NEET Physics · NCERT Class 11

Thermal Properties of Matter notes

Temperature & Heat, Thermal Expansion, Specific Heat & Calorimetry, Change of State & Latent Heat, Heat Transfer and Newton's Law of Cooling — explained topic by topic with key points, formulas, memory tricks and common mistakes.

  • 7 topics
  • 62 min read
  • 31 formulas
  • 16 PYQs
1

Chapter Overview

7 min

Thermal Properties of Matter explains how matter responds to heat. Temperature tells the degree of hotness and decides the direction of heat flow, while heat is energy transferred due to temperature difference. The chapter covers temperature scales, heat capacity, thermal expansion of solids and liquids, anomalous expansion of water, calorimetry, specific heat, change of state, latent heat and heat transfer by conduction, convection and radiation. Newton's law of cooling explains how hot bodies cool in surroundings. For NEET, this chapter is highly scoring because questions are usually formula-based, graph-based or application-based, especially from calorimetry, thermal expansion, latent heat, heat conduction and cooling curves.

Key points7

  • Kelvin temperature is absolute temperature and K = °C + 273.15 approximately.
  • Specific heat capacity depends on material and state.
  • During phase change, temperature remains constant even though heat is supplied or removed.
  • Water has maximum density at 4°C due to anomalous expansion.
  • Conduction requires material medium; radiation does not.
  • Black bodies are perfect absorbers and emitters of radiation.
  • Cooling rate depends on temperature difference between body and surroundings.

Memory tricks2

Heat vs Temperature: Temperature decides direction; heat is energy in transit.

Two Heat Formulas: Temperature change uses mcΔT; state change uses mL.

Examples2

Daily Life Example

A metal spoon in hot tea becomes warm by conduction, while the tea cools by conduction, convection, radiation and evaporation.

NEET Quick Example

To heat 0.5 kg water by 20 K, heat required is Q = mcΔT = 0.5 × 4200 × 20 = 42000 J.

Common mistakes3

Confusing Heat and Temperature

Heat is energy transferred due to temperature difference; temperature is a measure of hotness.

Using Q = mcΔT During Phase Change

During phase change, temperature is constant and heat is Q = mL.

Forgetting Kelvin in Radiation Problems

Thermal radiation formulas use absolute temperature in kelvin.

Reference tables2

Quick revision8

Formulas5

Celsius-Kelvin Conversion
T(K)=t(°C)+273.15T(K) = t(°C) + 273.15

Converts Celsius temperature to absolute Kelvin temperature.

T
Temperature in kelvin
t
Temperature in degree Celsius
Heat for Temperature Change
Q=mcΔTQ = mcΔT

Heat required to change temperature of a body without changing its state.

Q
Heat supplied or removed
m
Mass
c
Specific heat capacity
ΔT
Change in temperature
Latent Heat
Q=mLQ = mL

Heat required for phase change at constant temperature.

Q
Heat supplied or removed
m
Mass undergoing phase change
L
Specific latent heat
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2

Temperature & Heat

8 min

Temperature is the physical quantity that tells how hot or cold a body is and decides the direction of heat flow. When two bodies are in thermal contact, heat flows from the body at higher temperature to the body at lower temperature until thermal equilibrium is reached. Heat is energy in transit due to temperature difference, while internal energy is the total microscopic kinetic and potential energy of molecules of a body. Temperature can be measured using Celsius, Kelvin and Fahrenheit scales. Kelvin is the SI scale and begins at absolute zero. Heat capacity is the heat required to raise the temperature of a body by one kelvin, while specific heat capacity is per unit mass.

Key points6

  • A body does not contain heat; it contains internal energy.
  • Heat flows only because of temperature difference.
  • Two bodies can have different internal energies but same temperature.
  • Kelvin temperature cannot be negative in ordinary thermodynamics.
  • Heat capacity depends on mass and material.
  • Specific heat capacity is a material property for a given state and condition.

