NEET Physics · NCERT Class 11

Gravitation notes

Universal Law of Gravitation, Kepler's Laws, Acceleration due to Gravity, Gravitational Potential & Energy, Escape Velocity and Satellites & Orbital Motion — explained topic by topic with key points, formulas, memory tricks and common mistakes.

  • 7 topics
  • 63 min read
  • 35 formulas
  • 42 PYQs
1

Chapter Overview

7 min

Gravitation explains the attractive force between any two masses in the universe. Newton’s universal law gives this force as proportional to the product of masses and inversely proportional to the square of separation. This chapter connects falling bodies, planetary motion, satellites, tides, weightlessness and escape from planets. Kepler’s laws describe planetary orbits and are explained by Newton’s law. Acceleration due to gravity, g, changes with altitude, depth and Earth’s rotation. Gravitational potential and potential energy help solve energy-based problems, while escape velocity and orbital velocity explain rockets and satellites. For NEET, this chapter is highly scoring because formulas are direct and concepts are repeatedly tested in numerical and assertion-type questions.

Key points6

  • Gravitational force obeys inverse square law and superposition principle.
  • The value of G is universal, while g depends on planet, location and height.
  • Gravitational potential energy is negative when zero is taken at infinity.
  • Orbital velocity near Earth is v_o = √(GM/R) and escape velocity is √2 times orbital velocity.
  • Satellites are weightless because they and their occupants are in continuous free fall.
  • Geostationary satellites have period 24 hours and appear fixed over the equator.

Memory tricks2

Gravitation Flow: Remember F-G-E-S: Force law, g variation, Energy-potential, Satellites.

Escape vs Orbit: Escape speed is √2 times close-orbit speed: escape needs extra energy to reach infinity.

Examples2

Daily Life Example

A falling apple, Moon’s revolution around Earth, artificial satellites and ocean tides all involve gravitational attraction.

Quick NEET Check

If distance between two masses is doubled, gravitational force becomes one-fourth.

Common mistakes3

Confusing G and g

G is universal constant; g is local acceleration due to gravity and changes with planet and location.

Forgetting Negative Potential Energy

With zero at infinity, gravitational potential and potential energy near a mass are negative.

Thinking Satellite Weightlessness Means No Gravity

Gravity provides centripetal acceleration in orbit; weightlessness is due to continuous free fall.

Reference tables2

Quick revision8

Formulas4

Universal Law of Gravitation
F=Gm1m2/r2F = Gm1m2/r²

Attractive gravitational force between two point masses separated by distance r.

F
Gravitational force
G
Universal gravitational constant
m1, m2
Interacting masses
r
Distance between centres of masses
Acceleration due to Gravity
g=GM/R2g = GM/R²

Acceleration due to gravity at the surface of a planet of mass M and radius R.

g
Acceleration due to gravity
M
Mass of planet
R
Radius of planet
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Diagrams3

2

Universal Law of Gravitation

8 min

Newton’s universal law of gravitation states that every particle in the universe attracts every other particle with a force directly proportional to the product of their masses and inversely proportional to the square of the distance between them. The force acts along the line joining the two masses and is always attractive. The proportionality constant G is called the universal gravitational constant and has the same value everywhere in the universe. Gravitation is a long-range central force and obeys the inverse square law. When many masses are present, the net gravitational force is found by vector addition using the superposition principle. This topic is a frequent source of NEET ratio-based questions.

Key points6

  • The law applies accurately to point masses and spherically symmetric bodies treated as masses concentrated at centres.
  • Gravitational force between ordinary objects is weak because G is very small.
  • The force on m1 due to m2 and force on m2 due to m1 are equal and opposite.
  • Gravitational force does not depend on the medium between masses.
  • Superposition principle means each mass exerts force independently.
  • The inverse square nature is central to planetary and satellite motion.

Memory tricks2

Universal Law: Masses multiply, distance squares divide: F grows with masses and falls with r².

