NEET Physics · NCERT Class 12

Alternating Current notes

AC Fundamentals, AC in Resistor, Inductor & Capacitor, LCR Circuits & Resonance, Power Factor and Transformers — explained topic by topic with key points, formulas, memory tricks and common mistakes.

  • 6 topics
  • 58 min read
  • 30 formulas
  • 30 PYQs
1

Chapter Overview

8 min

Alternating Current studies current and voltage that vary periodically with time, usually sinusoidally. The chapter begins with AC fundamentals such as waveform, time period, frequency, angular frequency, peak value, mean value, RMS value and phase difference. It then explains how a resistor, inductor and capacitor behave separately in AC circuits using resistance, inductive reactance and capacitive reactance. Series LCR circuits combine all three and show resonance when inductive and capacitive effects cancel. Power factor explains how effectively AC power is used and why some current may be wattless. Finally, transformers apply mutual induction to step voltage up or down. For NEET, this chapter is formula-rich and frequently tests RMS values, reactance, resonance, power and transformer ratios.

Key points6

  • NEET often asks direct formulas from RMS values, reactance, impedance and transformer relations.
  • AC analysis requires both magnitude and phase, so phasors are very useful.
  • Inductor and capacitor do not consume average power in ideal pure AC circuits.
  • At resonance, impedance of series LCR circuit is minimum and current is maximum.
  • Average power in AC circuit is Pavg = VrmsIrms cosϕ.
  • Power factor correction improves useful power transfer and reduces losses.

Memory tricks2

RMS Meaning: RMS is the heating equivalent DC value: it tells how much heat AC can produce.

Chapter Flow Trick: Wave basics → RLC behaviour → resonance → power factor → transformer.

Examples2

NEET-Style Snapshot

If peak voltage is 220√2 V, RMS voltage is 220 V because Vrms = V0/√2.

Real-Life Example

Domestic supply is AC because voltage can be stepped up or down efficiently using transformers.

Common mistakes2

Using Peak Value Instead of RMS

Power and household voltage calculations usually use RMS values unless peak is specifically mentioned.

Ignoring Phase

In AC circuits, voltage and current may not peak together. Phase difference affects power.

Reference tables2

Quick revision8

Formulas5

Sinusoidal AC Current
I=I0sinωtI = I0 sinωt

Instantaneous current in a sinusoidal alternating current circuit.

I
Instantaneous current
I0
Peak current
ω
Angular frequency
t
Time
RMS Values
Irms =I0/√2\text{Irms }= I0/√2
Vrms =V0/√2\text{Vrms }= V0/√2

Effective AC values that produce the same heating effect as DC.

Irms
Root mean square current
Vrms
Root mean square voltage
I0, V0
Peak current and peak voltage
Reactances
XL=ωLXL = ωL
XC=1/(ωC)XC = 1/(ωC)

Opposition offered by inductor and capacitor to alternating current.

XL
Inductive reactance
XC
Capacitive reactance
L
Inductance
C
Capacitance
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Diagrams3

2

AC Fundamentals

9 min

Alternating current and voltage change magnitude and direction periodically with time. In most circuits, they are represented by sine or cosine functions such as I = I0 sinωt and V = V0 sinωt. A complete repetition is one cycle, whose duration is the time period T. Frequency f is the number of cycles per second, and angular frequency is ω = 2πf. Since AC changes continuously, useful values include peak, RMS and mean values. RMS value is most important because it gives the equivalent DC heating effect. Mean value over a full cycle of symmetrical AC is zero, while mean over a half cycle is non-zero. Phase difference tells how much one AC quantity leads or lags another.

Key points6

  • Peak value is maximum instantaneous value.
  • RMS value is used in heating, power and household AC ratings.
  • Mean value over half cycle of sine wave is 2I0/π.
  • A phase difference of π/2 means one quantity reaches maximum a quarter cycle earlier.
  • If two AC waves have the same phase, their peaks and zeros occur together.
  • Angular frequency is measured in rad s⁻¹, while frequency is measured in hertz.

Memory tricks2

RMS Shortcut: For sine AC, RMS is peak divided by root two.

Mean Value Reminder: Full-cycle mean of symmetrical AC is zero because positive and negative halves cancel.

Examples2

RMS Numerical

If peak current is 10 A, RMS current is Irms = 10/√2 = 7.07 A.

