Topics
5Chapter Overview
Overview
Alternating Current studies current and voltage that vary periodically with time, usually sinusoidally. The chapter begins with AC fundamentals such as waveform, time period, frequency, angular frequency, peak value, mean value, RMS value and phase difference. It then explains how a resistor, inductor and capacitor behave separately in AC circuits using resistance, inductive reactance and capacitive reactance. Series LCR circuits combine all three and show resonance when inductive and capacitive effects cancel. Power factor explains how effectively AC power is used and why some current may be wattless. Finally, transformers apply mutual induction to step voltage up or down. For NEET, this chapter is formula-rich and frequently tests RMS values, reactance, resonance, power and transformer ratios.
- 1NEET often asks direct formulas from RMS values, reactance, impedance and transformer relations.
- 2AC analysis requires both magnitude and phase, so phasors are very useful.
- 3Inductor and capacitor do not consume average power in ideal pure AC circuits.
- 4At resonance, impedance of series LCR circuit is minimum and current is maximum.
- 5Average power in AC circuit is Pavg = VrmsIrms cosϕ.
- 6Power factor correction improves useful power transfer and reduces losses.
RMS Meaning
RMS is the heating equivalent DC value: it tells how much heat AC can produce.
Chapter Flow Trick
Wave basics → RLC behaviour → resonance → power factor → transformer.
NEET-Style Snapshot
If peak voltage is 220√2 V, RMS voltage is 220 V because Vrms = V0/√2.
Real-Life Example
Domestic supply is AC because voltage can be stepped up or down efficiently using transformers.
Using Peak Value Instead of RMS
Power and household voltage calculations usually use RMS values unless peak is specifically mentioned.
Ignoring Phase
In AC circuits, voltage and current may not peak together. Phase difference affects power.
Instantaneous current in a sinusoidal alternating current circuit.
Variables
I=Instantaneous current
I0=Peak current
ω=Angular frequency
t=Time
Effective AC values that produce the same heating effect as DC.
Variables
Irms=Root mean square current
Vrms=Root mean square voltage
I0, V0=Peak current and peak voltage
Opposition offered by inductor and capacitor to alternating current.
Variables
XL=Inductive reactance
XC=Capacitive reactance
L=Inductance
C=Capacitance
AC Fundamentals
Overview
Alternating current and voltage change magnitude and direction periodically with time. In most circuits, they are represented by sine or cosine functions such as I = I0 sinωt and V = V0 sinωt. A complete repetition is one cycle, whose duration is the time period T. Frequency f is the number of cycles per second, and angular frequency is ω = 2πf. Since AC changes continuously, useful values include peak, RMS and mean values. RMS value is most important because it gives the equivalent DC heating effect. Mean value over a full cycle of symmetrical AC is zero, while mean over a half cycle is non-zero. Phase difference tells how much one AC quantity leads or lags another.
- 1Peak value is maximum instantaneous value.
- 2RMS value is used in heating, power and household AC ratings.
- 3Mean value over half cycle of sine wave is 2I0/π.
- 4A phase difference of π/2 means one quantity reaches maximum a quarter cycle earlier.
- 5If two AC waves have the same phase, their peaks and zeros occur together.
- 6Angular frequency is measured in rad s⁻¹, while frequency is measured in hertz.
RMS Shortcut
For sine AC, RMS is peak divided by root two.
Mean Value Reminder
Full-cycle mean of symmetrical AC is zero because positive and negative halves cancel.
RMS Numerical
If peak current is 10 A, RMS current is Irms = 10/√2 = 7.07 A.
Previous NEET-Type Question
For Indian domestic AC of frequency 50 Hz, time period T = 1/50 = 0.02 s and angular frequency ω = 100π rad/s.
Confusing Mean and RMS
Mean over full cycle is zero for sinusoidal AC, but RMS is not zero and is used for power.
Using Frequency Instead of Angular Frequency
In I = I0 sinωt, use angular frequency ω in rad/s, not frequency f directly.
Instantaneous sinusoidal current and voltage.
Variables
I, V=Instantaneous current and voltage
I0, V0=Peak current and peak voltage
ω=Angular frequency
t=Time
Frequency is reciprocal of time period.
Variables
f=Frequency
T=Time period
Rate of phase change in sinusoidal AC.
Variables
ω=Angular frequency
f=Frequency
T=Time period
AC in Resistor, Inductor & Capacitor
Overview
A resistor, inductor and capacitor respond differently to alternating current. In a pure resistor, current and voltage are in the same phase and energy is dissipated as heat. In a pure inductor, voltage leads current by 90° because the inductor opposes change in current; its opposition is inductive reactance XL = ωL. In a pure capacitor, current leads voltage by 90° because current is maximum when voltage changes fastest; its opposition is capacitive reactance XC = 1/ωC. These phase relations are best represented by phasor diagrams, where rotating vectors show relative phase. Ideal inductor and capacitor do not consume average power over a full cycle.
