

Concentration Terms

8 min

Concentration tells how much solute is present in a given amount of solution or solvent. NCERT and NEET use several concentration units because different experiments require different references. Percentage terms are useful for commercial solutions, ppm is used for very dilute solutions such as pollutants, mole fraction is important in vapour pressure and Raoult’s law, molarity is useful in volumetric analysis but changes with temperature, while molality is temperature independent and used in colligative properties. Normality is not emphasized deeply in NCERT but is useful for NEET practice in acid-base and redox calculations. Mastering interconversion between these terms prevents most numerical errors in this chapter.

Key points5

  • Always identify whether denominator is solution or solvent.
  • Use molality for boiling point elevation and freezing point depression.
  • Use mole fraction for Raoult’s law and partial vapour pressure.
  • 1 ppm commonly means 1 mg per kg or 1 mg per L for dilute water solutions.
  • Temperature affects volume-based units but not mass-based units.

Memory tricks2

Molarity vs Molality: Molarity has R for litre beaker volume; molality has LAL like kilogram solvent mass.

Denominator Alert: Percent and molarity use solution; molality uses solvent. This single distinction solves many NEET traps.

Examples2

Mass Percent Example

10 g NaCl in 90 g water gives mass percent = 10/100 × 100 = 10%.

Molarity Example

0.5 mol glucose in 250 mL solution gives M = 0.5/0.25 = 2.0 M.

Common mistakes2

Using solvent mass in mass percent

Mass percent denominator is mass of solution, not mass of solvent.

Forgetting temperature dependence

Molarity changes with temperature because volume changes; molality does not.

Reference tables2

Quick revision7

Formulas5

Mass Percentage
Mass \text{Mass }% = (\text{mass of solute }/\text{ mass of solution}) × 100

Used to express mass of solute in 100 parts by mass of solution.

mass of solute
Mass of dissolved substance
mass of solution
Mass of solute plus solvent
Mole Fraction
χA=nA/(nA+nB)χA = nA / (nA + nB)

Fraction of total moles contributed by component A in a binary solution.

χA
Mole fraction of component A
nA
Moles of component A
nB
Moles of component B
Molarity
M= moles of solute / volume of solution in litreM =\text{ moles of solute }/\text{ volume of solution in litre}

Moles of solute present in one litre of solution.

M
Molarity in mol L⁻¹
volume
Total volume of solution in litres
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3

Solubility of Solids and Gases

7 min

Solubility is the maximum amount of solute that can dissolve in a given amount of solvent at a specified temperature and pressure. For solids in liquids, solubility depends mainly on nature of solute-solvent interactions and temperature. If dissolution is endothermic, solubility generally increases with temperature; if exothermic, it may decrease. For gases in liquids, pressure plays a major role and is explained by Henry’s law: solubility of a gas is proportional to its partial pressure above the solution. Gas solubility usually decreases with increase in temperature, which is why warm water holds less dissolved oxygen. This concept is important for scuba diving, carbonated drinks and aquatic life.

Key points5

  • Solubility is an equilibrium property and must mention temperature.
  • Pressure has little effect on solid and liquid solubility but large effect on gas solubility.
  • Henry’s law applies best for dilute solutions and gases that do not react with solvent.
  • Deep-sea divers can suffer bends due to dissolved nitrogen escaping rapidly.
  • Carbonated drinks are bottled under high CO2 pressure.

Memory tricks2

Gas Rule: Gas likes cold and pressure: cold water and high pressure dissolve more gas.

Henry Constant: Higher KH means gas is harder to dissolve because x = p/KH.

Examples2

Soft Drink

CO2 is dissolved under high pressure; when bottle is opened pressure decreases and fizz appears.

Warm Lakes

Warm water contains less dissolved oxygen, which can stress aquatic animals.

Common mistakes2

Wrong KH interpretation

For p = KHx, larger KH means smaller x at same p, so lower solubility.

Applying Henry's law to reacting gases

Henry's law is not directly valid when the gas reacts strongly with solvent.