Memory tricks2

Heat vs Temperature: Temperature tells direction; heat is energy in transition.

Celsius to Fahrenheit: Multiply by 9/5 and add 32.

Examples2

Solved Example: Temperature Conversion

25°C in kelvin is 25 + 273.15 = 298.15 K. In Fahrenheit, F = 9×25/5 + 32 = 77°F.

Solved Example: Heat Capacity

If 500 J heat raises a body's temperature by 10 K, heat capacity C = Q/ΔT = 500/10 = 50 J K^-1.

Common mistakes3

Saying Heat Is Stored in a Body

A body stores internal energy, not heat. Heat is energy being transferred.

Using Celsius in Absolute Temperature Formulas

Use kelvin for thermodynamic formulas involving absolute temperature.

Confusing Heat Capacity and Specific Heat

Heat capacity is for the whole body, while specific heat is per unit mass.

Reference tables2

Quick revision8

Formulas5

Celsius to Kelvin
T(K)=t(°C)+273.15T(K) = t(°C) + 273.15

Conversion from Celsius temperature to Kelvin temperature.

T
Temperature in kelvin
t
Temperature in degree Celsius
Celsius to Fahrenheit
F=9C/5+32F = 9C/5 + 32

Conversion from Celsius to Fahrenheit scale.

F
Temperature in Fahrenheit
C
Temperature in Celsius
General Temperature Scale Relation
(C−0)/100=(F−32)/180=(K−273.15)/100(C - 0)/100 = (F - 32)/180 = (K - 273.15)/100

Relates Celsius, Fahrenheit and Kelvin scales using fixed points of water.

C
Celsius reading
F
Fahrenheit reading
K
Kelvin reading
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3

Thermal Expansion

9 min

Most materials expand when heated and contract when cooled because their particles vibrate with greater average separation at higher temperature. In solids, expansion can be measured as linear expansion, superficial expansion or volume expansion. Linear expansion describes change in length, superficial expansion describes change in area and volume expansion describes change in volume. Their coefficients are α, β and γ respectively, and for isotropic solids β ≈ 2α and γ ≈ 3α. Water behaves unusually between 0°C and 4°C: it contracts on heating from 0°C to 4°C and expands above 4°C, making its density maximum at 4°C. This anomalous expansion is important for aquatic life in winter.

Key points6

  • Thermal expansion depends on original dimension, temperature change and material coefficient.
  • Liquids show only volume expansion because they do not have fixed shape.
  • Apparent expansion of liquid is observed relative to container expansion.
  • Anomalous expansion of water prevents complete freezing of lakes from bottom to top.
  • A hole in a metal plate expands on heating as if the hole were made of the same material.
  • Thermal stress can develop if expansion is prevented.

Memory tricks2

Coefficient Relation: Length, area, volume go 1, 2, 3: α, 2α, 3α.

Water Anomaly: Water is densest at 4°C; this is why lakes freeze from top, not bottom.

Examples2

Numerical Problem

A 2 m rod with α = 12 × 10^-6 K^-1 is heated by 50 K. ΔL = αLΔT = 12×10^-6×2×50 = 1.2×10^-3 m.

Application Example

Railway tracks have small gaps so that rails do not buckle when they expand on hot days.

Common mistakes3

Forgetting Unit of Expansion Coefficient

Coefficient of expansion has unit K^-1 or °C^-1.

Using Linear Formula for Volume

Use ΔV = γVΔT for volume expansion, not ΔL = αLΔT.

Assuming Holes Shrink on Heating

A hole in a heated metal plate expands as if filled with the same material.

Reference tables2

Quick revision8

Formulas5

Linear Expansion
ΔL=αLΔTΔL = αLΔT

Change in length of a solid rod or wire due to temperature change.

ΔL
Change in length
α
Coefficient of linear expansion
L
Original length
ΔT
Change in temperature
Superficial Expansion
ΔA=βAΔTΔA = βAΔT

Change in area due to temperature change.

