NEET Physics · NCERT Class 12

Electrostatic Potential and Capacitance notes

Electrostatic Potential, Potential Energy, Equipotential Surfaces, Conductors & Dielectrics, Capacitors & Capacitance and Energy Stored in Capacitors — explained topic by topic with key points, formulas, memory tricks and common mistakes.

  • 7 topics
  • 65 min read
  • 32 formulas
  • 47 PYQs
1

Chapter Overview

8 min

Electrostatic Potential and Capacitance explains electrostatics using energy and potential instead of force alone. The chapter begins with work done in moving a charge, electric potential, potential difference and potential due to point or multiple charges. It then develops electrostatic potential energy of two charges and systems of charges using the conservative nature of electrostatic force. Equipotential surfaces visually connect electric field and potential. Conductors and dielectrics explain electrostatic equilibrium, shielding and polarisation. Capacitors store charge and electrical energy, and their capacitance depends on geometry and dielectric medium. For NEET, this chapter is highly scoring because formulas for potential, energy, capacitor combinations and dielectric effects are repeatedly tested.

Key points6

  • Potential is scalar, so potentials add algebraically, unlike electric field.
  • Electrostatic force is conservative, so work depends only on initial and final positions.
  • No work is done in moving a charge along an equipotential surface.
  • A dielectric reduces electric field inside a capacitor and increases capacitance.
  • Capacitors in series have same charge, while capacitors in parallel have same potential difference.
  • Energy lost during charge sharing is usually converted into heat, sound or radiation.

Memory tricks2

Potential vs Field: Field is slope of potential with a minus sign: electric field points toward decreasing potential.

Capacitor Combination: Parallel plates share voltage in parallel; series capacitors share charge in series.

Examples2

Real-Life Example

A camera flash capacitor stores electrical energy slowly and releases it quickly to produce a bright flash.

NEET-Style Snapshot

If potential difference across a capacitor is doubled while capacitance is constant, stored energy becomes four times because U ∝ V².

Common mistakes2

Treating Potential as Vector

Electric potential is a scalar. Add potentials with signs, not by vector components.

Confusing Capacitor Energy Formulas

Use the energy form based on what remains constant: Q constant uses Q²/2C; V constant uses 1/2 CV².

Reference tables2

Quick revision8

Formulas5

Electric Potential
V=W/q0V = W/q0

Potential at a point is work done per unit positive test charge in bringing it from infinity to that point.

V
Electric potential
W
Work done
q0
Positive test charge
Potential due to Point Charge
V=(1/4πε0)(q/r)V = (1/4πε0)(q/r)

Electric potential at distance r from a point charge q.

V
Electric potential
q
Source charge
r
Distance from charge
ε0
Permittivity of free space
Potential Energy of Two Charges
U=(1/4πε0)(q1q2/r)U = (1/4πε0)(q1q2/r)

Electrostatic potential energy of two point charges separated by distance r.

U
Potential energy
q1, q2
Two point charges
r
Separation between charges
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Diagrams3

2

Electrostatic Potential

9 min

Electrostatic potential at a point is the work done per unit positive test charge in bringing the charge from infinity to that point without acceleration. Potential difference between two points is the work done per unit charge in moving a test charge between them. Unlike electric field, potential is scalar, so the potential due to multiple charges is the algebraic sum of individual potentials. The potential due to a point charge is V = kq/r. Positive charges produce positive potential and negative charges produce negative potential. Electric field and potential are related by E = -dV/dr in one dimension, meaning electric field points in the direction of decreasing potential.

Key points6

  • Potential exists at a point even before placing a test charge.
  • Work done by external agent and work done by electric field may have opposite signs.
  • Zero potential is often chosen at infinity for isolated charges.
  • Potential due to multiple charges is easier than electric field because no vector addition is needed.
  • If potential is constant in a region, electric field is zero there.
  • Potential difference is physically more important than absolute potential.

Memory tricks2

Potential Addition: Potential is scalar: add with signs, not arrows.

Field from Potential: Electric field rolls downhill on the potential graph: E points toward decreasing V.

Examples3

Solved Example

Potential at 0.3 m from q = 2 μC is V = kq/r = 9 × 10⁹ × 2 × 10⁻⁶ / 0.3 = 6 × 10⁴ V.