Reference tables2

Quick revision7

Formulas2

Henry's Law
p=KH×xp = KH × x

Partial pressure of a gas above solution is proportional to its mole fraction in solution.

p
Partial pressure of gas
KH
Henry's law constant
x
Mole fraction of gas in solution
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4

Vapour Pressure and Raoult's Law

7 min

Vapour pressure is the pressure exerted by vapour in equilibrium with its liquid at a given temperature. When a non-volatile solute is added to a volatile solvent, fewer solvent molecules are present at the surface, so vapour pressure decreases. Raoult’s law states that for an ideal solution, partial vapour pressure of each volatile component equals its mole fraction multiplied by vapour pressure of the pure component. For a solution of non-volatile solute in volatile solvent, relative lowering of vapour pressure equals mole fraction of solute. This is the foundation of one colligative property and helps in determining molar mass of solutes.

Key points5

  • Raoult’s law is exactly obeyed by ideal solutions.
  • For volatile components, each component contributes partial vapour pressure.
  • For non-volatile solute, only solvent contributes to vapour pressure.
  • Lower vapour pressure leads to higher boiling point.
  • Mole fraction is the concentration term used in Raoult’s law.

Memory tricks2

Raoult Reminder: Partial pressure follows its fraction: pA follows χA.

Solute Blocks Surface: Non-volatile solute acts like chairs occupied at the surface, leaving fewer solvent molecules to escape.

Examples2

Sugar in Water

Sugar is non-volatile, so sugar solution has lower vapour pressure than pure water.

Benzene-Toluene Mixture

Nearly ideal mixture where each component contributes vapour pressure according to mole fraction.

Common mistakes2

Using molarity in Raoult's law

Raoult’s law uses mole fraction, not molarity or molality.

Forgetting volatile solute contribution

If both components are volatile, total pressure includes vapour pressure of both components.

Reference tables2

Quick revision6

Formulas3

Raoult's Law for Component A
pA=χApA°pA = χA pA°

Partial vapour pressure of A in an ideal solution is proportional to its mole fraction.

pA
Partial vapour pressure of component A
χA
Mole fraction of component A
pA°
Vapour pressure of pure component A
Total Vapour Pressure
ptotal =pA+pB\text{ptotal }= pA + pB

Total vapour pressure of a binary volatile solution is the sum of partial pressures.

ptotal
Total vapour pressure
pA
Partial pressure of component A
pB
Partial pressure of component B
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5

Ideal, Non-Ideal Solutions and Azeotropes

8 min

Ideal solutions obey Raoult’s law over the entire composition range and have zero enthalpy and volume change on mixing. This happens when A-B interactions are similar to A-A and B-B interactions, as in benzene-toluene. Non-ideal solutions deviate from Raoult’s law because solute-solvent interactions differ from pure component interactions. Positive deviation occurs when A-B attractions are weaker, causing higher vapour pressure and often minimum boiling azeotropes. Negative deviation occurs when A-B attractions are stronger, causing lower vapour pressure and often maximum boiling azeotropes. Azeotropes are constant-boiling mixtures whose vapour composition equals liquid composition, so they cannot be separated by simple fractional distillation.

Key points5

  • Compare A-B interaction with A-A and B-B interactions to predict deviation.
  • Positive deviation shows endothermic mixing and volume expansion.
  • Negative deviation shows exothermic mixing and volume contraction.
  • Ethanol-water forms a minimum boiling azeotrope.
  • HNO3-water forms a maximum boiling azeotrope.

Memory tricks2

Positive Means Pressure Up: Positive deviation = positive extra vapour pressure because molecules escape more easily.

Negative Means Net Attraction: Negative deviation has stronger A-B attraction, so molecules are held down and pressure drops.

Examples2

Positive Deviation

Ethanol and acetone show positive deviation because acetone disrupts ethanol-ethanol hydrogen bonding.

Negative Deviation

Chloroform and acetone show negative deviation due to strong attractive interactions between unlike molecules.

Common mistakes2

Mixing boiling point direction

Positive deviation gives minimum boiling azeotrope, while negative deviation gives maximum boiling azeotrope.

Calling azeotropes ideal

Azeotropes are non-ideal constant-boiling mixtures, not ideal solutions.

Reference tables2

Quick revision7

Formulas3

Ideal Mixing Enthalpy
ΔHmix =0Δ\text{Hmix }= 0

No heat is absorbed or released when ideal solution components mix.

