NEET Physics · NCERT Class 11

Mechanical Properties of Solids notes

Stress & Strain, Hooke's Law & Elastic Moduli, Stress-Strain Curve and Applications of Elasticity — explained topic by topic with key points, formulas, memory tricks and common mistakes.

  • 5 topics
  • 43 min read
  • 23 formulas
  • 11 PYQs
1

Chapter Overview

7 min

Mechanical Properties of Solids explains how solids respond when external forces stretch, compress, twist, shear or bend them. A solid resists deformation because internal restoring forces develop between its particles. Stress measures restoring force per unit area, while strain measures fractional deformation. If a body regains its original shape after the deforming force is removed, it shows elastic behaviour; if permanent deformation remains, it shows plastic behaviour. Hooke's law states that stress is proportional to strain within the proportional limit. The proportionality constants are elastic moduli: Young's modulus, bulk modulus and shear modulus. The stress-strain curve helps identify elastic limit, yield point, ultimate stress and breaking point, which are very important for NEET.

Key points6

  • Elasticity is the property by which a body regains its original shape and size after removal of deforming force.
  • Greater elastic modulus means greater stiffness and smaller strain for the same stress.
  • The slope of the linear part of stress-strain curve gives Young's modulus.
  • Area under stress-strain graph gives elastic energy stored per unit volume.
  • Safety factor is used in construction so that working stress stays much below breaking stress.
  • NEET commonly asks formulas, units, graph regions and comparisons of ductile and brittle materials.

Memory tricks2

Stress vs Strain: Stress is the force effect; strain is the shape effect.

Three Moduli: Young changes length, Bulk changes volume, Shear changes shape.

Examples2

Real-Life Example

Steel cables in cranes stretch slightly under heavy loads and return to original length if the elastic limit is not crossed.

NEET Quick Example

If stress is 2 × 10^8 Pa and strain is 10^-3, Young's modulus is 2 × 10^11 Pa.

Common mistakes3

Confusing Elasticity with Rigidity

Elasticity means ability to regain original shape; rigidity means resistance to deformation.

Treating Strain as Having Unit

Strain is dimensionless because it is a ratio of similar quantities.

Using Hooke's Law Beyond Limit

Hooke's law is valid only up to proportional limit, not for all deformations.

Reference tables2

Quick revision8

Formulas4

Stress
Stress =F/A\text{Stress }= F/A

Stress is the internal restoring force per unit area developed in a body under deforming force.

F
Restoring or applied force
A
Area of cross-section
Strain
Strain = change in dimension/original dimension\text{Strain }=\text{ change in dimension}/\text{original dimension}

Strain measures relative deformation and has no unit.

change in dimension
Change in length, volume or shape
original dimension
Initial length, volume or relevant dimension
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Diagrams3

2

Stress & Strain

9 min

When a deforming force is applied to a solid, the solid develops internal restoring forces that oppose deformation. Stress is defined as restoring force per unit area. It may be tensile, compressive, hydraulic or shear depending on the way force acts. Strain is the relative change in shape or size caused by stress. Longitudinal strain measures change in length, volumetric strain measures change in volume and shear strain measures change in shape. For small deformations, stress is proportional to strain, giving the stress-strain relationship. If deformation disappears after removing the force, it is elastic deformation. If a permanent change remains, it is plastic deformation.

Key points6

  • Stress is calculated using force per area but represents internal restoring response.
  • The direction of applied force decides the type of stress.
  • Strain has no dimensions because it is a ratio.
  • For a thin wire under tension, longitudinal stress and strain are most important.
  • Shear strain is approximately equal to angular displacement in radians for small angles.
  • Elastic and plastic deformation are separated by the elastic limit.

Memory tricks2

Stress Types: Pull stretches, push compresses, side force shears.

Strain Rule: Strain is always change divided by original.

Examples2

Solved Example: Stress

A force of 200 N acts on a wire of area 2 × 10^-6 m². Stress = F/A = 200/(2 × 10^-6) = 1 × 10^8 Pa.

Solved Example: Strain

A 2 m wire extends by 1 mm. Strain = 0.001/2 = 5 × 10^-4.

Common mistakes3

Using External Force Direction Incorrectly

Stress type depends on whether force is normal, tangential, tensile or compressive.

Forgetting Area in Stress

Same force produces larger stress in a thinner wire because area is smaller.

Confusing Elastic and Plastic Behaviour

Elastic recovery is complete; plastic deformation remains after unloading.

Reference tables3

Quick revision8

Formulas5

Normal Stress
σ=F/Aσ = F/A

Stress due to force normal to the cross-sectional area.

σ
Normal stress
F
Normal force
A
Area of cross-section
Longitudinal Strain
ε=ΔL/Lε = ΔL/L

Fractional change in length due to tensile or compressive stress.

ε
Longitudinal strain
ΔL
Change in length
L
Original length
Volumetric Strain
Volumetric strain =ΔV/V\text{Volumetric strain }= ΔV/V

Fractional change in volume due to hydraulic stress.

