PhysicsNCERT Class 11
🏋️

Laws of Motion Notes

Study Notes

6 Topics35 Formulas45 PYQs6 Videos43 Key Points

Topics

6
1

📖 1. Chapter Overview

Overview

Laws of Motion explains why objects start moving, stop moving, change direction or remain at rest. Aristotle believed force is necessary to keep a body moving, but Newton showed that force is required to change the state of motion, not to maintain uniform motion. The chapter introduces inertia, mass, force, momentum, impulse, equilibrium, friction and circular motion applications. Newton’s three laws form the core of mechanics and are used in blocks, pulleys, elevators, inclined planes and vehicle motion. For NEET, this chapter is very important because it gives direct conceptual questions, free body diagram problems, friction numericals and multi-body Newton’s law applications.

Key Points6
  • 1A body can move with constant velocity even when net force is zero.
  • 2Free body diagrams are the most important tool for solving Laws of Motion questions.
  • 3Internal forces cancel for a system, but external forces change total momentum.
  • 4Static friction is self-adjusting up to limiting friction.
  • 5Circular motion always requires inward centripetal force.
  • 6Most NEET mistakes happen due to wrong direction of friction, wrong normal reaction or missing pseudo-free body analysis.
Memory Tricks2

Newton’s Laws in One Line

First: no net force, no change. Second: net force gives acceleration. Third: forces come in pairs.

FBD Rule

Draw only forces acting on the selected body, never forces exerted by that body on others.

Examples2

Daily Life Example

When a bus suddenly starts, passengers tend to fall backward due to inertia of rest.

NEET Concept Check

If a 2 kg body has net force 10 N, acceleration is F/m = 5 m s^-2.

Reference Tables2
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Common Mistakes3

Believing Force Is Needed for Constant Motion

A body moving with constant velocity has zero net force. Force is needed to change velocity.

Action-Reaction on Same Body

Newton’s third-law pair acts on two different bodies, so they do not cancel on a single free body diagram.

Ignoring Normal Reaction Changes

Normal reaction is not always equal to mg. It changes in elevators, inclined planes and circular motion.

Formula Cards5
Newton’s Second Law

Net external force equals mass multiplied by acceleration for constant mass.

Variables

F_net=

Resultant external force

m=

Mass of body

a=

Acceleration

Momentum

Linear momentum is the product of mass and velocity.

Variables

p=

Linear momentum

m=

Mass

v=

Velocity

Impulse

Impulse is the change in momentum produced by force acting for a time interval.

Variables

J=

Impulse

F=

Average force

Δt=

Time interval

Δp=

Change in momentum

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2

🏋️ 2. Force, Inertia & Newton's Laws

Overview

Force is an interaction that can change the state of motion or shape of a body. Forces may be contact forces such as normal reaction, tension, friction and spring force, or non-contact forces such as gravitational, electrostatic and magnetic forces. Inertia is the natural tendency of a body to resist any change in rest or motion, and mass is its measure. Newton’s first law states that a body remains at rest or in uniform motion unless acted upon by a net external force. The second law relates net force to acceleration, F = ma. The third law states that every action has an equal and opposite reaction on another body.

Key Points6
  • 1Balanced forces produce zero acceleration, not necessarily zero velocity.
  • 2Unbalanced force produces acceleration in the direction of net force.
  • 3Weight is gravitational force mg; mass is the measure of inertia.
  • 4Normal reaction is perpendicular to contact surface.
  • 5Tension acts along a string, pulling away from the body.
  • 6FBD should include weight, normal, tension, friction, applied force and spring force wherever applicable.
Memory Tricks2

FBD Checklist

Remember WNTF: Weight, Normal, Tension, Friction or applied Force.

Third Law

Action and reaction are twins on different bodies: equal, opposite, separate.

Examples2

Real-Life Application

A seat belt prevents passengers from continuing forward due to inertia when a car stops suddenly.

Numerical Example

A 5 kg block is pulled by a 20 N horizontal force on a smooth surface. Acceleration = F/m = 20/5 = 4 m s^-2.

Reference Tables2
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Common Mistakes3

Drawing Action-Reaction on Same FBD

Do not draw the reaction exerted by the body on another object in its own FBD.

Assuming Normal Always Equals mg

Normal equals mg only in simple horizontal cases with no vertical acceleration and no extra vertical force.

Confusing Mass and Weight

Mass is inertia and remains same; weight is gravitational force and depends on g.

Formula Cards4
Newton’s Second Law

The acceleration of a body is proportional to net external force and inversely proportional to mass.

Variables

F_net=

Vector sum of all external forces

m=

Mass of body

a=

Acceleration

Weight

Gravitational force exerted by Earth on a body near its surface.

