NEET Physics · NCERT Class 12

Current Electricity notes

Electric Current & Drift Velocity, Ohm's Law & Resistivity, Electrical Energy & Power, Cells & Internal Resistance, Kirchhoff's Laws and Wheatstone & Metre Bridge — explained topic by topic with key points, formulas, memory tricks and common mistakes.

  • 7 topics
  • 67 min read
  • 33 formulas
  • 76 PYQs
1

Chapter Overview

8 min

Current Electricity studies charges in motion and the circuits through which they flow. The chapter begins with electric current, current density, drift velocity and mobility, connecting microscopic electron motion with measurable current. Ohm’s law, resistance, resistivity, conductivity and temperature dependence explain how materials oppose current. Electrical energy and power show how circuits convert electrical energy into heat and useful work. Cells introduce emf, terminal voltage and internal resistance. Kirchhoff’s laws allow systematic analysis of complex circuits using charge and energy conservation. Wheatstone bridge and metre bridge are important applications used to compare and measure resistance. For NEET, this chapter is highly scoring because most questions are formula-based, circuit-based and numerically direct.

Key points6

  • Conventional current is opposite to electron drift direction.
  • Drift velocity is very small, but electric signal through a circuit is established very fast.
  • Resistance depends on length, area, material and temperature.
  • In series combination current is same; in parallel combination voltage is same.
  • Internal resistance causes terminal voltage to differ from emf.
  • Wheatstone bridge is balanced when no current flows through the galvanometer.

Memory tricks2

Chapter Flow Trick: Remember: Charges move → resistance opposes → power heats → cells drive → Kirchhoff solves → bridges measure.

Series and Parallel Quick Rule: Series has same current; parallel has same voltage.

Examples2

Real-Life Example

A phone charger converts electrical energy from the supply into chemical energy stored in the battery, with some energy lost as heat.

NEET-Style Snapshot

If voltage across a fixed resistor is doubled, current doubles by Ohm’s law because I = V/R.

Common mistakes2

Confusing Electron Flow and Conventional Current

Electron drift is from negative to positive terminal, but conventional current is taken from positive to negative terminal.

Using Ideal Cell Formula for Real Cell

A real cell has internal resistance, so terminal voltage differs from emf when current flows.

Reference tables2

Quick revision8

Formulas5

Electric Current
I=dq/dtI = dq/dt

Rate of flow of charge through a cross-section.

I
Electric current
dq
Small amount of charge
dt
Small time interval
Drift Velocity Relation
I= neAvdI =\text{ neAvd}

Connects macroscopic current with microscopic drift velocity of charge carriers.

n
Number density of free electrons
e
Electronic charge
A
Area of cross-section
vd
Drift velocity
Ohm's Law
V=IRV = IR

Potential difference across an ohmic conductor is proportional to current through it.

V
Potential difference
I
Current
R
Resistance
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Diagrams3

2

Electric Current & Drift Velocity

9 min

Electric current is the rate of flow of charge through a cross-section of a conductor. In metals, free electrons are the charge carriers. Without an electric field, electrons move randomly and no net current exists. When an electric field is applied, electrons acquire a small average velocity opposite to the field, called drift velocity. Conventional current is taken in the direction of positive charge flow, opposite to electron drift. Current density J describes current per unit area and points along conventional current. Mobility measures how easily charge carriers drift under an electric field. The relation I = neAvd connects microscopic electron motion with measurable current, making it a frequent NEET formula.

Key points6

  • Random thermal motion of electrons does not produce net current.
  • Applied electric field causes a small average drift superimposed on random motion.
  • Drift velocity is very small, typically of the order of mm/s or less.
  • Current appears quickly because electric field propagates through the circuit rapidly.
  • Current density is a vector quantity.
  • For the same current, thinner wire has larger current density.

Memory tricks2

Drift Direction: Electrons are negative, so they drift opposite to electric field and conventional current.

Current Formula: I = neAvd: more carriers, more area or more drift means more current.

Examples3

Numerical Example

If 12 C charge passes through a wire in 4 s, current I = q/t = 12/4 = 3 A.

Drift Velocity Example

For I = 1 A, n = 8 × 10²⁸ m⁻³, A = 1 mm² and e = 1.6 × 10⁻¹⁹ C, vd = I/(neA) ≈ 7.8 × 10⁻⁵ m/s.

NEET-Type Concept

When wire area decreases for the same current, current density increases because J = I/A.

Common mistakes2

Thinking Electrons Move at Light Speed

Electron drift velocity is small; the electrical signal spreads rapidly through the circuit.

Using Electron Charge with Negative Sign in I = neAvd

In magnitude formula I = neAvd, e is the positive magnitude of electronic charge.