Multiple Charges Example

If +q and -q are equidistant from a point, net potential is kq/r + k(-q)/r = 0, although electric field may not be zero.

NEET-Type Question

If potential varies as V = 5x, then E = -dV/dx = -5 V/m along x-direction.

Common mistakes3

Adding Potential Vectorially

Potential due to many charges is an algebraic scalar sum. Do not resolve into components.

Forgetting Sign of Charge

Potential due to negative charge is negative. Use q with sign in V = kq/r.

Confusing Work by Field and External Work

Work done by external agent in slow movement is usually negative of work done by electric field.

Reference tables2

Quick revision8

Formulas5

Electric Potential
V=W/q0V = W/q0

Work done per unit positive test charge in bringing it from infinity.

V
Electric potential
W
Work done by external agent
q0
Positive test charge
Potential Difference
VB−VA=WAB/q0VB - VA = WAB/q0

Work done per unit charge in moving a test charge from A to B.

VB - VA
Potential difference between B and A
WAB
Work done in moving charge from A to B
q0
Test charge
Potential due to Point Charge
V=kq/rV = kq/r

Potential at distance r from a point charge q.

V
Electric potential
k
1/4πε0
q
Source charge
r
Distance from source charge
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Diagrams3

3

Potential Energy

9 min

Electrostatic potential energy is the energy stored due to the relative positions of charges. For two point charges, U = kq1q2/r. If charges have the same sign, U is positive because external work is required to bring them closer against repulsion. If charges have opposite signs, U is negative because the electric force attracts them. For a system of charges, total potential energy is the sum of potential energies of every distinct pair. Electrostatic force is conservative, so work done depends only on initial and final positions, not the path. Energy conservation helps solve problems where electric potential energy converts into kinetic energy or vice versa.

Key points6

  • Potential energy belongs to a system, not to an isolated single charge alone.
  • For three charges, include three pair energies: U12, U23 and U31.
  • Do not double-count charge pairs in system energy.
  • Negative potential energy means the system is bound relative to infinite separation.
  • Potential energy increases when like charges are brought closer.
  • Potential energy decreases when unlike charges are brought closer.

Memory tricks2

System Energy Rule: Pair once, not twice: for n charges, count each pair only one time.

Sign Trick: Like charges store positive energy; unlike charges have negative binding energy.

Examples3

Solved Numerical

For q1 = 2 μC, q2 = 3 μC and r = 0.3 m, U = kq1q2/r = 9 × 10⁹ × 2 × 10⁻⁶ × 3 × 10⁻⁶ / 0.3 = 0.18 J.

Previous NEET-Type Question

If separation between two like charges is doubled, potential energy becomes half because U ∝ 1/r.

Energy Conservation Example

If two like charges are released from rest, electric potential energy converts into kinetic energy as they move apart.

Common mistakes3

Double Counting Pair Energies

For charges q1, q2 and q3, write U12 + U23 + U31 only. Do not add U21 separately.

Ignoring Signs of Charges

Use charges with their signs in U = kq1q2/r.

Confusing Potential with Potential Energy

Potential V is property of a point; potential energy U = qV depends on the charge placed there.

Reference tables2

Quick revision8

Formulas5

Potential Energy of Two Charges
U=kq1q2/rU = kq1q2/r

Electrostatic potential energy of two point charges separated by r.

U
Electrostatic potential energy
k
Coulomb constant
q1, q2
Point charges
r
Separation between charges
Potential Energy of a System of Charges
U=k(q1q2/r12+q2q3/r23+q3q1/r31+...)U = k(q1q2/r12 + q2q3/r23 + q3q1/r31 + ...)

Total energy is sum of all distinct pair interactions.

U
Total electrostatic potential energy
q1, q2, q3
Charges in the system
r12, r23, r31
Pairwise separations
Work-Energy Relation
Wfield=−ΔUW_{\text{field}} = -ΔU

Work done by electrostatic force equals negative change in potential energy.