Variables

W=

Weight

m=

Mass

g=

Acceleration due to gravity

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3

🚀 3. Momentum & Impulse

Overview

Linear momentum measures the quantity of motion of a body and is defined as p = mv. It is a vector in the direction of velocity. For a system of particles, total momentum is the vector sum of individual momenta. If no external force acts on a system, its total momentum remains conserved. Impulse is the effect of a force acting for a short time and equals change in momentum. This idea explains why catching a ball softly reduces force by increasing stopping time. Collisions are interactions of short duration where momentum is conserved if external impulse is negligible. Elastic collisions conserve kinetic energy, while inelastic collisions do not.

Key Points6
  • 1Conservation of momentum applies to isolated systems.
  • 2Internal forces cannot change total momentum of a system.
  • 3Impulse has the same dimensions as momentum.
  • 4Large force for small time and small force for large time can give same impulse.
  • 5In a perfectly inelastic collision, bodies stick together after collision.
  • 6Momentum conservation must be applied vectorially with signs.
Memory Tricks2

Impulse

Impulse is force-time effect: push harder or push longer to change momentum.

Collision Rule

Momentum survives collisions; kinetic energy survives only elastic collisions.

Examples2

Impulse Numerical

A 0.2 kg ball changes velocity from 20 m/s to -10 m/s. Δp = 0.2(-10 - 20) = -6 kg m/s, so impulse magnitude is 6 N s.

Conservation Example

A 2 kg body at 4 m/s sticks to a 2 kg body at rest. Final speed = total momentum/total mass = 8/4 = 2 m/s.

Reference Tables2
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Common Mistakes3

Forgetting Momentum Is Vector

Use signs in one-dimensional collision problems. Opposite directions require opposite signs.

Assuming Kinetic Energy Always Conserved

Kinetic energy is conserved only in elastic collisions, not in general collisions.

Applying Momentum Conservation with External Force

Momentum conservation applies only when net external impulse is zero or negligible.

Formula Cards5
Linear Momentum

Momentum is the product of mass and velocity.

Variables

p=

Linear momentum

m=

Mass

v=

Velocity

Momentum of a System

Total momentum is vector sum of individual momenta.

Variables

P=

Total momentum

p1, p2, pn=

Momenta of individual particles

Conservation of Momentum

Total momentum remains constant when net external force is zero.

Variables

Σp_initial=

Total initial momentum

Σp_final=

Total final momentum

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4

⚖️ 4. Equilibrium of Particles

Overview

A particle is in equilibrium when the vector sum of all forces acting on it is zero. This means the particle has no acceleration; it may be at rest or moving with constant velocity. For forces in a plane, equilibrium requires both horizontal and vertical force components to separately add to zero. Many NEET problems involve strings, weights, inclined forces and concurrent forces meeting at one point. Free body diagrams and force resolution are the safest methods. Lami’s theorem is a shortcut for three concurrent, coplanar and non-parallel forces in equilibrium. It relates each force to the sine of the angle between the other two forces.

Key Points6
  • 1Equilibrium does not always mean rest; it means acceleration is zero.
  • 2If three forces keep a particle in equilibrium, their vector triangle closes.
  • 3For two forces to balance, they must be equal, opposite and collinear.
  • 4Resolve inclined forces into x and y components.
  • 5Lami’s theorem is useful for tensions in two strings supporting a weight.
  • 6Angles in Lami’s theorem are the angles between the other two forces, not arbitrary angles with axes.
Memory Tricks2

Equilibrium Components

Balance east-west and north-south separately: ΣFx = 0 and ΣFy = 0.

Lami’s Theorem

Each force sits over sine of the angle opposite to it.

Examples2

Practice Question

A 10 N weight is held by two equal strings symmetrically. Vertical components of tensions add to 10 N; horizontal components cancel.

Lami Example

If three equal forces are in equilibrium, the angle between any two forces is 120 degrees.

Reference Tables2
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Common Mistakes2

Applying Lami’s Theorem Without Concurrent Forces

Lami’s theorem is valid only for three concurrent coplanar forces in equilibrium.

Using Forces Exerted by the Particle

In FBD, draw forces acting on the particle, not forces exerted by it.

Formula Cards4
Condition of Equilibrium

Vector sum of all external forces on a particle must be zero.

Variables

ΣF=

Resultant force

Component Conditions

For equilibrium in a plane, net force in each perpendicular direction must be zero.