Previous NEET-Type Question

For Indian domestic AC of frequency 50 Hz, time period T = 1/50 = 0.02 s and angular frequency ω = 100π rad/s.

Common mistakes2

Confusing Mean and RMS

Mean over full cycle is zero for sinusoidal AC, but RMS is not zero and is used for power.

Using Frequency Instead of Angular Frequency

In I = I0 sinωt, use angular frequency ω in rad/s, not frequency f directly.

Reference tables2

Quick revision8

Formulas5

Alternating Current and Voltage
I=I0sinωtI = I0 sinωt
V=V0sinωtV = V0 sinωt

Instantaneous sinusoidal current and voltage.

I, V
Instantaneous current and voltage
I0, V0
Peak current and peak voltage
ω
Angular frequency
t
Time
Time Period and Frequency
f=1/Tf = 1/T

Frequency is reciprocal of time period.

f
Frequency
T
Time period
Angular Frequency
ω=2πf=2π/Tω = 2πf = 2π/T

Rate of phase change in sinusoidal AC.

ω
Angular frequency
f
Frequency
T
Time period
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Diagrams4

3

AC in Resistor, Inductor & Capacitor

11 min

A resistor, inductor and capacitor respond differently to alternating current. In a pure resistor, current and voltage are in the same phase and energy is dissipated as heat. In a pure inductor, voltage leads current by 90° because the inductor opposes change in current; its opposition is inductive reactance XL = ωL. In a pure capacitor, current leads voltage by 90° because current is maximum when voltage changes fastest; its opposition is capacitive reactance XC = 1/ωC. These phase relations are best represented by phasor diagrams, where rotating vectors show relative phase. Ideal inductor and capacitor do not consume average power over a full cycle.

Key points6

  • Reactance has unit ohm, like resistance.
  • Inductive reactance increases with frequency.
  • Capacitive reactance decreases with frequency.
  • In pure resistor, power factor is 1.
  • In pure inductor or capacitor, power factor is zero.
  • Phasors simplify phase relation and vector addition of AC quantities.

Memory tricks2

ELI the ICE Man: In inductor L, E or voltage leads I: ELI. In capacitor C, I leads E: ICE.

Reactance Frequency: L loves high frequency opposition; C cuts down opposition at high frequency.

Examples3

Inductive Reactance Example

For L = 0.5 H and f = 50 Hz, XL = 2πfL = 2π × 50 × 0.5 = 50π Ω ≈ 157 Ω.

Capacitive Reactance Example

For C = 100 μF and f = 50 Hz, XC = 1/(2πfC) = 1/(2π × 50 × 100 × 10⁻⁶) ≈ 31.8 Ω.

NEET-Type Question

In a purely capacitive circuit, current leads voltage by 90° and average power is zero.

Common mistakes2

Saying Inductor Consumes Average Power

An ideal inductor stores and returns energy; its average power over a full cycle is zero.

Confusing Lead and Lag

In pure L, current lags voltage. In pure C, current leads voltage.

Reference tables2

Quick revision8

Formulas5

AC Through Pure Resistor
V=IRV = IR
I0=V0/RI0 = V0/R

Voltage and current are in phase in a pure resistor.

V
Voltage across resistor
I
Current through resistor
R
Resistance
I0, V0
Peak current and voltage
AC Through Pure Inductor
XL=ωLXL = ωL
I0=V0/XLI0 = V0/XL

Inductor opposes AC with inductive reactance.

XL
Inductive reactance
ω
Angular frequency
L
Inductance
AC Through Pure Capacitor
XC=1/(ωC)XC = 1/(ωC)
I0=V0/XCI0 = V0/XC

Capacitor opposes AC with capacitive reactance.

XC
Capacitive reactance
ω
Angular frequency
C
Capacitance
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Diagrams5

4

LCR Circuits & Resonance

11 min

A series LCR circuit contains resistance, inductance and capacitance connected in series with an AC source. The resistor voltage is in phase with current, inductor voltage leads current by 90°, and capacitor voltage lags current by 90°. Their combined opposition is impedance, Z = √[R² + (XL - XC)²]. Resonance occurs when XL = XC, so inductive and capacitive reactances cancel. At resonance, impedance becomes minimum and equal to R, current becomes maximum, phase difference becomes zero and power factor becomes one. Resonance frequency is f0 = 1/(2π√LC). The quality factor describes sharpness of resonance. Resonance is used in radio tuning, filters and frequency selection circuits.

