Topics
6📖 1. Chapter Overview
Overview
Laws of Motion explains why objects start moving, stop moving, change direction or remain at rest. Aristotle believed force is necessary to keep a body moving, but Newton showed that force is required to change the state of motion, not to maintain uniform motion. The chapter introduces inertia, mass, force, momentum, impulse, equilibrium, friction and circular motion applications. Newton’s three laws form the core of mechanics and are used in blocks, pulleys, elevators, inclined planes and vehicle motion. For NEET, this chapter is very important because it gives direct conceptual questions, free body diagram problems, friction numericals and multi-body Newton’s law applications.
- 1A body can move with constant velocity even when net force is zero.
- 2Free body diagrams are the most important tool for solving Laws of Motion questions.
- 3Internal forces cancel for a system, but external forces change total momentum.
- 4Static friction is self-adjusting up to limiting friction.
- 5Circular motion always requires inward centripetal force.
- 6Most NEET mistakes happen due to wrong direction of friction, wrong normal reaction or missing pseudo-free body analysis.
Newton’s Laws in One Line
First: no net force, no change. Second: net force gives acceleration. Third: forces come in pairs.
FBD Rule
Draw only forces acting on the selected body, never forces exerted by that body on others.
Daily Life Example
When a bus suddenly starts, passengers tend to fall backward due to inertia of rest.
NEET Concept Check
If a 2 kg body has net force 10 N, acceleration is F/m = 5 m s^-2.
Believing Force Is Needed for Constant Motion
A body moving with constant velocity has zero net force. Force is needed to change velocity.
Action-Reaction on Same Body
Newton’s third-law pair acts on two different bodies, so they do not cancel on a single free body diagram.
Ignoring Normal Reaction Changes
Normal reaction is not always equal to mg. It changes in elevators, inclined planes and circular motion.
Net external force equals mass multiplied by acceleration for constant mass.
Variables
F_net=Resultant external force
m=Mass of body
a=Acceleration
Linear momentum is the product of mass and velocity.
Variables
p=Linear momentum
m=Mass
v=Velocity
Impulse is the change in momentum produced by force acting for a time interval.
Variables
J=Impulse
F=Average force
Δt=Time interval
Δp=Change in momentum
🏋️ 2. Force, Inertia & Newton's Laws
Overview
Force is an interaction that can change the state of motion or shape of a body. Forces may be contact forces such as normal reaction, tension, friction and spring force, or non-contact forces such as gravitational, electrostatic and magnetic forces. Inertia is the natural tendency of a body to resist any change in rest or motion, and mass is its measure. Newton’s first law states that a body remains at rest or in uniform motion unless acted upon by a net external force. The second law relates net force to acceleration, F = ma. The third law states that every action has an equal and opposite reaction on another body.
- 1Balanced forces produce zero acceleration, not necessarily zero velocity.
- 2Unbalanced force produces acceleration in the direction of net force.
- 3Weight is gravitational force mg; mass is the measure of inertia.
- 4Normal reaction is perpendicular to contact surface.
- 5Tension acts along a string, pulling away from the body.
- 6FBD should include weight, normal, tension, friction, applied force and spring force wherever applicable.
FBD Checklist
Remember WNTF: Weight, Normal, Tension, Friction or applied Force.
Third Law
Action and reaction are twins on different bodies: equal, opposite, separate.
Real-Life Application
A seat belt prevents passengers from continuing forward due to inertia when a car stops suddenly.
Numerical Example
A 5 kg block is pulled by a 20 N horizontal force on a smooth surface. Acceleration = F/m = 20/5 = 4 m s^-2.
Drawing Action-Reaction on Same FBD
Do not draw the reaction exerted by the body on another object in its own FBD.
Assuming Normal Always Equals mg
Normal equals mg only in simple horizontal cases with no vertical acceleration and no extra vertical force.
Confusing Mass and Weight
Mass is inertia and remains same; weight is gravitational force and depends on g.
The acceleration of a body is proportional to net external force and inversely proportional to mass.
Variables
F_net=Vector sum of all external forces
m=Mass of body
a=Acceleration
Gravitational force exerted by Earth on a body near its surface.