Variables

ΣFx=

Sum of x-components of forces

ΣFy=

Sum of y-components of forces

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5

🪵 5. Friction

Overview

Friction is a contact force that opposes relative motion or the tendency of relative motion between surfaces. Static friction acts when there is no slipping and adjusts itself according to need up to a maximum called limiting friction. Once sliding begins, kinetic friction acts and is usually slightly smaller than limiting friction. The coefficient of friction measures roughness and equals friction divided by normal reaction in limiting or kinetic cases. Angle of friction is related to the resultant contact force, while angle of repose is the minimum inclination at which a body just begins to slide. Friction is necessary for walking, writing, vehicle motion and braking, but also causes wear and energy loss.

Key Points6
  • 1Friction does not always oppose motion; it opposes relative motion or tendency at contact.
  • 2For a body at rest, friction may be less than μ_sN.
  • 3Normal reaction depends on surface geometry and other forces.
  • 4On an incline, components of weight are mg sinθ along plane and mg cosθ normal to plane.
  • 5At impending motion down an incline, mg sinθ = μmg cosθ.
  • 6Rolling friction is much smaller than sliding friction.
Memory Tricks2

Static Friction

Static friction is smart: it adjusts only as much as needed, up to its limit.

Angle of Repose

At repose angle, sliding is about to start, so tanθ = μ.

Examples2

Horizontal Surface Example

A 10 kg block has μ_s = 0.4. Maximum static friction = μ_smg = 0.4×10×10 = 40 N.

Angle of Repose Example

If μ = 1/√3, angle of repose θ satisfies tanθ = 1/√3, so θ = 30 degrees.

Reference Tables2
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Common Mistakes3

Always Writing f = μN for Static Friction

Static friction equals μ_sN only at limiting condition. Otherwise it may be smaller.

Wrong Friction Direction

Friction opposes relative motion or tendency at contact, not always the motion of the body relative to ground.

Taking N = mg on Incline

On an incline, normal reaction is mg cosθ if no other perpendicular forces exist.

Formula Cards6
Static Friction

Static friction adjusts from zero up to limiting value.

Variables

f_s=

Static friction

μ_s=

Coefficient of static friction

N=

Normal reaction

Limiting Friction

Maximum value of static friction just before slipping begins.

Variables

f_lim=

Limiting friction

μ_s=

Coefficient of static friction

N=

Normal reaction

Kinetic Friction

Frictional force during sliding motion.

Variables

f_k=

Kinetic friction

μ_k=

Coefficient of kinetic friction

N=

Normal reaction

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6

🔄 6. Circular Motion Applications

Overview

Circular motion applications use Newton’s second law toward the centre of the circle. A body moving in a circle requires centripetal force mv²/r, which is not a new force but the inward resultant of real forces such as tension, friction, gravity or normal reaction. In a vehicle moving on a curved road, friction or banking supplies the required centripetal force. Banking reduces dependence on friction by using a component of normal reaction. A conical pendulum moves in a horizontal circle, where horizontal tension gives centripetal force and vertical tension balances weight. In vertical circular motion, tension and weight change at different points, making top and bottom conditions important.

Key Points6
  • 1Always choose radial inward direction for centripetal equation.
  • 2Tangential velocity is perpendicular to radius.
  • 3On a flat road, maximum safe speed is v = √(μrg).
  • 4Banked road design speed does not require friction when tanθ = v²/rg.
  • 5In vertical circle, weight may help or oppose centripetal requirement depending on position.
  • 6For a string just taut at top, tension at top becomes zero.
Memory Tricks2

Centripetal Force

Centripetal means centre-seeking: always write radial equation toward the centre.

Banking

Banking tilts normal reaction so it can help turn the vehicle.

Examples2

Flat Road Example

If μ = 0.25 and r = 40 m, maximum speed = √(0.25×40×10) = 10 m/s.

Conical Pendulum Example

For a conical pendulum, dividing T sinθ = mv²/r by T cosθ = mg gives tanθ = v²/rg.

Reference Tables2
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Common Mistakes3

Calling Centripetal Force a Separate Force

Centripetal force is the net inward force, supplied by real forces like friction, tension or gravity.

Wrong Direction of Acceleration

Centripetal acceleration is always inward, not in the direction of velocity.

Using Same Vertical Circle Equation Everywhere

At top and bottom, radial directions differ, so tension equations are different.

Formula Cards5
Centripetal Force

Net inward force required for circular motion.

Variables

F_c=

Centripetal force

m=

Mass

v=

Speed

r=

Radius

Flat Curved Road Maximum Speed

Maximum speed on a flat road when friction provides centripetal force.

Variables

v_max=

Maximum safe speed

μ=

Coefficient of friction

r=

Radius of curve

g=

Acceleration due to gravity

Banking of Roads Without Friction

Condition for safe turning on a banked road without relying on friction.

