Topics
6Chapter Overview
Overview
Current Electricity studies charges in motion and the circuits through which they flow. The chapter begins with electric current, current density, drift velocity and mobility, connecting microscopic electron motion with measurable current. Ohm’s law, resistance, resistivity, conductivity and temperature dependence explain how materials oppose current. Electrical energy and power show how circuits convert electrical energy into heat and useful work. Cells introduce emf, terminal voltage and internal resistance. Kirchhoff’s laws allow systematic analysis of complex circuits using charge and energy conservation. Wheatstone bridge and metre bridge are important applications used to compare and measure resistance. For NEET, this chapter is highly scoring because most questions are formula-based, circuit-based and numerically direct.
- 1Conventional current is opposite to electron drift direction.
- 2Drift velocity is very small, but electric signal through a circuit is established very fast.
- 3Resistance depends on length, area, material and temperature.
- 4In series combination current is same; in parallel combination voltage is same.
- 5Internal resistance causes terminal voltage to differ from emf.
- 6Wheatstone bridge is balanced when no current flows through the galvanometer.
Chapter Flow Trick
Remember: Charges move → resistance opposes → power heats → cells drive → Kirchhoff solves → bridges measure.
Series and Parallel Quick Rule
Series has same current; parallel has same voltage.
Real-Life Example
A phone charger converts electrical energy from the supply into chemical energy stored in the battery, with some energy lost as heat.
NEET-Style Snapshot
If voltage across a fixed resistor is doubled, current doubles by Ohm’s law because I = V/R.
Confusing Electron Flow and Conventional Current
Electron drift is from negative to positive terminal, but conventional current is taken from positive to negative terminal.
Using Ideal Cell Formula for Real Cell
A real cell has internal resistance, so terminal voltage differs from emf when current flows.
Rate of flow of charge through a cross-section.
Variables
I=Electric current
dq=Small amount of charge
dt=Small time interval
Connects macroscopic current with microscopic drift velocity of charge carriers.
Variables
n=Number density of free electrons
e=Electronic charge
A=Area of cross-section
vd=Drift velocity
Potential difference across an ohmic conductor is proportional to current through it.
Variables
V=Potential difference
I=Current
R=Resistance
Electric Current & Drift Velocity
Overview
Electric current is the rate of flow of charge through a cross-section of a conductor. In metals, free electrons are the charge carriers. Without an electric field, electrons move randomly and no net current exists. When an electric field is applied, electrons acquire a small average velocity opposite to the field, called drift velocity. Conventional current is taken in the direction of positive charge flow, opposite to electron drift. Current density J describes current per unit area and points along conventional current. Mobility measures how easily charge carriers drift under an electric field. The relation I = neAvd connects microscopic electron motion with measurable current, making it a frequent NEET formula.
- 1Random thermal motion of electrons does not produce net current.
- 2Applied electric field causes a small average drift superimposed on random motion.
- 3Drift velocity is very small, typically of the order of mm/s or less.
- 4Current appears quickly because electric field propagates through the circuit rapidly.
- 5Current density is a vector quantity.
- 6For the same current, thinner wire has larger current density.
Drift Direction
Electrons are negative, so they drift opposite to electric field and conventional current.
Current Formula
I = neAvd: more carriers, more area or more drift means more current.
Numerical Example
If 12 C charge passes through a wire in 4 s, current I = q/t = 12/4 = 3 A.
Drift Velocity Example
For I = 1 A, n = 8 × 10²⁸ m⁻³, A = 1 mm² and e = 1.6 × 10⁻¹⁹ C, vd = I/(neA) ≈ 7.8 × 10⁻⁵ m/s.
NEET-Type Concept
When wire area decreases for the same current, current density increases because J = I/A.
Thinking Electrons Move at Light Speed
Electron drift velocity is small; the electrical signal spreads rapidly through the circuit.
Using Electron Charge with Negative Sign in I = neAvd
In magnitude formula I = neAvd, e is the positive magnitude of electronic charge.
Current is the rate of charge flow through a cross-section.
Variables
I=Electric current
dq=Charge passing through area
dt=Time interval
Average current when charge q flows in time t.