Force Nature: Gravity never pushes; it only pulls.

Examples2

Ratio Example

If the distance between two masses becomes 3 times, force becomes F/9.

Numerical Example

Two 1 kg masses separated by 1 m attract with force F = 6.67 × 10^-11 N.

Common mistakes3

Using Surface Distance Instead of Centre Distance

For spherical bodies, r is the distance between centres, not distance between surfaces.

Forgetting Vector Addition

For many masses, gravitational forces must be added vectorially, not simply by magnitudes.

Confusing G with g

G is universal and constant; g is local acceleration due to gravity.

Reference tables2

Quick revision8

Formulas4

Universal Law of Gravitation
F=Gm1m2/r2F = Gm1m2/r²

Magnitude of gravitational attraction between two point masses.

F
Gravitational force
G
Universal gravitational constant
m1, m2
Masses attracting each other
r
Separation between masses
Vector Form
F12=−Gm1m2rhat/r2F_12 = -Gm1m2 r_{hat}/r²

Force is attractive; negative sign indicates force on one mass is toward the other.

F_12
Force on mass 1 due to mass 2
r_hat
Unit vector from source to field point as chosen
r
Distance between masses
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Diagrams3

3

Kepler's Laws

8 min

Kepler’s laws describe how planets move around the Sun. The first law states that planets move in elliptical orbits with the Sun at one focus, not at the centre. The second law says the line joining the planet and Sun sweeps equal areas in equal intervals of time; this means a planet moves faster near the Sun and slower when far away. The third law states that the square of orbital period is proportional to the cube of semi-major axis: T² ∝ a³. Newton later explained these laws using universal gravitation and centripetal force. NEET commonly asks statements, area law interpretation and period-radius comparison.

Key points6

  • The Sun is at a focus of the ellipse, not at the centre.
  • The semi-major axis decides the time period in Kepler’s third law.
  • Equal area law means areal velocity is constant.
  • Kepler’s laws apply to satellites around planets also, with the central mass replacing the Sun.
  • For planets orbiting the same star, T²/r³ is constant.
  • The law of areas is connected to zero torque under central gravitational force.

Memory tricks2

Kepler 1-2-3: 1 shape, 2 sweep, 3 period: ellipse, equal areas, T² proportional to a³.

Area Law: Near Sun, run; far Sun, slow.

Examples2

Period Ratio Example

If orbital radius becomes 4 times for circular orbit, T² becomes 64 times, so T becomes 8 times.

Concept Example

A comet moves fastest at perihelion because it is closest to the Sun and must sweep equal area in equal time.

Common mistakes3

Putting Sun at Centre of Ellipse

Kepler’s first law places the Sun at one focus, not at the centre.

Using Radius Instead of Semi-Major Axis for Ellipse

For elliptical orbit, Kepler’s third law uses semi-major axis a.

Assuming Speed Is Constant in Ellipse

Planetary speed varies in elliptical orbit; areal velocity remains constant.

Reference tables2

Quick revision8

Formulas4

Kepler’s Third Law
T2∝a3T² ∝ a³

Square of time period is proportional to cube of semi-major axis of elliptical orbit.

T
Orbital time period
a
Semi-major axis of orbit
Third Law for Circular Orbit
T2=4π2r3/(GM)T² = 4π²r³/(GM)

Time period of a small body orbiting a central mass M in a circular orbit.

r
Orbital radius
M
Mass of central body
G
Universal gravitational constant
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Diagrams3

4

Acceleration due to Gravity

10 min

Acceleration due to gravity, g, is the acceleration acquired by a body falling freely under Earth’s gravitational pull. At Earth’s surface, it is obtained by equating weight mg with gravitational force GMm/R², giving g = GM/R². Unlike G, g is not universal; it changes with altitude, depth, latitude and Earth’s rotation. At height above Earth, g decreases according to inverse square law. Inside Earth, assuming uniform density, g decreases linearly with depth and becomes zero at the centre. Earth’s rotation reduces effective gravity, most at the equator and least at the poles. Weightlessness occurs when normal reaction becomes zero, such as in free fall or orbiting satellites.

