NEET Physics · NCERT Class 11

Kinetic Theory notes

Molecular Nature of Matter, Equation of State, Kinetic Theory of Gases, Equipartition of Energy and Mean Free Path & Specific Heat — explained topic by topic with key points, formulas, memory tricks and common mistakes.

  • 6 topics
  • 53 min read
  • 25 formulas
  • 21 PYQs
1

Chapter Overview

7 min

Kinetic Theory connects the invisible motion of molecules with measurable quantities such as pressure, volume, temperature and heat capacity. The chapter begins with the molecular nature of matter and the assumptions of ideal gases, then develops the ideal gas equation and explains pressure using molecular collisions. It also introduces rms speed, average speed, most probable speed, degrees of freedom, equipartition of energy, internal energy, mean free path and molar specific heats. For NEET, this chapter is formula-rich and conceptually scoring because most questions combine ideal gas law, molecular speeds, energy per degree of freedom and C_P-C_V relations.

Key points5

  • NEET often asks direct formula questions from gas laws, rms speed, equipartition and specific heat.
  • Macroscopic variables P, V and T are explained using microscopic molecular motion.
  • The ideal gas model ignores intermolecular forces except during elastic collisions.
  • Degrees of freedom decide internal energy and molar heat capacities.
  • Mean free path describes average distance travelled between two successive collisions.

Memory tricks2

Chapter Flow Trick: Remember: Matter → Gas Equation → Molecular Pressure → Energy Sharing → Collisions → Heat Capacity.

Speed Order: Most probable < Average < RMS. Mnemonic: MP is Minimum, Average is middle, RMS is maximum.

Examples2

Real-Life View

A tyre pressure increases after a long drive because temperature rises and faster air molecules hit the tyre walls more frequently and strongly.

NEET-Style Snapshot

If temperature of an ideal gas is quadrupled, v_rms becomes twice because v_rms ∝ √T.

Common mistakes2

Using Celsius in Gas Formulae

Always convert temperature to kelvin before using PV = nRT or speed formulae.

Confusing Molar Mass Units

In v_rms = √(3RT/M), use M in kg mol⁻¹, not g mol⁻¹.

Reference tables2

Quick revision8

Formulas4

Ideal Gas Equation
PV=nRT=NkBTPV = nRT = Nk_BT

Connects pressure, volume, temperature and amount of gas.

P
Pressure of gas
V
Volume occupied by gas
n
Number of moles
R
Universal gas constant
N
Number of molecules
k_B
Boltzmann constant
T
Absolute temperature in kelvin
Average Translational Kinetic Energy
Kavg=3/2kBTK_{avg} = 3/2 k_BT

Mean translational kinetic energy of one molecule of an ideal gas.

K_avg
Average kinetic energy per molecule
k_B
Boltzmann constant
T
Absolute temperature
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Diagrams3

2

Molecular Nature of Matter

8 min

The molecular nature of matter states that all substances are made of tiny particles such as atoms, molecules or ions. These particles are not at rest; they are in continuous random motion, and their motion becomes more intense when temperature increases. Brownian motion provides strong evidence for this molecular agitation because pollen or dust particles move irregularly due to collisions with invisible fluid molecules. Intermolecular forces are attractive at moderate separation and strongly repulsive at very small separation. In ideal gas theory, molecules are treated as point masses with negligible volume and no intermolecular force except during perfectly elastic collisions.

Key points5

  • Atomic hypothesis explains macroscopic properties using microscopic particles.
  • Brownian motion becomes more vigorous at higher temperature and for smaller suspended particles.
  • Real gases deviate from ideal behaviour at high pressure and low temperature.
  • Intermolecular potential energy is minimum at equilibrium separation.
  • Ideal gas assumptions simplify pressure and temperature calculations.

Memory tricks2

Ideal Gas Assumption Trick: Remember PERL: Point particles, Elastic collisions, Random motion, Low/no intermolecular force.

Brownian Motion Clue: Brownian means Bumping: visible particles bump around due to invisible molecular hits.

Examples3

Dust in Sunlight

Dust particles dancing in a beam of sunlight illustrate random impacts by air molecules.

Perfume Spreading

Perfume molecules spread through air because molecules are in continuous random motion.

Solved Example

If 2 moles of gas are present, number of molecules N = 2 × 6.022 × 10²³ = 1.2044 × 10²⁴ molecules.

Common mistakes2

Average Velocity vs Average Speed

In random molecular motion, average velocity can be zero, but average speed is never zero.

Ideal Gas Does Not Mean Molecules Stop Colliding

Ideal gas molecules do collide; the assumption is that collisions are perfectly elastic and intermolecular forces are negligible except during collision.

Reference tables2

Quick revision6

Formulas3

Number of Molecules
N=nNAN = nN_A

Calculates total molecules from number of moles.