- 1Reactance has unit ohm, like resistance.
- 2Inductive reactance increases with frequency.
- 3Capacitive reactance decreases with frequency.
- 4In pure resistor, power factor is 1.
- 5In pure inductor or capacitor, power factor is zero.
- 6Phasors simplify phase relation and vector addition of AC quantities.
ELI the ICE Man
In inductor L, E or voltage leads I: ELI. In capacitor C, I leads E: ICE.
Reactance Frequency
L loves high frequency opposition; C cuts down opposition at high frequency.
Inductive Reactance Example
For L = 0.5 H and f = 50 Hz, XL = 2πfL = 2π × 50 × 0.5 = 50π Ω ≈ 157 Ω.
Capacitive Reactance Example
For C = 100 μF and f = 50 Hz, XC = 1/(2πfC) = 1/(2π × 50 × 100 × 10⁻⁶) ≈ 31.8 Ω.
NEET-Type Question
In a purely capacitive circuit, current leads voltage by 90° and average power is zero.
Saying Inductor Consumes Average Power
An ideal inductor stores and returns energy; its average power over a full cycle is zero.
Confusing Lead and Lag
In pure L, current lags voltage. In pure C, current leads voltage.
Voltage and current are in phase in a pure resistor.
Variables
V=Voltage across resistor
I=Current through resistor
R=Resistance
I0, V0=Peak current and voltage
Inductor opposes AC with inductive reactance.
Variables
XL=Inductive reactance
ω=Angular frequency
L=Inductance
Capacitor opposes AC with capacitive reactance.
Variables
XC=Capacitive reactance
ω=Angular frequency
C=Capacitance
LCR Circuits & Resonance
Overview
A series LCR circuit contains resistance, inductance and capacitance connected in series with an AC source. The resistor voltage is in phase with current, inductor voltage leads current by 90°, and capacitor voltage lags current by 90°. Their combined opposition is impedance, Z = √[R² + (XL - XC)²]. Resonance occurs when XL = XC, so inductive and capacitive reactances cancel. At resonance, impedance becomes minimum and equal to R, current becomes maximum, phase difference becomes zero and power factor becomes one. Resonance frequency is f0 = 1/(2π√LC). The quality factor describes sharpness of resonance. Resonance is used in radio tuning, filters and frequency selection circuits.
- 1LCR resonance occurs only when inductive and capacitive effects cancel.
- 2At low frequency, capacitive reactance dominates.
- 3At high frequency, inductive reactance dominates.
- 4At resonance, circuit behaves like a pure resistor.
- 5Quality factor is higher when resistance is small.
- 6Voltage across L or C can be much larger than supply voltage near resonance.
Resonance Condition
At resonance, L and C cancel each other: XL equals XC.
Minimum Impedance
At resonance, only R remains, so current becomes maximum.
Resonance Frequency Example
For L = 1 H and C = 100 μF, f0 = 1/(2π√LC) = 1/(2π√10⁻⁴) ≈ 15.9 Hz.
Impedance Example
If R = 30 Ω, XL = 80 Ω and XC = 40 Ω, then Z = √[30² + 40²] = 50 Ω.
NEET-Type Question
At resonance in a series LCR circuit, current is maximum and power factor is unity.
Adding Reactances Directly
In series LCR, net reactance is XL - XC, not XL + XC, because they are opposite in phase.
Thinking Voltage Across L and C Is Zero at Resonance
At resonance, VL and VC cancel in net voltage, but individually they can be large.
Total opposition to alternating current in a series LCR circuit.
Variables
Z=Impedance
R=Resistance
XL=Inductive reactance
XC=Capacitive reactance
RMS current in series LCR circuit.
Variables
Irms=RMS current
Vrms=RMS applied voltage
Z=Impedance
Phase angle between applied voltage and current in series LCR circuit.
Variables
ϕ=Phase angle
XL=Inductive reactance
XC=Capacitive reactance
R=Resistance
Power Factor
Overview
Power factor tells how effectively an AC circuit converts supplied electrical energy into useful work. In an AC circuit, voltage and current may have a phase difference ϕ. Average power consumed is Pavg = VrmsIrms cosϕ, where cosϕ is the power factor. If voltage and current are in phase, cosϕ = 1 and power use is maximum. If phase difference is 90°, as in an ideal inductor or capacitor, average power is zero and current is called wattless current. In practical circuits, low power factor increases current for the same useful power, causing greater transmission loss I²R. Power factor correction uses capacitors or suitable devices to reduce phase difference and improve efficiency.
- 1Power factor is dimensionless.
- 2Only the in-phase component of current contributes to average power.
- 3Reactive current circulates energy between source and reactive elements.
- 4Lagging power factor occurs when circuit is inductive.
- 5Leading power factor occurs when circuit is capacitive.