Key points6

  • G is constant everywhere, but g varies from place to place.
  • g decreases with altitude because distance from Earth’s centre increases.
  • g decreases with depth because only mass inside that radius effectively contributes.
  • g is maximum near poles and minimum near equator due to rotation and shape of Earth.
  • Apparent weight is N, not mg; in free fall N = 0.
  • Astronauts in orbit are weightless, not gravityless.

Memory tricks2

Altitude vs Depth: Altitude uses square law; depth uses straight line law.

Rotation Effect: Earth spins fastest effectively at equator, so g is least there.

Examples3

Altitude Example

At height h = R above Earth, g_h = g(R/2R)² = g/4.

Depth Example

At depth d = R/2, g_d = g(1 - 1/2) = g/2.

Weightlessness Example

A freely falling lift has apparent weight zero because the normal reaction on a person is zero.

Common mistakes3

Assuming g Is Constant Everywhere

g is approximately constant only near Earth’s surface for small height changes.

Saying Gravity Is Zero in Satellite

Gravity is present in orbit; apparent weight is zero due to free fall.

Using Depth Formula for Altitude

Depth and altitude have different formulas; do not interchange them.

Reference tables2

Quick revision8

Formulas6

Relation Between G and g
g=GM/R2g = GM/R²

Acceleration due to gravity at the surface of a spherical planet.

g
Acceleration due to gravity
G
Universal gravitational constant
M
Mass of planet
R
Radius of planet
Variation with Altitude
gh=g(R/(R+h))2g_h = g(R/(R+h))²

Gravity at height h above planet surface.

g_h
Acceleration due to gravity at height h
h
Height above surface
Small Height Approximation
gh≈g(1−2h/R)g_h ≈ g(1 - 2h/R)

Approximate formula when h is much smaller than R.

h
Small height above surface
R
Planet radius
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Diagrams4

5

Gravitational Potential & Energy

10 min

Gravitational potential at a point is the work done per unit mass by an external agent in bringing a small test mass from infinity to that point without changing kinetic energy. Taking potential zero at infinity, potential due to a mass M is V = -GM/r. Gravitational potential energy of mass m is U = mV = -GMm/r. The negative sign means the mass is bound to the gravitational field and energy must be supplied to take it to infinity. Gravitational field is related to potential by g = -dV/dr. Equipotential surfaces have the same potential everywhere, so no work is done in moving a mass along them. Potentials due to multiple bodies add algebraically.

Key points6

  • Potential is zero at infinity by convention.
  • Gravitational potential is always negative near an isolated mass with infinity as zero.
  • Potential energy depends on both source mass and test mass.
  • Field is vector, but potential is scalar.
  • For multiple bodies, add potentials directly without resolving directions.
  • A spherical mass has equipotential surfaces as concentric spheres outside it.

Memory tricks2

Potential vs Field: Potential is scalar energy per kg; field is vector force per kg.

Negative Potential: Gravity binds, so with infinity as zero, gravitational potential is below zero.

Examples3

Potential Example

At distance r from mass M, potential is -GM/r. At double distance, potential becomes -GM/(2r), closer to zero.

Multiple Bodies Example

If two equal masses M are each at distance r from a point, net potential is -GM/r - GM/r = -2GM/r.

Escape Energy Example

Energy required to take mass m from Earth surface to infinity is GMm/R, ignoring atmosphere and Earth rotation.

Common mistakes3

Adding Potential Vectorially

Potential is scalar. Add potentials algebraically, not by vector components.

Missing Negative Sign

V = -GM/r and U = -GMm/r when zero is taken at infinity.

Confusing Potential with Potential Energy

Potential is per unit mass; potential energy belongs to a specific mass m.