Variables

θ=

Banking angle

v=

Design speed

r=

Radius of road curve

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7

📝 7. Problem Solving

Overview

Problem solving in Laws of Motion depends on selecting the body or system, drawing a correct free body diagram and applying Newton’s second law along suitable axes. For a block on a horizontal surface, horizontal forces decide acceleration and vertical forces decide normal reaction. For an inclined plane, axes along and perpendicular to the plane simplify equations. Connected blocks and pulleys require separate FBDs and constraint relations because connected bodies often have related accelerations. Elevator problems modify apparent weight due to vertical acceleration. Friction-based problems require deciding whether friction is static, limiting or kinetic. Mixed NEET problems usually combine FBD, friction, pulley tension and acceleration equations.

Key Points7
  • 1For a block on smooth horizontal surface, acceleration is applied force divided by mass.
  • 2For a block sliding down smooth incline, acceleration is g sinθ.
  • 3For connected blocks, tension is usually internal if the whole system is selected.
  • 4In a massless frictionless pulley, tension is same throughout the same string.
  • 5Elevator apparent weight is N = m(g + a) upward acceleration and N = m(g - a) downward acceleration.
  • 6Constraint relation means connected bodies may have equal or related accelerations.
  • 7If assumed friction direction gives negative value, actual friction direction is opposite.
Memory Tricks3

Newton Problem Method

FBD first, formula later. Most mistakes disappear when the diagram is correct.

Incline Components

On incline: sin slides, cos presses.

Elevator

Accelerating up feels heavier; accelerating down feels lighter.

Examples4

Block on Incline

A block slides down a smooth 30 degree incline. Acceleration = g sin30 = 10 × 1/2 = 5 m s^-2.

Connected Blocks

Two blocks 2 kg and 3 kg on a smooth surface are pulled by 10 N. System acceleration = 10/(2+3) = 2 m s^-2.

Elevator Example

A 60 kg person in an elevator accelerating upward at 2 m s^-2 has apparent weight N = 60(10+2) = 720 N.

Friction Example

A 5 kg block has μ = 0.2 and is pulled by 20 N. Friction = 0.2×5×10 = 10 N, so acceleration = (20-10)/5 = 2 m s^-2.

Reference Tables3
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Common Mistakes4

Skipping FBD

Direct formula use fails in mixed problems. Always draw forces before equations.

Using Same Acceleration Without Constraint

Connected bodies may have equal acceleration only when string geometry demands it.

Ignoring Static Friction Check

Before using kinetic friction, verify whether the applied force exceeds maximum static friction.

Wrong Tension Assumption

Tension is same only in a massless string over a frictionless pulley.

Formula Cards6
Block on Horizontal Smooth Surface

Acceleration when a net horizontal force F acts on mass m without friction.

Variables

a=

Acceleration

F=

Applied horizontal force

m=

Mass

Block on Rough Horizontal Surface

Acceleration of a sliding block pulled horizontally on a rough surface.

Variables

μ=

Coefficient of kinetic friction

mg=

Weight

Block on Smooth Inclined Plane

Acceleration down a smooth incline due to component of gravity.

Variables

θ=

Angle of inclination

g=

Acceleration due to gravity

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Formula Sheet

10
Newton’s Second Law

Net external force equals mass multiplied by acceleration for constant mass.

Variables

F_net=

Resultant external force

m=

Mass of body

a=

Acceleration

Momentum

Linear momentum is the product of mass and velocity.

Variables

p=

Linear momentum

m=

Mass

v=

Velocity

Impulse

Impulse is the change in momentum produced by force acting for a time interval.

Variables

J=

Impulse

F=

Average force

Δt=

Time interval

Δp=

Change in momentum

Friction

Static friction adjusts up to a maximum value, while kinetic friction has nearly constant magnitude.

Variables

f_s=

Static friction

f_k=

Kinetic friction

μ_s, μ_k=

Coefficients of static and kinetic friction

N=

Normal reaction

Centripetal Force

Net inward force required for circular motion.

Variables

F_c=

Centripetal force

v=

Speed in circular path

r=

Radius of circular path

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NEET PYQs — Laws of Motion

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NEET 2026Set 11EasyQ1

The magnitude and direction of the acceleration produced in a body of mass 5 kg when two mutually perpendicular forces 8 N and 6 N act on it, are respectively:

NEET 2026Set 11EasyQ2

A box of mass 15 kg is kept on the floor of a stationary trolley. The coefficient of static friction between the box and the trolley is 0.12. Keeping the box in stationary state over the trolley, the maximum acceleration with which the trolley can be moved horizontally in m s⁻² is: (g = 10 m/s²)

NEET 2025Set 45MediumQ3

A uniform rod of mass 20 kg and length 5 m leans against a smooth vertical wall making an angle of 60° with it. The other end rests on a rough horizontal floor. The friction force that the floor exerts on the rod is (g = 10 m/s²)

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