Variables
W=Weight
m=Mass
g=Acceleration due to gravity
🚀 3. Momentum & Impulse
Overview
Linear momentum measures the quantity of motion of a body and is defined as p = mv. It is a vector in the direction of velocity. For a system of particles, total momentum is the vector sum of individual momenta. If no external force acts on a system, its total momentum remains conserved. Impulse is the effect of a force acting for a short time and equals change in momentum. This idea explains why catching a ball softly reduces force by increasing stopping time. Collisions are interactions of short duration where momentum is conserved if external impulse is negligible. Elastic collisions conserve kinetic energy, while inelastic collisions do not.
- 1Conservation of momentum applies to isolated systems.
- 2Internal forces cannot change total momentum of a system.
- 3Impulse has the same dimensions as momentum.
- 4Large force for small time and small force for large time can give same impulse.
- 5In a perfectly inelastic collision, bodies stick together after collision.
- 6Momentum conservation must be applied vectorially with signs.
Impulse
Impulse is force-time effect: push harder or push longer to change momentum.
Collision Rule
Momentum survives collisions; kinetic energy survives only elastic collisions.
Impulse Numerical
A 0.2 kg ball changes velocity from 20 m/s to -10 m/s. Δp = 0.2(-10 - 20) = -6 kg m/s, so impulse magnitude is 6 N s.
Conservation Example
A 2 kg body at 4 m/s sticks to a 2 kg body at rest. Final speed = total momentum/total mass = 8/4 = 2 m/s.
Forgetting Momentum Is Vector
Use signs in one-dimensional collision problems. Opposite directions require opposite signs.
Assuming Kinetic Energy Always Conserved
Kinetic energy is conserved only in elastic collisions, not in general collisions.
Applying Momentum Conservation with External Force
Momentum conservation applies only when net external impulse is zero or negligible.
Momentum is the product of mass and velocity.
Variables
p=Linear momentum
m=Mass
v=Velocity
Total momentum is vector sum of individual momenta.
Variables
P=Total momentum
p1, p2, pn=Momenta of individual particles
Total momentum remains constant when net external force is zero.
Variables
Σp_initial=Total initial momentum
Σp_final=Total final momentum
⚖️ 4. Equilibrium of Particles
Overview
A particle is in equilibrium when the vector sum of all forces acting on it is zero. This means the particle has no acceleration; it may be at rest or moving with constant velocity. For forces in a plane, equilibrium requires both horizontal and vertical force components to separately add to zero. Many NEET problems involve strings, weights, inclined forces and concurrent forces meeting at one point. Free body diagrams and force resolution are the safest methods. Lami’s theorem is a shortcut for three concurrent, coplanar and non-parallel forces in equilibrium. It relates each force to the sine of the angle between the other two forces.
- 1Equilibrium does not always mean rest; it means acceleration is zero.
- 2If three forces keep a particle in equilibrium, their vector triangle closes.
- 3For two forces to balance, they must be equal, opposite and collinear.
- 4Resolve inclined forces into x and y components.
- 5Lami’s theorem is useful for tensions in two strings supporting a weight.
- 6Angles in Lami’s theorem are the angles between the other two forces, not arbitrary angles with axes.
Equilibrium Components
Balance east-west and north-south separately: ΣFx = 0 and ΣFy = 0.
Lami’s Theorem
Each force sits over sine of the angle opposite to it.
Practice Question
A 10 N weight is held by two equal strings symmetrically. Vertical components of tensions add to 10 N; horizontal components cancel.
Lami Example
If three equal forces are in equilibrium, the angle between any two forces is 120 degrees.
Applying Lami’s Theorem Without Concurrent Forces
Lami’s theorem is valid only for three concurrent coplanar forces in equilibrium.
Using Forces Exerted by the Particle
In FBD, draw forces acting on the particle, not forces exerted by it.
Vector sum of all external forces on a particle must be zero.
Variables
ΣF=Resultant force
For equilibrium in a plane, net force in each perpendicular direction must be zero.
Variables
ΣFx=Sum of x-components of forces
ΣFy=Sum of y-components of forces
🪵 5. Friction
Overview
Friction is a contact force that opposes relative motion or the tendency of relative motion between surfaces. Static friction acts when there is no slipping and adjusts itself according to need up to a maximum called limiting friction. Once sliding begins, kinetic friction acts and is usually slightly smaller than limiting friction. The coefficient of friction measures roughness and equals friction divided by normal reaction in limiting or kinetic cases. Angle of friction is related to the resultant contact force, while angle of repose is the minimum inclination at which a body just begins to slide. Friction is necessary for walking, writing, vehicle motion and braking, but also causes wear and energy loss.