- 6Capacitors are often used to improve lagging power factor in industrial loads.
Power Factor Meaning
Power factor tells what fraction of apparent power becomes useful real power.
Wattless Current
Wattless means current flows but average watts are zero.
Numerical Example
If Vrms = 220 V, Irms = 5 A and power factor is 0.8, average power is P = 220 × 5 × 0.8 = 880 W.
Power Loss Example
If line current doubles, transmission loss becomes four times because Ploss = I²Rline.
NEET-Type Question
At resonance in a series LCR circuit, cosϕ = 1, so average power is maximum.
Using P = VI Always
In AC circuits with phase difference, use Pavg = VrmsIrms cosϕ, not just VI.
Calling Wattless Current Useless in All Sense
Wattless current does not consume average power but affects line current and losses.
Average power consumed in an AC circuit with phase difference ϕ.
Variables
Pavg=Average power
Vrms=RMS voltage
Irms=RMS current
ϕ=Phase angle between voltage and current
Ratio of resistance to impedance in a series LCR circuit.
Variables
cosϕ=Power factor
R=Resistance
Z=Impedance
Transformers
Overview
A transformer is an AC device that changes voltage using mutual induction. It consists of primary and secondary coils wound on a laminated soft iron core. When AC flows in the primary coil, it produces changing magnetic flux in the core. This changing flux links the secondary coil and induces an emf according to Faraday’s law. In an ideal transformer, Vs/Vp = Ns/Np and input power equals output power, so VpIp = VsIs. A step-up transformer has more turns in the secondary and increases voltage while decreasing current. A step-down transformer has fewer secondary turns and decreases voltage while increasing current. Practical transformers have losses due to copper resistance, eddy currents, hysteresis and flux leakage.
- 1Transformer changes voltage but not frequency.
- 2Soft iron core provides a low reluctance path for magnetic flux.
- 3Primary coil receives input AC; secondary coil delivers output AC.
- 4In step-up transformer, current decreases because power is nearly conserved.
- 5Copper loss is I²R heating in windings.
- 6Hysteresis loss is reduced by using soft iron with narrow hysteresis loop.
Transformer Ratio
Voltage follows turns: more secondary turns means more secondary voltage.
Current Ratio
Current goes opposite to voltage in ideal transformer because power is conserved.
Step-Up Numerical
If Vp = 220 V, Np = 500 and Ns = 2000, then Vs = Vp × Ns/Np = 220 × 4 = 880 V.
Current Ratio Example
For an ideal transformer with Vp = 100 V, Ip = 2 A and Vs = 200 V, output current Is = VpIp/Vs = 100 × 2/200 = 1 A.
Application
Power stations use step-up transformers for long-distance transmission to reduce current and I²R losses.
Using Transformer with DC
A transformer requires changing magnetic flux. Steady DC cannot produce continuous induced emf in the secondary.
Thinking Transformer Changes Frequency
A transformer changes voltage and current, but output frequency remains the same as input frequency.
For an ideal transformer, voltage ratio equals turns ratio.
Variables
Vs=Secondary voltage
Vp=Primary voltage
Ns=Number of turns in secondary coil
Np=Number of turns in primary coil
For an ideal transformer, current ratio is inverse of turns ratio.
Variables
Is=Secondary current
Ip=Primary current
Np=Primary turns
Ns=Secondary turns
Input power equals output power in an ideal transformer.
Variables
Vp, Vs=Primary and secondary voltages
Ip, Is=Primary and secondary currents
Formula Sheet
10Instantaneous current in a sinusoidal alternating current circuit.
Variables
I=Instantaneous current
I0=Peak current
ω=Angular frequency
t=Time
Effective AC values that produce the same heating effect as DC.
Variables
Irms=Root mean square current
Vrms=Root mean square voltage
I0, V0=Peak current and peak voltage
Opposition offered by inductor and capacitor to alternating current.
Variables
XL=Inductive reactance
XC=Capacitive reactance
L=Inductance
C=Capacitance
Net opposition to AC in a series LCR circuit.
Variables
Z=Impedance
R=Resistance
XL=Inductive reactance
XC=Capacitive reactance
Average power consumed in an AC circuit.
Variables
Pavg=Average power
Vrms=RMS voltage
Irms=RMS current
cosϕ=Power factor
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NEET PYQs — Alternating Current
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An AC circuit contains a resistance of 1 kΩ, a capacitor of 0.1 μF and an inductor of 1 mH connected in series. The resonance frequency of the circuit is approximately:
A series R-C circuit is connected to an alternating voltage source. Consider two situations: (a) When the capacitor is air filled. (b) When the capacitor is mica filled. Current through the resistor is $i$ and voltage across the capacitor is $V$. Then:
A coil of self-inductance $L$ is connected in series with a bulb $B$ and an AC source. Brightness of the bulb decreases when
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