Variables
I=Average current
q=Total charge
t=Time
Current flowing per unit area normal to the flow.
Variables
J=Current density
I=Current
A=Cross-sectional area
Ohm's Law & Resistivity
Overview
Ohm’s law states that at constant temperature and physical conditions, current through a conductor is directly proportional to potential difference across it: V = IR. Resistance measures opposition to current and depends on material, length, area and temperature. For a uniform wire, R = ρL/A, where ρ is resistivity, a material property. Conductivity is reciprocal of resistivity. Metals usually have positive temperature coefficient of resistance, so resistance increases with temperature. Semiconductors often show the opposite trend. V-I characteristics help identify ohmic and non-ohmic devices. For NEET, this topic commonly appears as direct I = V/R numericals, V-I graph slope questions and resistance-temperature calculations.
- 1Ohm’s law is valid only when temperature and physical conditions remain constant.
- 2Resistance increases with length because electrons suffer more collisions.
- 3Resistance decreases with area because more conducting paths are available.
- 4Resistivity depends on material and temperature, not on dimensions.
- 5Ohmic conductors have straight-line V-I graphs through origin.
- 6A diode is non-ohmic because its V-I graph is nonlinear.
Resistance Geometry
Long wire is like a long road: more resistance. Thick wire is like a wide road: less resistance.
Graph Slope Trick
If V is on y-axis and I on x-axis, slope is R. If I is on y-axis and V on x-axis, slope is 1/R.
Given Numerical Example
For Vs = 23.5 V and R = 20.0 Ω, current I = V/R = 23.5/20.0 = 1.18 A.
Resistance of Wire Example
If length of a wire is doubled and area remains same, resistance doubles because R ∝ L.
Previous NEET-Type Question
A V-I graph through origin has slope 5 Ω when V is on y-axis. The resistance is 5 Ω.
Using Ohm's Law Without Constant Temperature
Ohm’s law requires constant temperature and physical conditions. Heating may change resistance.
Confusing Resistivity and Resistance
Resistance depends on dimensions; resistivity is a material property at a given temperature.
Potential difference across an ohmic conductor is proportional to current through it.
Variables
V=Potential difference
I=Current
R=Resistance
Current through a resistor connected across voltage V. Example: I = Vs/R = 23.5 V/20.0 Ω = 1.18 A.
Variables
I=Current in ampere
V=Potential difference in volt
R=Resistance in ohm
Resistance of a uniform conductor of length L and cross-sectional area A.
Variables
R=Resistance
ρ=Resistivity
L=Length of conductor
A=Area of cross-section
Electrical Energy & Power
Overview
Electrical work is done when charges move through a potential difference. If charge q moves through voltage V, work done is W = qV. Since current is charge per unit time, electrical power is P = VI. For a resistor, using Ohm’s law gives P = I²R and P = V²/R. Joule’s law of heating states that heat produced in a resistor is H = I²Rt. Electrical energy consumed is power multiplied by time. The commercial unit of electrical energy is kilowatt-hour, where 1 kWh = 3.6 × 10⁶ J. NEET questions often involve power ratings, heater calculations, fuse selection and electricity bill calculations.
- 1Power is rate of conversion of electrical energy.
- 2A device rated 100 W consumes 100 J of energy each second at rated voltage.
- 3Use P = V²/R when voltage and resistance are given.
- 4Use P = I²R when current and resistance are given.
- 5Heating effect is useful in heaters, irons and fuses.
- 6Commercial electricity bills are based on energy in kWh, not power alone.
Power Formula Triangle
Start with P = VI. If R appears, use V = IR to get I²R or V²/R.
kWh Meaning
kWh is not power; it is energy. It means kilowatt multiplied by hour.
Power Consumption Calculation
A 100 W bulb used for 10 h consumes energy = 0.1 kW × 10 h = 1 kWh.
Solved Example
A 5 Ω resistor carries 2 A for 10 s. Heat produced H = I²Rt = 4 × 5 × 10 = 200 J.
NEET-Type Shortcut
If current through a resistor is doubled, heat produced in the same time becomes four times because H ∝ I².
Confusing kW and kWh
kW is power, while kWh is energy. Electricity bills charge energy in kWh.