- 1Friction does not always oppose motion; it opposes relative motion or tendency at contact.
- 2For a body at rest, friction may be less than μ_sN.
- 3Normal reaction depends on surface geometry and other forces.
- 4On an incline, components of weight are mg sinθ along plane and mg cosθ normal to plane.
- 5At impending motion down an incline, mg sinθ = μmg cosθ.
- 6Rolling friction is much smaller than sliding friction.
Static Friction
Static friction is smart: it adjusts only as much as needed, up to its limit.
Angle of Repose
At repose angle, sliding is about to start, so tanθ = μ.
Horizontal Surface Example
A 10 kg block has μ_s = 0.4. Maximum static friction = μ_smg = 0.4×10×10 = 40 N.
Angle of Repose Example
If μ = 1/√3, angle of repose θ satisfies tanθ = 1/√3, so θ = 30 degrees.
Always Writing f = μN for Static Friction
Static friction equals μ_sN only at limiting condition. Otherwise it may be smaller.
Wrong Friction Direction
Friction opposes relative motion or tendency at contact, not always the motion of the body relative to ground.
Taking N = mg on Incline
On an incline, normal reaction is mg cosθ if no other perpendicular forces exist.
Static friction adjusts from zero up to limiting value.
Variables
f_s=Static friction
μ_s=Coefficient of static friction
N=Normal reaction
Maximum value of static friction just before slipping begins.
Variables
f_lim=Limiting friction
μ_s=Coefficient of static friction
N=Normal reaction
Frictional force during sliding motion.
Variables
f_k=Kinetic friction
μ_k=Coefficient of kinetic friction
N=Normal reaction
🔄 6. Circular Motion Applications
Overview
Circular motion applications use Newton’s second law toward the centre of the circle. A body moving in a circle requires centripetal force mv²/r, which is not a new force but the inward resultant of real forces such as tension, friction, gravity or normal reaction. In a vehicle moving on a curved road, friction or banking supplies the required centripetal force. Banking reduces dependence on friction by using a component of normal reaction. A conical pendulum moves in a horizontal circle, where horizontal tension gives centripetal force and vertical tension balances weight. In vertical circular motion, tension and weight change at different points, making top and bottom conditions important.
- 1Always choose radial inward direction for centripetal equation.
- 2Tangential velocity is perpendicular to radius.
- 3On a flat road, maximum safe speed is v = √(μrg).
- 4Banked road design speed does not require friction when tanθ = v²/rg.
- 5In vertical circle, weight may help or oppose centripetal requirement depending on position.
- 6For a string just taut at top, tension at top becomes zero.
Centripetal Force
Centripetal means centre-seeking: always write radial equation toward the centre.
Banking
Banking tilts normal reaction so it can help turn the vehicle.
Flat Road Example
If μ = 0.25 and r = 40 m, maximum speed = √(0.25×40×10) = 10 m/s.
Conical Pendulum Example
For a conical pendulum, dividing T sinθ = mv²/r by T cosθ = mg gives tanθ = v²/rg.
Calling Centripetal Force a Separate Force
Centripetal force is the net inward force, supplied by real forces like friction, tension or gravity.
Wrong Direction of Acceleration
Centripetal acceleration is always inward, not in the direction of velocity.
Using Same Vertical Circle Equation Everywhere
At top and bottom, radial directions differ, so tension equations are different.
Net inward force required for circular motion.
Variables
F_c=Centripetal force
m=Mass
v=Speed
r=Radius
Maximum speed on a flat road when friction provides centripetal force.
Variables
v_max=Maximum safe speed
μ=Coefficient of friction
r=Radius of curve
g=Acceleration due to gravity
Condition for safe turning on a banked road without relying on friction.
Variables
θ=Banking angle
v=Design speed
r=Radius of road curve
📝 7. Problem Solving
Overview
Problem solving in Laws of Motion depends on selecting the body or system, drawing a correct free body diagram and applying Newton’s second law along suitable axes. For a block on a horizontal surface, horizontal forces decide acceleration and vertical forces decide normal reaction. For an inclined plane, axes along and perpendicular to the plane simplify equations. Connected blocks and pulleys require separate FBDs and constraint relations because connected bodies often have related accelerations. Elevator problems modify apparent weight due to vertical acceleration. Friction-based problems require deciding whether friction is static, limiting or kinetic. Mixed NEET problems usually combine FBD, friction, pulley tension and acceleration equations.