W_field
Work done by electric field
ΔU
Change in electrostatic potential energy
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Diagrams3

4

Equipotential Surfaces

8 min

An equipotential surface is a surface on which electric potential is the same at every point. Since potential difference between any two points on the surface is zero, no work is done in moving a charge along an equipotential surface. Electric field is always perpendicular to equipotential surfaces; if it had a tangential component, charges would move along the surface and potential would not remain constant. Around a point charge, equipotential surfaces are concentric spheres. In a uniform electric field, equipotential surfaces are parallel planes perpendicular to the field. Conductors in electrostatic equilibrium are equipotential bodies. Equipotential surfaces help visualize electric potential and simplify work calculations.

Key points6

  • A charge can move along an equipotential surface without change in electric potential energy.
  • Field lines cross equipotential surfaces at right angles.
  • No two equipotential surfaces at different potentials can intersect.
  • Higher density of equipotential surfaces means larger potential gradient and stronger field.
  • The surface of a charged conductor is always equipotential.
  • Equipotential diagrams are like contour maps of electric potential.

Memory tricks2

Equipotential Work Trick: Equal potential means no potential difference, so no work.

Contour Map Analogy: Equipotential surfaces are like height contours; field points down the steepest potential slope.

Examples2

Solved Example

A 5 μC charge is moved along an equipotential surface. Since ΔV = 0, work done W = qΔV = 0.

Application

The metal body of a conductor in electrostatic equilibrium is equipotential, which is why no current flows inside due to electrostatic potential differences.

Common mistakes2

Drawing Field Lines Along Equipotential Surface

Electric field is perpendicular to equipotential surfaces, not tangent to them.

Thinking Equipotential Means No Field Everywhere

Electric field along the surface is zero, but field normal to the surface can exist.

Reference tables2

Quick revision8

Formulas3

Work on Equipotential Surface
W=qΔV=0W = qΔV = 0

No work is required to move a charge along an equipotential surface.

W
Work done
q
Charge moved
ΔV
Potential difference, zero on equipotential surface
Field and Potential Gradient
E=−dV/dnE = -dV/dn

Electric field magnitude is the rate of decrease of potential normal to equipotential surfaces.

E
Electric field
dV/dn
Potential gradient normal to surface
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Diagrams4

5

Conductors & Dielectrics

10 min

Conductors contain free charges that move under electric field. In electrostatic equilibrium, charges rearrange until electric field inside the conductor becomes zero and the entire conductor becomes equipotential. Excess charge resides on the outer surface, and the electric field just outside is normal to the surface. Electrostatic shielding occurs because a closed conductor blocks external electrostatic fields from its interior. Dielectrics are insulating materials that do not have free charges but contain bound charges. In an external electric field, dielectric molecules polarise, creating an induced field opposite to the applied field. This reduces net electric field and increases the capacitance of capacitors by a factor called dielectric constant.

Key points6

  • If electric field existed inside a conductor, free charges would keep moving, so equilibrium would not exist.
  • Tangential electric field at conductor surface must be zero in electrostatic equilibrium.
  • Charge density is higher near sharper conductor surfaces.
  • Dielectric constant K is greater than 1 for ordinary dielectrics.
  • A dielectric reduces net electric field inside the material.
  • Inserting dielectric fully between capacitor plates increases capacitance.

Memory tricks2

Conductor Equilibrium: Conductor at rest has no internal field: if E existed, charges would still move.

Dielectric Effect: Dielectric dilutes field and boosts capacitance: field decreases, C increases.

Examples3

Previous NEET-Type Question

Electric field inside a charged conductor in electrostatic equilibrium is zero because free charges redistribute to cancel internal field.

Dielectric Example

If a capacitor of capacitance 5 μF is fully filled with dielectric of K = 4, new capacitance is C = KC0 = 20 μF.

Real-Life Application

A metal enclosure protects sensitive electronics from external electrostatic fields by electrostatic shielding.

Common mistakes3

Thinking Dielectric Has Free Charges

Dielectrics have bound charges that shift slightly; they do not conduct like metals.

Assuming Field Just Outside Conductor Is Tangential

At conductor surface in electrostatic equilibrium, field is normal to the surface.

Forgetting Conductor Is Equipotential

Since E = 0 inside a conductor, potential is constant throughout it.

Reference tables2

Quick revision8

Formulas4

Field Inside Conductor
Einside=0E_{\text{inside}} = 0

Electric field inside a conductor in electrostatic equilibrium is zero.