Using P = V²/R for Series Current Problems Without Checking Voltage
Use the voltage across that specific resistor, not necessarily total battery voltage.
Work done in moving charge q through potential difference V.
Variables
W=Electrical work
q=Charge
V=Potential difference
Rate of electrical work done or energy consumed.
Variables
P=Power
V=Voltage
I=Current
Power dissipated as heat in a resistor.
Variables
P=Power dissipated
I=Current
R=Resistance
V=Voltage across resistor
Cells & Internal Resistance
Overview
An electric cell converts chemical energy into electrical energy and maintains potential difference in a circuit. EMF is the work done per unit charge by the cell in driving charge through the complete circuit when no current is drawn. A real cell has internal resistance due to opposition inside the electrolyte and electrodes. When the cell supplies current, some voltage is lost inside the cell, so terminal voltage becomes V = ε - Ir. During charging, terminal voltage can be greater than emf: V = ε + Ir. Cells may be connected in series to increase voltage or in parallel to increase current capacity and reduce effective internal resistance. NEET often asks terminal voltage and cell combination problems.
- 1EMF is not a force; it is energy supplied per unit charge.
- 2Terminal voltage is less than emf when the cell delivers current.
- 3Internal resistance is inside the cell and cannot be ignored in many NEET questions.
- 4Maximum current from a cell occurs when external resistance is very small.
- 5Series combination is useful when external resistance is large.
- 6Parallel combination is useful when external resistance is small.
Discharging Cell
When cell gives current, terminal voltage gets reduced: V = ε - Ir.
Charging Cell
When cell is forced to charge, applied voltage must overcome emf and internal drop: V = ε + Ir.
Terminal Voltage Example
A cell of ε = 2 V and r = 0.5 Ω supplies 1 A. Terminal voltage V = ε - Ir = 2 - 0.5 = 1.5 V.
Series Cells Example
Three identical cells of emf 1.5 V and internal resistance 0.2 Ω in series have εeq = 4.5 V and req = 0.6 Ω.
NEET-Type Question
If a voltmeter reads emf when no current is drawn, it reads terminal voltage when the cell is connected to a load.
Calling EMF a Force
EMF is energy per unit charge, measured in volt, not a mechanical force.
Forgetting Internal Resistance in Current
For a real cell, total resistance is R + r, so I = ε/(R + r).
Current supplied by a cell of emf ε and internal resistance r connected to external resistance R.
Variables
I=Circuit current
ε=EMF of cell
R=External resistance
r=Internal resistance
Terminal voltage when cell supplies current to external circuit.
Variables
V=Terminal voltage
ε=EMF
I=Current
r=Internal resistance
Terminal voltage when external source charges the cell.
Variables
V=Applied terminal voltage
ε=EMF of cell
I=Charging current
r=Internal resistance
Kirchhoff's Laws
Overview
Kirchhoff’s laws are used to solve circuits that cannot be simplified easily using simple series and parallel rules. The junction rule states that the algebraic sum of currents at a junction is zero, or total current entering equals total current leaving. It is based on conservation of charge. The loop rule states that the algebraic sum of potential changes around any closed loop is zero, based on conservation of energy. Correct sign convention is essential: crossing a resistor in the direction of current gives a potential drop -IR, while crossing a cell from negative to positive terminal gives +ε. These laws are important for multi-loop circuit problems and bridge circuits.
- 1Assume current directions if unknown; a negative answer means actual direction is opposite.
- 2Use independent loops only to avoid redundant equations.
- 3Choose a loop direction and consistently follow it.
- 4Ideal ammeter has negligible resistance; ideal voltmeter has very high resistance.
- 5Kirchhoff’s laws apply to steady current circuits.
- 6They are the basis of Wheatstone bridge balance derivation.
Junction Rule
Current cannot pile up at a junction: what enters must leave.
Loop Rule
After one full circuit round, potential comes back to starting value, so total change is zero.
Loop Analysis Example
For a single loop with cell ε and resistors R1 and R2 in series, loop rule gives ε - IR1 - IR2 = 0, so I = ε/(R1 + R2).
Practice Problem
At a junction, 5 A enters and currents 2 A and I leave. By junction rule, 5 = 2 + I, so I = 3 A.