ΔV
Change in volume
V
Original volume
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Diagrams3

3

Hooke's Law & Elastic Moduli

10 min

Hooke's law states that stress is directly proportional to strain within the proportional limit. This simple law allows us to define elastic moduli, which measure stiffness of a material. Young's modulus describes resistance to change in length, bulk modulus describes resistance to change in volume and shear modulus describes resistance to change in shape. These constants are material properties and have the same unit as stress because strain is dimensionless. Elastic constants are related through Poisson's ratio for isotropic materials. When a body is elastically deformed, work done by external force is stored as elastic potential energy. Elastic energy density equals the area under the stress-strain graph in the linear region.

Key points6

  • Hooke's law does not apply beyond proportional limit.
  • Young's modulus is high for steel, so steel is difficult to stretch.
  • Bulk modulus is high for nearly incompressible materials.
  • Shear modulus is related to shape rigidity.
  • Fluids cannot sustain static shear, so shear modulus is effectively zero for fluids.
  • Energy stored in a stretched wire equals area under force-extension graph.

Memory tricks2

Y-B-G Shortcut: Y changes length, B changes bulk volume, G changes geometry or shape.

Elastic Energy: Stretching energy has a half because force rises gradually from zero to F.

Examples2

Numerical Problem: Young's Modulus

A wire of length 2 m and area 1 × 10^-6 m² extends by 1 mm under 100 N. Y = FL/(AΔL) = 100×2/(10^-6×10^-3) = 2 × 10^11 Pa.

Numerical Problem: Elastic Energy

A wire stretches by 2 mm under final force 50 N. U = 1/2 FΔL = 1/2×50×0.002 = 0.05 J.

Common mistakes3

Missing Minus Sign in Bulk Modulus

Compression makes ΔV negative, so K = -P/(ΔV/V) is positive.

Confusing Energy and Energy Density

Energy is in joule, while energy density is energy per unit volume.

Assuming Higher Modulus Means More Stretching

Higher modulus means less strain for the same stress, so the material is stiffer.

Reference tables2

Quick revision8

Formulas7

Hooke's Law
Stress = constant × strain\text{Stress }=\text{ constant }×\text{ strain}

Within proportional limit, stress varies linearly with strain.

constant
Elastic modulus for the deformation type
strain
Relative deformation
Young's Modulus
Y=FL/(AΔL)Y = FL/(AΔL)

Young's modulus measures resistance to longitudinal stretching or compression.

Y
Young's modulus
F
Longitudinal force
L
Original length
A
Area of cross-section
ΔL
Change in length
Bulk Modulus
K=−P/(ΔV/V)K = -P/(ΔV/V)

Bulk modulus measures resistance to volume compression.

K
Bulk modulus
P
Applied pressure or hydraulic stress
ΔV/V
Volumetric strain
Shear Modulus
G=(F/A)/θG = (F/A)/θ

Shear modulus measures resistance to change in shape.

G
Shear modulus or modulus of rigidity
F/A
Shear stress
θ
Shear strain in radians
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Diagrams4

4

Stress-Strain Curve

9 min

The stress-strain curve shows how a material responds as stress is gradually increased. Initially, the graph is a straight line and Hooke's law is obeyed up to the proportional limit. The elastic limit is the maximum stress up to which the material completely regains its original shape on unloading. Beyond this, plastic deformation begins. The yield point marks the stage where strain increases greatly with little increase in stress. Ultimate stress is the maximum stress the material can bear. After this, necking or weakening may occur, and the specimen finally breaks at the breaking point. Ductile materials show large plastic deformation, while brittle materials break with little strain.

Key points6

  • Proportional limit and elastic limit may be close but are conceptually different.
  • Beyond elastic limit, unloading leaves permanent strain.
  • Ultimate stress can be higher than breaking stress for ductile materials.
  • Brittle materials do not show a well-defined yield region.
  • Ductile materials can be drawn into wires because they undergo large plastic deformation.
  • NEET frequently tests graph labeling and comparison of ductile versus brittle materials.

Memory tricks2

Curve Order: Remember P-E-Y-U-B: Proportional, Elastic, Yield, Ultimate, Breaking.

Ductile vs Brittle: Ductile draws into wire; brittle breaks like glass.

Examples2

Previous NEET Concept

If a stress-strain graph is initially a straight line, its slope represents Young's modulus.

Material Example

Copper is ductile because it can undergo large plastic deformation before breaking, while glass is brittle because it fractures suddenly.

Common mistakes3

Confusing Proportional Limit and Elastic Limit

Hooke's law ends at proportional limit, but elastic recovery may continue up to elastic limit.

Thinking Ultimate Stress Is Breaking Stress

Ultimate stress is maximum stress; breaking stress is stress at fracture and may be lower in ductile materials.

Ignoring Permanent Set

Beyond elastic limit, unloading does not bring the material back to original length.