ΔHmix
Enthalpy change on mixing
Ideal Mixing Volume
ΔVmix =0Δ\text{Vmix }= 0

Total volume of ideal solution equals sum of component volumes.

ΔVmix
Volume change on mixing
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6

Colligative Properties: Vapour Pressure, Boiling and Freezing

9 min

Colligative properties depend only on the number of solute particles, not their chemical identity, for dilute solutions. Addition of a non-volatile solute lowers vapour pressure, raises boiling point and lowers freezing point of the solvent. Relative lowering of vapour pressure is directly related to mole fraction of solute. Elevation in boiling point is proportional to molality and uses the ebullioscopic constant Kb. Depression in freezing point is also proportional to molality and uses the cryoscopic constant Kf. These properties are extensively used to determine molar mass of solutes. NEET numericals usually require careful use of molality, solute mass, solvent mass in kg and molar mass.

Key points5

  • Colligative properties are best applied to dilute solutions.
  • Kb and Kf are characteristic constants of solvent, not solute.
  • Elevation of boiling point occurs because solution vapour pressure reaches atmospheric pressure at higher temperature.
  • Depression of freezing point occurs because solution has lower chemical potential than pure solvent.
  • For electrolytes, include van’t Hoff factor i.

Memory tricks2

Boil Up, Freeze Down: Adding solute makes boiling point go up and freezing point go down.

Kb and Kf Belong to Solvent: K constants are like the solvent’s personality, not the solute’s identity.

Examples2

Antifreeze

Ethylene glycol lowers freezing point of water in car radiators.

Cooking Salt

Adding salt slightly raises boiling point of water, though household effect is small.

Common mistakes2

Using mass of solution instead of solvent

Molality uses kg of solvent only, not total solution mass.

Using final boiling point as ΔTb

ΔTb is solution boiling point minus pure solvent boiling point.

Reference tables2

Quick revision7

Formulas4

Elevation of Boiling Point
ΔTb=KbmΔTb = Kb m

Increase in boiling point is proportional to molality for dilute non-electrolyte solutions.

ΔTb
Boiling point elevation
Kb
Ebullioscopic constant of solvent
m
Molality of solution
Depression of Freezing Point
ΔTf=KfmΔTf = Kf m

Decrease in freezing point is proportional to molality for dilute non-electrolyte solutions.

ΔTf
Freezing point depression
Kf
Cryoscopic constant of solvent
m
Molality of solution
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7

Osmosis and Osmotic Pressure

7 min

Osmosis is the spontaneous flow of solvent molecules through a semipermeable membrane from dilute solution or pure solvent to concentrated solution. The pressure required to stop this flow is osmotic pressure, represented by π. For dilute solutions, osmotic pressure follows an equation similar to the ideal gas equation: π = CRT or πV = nRT. It is a colligative property because it depends on the number of solute particles. Osmotic pressure is especially useful for determining molar masses of biomolecules because it is measurable even at low concentrations and room temperature. Biological systems depend on isotonic balance to prevent cell swelling or shrinkage.

Key points5

  • Semipermeable membrane allows solvent but not solute particles.
  • Osmotic pressure uses molarity, unlike ΔTb and ΔTf which use molality.
  • Osmotic pressure is directly proportional to temperature and concentration.
  • Reverse osmosis is used in desalination and water purification.
  • For electrolytes, osmotic pressure becomes π = iCRT.

Memory tricks2

Water Goes Where Solute Is More: In osmosis, solvent moves toward the side that has more solute particles.

π Uses C: Osmotic pressure uses concentration C or molarity, not molality.

Examples2

Raisins in Water

Raisins swell in water because water enters cells by osmosis.

Reverse Osmosis Purifier

External pressure greater than osmotic pressure pushes water through a membrane, leaving salts behind.

Common mistakes2

Reversing osmosis direction

Solvent moves from dilute to concentrated solution, not solute from concentrated to dilute.

Forgetting Kelvin temperature

Always use T in kelvin in π = CRT.

Reference tables2

Quick revision7

Formulas3

Osmotic Pressure
π=CRTπ = C R T

Osmotic pressure of a dilute non-electrolyte solution.