E_inside
Electric field inside conductor
Field Just Outside Conductor
E=σ/ε0E = σ/ε0

Electric field immediately outside a charged conductor surface.

E
Electric field just outside
σ
Surface charge density
ε0
Permittivity of free space
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Diagrams5

6

Capacitors & Capacitance

11 min

A capacitor is a device used to store electric charge and electrical energy. Its capacitance is C = Q/V, the charge stored per unit potential difference. The simplest capacitor is a parallel plate capacitor with two conducting plates separated by a small distance. Without dielectric, its capacitance is C = ε0A/d; with a dielectric fully inserted, C = Kε0A/d. Capacitors can be combined in series or parallel. In series, all capacitors carry the same charge and equivalent capacitance is smaller than the smallest capacitor. In parallel, all capacitors have the same voltage and equivalent capacitance is the sum of individual capacitances. NEET frequently asks combinations and dielectric effects.

Key points6

  • Capacitance depends on geometry and medium, not directly on Q or V for an ideal capacitor.
  • Increasing plate area increases capacitance.
  • Increasing separation between plates decreases capacitance.
  • Dielectric increases capacitance by reducing effective electric field and potential difference for fixed charge.
  • In series, equivalent capacitance decreases.
  • In parallel, equivalent capacitance increases.

Memory tricks2

Series-Parallel Memory: Capacitors behave opposite to resistors: series uses reciprocal, parallel adds directly.

Same Quantity Rule: Series means Same charge; Parallel means same Potential.

Examples3

Parallel Plate Numerical

For A = 0.02 m² and d = 1 mm, C = ε0A/d = 8.85 × 10⁻¹² × 0.02 / 10⁻³ = 1.77 × 10⁻¹⁰ F.

Series Combination Example

For C1 = 2 μF and C2 = 3 μF in series, Ceq = C1C2/(C1 + C2) = 6/5 = 1.2 μF.

Parallel Combination Example

For 2 μF and 3 μF in parallel, Ceq = 2 + 3 = 5 μF.

Common mistakes3

Using Resistor Rules for Capacitors

For capacitors, parallel capacitances add directly; series capacitances add reciprocally.

Thinking Capacitance Depends on Charge

For an ideal capacitor, capacitance depends on geometry and medium, not on how much charge is currently stored.

Forgetting Dielectric Constant

If dielectric fully fills the capacitor, multiply capacitance by K.

Reference tables2

Quick revision8

Formulas5

Capacitance
C=Q/VC = Q/V

Charge stored per unit potential difference.

C
Capacitance
Q
Charge on capacitor
V
Potential difference
Parallel Plate Capacitor
C=ε0A/dC = ε0A/d

Capacitance of parallel plate capacitor without dielectric, neglecting edge effects.

C
Capacitance
ε0
Permittivity of free space
A
Area of each plate
d
Separation between plates
Capacitor with Dielectric Medium
C=Kε0A/dC = Kε0A/d

Capacitance when dielectric of constant K completely fills the gap.

K
Dielectric constant
ε0
Permittivity of free space
A
Plate area
d
Plate separation
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Diagrams5

7

Energy Stored in Capacitors

10 min

A capacitor stores energy because work is required to move charge from one plate to the other against the growing potential difference. During charging, the potential difference gradually rises from zero to V, so the stored energy is U = 1/2 QV = 1/2 CV² = Q²/(2C). This energy resides in the electric field between the plates. Energy density in an electric field is u = 1/2 εE². When charged capacitors are connected together, charge redistributes until common potential is reached. Total charge is conserved, but electrostatic energy may decrease; the lost energy is dissipated as heat, spark, sound or electromagnetic radiation. Capacitors are used in camera flashes, filters, power supplies and energy storage circuits.

Key points6

  • The factor 1/2 appears because capacitor voltage rises gradually during charging.
  • Use U = Q²/(2C) when charge is constant.
  • Use U = 1/2 CV² when voltage is constant.
  • For a parallel plate capacitor, field energy density fills the region between plates.
  • Charge sharing problems first require final common potential.
  • Capacitors can deliver stored energy quickly, making them useful in flash circuits.