ΔA
Change in area
β
Coefficient of superficial expansion
A
Original area
Volume Expansion
ΔV=γVΔTΔV = γVΔT

Change in volume due to temperature change.

ΔV
Change in volume
γ
Coefficient of volume expansion
V
Original volume
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4

Specific Heat & Calorimetry

10 min

Specific heat capacity is the heat required to raise the temperature of unit mass of a substance by one kelvin. Heat capacity is the heat required for the whole body, while molar heat capacity is the heat required to raise the temperature of one mole by one kelvin. Calorimetry is the measurement of heat exchange. The principle of calorimetry states that if no heat is lost to surroundings, heat lost by hotter bodies equals heat gained by colder bodies. This principle is used in mixture problems, finding final temperature, and determining specific heat. Water has high specific heat, so it absorbs or releases large heat for small temperature change, affecting climate and cooling systems.

Key points6

  • Specific heat is a property of material, while heat capacity also depends on mass.
  • Temperature change in kelvin and Celsius has the same numerical value.
  • In calorimetry, assign heat gained positive and heat lost negative or equate magnitudes carefully.
  • For mixtures of same substance, final temperature can be found by weighted average using masses.
  • If phase change occurs, include latent heat terms.
  • NEET mixture questions often require careful heat balance.

Memory tricks2

Calorimetry Principle: In an insulated setup: hot loses, cold gains.

Heat Capacity vs Specific Heat: Heat capacity is for body; specific heat is for 1 kg.

Examples2

Solved Mixture Example

100 g water at 80°C is mixed with 100 g water at 20°C. Same mass and same specific heat give final temperature = (80 + 20)/2 = 50°C.

Specific Heat Example

A 2 kg metal absorbs 1000 J and temperature rises by 5 K. c = Q/(mΔT) = 1000/(2×5) = 100 J kg^-1 K^-1.

Common mistakes3

Forgetting Calorimeter Heat Capacity

If calorimeter heat capacity is given, include heat gained or lost by calorimeter.

Using Celsius Instead of Temperature Difference

Temperature difference in °C and K is numerically same, so use ΔT carefully.

Ignoring Phase Change

If ice melts or steam condenses, include latent heat along with mcΔT.

Reference tables3

Quick revision8

Formulas5

Heat Capacity
C=Q/ΔTC = Q/ΔT

Heat required to raise the temperature of a body by one kelvin.

C
Heat capacity
Q
Heat supplied
ΔT
Temperature change
Specific Heat Capacity
c=Q/(mΔT)c = Q/(mΔT)

Heat required to raise temperature of unit mass by one kelvin.

c
Specific heat capacity
m
Mass
ΔT
Temperature change
Molar Heat Capacity
Cm=Q/(nΔT)Cm = Q/(nΔT)

Heat required to raise temperature of one mole by one kelvin.

Cm
Molar heat capacity
n
Number of moles
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5

Change of State & Latent Heat

9 min

Matter commonly exists as solid, liquid and gas. A change of state occurs when matter changes from one state to another due to heat exchange. Melting changes solid to liquid, freezing changes liquid to solid, vaporisation changes liquid to gas, condensation changes gas to liquid and sublimation changes solid directly to gas. During a phase change at constant pressure, temperature remains constant even though heat is supplied or removed. This hidden heat is called latent heat because it changes internal molecular arrangement rather than temperature. Latent heat of fusion is used in melting and freezing, while latent heat of vaporisation is used in boiling and condensation. Heating and cooling curves help visualize these processes.

Key points6

  • Latent heat does not raise temperature; it changes state.
  • Latent heat of vaporisation is usually larger than latent heat of fusion.
  • Melting point and boiling point depend on pressure.
  • Steam at 100°C causes more severe burns than water at 100°C because steam releases latent heat on condensation.
  • Cooling curve is reverse of heating curve.
  • NEET often asks heating curve, ice-water mixing and steam-water mixing problems.