π
Osmotic pressure
C
Molar concentration of solution
R
Gas constant
T
Temperature in kelvin
Osmotic Pressure in Mole Form
πV=nRTπV = nRT

Useful when moles of solute and volume of solution are given.

V
Volume of solution
n
Moles of solute
R
Gas constant
T
Temperature in kelvin
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8

Abnormal Molar Mass and Van't Hoff Factor

9 min

Colligative properties depend on number of solute particles. If solute particles associate, the number of particles decreases and observed colligative effect becomes smaller, giving an abnormally high molar mass. If solute particles dissociate into ions, the number of particles increases and observed colligative effect becomes larger, giving an abnormally low molar mass. Van’t Hoff factor i corrects this behaviour by comparing observed colligative property with normal calculated value. For association, i is less than 1; for dissociation, i is greater than 1. NEET often asks relation of i with degree of dissociation or association and its use in ΔTb, ΔTf and osmotic pressure.

Key points5

  • Abnormal molar mass is not an error; it indicates particle number change.
  • Association commonly occurs through hydrogen bonding or dimer formation.
  • Dissociation occurs for electrolytes such as NaCl, KCl and CaCl2.
  • Actual i may be less than theoretical due to incomplete dissociation or ion pairing.
  • Use total effective particles after association/dissociation to judge colligative effect.

Memory tricks2

A-D Rule: Association Adds together so particles decrease; Dissociation Divides apart so particles increase.

i Direction: i < 1 means joining; i > 1 means breaking.

Examples2

Benzoic Acid

Benzoic acid associates as dimers in benzene, so observed molar mass is nearly double.

Sodium Chloride

NaCl dissociates into Na+ and Cl-, so colligative effect is nearly twice that of a non-electrolyte of same molality.

Common mistakes2

Using theoretical i blindly

Actual i may be lower than theoretical if dissociation is incomplete.

Reversing abnormal molar mass

Association gives higher observed molar mass; dissociation gives lower observed molar mass.

Reference tables2

Quick revision7

Formulas4

Van't Hoff Factor
i= observed colligative property / calculated colligative propertyi =\text{ observed colligative property }/\text{ calculated colligative property}

Measures how the actual number of particles differs from expected number.

i
Van't Hoff factor
observed colligative property
Experimental value
calculated colligative property
Value expected for no association or dissociation
Molar Mass Relation
i= normal molar mass / observed molar massi =\text{ normal molar mass }/\text{ observed molar mass}

Used to interpret abnormal molar mass in colligative property experiments.

normal molar mass
True formula molar mass
observed molar mass
Molar mass calculated without considering i
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9

NEET Numerical Strategy and Formula Sheet

6 min

Most NEET questions from Solutions are formula-based but conceptually tricky because of units, concentration choice and abnormal molar mass. Start by identifying the property: vapour pressure uses mole fraction, boiling and freezing point use molality, and osmotic pressure uses molarity. Convert solvent mass into kg for molality and solution volume into litre for molarity. Check whether the solute is an electrolyte, associates or dissociates; if yes, include van’t Hoff factor i. For molar mass questions, carefully distinguish solute mass from solvent mass. A systematic approach prevents errors and allows quick solving under exam pressure. This topic acts as a final revision formula sheet.

Key points5

  • Identify property before selecting formula.
  • Write units beside every value to avoid denominator mistakes.
  • For electrolytes, multiply colligative property by i.
  • For molar mass determination, rearrange formula only after substituting correct units.
  • NEET often hides solvent mass and solute mass in word problems.

Memory tricks2

χ-m-C Map: Raoult uses χ, boiling/freezing use m, osmosis uses C.

i Multiplies Effects: Whenever particles change, put i in front of every colligative formula.

Examples2

Fast Boiling Point Setup

For 2 g solute in 100 g solvent, first write m = (2/M2)/(0.100), then use ΔTb = iKb m.

Fast Osmosis Setup

If 0.01 mol solute is in 500 mL at 300 K, C = 0.01/0.5 = 0.02 M, then π = iCRT.

Common mistakes2

Wrong gas constant unit

Use R = 0.0821 only with litre-atm units; use 8.314 with SI units.

Missing factor 1000

Direct molar mass formulas using solvent mass in grams need the factor 1000.