Key points6

  • LCR resonance occurs only when inductive and capacitive effects cancel.
  • At low frequency, capacitive reactance dominates.
  • At high frequency, inductive reactance dominates.
  • At resonance, circuit behaves like a pure resistor.
  • Quality factor is higher when resistance is small.
  • Voltage across L or C can be much larger than supply voltage near resonance.

Memory tricks2

Resonance Condition: At resonance, L and C cancel each other: XL equals XC.

Minimum Impedance: At resonance, only R remains, so current becomes maximum.

Examples3

Resonance Frequency Example

For L = 1 H and C = 100 μF, f0 = 1/(2π√LC) = 1/(2π√10⁻⁴) ≈ 15.9 Hz.

Impedance Example

If R = 30 Ω, XL = 80 Ω and XC = 40 Ω, then Z = √[30² + 40²] = 50 Ω.

NEET-Type Question

At resonance in a series LCR circuit, current is maximum and power factor is unity.

Common mistakes2

Adding Reactances Directly

In series LCR, net reactance is XL - XC, not XL + XC, because they are opposite in phase.

Thinking Voltage Across L and C Is Zero at Resonance

At resonance, VL and VC cancel in net voltage, but individually they can be large.

Reference tables2

Quick revision8

Formulas6

Impedance of Series LCR Circuit
Z=√[R2+(XL−XC)2]Z = √[R² + (XL - XC)²]

Total opposition to alternating current in a series LCR circuit.

Z
Impedance
R
Resistance
XL
Inductive reactance
XC
Capacitive reactance
Current in Series LCR
Irms = Vrms/Z\text{Irms }=\text{ Vrms}/Z

RMS current in series LCR circuit.

Irms
RMS current
Vrms
RMS applied voltage
Z
Impedance
Phase Angle
tanϕ=(XL−XC)/Rtanϕ = (XL - XC)/R

Phase angle between applied voltage and current in series LCR circuit.

ϕ
Phase angle
XL
Inductive reactance
XC
Capacitive reactance
R
Resistance
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Diagrams4

5

Power Factor

9 min

Power factor tells how effectively an AC circuit converts supplied electrical energy into useful work. In an AC circuit, voltage and current may have a phase difference ϕ. Average power consumed is Pavg = VrmsIrms cosϕ, where cosϕ is the power factor. If voltage and current are in phase, cosϕ = 1 and power use is maximum. If phase difference is 90°, as in an ideal inductor or capacitor, average power is zero and current is called wattless current. In practical circuits, low power factor increases current for the same useful power, causing greater transmission loss I²R. Power factor correction uses capacitors or suitable devices to reduce phase difference and improve efficiency.

Key points6

  • Power factor is dimensionless.
  • Only the in-phase component of current contributes to average power.
  • Reactive current circulates energy between source and reactive elements.
  • Lagging power factor occurs when circuit is inductive.
  • Leading power factor occurs when circuit is capacitive.
  • Capacitors are often used to improve lagging power factor in industrial loads.

Memory tricks2

Power Factor Meaning: Power factor tells what fraction of apparent power becomes useful real power.

Wattless Current: Wattless means current flows but average watts are zero.

Examples3

Numerical Example

If Vrms = 220 V, Irms = 5 A and power factor is 0.8, average power is P = 220 × 5 × 0.8 = 880 W.

Power Loss Example

If line current doubles, transmission loss becomes four times because Ploss = I²Rline.

NEET-Type Question

At resonance in a series LCR circuit, cosϕ = 1, so average power is maximum.

Common mistakes2

Using P = VI Always

In AC circuits with phase difference, use Pavg = VrmsIrms cosϕ, not just VI.

Calling Wattless Current Useless in All Sense

Wattless current does not consume average power but affects line current and losses.

Reference tables2

Quick revision8

Formulas4

Average Power in AC Circuit
Pavg = VrmsIrms cosϕ\text{Pavg }=\text{ VrmsIrms cos}ϕ

Average power consumed in an AC circuit with phase difference ϕ.