Previous NEET-Type Question
Kirchhoff’s junction law is based on conservation of charge, while loop law is based on conservation of energy.
Changing Sign Convention Midway
Choose a loop direction and apply signs consistently throughout the equation.
Treating Negative Current as Wrong
A negative current simply means actual current is opposite to the assumed direction.
Writing Too Many Dependent Equations
Use independent junction and loop equations; dependent equations do not add new information.
Total current entering a junction equals total current leaving it.
Variables
I_in=Currents entering junction
I_out=Currents leaving junction
Algebraic sum of currents at any junction is zero.
Variables
ΣI=Sum of signed currents at junction
Wheatstone & Metre Bridge
Overview
Wheatstone bridge is a network of four resistances used to compare or measure unknown resistance. In the balanced condition, no current flows through the galvanometer because the potentials of its two terminals are equal. The balance condition is P/Q = R/S. A metre bridge is a practical form of Wheatstone bridge using a uniform 1 m wire. At balance, the ratio of resistances equals the ratio of balancing lengths: R/X = l/(100 - l), depending on which gap contains the unknown. The bridge method is accurate because it detects null deflection, so the result does not depend on galvanometer resistance. NEET commonly asks bridge balance, unknown resistance and metre bridge length calculations.
- 1Wheatstone bridge is based on Kirchhoff’s laws.
- 2No current through galvanometer means that branch can be ignored at balance.
- 3The resistance of a uniform wire is proportional to its length.
- 4In metre bridge, end corrections are minimized by interchanging known and unknown resistances.
- 5The balance point should ideally lie between 30 cm and 70 cm for accuracy.
- 6A balanced bridge is not affected by galvanometer resistance because no current passes through it.
Wheatstone Balance
Bridge balances when ratios match: left upper over right upper equals left lower over right lower.
Metre Bridge
Resistance follows length: longer wire segment means larger resistance.
Wheatstone Numerical
If P = 2 Ω, Q = 3 Ω and R = 4 Ω, then at balance S = QR/P = 3 × 4/2 = 6 Ω.
Metre Bridge Example
If R = 5 Ω is in the left gap and balance length l = 40 cm, then R/X = 40/60, so X = 5 × 60/40 = 7.5 Ω.
Quick Revision Note
At balanced Wheatstone bridge, no current flows through galvanometer, so its resistance does not affect balance condition.
Using Bridge Formula When Not Balanced
P/Q = R/S is valid only when galvanometer current is zero.
Wrong Length Ratio in Metre Bridge
Check which resistance is in the left gap and which is in the right gap before writing R/X = l/(100-l).
Ignoring End Corrections
In practical metre bridge, balance near the middle reduces end correction errors.
Balanced bridge condition when galvanometer current is zero.
Variables
P, Q, R, S=Four resistances in the bridge arms
Finds unknown resistance S when P, Q and R are known.
Variables
S=Unknown resistance
P, Q, R=Known bridge resistances
Formula Sheet
10Rate of flow of charge through a cross-section.
Variables
I=Electric current
dq=Small amount of charge
dt=Small time interval
Connects macroscopic current with microscopic drift velocity of charge carriers.
Variables
n=Number density of free electrons
e=Electronic charge
A=Area of cross-section
vd=Drift velocity
Potential difference across an ohmic conductor is proportional to current through it.
Variables
V=Potential difference
I=Current
R=Resistance
Rate of electrical energy consumption or conversion.
Variables
P=Power
V=Voltage
I=Current
R=Resistance
Terminal voltage of a cell while delivering current.
Variables
V=Terminal voltage
ε=EMF of cell
I=Current
r=Internal resistance
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NEET PYQs — Current Electricity
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In a metre bridge experiment (see figure), the positions of the cell E and galvanometer G are interchanged. We shall observe in the galvanometer:
A room heater is rated 400 W, 220 V. If the supply voltage drops to 200 V, what will be the power consumed (approximately)?
A uniform metallic wire having resistance 4 Ω is bent to form a square loop (ABCD). A resistance of 2 Ω is connected between points B and D and a battery of 2 V is connected across points A and C as shown. The value of current I is:
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