Reference tables2

Quick revision7

Formulas4

Master Colligative Formula
Observed property =i× normal colligative property\text{Observed property }= i ×\text{ normal colligative property}

Universal correction for association or dissociation.

i
Van't Hoff factor
normal colligative property
Value for non-electrolyte without association
Boiling Point Shortcut
ΔTb=iKb(w2×1000)/(M2×w1)ΔTb = i Kb (w2 × 1000) / (M2 × w1)

Direct formula using solute mass, molar mass and solvent mass in grams.

w2
Mass of solute in grams
w1
Mass of solvent in grams
M2
Molar mass of solute
i
Van't Hoff factor
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10

Complete Chapter Mind Map and Quick Revision

5 min

The chapter Solutions connects mixture formation, concentration expression, solubility, vapour pressure and particle-number effects. Begin with the idea of homogeneous mixtures and types of solutions. Then learn concentration units because every numerical depends on choosing the correct unit. Solubility explains how temperature, pressure and molecular interactions decide dissolution; Henry’s law is central for gases. Raoult’s law connects mole fraction to vapour pressure and separates ideal from non-ideal behaviour. Colligative properties show how non-volatile solutes lower vapour pressure, raise boiling point, lower freezing point and create osmotic pressure. Finally, abnormal molar mass and van’t Hoff factor correct formulas when solutes associate or dissociate.

Key points5

  • Always attach temperature to solubility and vapour pressure.
  • Mole fraction is unitless and central to vapour pressure.
  • Molality is preferred for temperature-dependent colligative properties.
  • Osmotic pressure is highly useful for biomolecular molar mass.
  • i summarizes effective particle count and modifies all colligative formulas.

Memory tricks2

Chapter Chain: Types → Concentration → Solubility → Raoult → Deviations → Colligative → i.

Three Concentration Anchors: χ for vapour, m for temperature changes, C for osmosis.

Examples2

Integrated Example

NaCl in water affects boiling point, freezing point and osmotic pressure more than glucose of same molality because NaCl dissociates into ions.

Concept Map Example

Adding sugar to water lowers vapour pressure; this causes boiling point elevation and freezing point depression.

Common mistakes2

Learning formulas without conditions

Most formulas assume dilute solutions and often non-volatile solute; check conditions before applying.

Ignoring NCERT examples

Examples like benzene-toluene, ethanol-water, chloroform-acetone and benzoic acid dimer are high-yield.

Reference tables1

Quick revision7

Formulas3

Raoult's Law
pA=χApA°pA = χA pA°

Vapour pressure relation for ideal liquid solutions.

pA
Partial pressure of component A
χA
Mole fraction of A
pA°
Vapour pressure of pure A
Henry's Law
p=KHxp = KHx

Pressure-solubility relation for gases in liquids.

p
Partial pressure of gas
KH
Henry's law constant
x
Mole fraction of gas
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NEET PYQs from Solutions

The latest 3 of 43 previous-year questions from this chapter.

  1. NEET 2026Set 50EasyQ1

    Assertion A: For an ideal solution formed by mixing liquids P and Q, $\Delta_{mix}H = 0$ and $\Delta_{mix}V = 0$ Reason R: No interactions occur between P and Q In the light of the above statements, choose the most appropriate answer from the options given below.

    • ABoth A and R are correct and R is the correct explanation of A
    • BBoth A and R are correct but R is NOT the correct explanation of A
    • CA is correct but R is not correct
    • DA is not correct but R is correct
  2. NEET 2026Set 50EasyQ2

    Consider the following statements about the solutions formed by mixing two liquids. A. An ideal solution thus formed obeys Raoult's law throughout the composition range. B. Mixture of chloroform and acetone shows negative deviation from Raoult's law. C. Mixture of aniline and phenol shows positive deviation from Raoult's law.

    • AA and B only
    • BB and C only
    • CA only
    • DA and C only
  3. NEET 2026Set 11EasyQ3

    Mixture of chloroform and acetone forms a solution with negative deviation from Raoult’s law due to:

    • AIncrease in escaping tendency of molecules of each component
    • BFormation of hydrogen bonding between acetone and chloroform
    • CStronger intermolecular forces between chloroform molecules than those between chloroform and acetone molecules
    • DRepulsive forces

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