Reference tables2

Quick revision8

Formulas5

Electric Current
I=dq/dtI = dq/dt

Current is the rate of charge flow through a cross-section.

I
Electric current
dq
Charge passing through area
dt
Time interval
Average Current
I=q/tI = q/t

Average current when charge q flows in time t.

I
Average current
q
Total charge
t
Time
Current Density
J=I/AJ = I/A

Current flowing per unit area normal to the flow.

J
Current density
I
Current
A
Cross-sectional area
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Diagrams3

3

Ohm's Law & Resistivity

10 min

Ohm’s law states that at constant temperature and physical conditions, current through a conductor is directly proportional to potential difference across it: V = IR. Resistance measures opposition to current and depends on material, length, area and temperature. For a uniform wire, R = ρL/A, where ρ is resistivity, a material property. Conductivity is reciprocal of resistivity. Metals usually have positive temperature coefficient of resistance, so resistance increases with temperature. Semiconductors often show the opposite trend. V-I characteristics help identify ohmic and non-ohmic devices. For NEET, this topic commonly appears as direct I = V/R numericals, V-I graph slope questions and resistance-temperature calculations.

Key points6

  • Ohm’s law is valid only when temperature and physical conditions remain constant.
  • Resistance increases with length because electrons suffer more collisions.
  • Resistance decreases with area because more conducting paths are available.
  • Resistivity depends on material and temperature, not on dimensions.
  • Ohmic conductors have straight-line V-I graphs through origin.
  • A diode is non-ohmic because its V-I graph is nonlinear.

Memory tricks2

Resistance Geometry: Long wire is like a long road: more resistance. Thick wire is like a wide road: less resistance.

Graph Slope Trick: If V is on y-axis and I on x-axis, slope is R. If I is on y-axis and V on x-axis, slope is 1/R.

Examples3

Given Numerical Example

For Vs = 23.5 V and R = 20.0 Ω, current I = V/R = 23.5/20.0 = 1.18 A.

Resistance of Wire Example

If length of a wire is doubled and area remains same, resistance doubles because R ∝ L.

Previous NEET-Type Question

A V-I graph through origin has slope 5 Ω when V is on y-axis. The resistance is 5 Ω.

Common mistakes2

Using Ohm's Law Without Constant Temperature

Ohm’s law requires constant temperature and physical conditions. Heating may change resistance.

Confusing Resistivity and Resistance

Resistance depends on dimensions; resistivity is a material property at a given temperature.

Reference tables2

Quick revision8

Formulas5

Ohm's Law
V=IRV = IR

Potential difference across an ohmic conductor is proportional to current through it.

V
Potential difference
I
Current
R
Resistance
Current from Ohm's Law
I=V/RI = V/R

Current through a resistor connected across voltage V. Example: I = Vs/R = 23.5 V/20.0 Ω = 1.18 A.

I
Current in ampere
V
Potential difference in volt
R
Resistance in ohm
Resistance of a Wire
R=ρL/AR = ρL/A

Resistance of a uniform conductor of length L and cross-sectional area A.

R
Resistance
ρ
Resistivity
L
Length of conductor
A
Area of cross-section
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Diagrams4

4

Electrical Energy & Power

9 min

Electrical work is done when charges move through a potential difference. If charge q moves through voltage V, work done is W = qV. Since current is charge per unit time, electrical power is P = VI. For a resistor, using Ohm’s law gives P = I²R and P = V²/R. Joule’s law of heating states that heat produced in a resistor is H = I²Rt. Electrical energy consumed is power multiplied by time. The commercial unit of electrical energy is kilowatt-hour, where 1 kWh = 3.6 × 10⁶ J. NEET questions often involve power ratings, heater calculations, fuse selection and electricity bill calculations.

Key points6

  • Power is rate of conversion of electrical energy.
  • A device rated 100 W consumes 100 J of energy each second at rated voltage.
  • Use P = V²/R when voltage and resistance are given.
  • Use P = I²R when current and resistance are given.
  • Heating effect is useful in heaters, irons and fuses.
  • Commercial electricity bills are based on energy in kWh, not power alone.

Memory tricks2

Power Formula Triangle: Start with P = VI. If R appears, use V = IR to get I²R or V²/R.

kWh Meaning: kWh is not power; it is energy. It means kilowatt multiplied by hour.

Examples3

Power Consumption Calculation

A 100 W bulb used for 10 h consumes energy = 0.1 kW × 10 h = 1 kWh.

Solved Example

A 5 Ω resistor carries 2 A for 10 s. Heat produced H = I²Rt = 4 × 5 × 10 = 200 J.