Memory tricks2

Energy Formula Choice: Constant V: use CV². Constant Q: use Q²/C. Both have the 1/2 factor.

Why Half?: Capacitor voltage starts from zero and rises to V, so average charging voltage is V/2.

Examples4

Solved Example

A 4 μF capacitor is charged to 100 V. Energy stored U = 1/2 CV² = 1/2 × 4 × 10⁻⁶ × 100² = 0.02 J.

Previous NEET-Type Question

If a charged isolated capacitor is filled with dielectric K, capacitance becomes KC and energy becomes U/K because Q remains constant.

Charge Sharing Example

Capacitors 2 μF at 10 V and 3 μF at 0 V are connected in parallel with like plates. Final potential Vf = (2×10 + 3×0)/(2+3) = 4 V.

Quick Revision Card

Battery connected: V fixed. Battery removed: Q fixed. This single decision solves most dielectric-energy questions.

Common mistakes3

Forgetting Energy Loss in Charge Sharing

Charge is conserved during sharing, but electrostatic energy is not necessarily conserved because some energy dissipates.

Using Wrong Energy Formula After Dielectric Insertion

Check whether the capacitor is isolated or battery-connected. Isolated means Q constant; battery-connected means V constant.

Missing the Factor 1/2

Capacitor energy is not CV²; it is 1/2 CV².

Reference tables3

Quick revision8

Formulas5

Energy Stored in Capacitor
U=1/2QVU = 1/2 QV

Energy stored in a charged capacitor.

U
Stored energy
Q
Charge on capacitor
V
Potential difference
Energy in Terms of Capacitance and Voltage
U=1/2CV2U = 1/2 CV²

Best used when capacitance and voltage are known or voltage remains constant.

U
Stored energy
C
Capacitance
V
Potential difference
Energy in Terms of Charge and Capacitance
U=Q2/(2C)U = Q²/(2C)

Best used when charge remains constant.

U
Stored energy
Q
Charge
C
Capacitance
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Diagrams5

Videos for Electrostatic Potential and Capacitance

  • ELECTROSTATIC POTENTIAL AND CAPACITANCE | Class 12th One ShotPW NEET English · English
  • Electrostatic Potential And Capacitance | Part 1Vedantu NEET English · English
  • Electrostatic Potential And Capacitance | Part 2Vedantu NEET English · English
  • Physics | Electric Potential & Capacitance Complete Chapter | NEET 2026 | Yawar GUnacademy NEET English · English
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NEET PYQs from Electrostatic Potential and Capacitance

The latest 3 of 47 previous-year questions from this chapter.

  1. NEET 2026Set 11MediumQ1

    Five capacitors of capacitances C₁ = C₂ = C₃ = C₄ = 10 μF and C₅ = 2.5 μF are connected as shown, along with a battery of 50 V. The equivalent capacitance and the charges on each capacitor respectively are:

    • A5 μF, 125 μC on C₁ to C₄ and 25 μC on C₅
    • B5 μF, 125 μC on all capacitors
    • C5 μF, 250 μC on all capacitors
    • D4 μF, 250 μC on C₁ to C₄ and 125 μC on C₅
  2. NEET 2026Set 50MediumQ2

    Three identical capacitors, $P$, $Q$ and $S$, each of the capacitance $C$, are connected to a battery of voltage $V$, as shown in the figure. If the energy stored in the capacitor $P$ and total energy stored in the system are $U_P$ and $U_T$, respectively, then the ratio $\frac{U_P}{U_T}$ is:

    • A$2/3$
    • B$1/3$
    • C$1/2$
    • D$1/6$
  3. NEET 2026Set 50MediumQ3

    A unit positive point charge is taken slowly through an infinitesimally thin tube that is inside a charged dielectric sphere of radius $R$, having uniform positive charge density $\rho$, as shown in the figure. The initial and final positions of the charge are marked by $A$ and $B$ at distance $2R$ and $3R$ respectively, from the centre of the sphere. In this process, the magnitude of the total work done on the point charge is $\frac{\rho R^2}{n\varepsilon_0}$. The value of $n$ is : ($\varepsilon_0$ is the permittivity of vacuum)

    • A$2$
    • B$6$
    • C$9$
    • D$18$

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