N
Total number of molecules
n
Number of moles
N_A
Avogadro constant, 6.022 × 10²³ mol⁻¹
Moles from Mass
n=m/Mn = m/M

Converts given mass of a gas into moles.

n
Number of moles
m
Given mass
M
Molar mass
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Diagrams3

3

Equation of State

9 min

The equation of state describes the relation between pressure, volume, temperature and amount of gas. For an ideal gas, the equation is PV = nRT, where R is the universal gas constant. It combines Boyle's law, Charles' law, Gay-Lussac's law and Avogadro's law into one compact form. Pressure is due to molecular impacts on container walls, volume is the space available for molecular motion and temperature represents molecular kinetic energy. In NEET, most questions involve comparing two states of a gas using P₁V₁/T₁ = P₂V₂/T₂ for fixed moles or using PV = nRT to calculate unknown variables.

Key points5

  • R = 8.314 J mol⁻¹ K⁻¹ and k_B = R/N_A.
  • One mole of any ideal gas contains Avogadro number of molecules.
  • At STP commonly used in school-level problems, one mole ideal gas occupies about 22.4 L.
  • The combined gas law applies only when the amount of gas is constant.
  • Real gases approach ideal behaviour at low pressure and high temperature.

Memory tricks2

Gas Law Shortcut: Boyle is 'B' for Bend: P-V graph bends as a hyperbola. Charles and Gay-Lussac are straight lines with T in kelvin.

State Equation Memory: PV = nRT: Pressure × Volume equals number of moles × gas constant × temperature.

Examples3

Solved Numerical

For 2 mol ideal gas at 300 K in 0.05 m³, P = nRT/V = 2 × 8.314 × 300 / 0.05 = 9.98 × 10⁴ Pa.

Real-Life Application

A syringe outlet closed with a finger becomes harder to push because decreasing volume increases pressure.

NEET Shortcut

If pressure is doubled and temperature is unchanged for fixed gas, volume becomes half by Boyle's law.

Common mistakes2

Applying Combined Gas Law When Moles Change

P₁V₁/T₁ = P₂V₂/T₂ is valid only when the amount of gas remains constant.

Using Litres With SI Pressure Without Conversion

If R = 8.314 J mol⁻¹ K⁻¹ is used, volume must be in m³ and pressure in pascal.

Reference tables2

Quick revision8

Formulas4

Ideal Gas Equation
PV=nRTPV = nRT

Used for pressure-volume-temperature calculations for an ideal gas.

P
Pressure
V
Volume
n
Number of moles
R
Universal gas constant
T
Temperature in kelvin
Combined Gas Law
P1V1/T1=P2V2/T2P₁V₁/T₁ = P₂V₂/T₂

Compares two states of a fixed amount of gas.

P₁, V₁, T₁
Initial pressure, volume and temperature
P₂, V₂, T₂
Final pressure, volume and temperature
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Diagrams4

4

Kinetic Theory of Gases

10 min

Kinetic Theory of Gases explains pressure and temperature using molecular motion. Gas molecules move randomly with different speeds and collide elastically with container walls. Every collision changes molecular momentum, and the total rate of momentum transfer produces pressure. For a gas of density ρ, pressure is P = 1/3 ρv_rms². Temperature is directly related to average translational kinetic energy, so hotter gases have faster molecules. This topic also compares most probable, average and rms speeds, where v_mp < v_avg < v_rms. Degrees of freedom describe independent ways in which a molecule can store energy.

Key points5

  • The factor 1/3 in pressure formula comes from equal distribution of motion along x, y and z directions.
  • Temperature depends on mean square speed, not directly on average velocity.
  • RMS speed is most useful in kinetic energy calculations.
  • Molecular speed increases with temperature and decreases with molar mass.
  • At the same temperature, lighter gases move faster than heavier gases.

Memory tricks2

Speed Ranking: Remember: MP < AVG < RMS using 'My Average Runs More Slowly' in order of names, but the numeric order is MP, Average, RMS.

Pressure Formula: P = one-third rho v-square: the one-third comes from three equal spatial directions.

Examples3

Solved Numerical

For nitrogen, M = 28 × 10⁻³ kg mol⁻¹ at 300 K. v_rms = √(3 × 8.314 × 300 / 0.028) ≈ 517 m s⁻¹.

Previous NEET-Type Question

If temperature becomes 4T, rms speed becomes 2v_rms because v_rms ∝ √T.

Real-Life Example

Hydrogen diffuses faster than oxygen at the same temperature because hydrogen has much smaller molar mass.

Common mistakes3

Confusing RMS Speed with Average Speed

RMS speed is not the arithmetic mean; use it when kinetic energy or pressure is involved.

Ignoring Molar Mass Units

Convert molar mass from g mol⁻¹ to kg mol⁻¹ before using R-based speed formulas.

Saying Temperature Depends on Average Velocity

Average velocity may be zero; temperature depends on average kinetic energy or mean square speed.

Reference tables2

Quick revision8

Formulas5

Pressure Due to Gas Molecules
P=1/3ρvrms2P = 1/3 ρv_{rms}²

Relates pressure to density and rms speed of molecules.