NEET-Type Shortcut

If current through a resistor is doubled, heat produced in the same time becomes four times because H ∝ I².

Common mistakes2

Confusing kW and kWh

kW is power, while kWh is energy. Electricity bills charge energy in kWh.

Using P = V²/R for Series Current Problems Without Checking Voltage

Use the voltage across that specific resistor, not necessarily total battery voltage.

Reference tables2

Quick revision8

Formulas5

Electrical Work
W=qVW = qV

Work done in moving charge q through potential difference V.

W
Electrical work
q
Charge
V
Potential difference
Electric Power
P=VIP = VI

Rate of electrical work done or energy consumed.

P
Power
V
Voltage
I
Current
Power in a Resistor
P=I2R=V2/RP = I²R = V²/R

Power dissipated as heat in a resistor.

P
Power dissipated
I
Current
R
Resistance
V
Voltage across resistor
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Diagrams3

5

Cells & Internal Resistance

10 min

An electric cell converts chemical energy into electrical energy and maintains potential difference in a circuit. EMF is the work done per unit charge by the cell in driving charge through the complete circuit when no current is drawn. A real cell has internal resistance due to opposition inside the electrolyte and electrodes. When the cell supplies current, some voltage is lost inside the cell, so terminal voltage becomes V = ε - Ir. During charging, terminal voltage can be greater than emf: V = ε + Ir. Cells may be connected in series to increase voltage or in parallel to increase current capacity and reduce effective internal resistance. NEET often asks terminal voltage and cell combination problems.

Key points6

  • EMF is not a force; it is energy supplied per unit charge.
  • Terminal voltage is less than emf when the cell delivers current.
  • Internal resistance is inside the cell and cannot be ignored in many NEET questions.
  • Maximum current from a cell occurs when external resistance is very small.
  • Series combination is useful when external resistance is large.
  • Parallel combination is useful when external resistance is small.

Memory tricks2

Discharging Cell: When cell gives current, terminal voltage gets reduced: V = ε - Ir.

Charging Cell: When cell is forced to charge, applied voltage must overcome emf and internal drop: V = ε + Ir.

Examples3

Terminal Voltage Example

A cell of ε = 2 V and r = 0.5 Ω supplies 1 A. Terminal voltage V = ε - Ir = 2 - 0.5 = 1.5 V.

Series Cells Example

Three identical cells of emf 1.5 V and internal resistance 0.2 Ω in series have εeq = 4.5 V and req = 0.6 Ω.

NEET-Type Question

If a voltmeter reads emf when no current is drawn, it reads terminal voltage when the cell is connected to a load.

Common mistakes2

Calling EMF a Force

EMF is energy per unit charge, measured in volt, not a mechanical force.

Forgetting Internal Resistance in Current

For a real cell, total resistance is R + r, so I = ε/(R + r).

Reference tables2

Quick revision8

Formulas5

Current from a Cell
I=ε/(R+r)I = ε/(R + r)

Current supplied by a cell of emf ε and internal resistance r connected to external resistance R.

I
Circuit current
ε
EMF of cell
R
External resistance
r
Internal resistance
Terminal Voltage During Discharge
V=ε−IrV = ε - Ir

Terminal voltage when cell supplies current to external circuit.

V
Terminal voltage
ε
EMF
I
Current
r
Internal resistance
Terminal Voltage During Charging
V=ε+IrV = ε + Ir

Terminal voltage when external source charges the cell.

V
Applied terminal voltage
ε
EMF of cell
I
Charging current
r
Internal resistance
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Diagrams4

6

Kirchhoff's Laws

11 min

Kirchhoff’s laws are used to solve circuits that cannot be simplified easily using simple series and parallel rules. The junction rule states that the algebraic sum of currents at a junction is zero, or total current entering equals total current leaving. It is based on conservation of charge. The loop rule states that the algebraic sum of potential changes around any closed loop is zero, based on conservation of energy. Correct sign convention is essential: crossing a resistor in the direction of current gives a potential drop -IR, while crossing a cell from negative to positive terminal gives +ε. These laws are important for multi-loop circuit problems and bridge circuits.

Key points6

  • Assume current directions if unknown; a negative answer means actual direction is opposite.
  • Use independent loops only to avoid redundant equations.
  • Choose a loop direction and consistently follow it.
  • Ideal ammeter has negligible resistance; ideal voltmeter has very high resistance.
  • Kirchhoff’s laws apply to steady current circuits.
  • They are the basis of Wheatstone bridge balance derivation.

Memory tricks2

Junction Rule: Current cannot pile up at a junction: what enters must leave.

Loop Rule: After one full circuit round, potential comes back to starting value, so total change is zero.