Reference tables2

Quick revision8

Formulas5

Gravitational Potential
V=−GM/rV = -GM/r

Potential at distance r from a point or spherical mass M.

V
Gravitational potential
G
Universal gravitational constant
M
Source mass
r
Distance from source mass
Gravitational Potential Energy
U=mV=−GMm/rU = mV = -GMm/r

Potential energy of mass m at distance r from mass M.

U
Gravitational potential energy
m
Test mass
Relation Between Field and Potential
g=−dV/drg = -dV/dr

Gravitational field equals negative rate of change of potential with distance.

g
Gravitational field intensity
dV/dr
Potential gradient
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Diagrams4

6

Escape Velocity

9 min

Escape velocity is the minimum speed with which a body must be projected from the surface of a planet so that it can reach infinity with zero speed, without further propulsion. It is derived using conservation of mechanical energy: the initial kinetic energy must equal the energy needed to overcome gravitational binding. Thus, v_e = √(2GM/R) = √(2gR). Escape velocity depends on the mass and radius of the planet, but not on the mass of the escaping object or the direction of projection if air resistance and rotation are ignored. It is related to orbital velocity near the planet by v_e = √2 v_o. NEET often asks comparisons between planets.

Key points6

  • Escape velocity ignores air resistance unless stated.
  • A heavier object does not require greater escape velocity than a lighter object.
  • Larger planet mass increases escape velocity.
  • Larger radius decreases escape velocity if mass is fixed.
  • Escape requires total mechanical energy to be zero or positive.
  • Rocket engines may provide energy gradually, so actual launch speed need not instantly equal escape velocity.

Memory tricks2

Escape Formula: Escape is root two times orbit: v_e = √2 v_o.

Mass Independence: A pebble and a rocket need the same ideal escape speed from the same planet.

Examples3

Earth Example

Using g = 9.8 m/s² and R = 6.4 × 10^6 m, v_e = √(2gR) ≈ 11.2 km/s.

Planet Ratio Example

If a planet has same mass as Earth but twice the radius, its escape velocity becomes 1/√2 times Earth’s.

Previous Year Style

If orbital velocity near a planet is 8 km/s, escape velocity is 8√2 km/s.

Common mistakes3

Including Object Mass in Final Escape Velocity

Mass m cancels in derivation, so escape velocity does not depend on escaping body mass.

Confusing Escape Velocity and Orbital Velocity

Escape velocity is larger than orbital velocity by factor √2 near the surface.

Assuming Escape Means Infinite Speed at Infinity

Minimum escape velocity means speed becomes zero at infinity.

Reference tables2

Quick revision8

Formulas5

Escape Velocity
ve=√(2GM/R)v_e = √(2GM/R)

Minimum speed required from planet surface to escape gravitational field.

v_e
Escape velocity
G
Universal gravitational constant
M
Mass of planet
R
Radius of planet
Escape Velocity Using g
ve=√(2gR)v_e = √(2gR)

Surface escape velocity written using surface gravity.

g
Acceleration due to gravity at surface
R
Planet radius
Escape Energy Condition
1/2mve2=GMm/R1/2 mv_e² = GMm/R

Initial kinetic energy equals gravitational binding energy.

m
Mass of escaping object
GMm/R
Energy needed to reach infinity
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Diagrams3

7

Satellites & Orbital Motion

11 min

A satellite is a body revolving around a planet under gravitational attraction. In a circular orbit, gravity provides the required centripetal force, so GMm/r² = mv²/r. This gives orbital velocity v = √(GM/r), where r is distance from the planet’s centre. The orbital period is T = 2π√(r³/GM). Artificial satellites are launched for communication, weather monitoring, navigation, defence and scientific observation. A geostationary satellite has a 24-hour period, moves in the equatorial plane in the same direction as Earth’s rotation and appears fixed over one point. Polar satellites pass over poles and scan the entire Earth. Satellites and astronauts feel weightless because they are in continuous free fall.