Memory tricks2

Phase Change Heat: Temperature change uses c; state change uses L.

Latent Meaning: Latent means hidden: heat is absorbed but temperature does not rise.

Examples2

Solved Example: Melting Ice

To melt 0.1 kg ice at 0°C, if Lf = 3.36 × 10^5 J kg^-1, Q = mLf = 0.1 × 3.36 × 10^5 = 3.36 × 10^4 J.

Steam Example

Steam at 100°C gives more heat than water at 100°C because it first condenses and releases latent heat of vaporisation.

Common mistakes3

Adding Temperature Rise During Melting

During melting or boiling, temperature remains constant until phase change completes.

Using Same Specific Heat for All States

Ice, water and steam have different specific heat capacities.

Ignoring Latent Heat in Ice or Steam Problems

Always include mL when phase change occurs.

Reference tables2

Quick revision8

Formulas4

Latent Heat
Q=mLQ = mL

Heat required to change state of mass m at constant temperature.

Q
Heat supplied or removed
m
Mass changing state
L
Specific latent heat
Latent Heat of Fusion
Q=mLfQ = mLf

Heat required to convert solid into liquid at melting point without temperature change.

Lf
Specific latent heat of fusion
m
Mass melted or frozen
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6

Heat Transfer

10 min

Heat transfer occurs by conduction, convection and radiation. Conduction is heat transfer through a material without bulk movement of matter, mainly due to molecular collisions and free electrons. It is important in solids and is described by thermal conductivity. Convection is heat transfer by bulk motion of fluid; hot fluid rises and cold fluid sinks, producing convection currents. Radiation is heat transfer by electromagnetic waves and does not require a material medium. A black body is an ideal absorber and emitter of radiation, while emissivity measures how effectively a real body emits compared with a black body. Everyday examples include cooking, sea breeze, thermos flasks, warm clothes, room heaters and cooling fins.

Key points7

  • Metals are good conductors mainly due to free electrons.
  • Air is a poor conductor, so woollen clothes trap air for insulation.
  • Convection cannot occur in solids because bulk movement is not possible.
  • Radiation intensity increases strongly with absolute temperature.
  • Shiny surfaces are poor absorbers and poor emitters.
  • Blackened surfaces absorb and radiate heat efficiently.
  • Thermos flask reduces conduction, convection and radiation.

Memory tricks2

Modes of Heat Transfer: Conduction contacts, convection circulates, radiation radiates.

Radiation: Radiation needs no medium; sunlight reaches Earth through vacuum.

Examples3

Conduction Example

A metal spoon placed in hot soup becomes hot because heat is conducted through the metal.

Convection Example

Sea breeze forms because land heats faster than sea, producing convection currents in air.

Radiation Example

You feel heat from a fire even without touching it because thermal radiation reaches you.

Common mistakes3

Thinking Convection Occurs in Solids

Convection needs bulk motion, so it occurs in fluids, not solids.

Using Celsius in Stefan Law

Radiation formulas require absolute temperature in kelvin.

Confusing Good Absorber and Poor Emitter

Good absorbers are generally good emitters; black surfaces are good at both.

Reference tables3

Quick revision8

Formulas4

Heat Current by Conduction
H=Q/t=kA(T1−T2)/lH = Q/t = kA(T1 - T2)/l

Rate of heat flow through a slab of thickness l and area A.

H
Heat current or rate of heat transfer
Q
Heat transferred
t
Time
k
Thermal conductivity
A
Area
T1 - T2
Temperature difference
l
Thickness or length
Thermal Resistance
Rth=l/(kA)R_{th} = l/(kA)

Resistance offered by a slab to heat conduction.