Reference tables3

Quick revision8

Formulas3

Young's Modulus from Curve
Y= slope of initial straight part = stress/strainY =\text{ slope of initial straight part }=\text{ stress}/\text{strain}

The initial linear portion of the stress-strain graph gives Young's modulus.

Y
Young's modulus
stress
Longitudinal stress
strain
Longitudinal strain
Breaking Stress
Breaking stress = breaking force/original area\text{Breaking stress }=\text{ breaking force}/\text{original area}

Stress corresponding to final fracture of the material.

breaking force
Force at which body breaks
original area
Initial area of cross-section
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Diagrams3

5

Applications of Elasticity

8 min

Elasticity is essential in designing safe buildings, bridges, cranes, cables, springs and machines. Materials in engineering structures must withstand stress without exceeding elastic or breaking limits. A safety factor is used so that working stress remains much smaller than breaking stress. Suspension bridges use steel cables because steel has high Young's modulus, high tensile strength and reliable elastic behaviour. Elasticity also appears in daily life through springs, rubber bands, vehicle suspension, mattresses, shock absorbers and sports equipment. Practical NEET applications often test why certain materials are chosen, how safe load is calculated and how extension changes with length, area and Young's modulus.

Key points6

  • Engineering structures are designed to stay within elastic limit under normal working loads.
  • Safety factor accounts for sudden loads, fatigue, defects and environmental effects.
  • A high breaking stress means the material can withstand large stress before failure.
  • A high Young's modulus means the material does not deform much under stress.
  • Elasticity in daily life helps absorb shocks and restore shape.
  • NEET often combines application-based theory with Young's modulus formula.

Memory tricks2

Safety Factor: Break divided by work: safety factor tells how far working stress is from failure.

Extension Control: To reduce stretch: make it shorter, thicker or use a stiffer material.

Examples3

Real-World Example

Suspension bridge cables are made thick and strong so that actual working stress remains much less than breaking stress.

Solved Practice

A material has breaking stress 900 MPa and safety factor 3. Working stress = 900/3 = 300 MPa.

Practical NEET Application

If two wires of the same material and length support the same load, the wire with larger area has smaller stress and smaller extension.

Common mistakes3

Confusing Strength and Stiffness

Strength relates to breaking stress, while stiffness relates to Young's modulus.

Ignoring Safety Factor

Structures are never designed to work near breaking stress because sudden loads and defects can cause failure.

Assuming Elastic Materials Cannot Break

Elastic materials break if stress exceeds breaking stress.

Reference tables3

Quick revision8

Formulas4

Safety Factor
Safety factor = breaking stress/working stress\text{Safety factor }=\text{ breaking stress}/\text{working stress}

Safety factor tells how many times stronger a material is compared with the stress allowed in use.

breaking stress
Stress at which material breaks
working stress
Maximum stress permitted during normal operation
Safe Load
Fsafe= working stress ×AF_{\text{safe}} =\text{ working stress }× A

Maximum safe force a cable or rod can support under working stress.

F_safe
Safe load
A
Cross-sectional area
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Diagrams4

Videos for Mechanical Properties of Solids

  • Mechanical Properties of SolidsVedantu NEET English · English
  • MECHANICAL PROPERTIES OF SOLIDS 01 | Elasticity | PhysicsPW English Medium · English
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  • Stress & strain | Class 11 (India) | PhysicsKhan Academy India - English · English
  • Stress, Strain and Hooke's Law | Mechanical Properties of Solids | Physics | Class 11 | AASOKAAasoka · English
  • MECHANICAL PROPERTIES OF SOLIDS 02 | Bulk Modulus of Elasticity | Physics | Class 11th/NEET/JEEPW English Medium · English
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NEET PYQs from Mechanical Properties of Solids

The latest 3 of 11 previous-year questions from this chapter.

  1. NEET 2026Set 11EasyQ1

    Match List I with List II: Choose the correct answer from the options given below:

    • AA-IV, B-I, C-II, D-III
    • BA-III, B-II, C-I, D-IV
    • CA-I, B-IV, C-III, D-II
    • DA-II, B-III, C-IV, D-I
  2. NEET 2024Set T1MediumQ2

    The maximum elongation of a steel wire of 1 m length if the elastic limit of steel and its Young modulus, respectively, are 8 × 10⁸ N m⁻² and 2 × 10¹¹ N m⁻², is:

    • A40 mm
    • B8 mm
    • C4 mm
    • D0.4 mm
  3. NEET 2024Set T1MediumQ3

    A metallic bar of Young’s modulus 0.5 × 10¹¹ N m⁻² and coefficient of linear expansion 10⁻⁵ °C⁻¹, length 1 m and area of cross-section 10⁻³ m² is heated from 0°C to 100°C without expansion or bending. The compressive force developed in it is:

    • A100 × 10³ N
    • B2 × 10³ N
    • C5 × 10³ N
    • D50 × 10³ N

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