Key points6

  • Orbital velocity is independent of satellite mass.
  • Higher orbit means lower orbital speed but larger time period.
  • Geostationary satellites must be equatorial, prograde and have period 24 hours.
  • Polar satellites are useful for Earth mapping and weather observation.
  • Weightlessness in satellites is due to free fall, not absence of gravity.
  • Total energy of a bound satellite is negative.

Memory tricks3

Satellite Energy: For circular satellite: U is negative double of K, and total energy is negative K.

Geostationary Conditions: Geo-stationary means same Earth station: equatorial, eastward, 24-hour period.

Orbit Speed: Higher orbit means slower speed but longer period.

Examples3

Orbital Velocity Example

Near Earth, v_o = √(gR) ≈ √(9.8 × 6.4 × 10^6) ≈ 7.9 km/s.

Energy Example

If a satellite has kinetic energy K in circular orbit, its potential energy is -2K and total energy is -K.

Period Concept

A satellite in a higher orbit has larger r, so from T = 2π√(r³/GM), its period is longer.

Common mistakes4

Using Earth Radius Instead of Orbital Radius

In satellite formulas, r is distance from Earth’s centre, equal to R + h.

Saying Orbital Velocity Depends on Satellite Mass

Satellite mass cancels, so orbital speed is independent of satellite mass.

Confusing Geostationary and Polar Satellites

Geostationary satellites stay above the equator; polar satellites pass near poles.

Assuming No Gravity in Orbit

Gravity is the centripetal force that keeps the satellite in orbit.

Reference tables3

Quick revision8

Formulas7

Orbital Velocity
vo=√(GM/r)v_o = √(GM/r)

Speed needed for a circular orbit of radius r around mass M.

v_o
Orbital velocity
G
Universal gravitational constant
M
Mass of planet
r
Orbital radius from planet centre
Near-Earth Orbital Velocity
vo=√(gR)v_o = √(gR)

Orbital velocity close to Earth’s surface ignoring atmosphere.

g
Surface acceleration due to gravity
R
Earth radius
Orbital Period
T=2π√(r3/GM)T = 2π√(r³/GM)

Time taken by a satellite to complete one circular orbit.

T
Orbital period
r
Orbital radius
Satellite Kinetic Energy
K=GMm/(2r)K = GMm/(2r)

Kinetic energy of satellite in circular orbit.

K
Kinetic energy
m
Satellite mass
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Diagrams4

Videos for Gravitation

  • Understanding Universal law of GravitationNEET MIND · English
  • Kepler's Law of Planetary MotionEncyclopaedia Britannica · English
  • Orbital motion | Physics | Khan AcademyKhan Academy · English
  • Understanding Universal law of Gravitation!Sabins · English
  • Class 11th – Acceleration due to GravityTutorialsPoint · English
  • Acceleration due to gravity of the earth // Class 11Sanitha Physics · English
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NEET PYQs from Gravitation

The latest 3 of 42 previous-year questions from this chapter.

  1. NEET 2026Set 50EasyQ1

    Two planets $P_1$ and $P_2$ with equal mass have radii $R_1$ and $R_2$, respectively, where $R_2 = \frac{R_1}{2}$. The escape speeds of $P_1$ and $P_2$ are $v_1$ and $v_2$, respectively. Then $\frac{v_2}{v_1}$ is:

    • A$\frac{1}{\sqrt{2}}$
    • B$1$
    • C$\sqrt{2}$
    • D$2$
  2. NEET 2026Set 50EasyQ2

    In a solar system, the time-period of revolution of a planet tracing a circular orbit of radius $R$ is proportional to:

    • A$R^{1/2}$
    • B$R^{3/2}$
    • C$R^2$
    • D$R^3$
  3. NEET 2026Set 11EasyQ3

    The amount of work done to raise a mass 'm' from the surface of the Earth to a height equal to the radius of the Earth 'R' will be:

    • A2mgR
    • BmgR/4
    • CmgR
    • DmgR/2

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