Examples3

Loop Analysis Example

For a single loop with cell ε and resistors R1 and R2 in series, loop rule gives ε - IR1 - IR2 = 0, so I = ε/(R1 + R2).

Practice Problem

At a junction, 5 A enters and currents 2 A and I leave. By junction rule, 5 = 2 + I, so I = 3 A.

Previous NEET-Type Question

Kirchhoff’s junction law is based on conservation of charge, while loop law is based on conservation of energy.

Common mistakes3

Changing Sign Convention Midway

Choose a loop direction and apply signs consistently throughout the equation.

Treating Negative Current as Wrong

A negative current simply means actual current is opposite to the assumed direction.

Writing Too Many Dependent Equations

Use independent junction and loop equations; dependent equations do not add new information.

Reference tables2

Quick revision8

Formulas4

Junction Rule
ΣIin=ΣIoutΣI_{in} = ΣI_{out}

Total current entering a junction equals total current leaving it.

I_in
Currents entering junction
I_out
Currents leaving junction
Algebraic Current Law
ΣI=0ΣI = 0

Algebraic sum of currents at any junction is zero.

ΣI
Sum of signed currents at junction
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Diagrams4

7

Wheatstone & Metre Bridge

10 min

Wheatstone bridge is a network of four resistances used to compare or measure unknown resistance. In the balanced condition, no current flows through the galvanometer because the potentials of its two terminals are equal. The balance condition is P/Q = R/S. A metre bridge is a practical form of Wheatstone bridge using a uniform 1 m wire. At balance, the ratio of resistances equals the ratio of balancing lengths: R/X = l/(100 - l), depending on which gap contains the unknown. The bridge method is accurate because it detects null deflection, so the result does not depend on galvanometer resistance. NEET commonly asks bridge balance, unknown resistance and metre bridge length calculations.

Key points6

  • Wheatstone bridge is based on Kirchhoff’s laws.
  • No current through galvanometer means that branch can be ignored at balance.
  • The resistance of a uniform wire is proportional to its length.
  • In metre bridge, end corrections are minimized by interchanging known and unknown resistances.
  • The balance point should ideally lie between 30 cm and 70 cm for accuracy.
  • A balanced bridge is not affected by galvanometer resistance because no current passes through it.

Memory tricks2

Wheatstone Balance: Bridge balances when ratios match: left upper over right upper equals left lower over right lower.

Metre Bridge: Resistance follows length: longer wire segment means larger resistance.

Examples3

Wheatstone Numerical

If P = 2 Ω, Q = 3 Ω and R = 4 Ω, then at balance S = QR/P = 3 × 4/2 = 6 Ω.

Metre Bridge Example

If R = 5 Ω is in the left gap and balance length l = 40 cm, then R/X = 40/60, so X = 5 × 60/40 = 7.5 Ω.

Quick Revision Note

At balanced Wheatstone bridge, no current flows through galvanometer, so its resistance does not affect balance condition.

Common mistakes3

Using Bridge Formula When Not Balanced

P/Q = R/S is valid only when galvanometer current is zero.

Wrong Length Ratio in Metre Bridge

Check which resistance is in the left gap and which is in the right gap before writing R/X = l/(100-l).

Ignoring End Corrections

In practical metre bridge, balance near the middle reduces end correction errors.

Reference tables2

Quick revision8

Formulas4

Wheatstone Bridge Principle
P/Q=R/SP/Q = R/S

Balanced bridge condition when galvanometer current is zero.

P, Q, R, S
Four resistances in the bridge arms
Unknown Resistance in Wheatstone Bridge
S=QR/PS = QR/P

Finds unknown resistance S when P, Q and R are known.

S
Unknown resistance
P, Q, R
Known bridge resistances
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Diagrams4

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NEET PYQs from Current Electricity

The latest 3 of 76 previous-year questions from this chapter.

  1. NEET 2026Set 11MediumQ1

    In a metre bridge experiment (see figure), the positions of the cell E and galvanometer G are interchanged. We shall observe in the galvanometer:

    • AOnly the left-sided deflection
    • BThere will be no deflection irrespective of the position of the jockey
    • COnly the right-sided deflection
    • DBoth right-sided and left-sided deflection and at balance point, no deflection
  2. NEET 2026Set 11EasyQ2

    The current (I) in the circuit shown below is: (All diodes are ideal and identical)

    • A5/3 A
    • B5/9 A
    • C1/3 A
    • D15/2 A
  3. NEET 2026Set 11EasyQ3

    A resistor is connected to a battery of 12 V emf and internal resistance 2 Ω. If the current in the circuit is 0.6 A, the terminal voltage of the battery is:

    • A10 V
    • B1.2 V
    • C12 V
    • D10.8 V

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