Pavg
Average power
Vrms
RMS voltage
Irms
RMS current
ϕ
Phase angle between voltage and current
Power Factor
power factor =cosϕ=R/Z\text{power factor }= cosϕ = R/Z

Ratio of resistance to impedance in a series LCR circuit.

cosϕ
Power factor
R
Resistance
Z
Impedance
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Diagrams4

6

Transformers

10 min

A transformer is an AC device that changes voltage using mutual induction. It consists of primary and secondary coils wound on a laminated soft iron core. When AC flows in the primary coil, it produces changing magnetic flux in the core. This changing flux links the secondary coil and induces an emf according to Faraday’s law. In an ideal transformer, Vs/Vp = Ns/Np and input power equals output power, so VpIp = VsIs. A step-up transformer has more turns in the secondary and increases voltage while decreasing current. A step-down transformer has fewer secondary turns and decreases voltage while increasing current. Practical transformers have losses due to copper resistance, eddy currents, hysteresis and flux leakage.

Key points6

  • Transformer changes voltage but not frequency.
  • Soft iron core provides a low reluctance path for magnetic flux.
  • Primary coil receives input AC; secondary coil delivers output AC.
  • In step-up transformer, current decreases because power is nearly conserved.
  • Copper loss is I²R heating in windings.
  • Hysteresis loss is reduced by using soft iron with narrow hysteresis loop.

Memory tricks2

Transformer Ratio: Voltage follows turns: more secondary turns means more secondary voltage.

Current Ratio: Current goes opposite to voltage in ideal transformer because power is conserved.

Examples3

Step-Up Numerical

If Vp = 220 V, Np = 500 and Ns = 2000, then Vs = Vp × Ns/Np = 220 × 4 = 880 V.

Current Ratio Example

For an ideal transformer with Vp = 100 V, Ip = 2 A and Vs = 200 V, output current Is = VpIp/Vs = 100 × 2/200 = 1 A.

Application

Power stations use step-up transformers for long-distance transmission to reduce current and I²R losses.

Common mistakes2

Using Transformer with DC

A transformer requires changing magnetic flux. Steady DC cannot produce continuous induced emf in the secondary.

Thinking Transformer Changes Frequency

A transformer changes voltage and current, but output frequency remains the same as input frequency.

Reference tables3

Quick revision8

Formulas5

Transformer Voltage Ratio
Vs/Vp=Ns/NpVs/Vp = Ns/Np

For an ideal transformer, voltage ratio equals turns ratio.

Vs
Secondary voltage
Vp
Primary voltage
Ns
Number of turns in secondary coil
Np
Number of turns in primary coil
Transformer Current Ratio
Is/Ip=Np/NsIs/Ip = Np/Ns

For an ideal transformer, current ratio is inverse of turns ratio.

Is
Secondary current
Ip
Primary current
Np
Primary turns
Ns
Secondary turns
Ideal Power Relation
VpIp = VsIs\text{VpIp }=\text{ VsIs}

Input power equals output power in an ideal transformer.

Vp, Vs
Primary and secondary voltages
Ip, Is
Primary and secondary currents
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Diagrams4

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NEET PYQs from Alternating Current

The latest 3 of 30 previous-year questions from this chapter.

  1. NEET 2026Set 50EasyQ1

    An ac voltage $V = 220\sin(2 \times 10^3 t)$ Volt is applied to a series LCR circuit. Then the current amplitude in this circuit is: (Given : $L = 10\ \mathrm{mH}$, $C = 25\ \mu\mathrm{F}$, $R = 100\ \Omega$)

    • A$2.2\ \mathrm{A}$
    • B$5.5\ \mathrm{A}$
    • C$11.0\ \mathrm{A}$
    • D$22.0\ \mathrm{A}$
  2. NEET 2026Set 11EasyQ2

    The peak value of an alternating current is 5 A and frequency is 60 Hz. How long will the current, starting from zero, take to reach the peak value?

    • A1/120 s
    • B1/60 s
    • C1/30 s
    • D1/240 s
  3. NEET 2026Set 11EasyQ3

    An AC circuit contains a resistance of 1 kΩ, a capacitor of 0.1 μF and an inductor of 1 mH connected in series. The resonance frequency of the circuit is approximately:

    • A13.5 kHz
    • B10.1 kHz
    • C20.7 kHz
    • D15.9 kHz

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