R_th
Thermal resistance
l
Thickness
k
Thermal conductivity
A
Area
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7

Newton's Law of Cooling

9 min

Newton's law of cooling states that the rate of loss of heat or fall of temperature of a body is directly proportional to the temperature difference between the body and its surroundings, provided the temperature difference is small and surrounding temperature remains constant. Mathematically, dT/dt = -k(T - Ts). The negative sign shows that body temperature decreases during cooling. The cooling curve is exponential: the body cools quickly at first when temperature difference is large and slowly later as it approaches room temperature. The law is used to estimate cooling of hot liquids, forensic time of death, thermometer response and heat loss from objects. Experimental verification involves recording temperature at equal time intervals.

Key points6

  • The greater the temperature difference, the faster the cooling.
  • The negative sign indicates fall in body temperature.
  • For small temperature intervals, average temperature difference can be used.
  • Radiation, convection and conduction may all contribute to cooling.
  • Cooling constant depends on surface area, nature of surface, mass, specific heat and surroundings.
  • Blackened surfaces cool faster than polished surfaces due to better radiation.

Memory tricks2

Cooling Law: Cooling speed depends on temperature gap: bigger gap, faster cooling.

Curve Shape: Cooling is fast first, flat later; think exponential fall.

Examples2

Solved Example

A body cools from 80°C to 70°C in 5 min in surroundings at 30°C. Average excess temperature = ((80+70)/2) - 30 = 45°C. Cooling rate = 10/5 = 2°C/min.

Application Example

Tea cools faster when it is very hot because its temperature difference with room air is larger initially.

Common mistakes3

Assuming Constant Cooling Rate

Cooling rate decreases as body temperature approaches surrounding temperature.

Ignoring Surrounding Temperature

The law depends on T - Ts, not only on body temperature.

Using Law for Very Large Temperature Differences

Newton's law of cooling is most valid for small temperature differences.

Reference tables3

Quick revision8

Formulas3

Newton's Law of Cooling
dT/dt=−k(T−Ts)dT/dt = -k(T - Ts)

Rate of temperature fall is proportional to excess temperature of body over surroundings.

T
Temperature of body
Ts
Temperature of surroundings
k
Cooling constant
Exponential Cooling
T−Ts=(T0−Ts)e(−kt)T - Ts = (T0 - Ts)e^(-kt)

Temperature difference decreases exponentially with time.

T0
Initial temperature of body
t
Time elapsed
e
Base of natural logarithm
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Diagrams4

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NEET PYQs from Thermal Properties of Matter

The latest 3 of 16 previous-year questions from this chapter.

  1. NEET 2026Set 50EasyQ1

    The temperature of a metallic sphere of radius $R$ is increased by a small amount $\Delta T$. If the linear coefficient of thermal expansion of the metal is $\alpha$, the approximate increase in the volume of the sphere is:

    • A$2\pi R^3\alpha\Delta T$
    • B$3\pi R^3\alpha\Delta T$
    • C$4\pi R^3\alpha\Delta T$
    • D$6\pi R^3\alpha\Delta T$
  2. NEET 2025Set 45MediumQ2

    Three identical heat conducting rods are connected in series as shown in the figure. The rods on the sides have thermal conductivity 2K while that in the middle has thermal conductivity K. The left end of the combination is maintained at temperature 3T and the right end at T. The rods are thermally insulated from outside. In steady state, the temperature at the left junction is $T_1$ and that at the right junction is $T_2$. The ratio $T_1$/$T_2$ is

    • A3/2
    • B4/3
    • C5/3
    • D5/4
  3. NEET 2021Set P3MediumQ3

    A cup of coffee cools from $90^\circ C$ to $80^\circ C$ in $t$ minutes, when the room temperature is $20^\circ C$. The time taken by a similar cup of coffee to cool from $80^\circ C$ to $60^\circ C$ at the same room temperature of $20^\circ C$ is:

    • A$\frac{5}{13}t$
    • B$\frac{13}{10}t$
    • C$\frac{13}{5}t$
    • D$\frac{10}{13}t$

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