- 1For a block on smooth horizontal surface, acceleration is applied force divided by mass.
- 2For a block sliding down smooth incline, acceleration is g sinθ.
- 3For connected blocks, tension is usually internal if the whole system is selected.
- 4In a massless frictionless pulley, tension is same throughout the same string.
- 5Elevator apparent weight is N = m(g + a) upward acceleration and N = m(g - a) downward acceleration.
- 6Constraint relation means connected bodies may have equal or related accelerations.
- 7If assumed friction direction gives negative value, actual friction direction is opposite.
Newton Problem Method
FBD first, formula later. Most mistakes disappear when the diagram is correct.
Incline Components
On incline: sin slides, cos presses.
Elevator
Accelerating up feels heavier; accelerating down feels lighter.
Block on Incline
A block slides down a smooth 30 degree incline. Acceleration = g sin30 = 10 × 1/2 = 5 m s^-2.
Connected Blocks
Two blocks 2 kg and 3 kg on a smooth surface are pulled by 10 N. System acceleration = 10/(2+3) = 2 m s^-2.
Elevator Example
A 60 kg person in an elevator accelerating upward at 2 m s^-2 has apparent weight N = 60(10+2) = 720 N.
Friction Example
A 5 kg block has μ = 0.2 and is pulled by 20 N. Friction = 0.2×5×10 = 10 N, so acceleration = (20-10)/5 = 2 m s^-2.
Skipping FBD
Direct formula use fails in mixed problems. Always draw forces before equations.
Using Same Acceleration Without Constraint
Connected bodies may have equal acceleration only when string geometry demands it.
Ignoring Static Friction Check
Before using kinetic friction, verify whether the applied force exceeds maximum static friction.
Wrong Tension Assumption
Tension is same only in a massless string over a frictionless pulley.
Acceleration when a net horizontal force F acts on mass m without friction.
Variables
a=Acceleration
F=Applied horizontal force
m=Mass
Acceleration of a sliding block pulled horizontally on a rough surface.
Variables
μ=Coefficient of kinetic friction
mg=Weight
Acceleration down a smooth incline due to component of gravity.
Variables
θ=Angle of inclination
g=Acceleration due to gravity
Formula Sheet
10Net external force equals mass multiplied by acceleration for constant mass.
Variables
F_net=Resultant external force
m=Mass of body
a=Acceleration
Linear momentum is the product of mass and velocity.
Variables
p=Linear momentum
m=Mass
v=Velocity
Impulse is the change in momentum produced by force acting for a time interval.
Variables
J=Impulse
F=Average force
Δt=Time interval
Δp=Change in momentum
Static friction adjusts up to a maximum value, while kinetic friction has nearly constant magnitude.
Variables
f_s=Static friction
f_k=Kinetic friction
μ_s, μ_k=Coefficients of static and kinetic friction
N=Normal reaction
Net inward force required for circular motion.
Variables
F_c=Centripetal force
v=Speed in circular path
r=Radius of circular path
5 more formulas locked
Sign up free to access all formulas with variables and explanations.
Quick Revision
12 Sign up to accessUnlock 12 Quick Revision Points
Sign up free to access all content, practice PYQs, and get AI explanations.
Learning Videos
6 Sign up to accessUnlock 6 Learning Videos
Sign up free to access all content, practice PYQs, and get AI explanations.
NEET PYQs — Laws of Motion
45 Sign up to accessShowing 3 of 45 questions. Sign up to practice all with answers, explanations, and AI help.
The magnitude and direction of the acceleration produced in a body of mass 5 kg when two mutually perpendicular forces 8 N and 6 N act on it, are respectively:
A box of mass 15 kg is kept on the floor of a stationary trolley. The coefficient of static friction between the box and the trolley is 0.12. Keeping the box in stationary state over the trolley, the maximum acceleration with which the trolley can be moved horizontally in m s⁻² is: (g = 10 m/s²)
A uniform rod of mass 20 kg and length 5 m leans against a smooth vertical wall making an angle of 60° with it. The other end rests on a rough horizontal floor. The friction force that the floor exerts on the rod is (g = 10 m/s²)
Unlock the full Laws of Motion experience
All diagrams, videos, quick revision, PYQ practice with AI explanations — plus mock tests, flashcards, and a personalised study plan.



![Forces and Newton's Laws of Motion [Overview]](https://img.youtube.com/vi/_BC-PfpyExo/mqdefault.jpg)