P
Pressure of gas
ρ
Mass density of gas
v_rms
Root mean square speed
Kinetic Energy and Temperature
1/2mvrms2=3/2kBT1/2 mv_{rms}² = 3/2 k_BT

Shows that absolute temperature measures average translational kinetic energy.

m
Mass of one molecule
v_rms
Root mean square speed
k_B
Boltzmann constant
T
Absolute temperature
Most Probable Speed
vmp=√(2RT/M)v_{mp} = √(2RT/M)

Speed possessed by the maximum number of molecules.

v_mp
Most probable speed
R
Universal gas constant
T
Absolute temperature
M
Molar mass
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Diagrams4

5

Equipartition of Energy

9 min

The law of equipartition of energy states that in thermal equilibrium, energy is equally shared among all active degrees of freedom. Each quadratic degree of freedom contributes 1/2 k_BT per molecule or 1/2 RT per mole. Translational motion gives three degrees of freedom for all gases. Rotational degrees become important in diatomic and polyatomic gases, while vibrational degrees usually become active at high temperature. This law explains internal energy and molar heat capacities of ideal gases. For NEET, remember that monatomic gases have f = 3, diatomic gases generally have f = 5 at room temperature and internal energy is U = f/2 nRT.

Key points5

  • Translational degrees are always three in 3D space.
  • Linear diatomic molecules have two rotational degrees at ordinary temperature.
  • A vibrational mode contributes k_BT per molecule because it has two quadratic energy terms.
  • Equipartition is most accurate when the corresponding mode is thermally active.
  • Heat capacity increases when more degrees of freedom become active.

Memory tricks2

Equipartition Formula Trick: Each freedom gets half: every active degree contributes 1/2 k_BT per molecule.

Degrees of Freedom Memory: Mono = 3, Di = 5, Non-linear poly = 6 at ordinary temperature.

Examples3

Solved Example

For 2 moles of monatomic ideal gas at 300 K, U = 3/2 nRT = 1.5 × 2 × 8.314 × 300 ≈ 7483 J.

Practice Question

Find C_V for a diatomic gas at ordinary temperature. Since f = 5, C_V = 5R/2.

Real-Life Analogy

Energy shared among degrees of freedom is like distributing equal coins among available pockets; more pockets means greater heat capacity.

Common mistakes3

Counting Vibrational Mode Incorrectly

One vibrational mode contributes two degrees of freedom because it has kinetic and potential energy parts.

Assuming All Degrees Are Always Active

Vibrational modes may be inactive at ordinary temperature; use NCERT standard values unless stated otherwise.

Using Internal Energy Formula for Non-Ideal Cases

U = f/2 nRT is for ideal gases with fixed active degrees of freedom.

Reference tables2

Quick revision8

Formulas4

Energy per Molecule
E=f/2kBTE = f/2 k_BT

Average energy per molecule for f active degrees of freedom.

E
Energy per molecule
f
Number of active degrees of freedom
k_B
Boltzmann constant
T
Absolute temperature
Internal Energy of Ideal Gas
U=f/2nRTU = f/2 nRT

Total internal energy of n moles of ideal gas with f degrees of freedom.

U
Internal energy
f
Degrees of freedom
n
Number of moles
R
Universal gas constant
T
Absolute temperature
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Diagrams3

6

Mean Free Path & Specific Heat

10 min

Mean free path is the average distance a gas molecule travels between two successive collisions. It depends on molecular diameter and number density, so it becomes smaller when gas is compressed or molecules are larger. Collision frequency is the number of collisions made per second and is related to molecular speed divided by mean free path. Specific heat describes heat required to raise temperature. For gases, molar heat capacities at constant volume and constant pressure are different because at constant pressure the gas expands and does external work. Mayer's formula, C_P - C_V = R, is a high-yield NEET relation for ideal gases.

Key points5

  • Mean free path increases with temperature at constant pressure.
  • Mean free path decreases with pressure at constant temperature.
  • Larger molecular diameter means more collision chance and smaller mean free path.
  • C_P is always greater than C_V for an ideal gas.
  • Molar heat capacities depend on degrees of freedom.

Memory tricks3

Mayer's Formula: C_P is Plus work, so C_P is bigger; the extra amount for one mole ideal gas is R.

Mean Free Path Dependence: High Pressure means Heavy crowding, so molecules travel a shorter free path.

Gamma Shortcut: γ = 1 + 2/f. For mono f=3 gives 5/3; for di f=5 gives 7/5.

Examples4

Solved Example: Heat Capacity

For monatomic ideal gas, f = 3. C_V = 3R/2 and C_P = 5R/2. Therefore C_P - C_V = R and γ = 5/3.

Solved Example: Pressure Effect

If pressure doubles at constant temperature, λ becomes half because λ ∝ 1/P.

NEET Shortcut

If a question gives γ, find f quickly using f = 2/(γ - 1). For γ = 7/5, f = 5.

Real-Life Example

At high altitude, air pressure is low, so mean free path is larger than near sea level.

Common mistakes3

Thinking C_P Equals C_V

For gases, C_P > C_V because constant-pressure heating includes expansion work.

Forgetting the √2 Factor in Mean Free Path

The √2 appears because all molecules are moving, not just one molecule through fixed targets.

Using Specific Heat Per Gram Instead of Molar Heat Capacity

C_P and C_V in Mayer's formula are molar heat capacities, not mass specific heats.

Reference tables3

Quick revision8

Formulas5

Mean Free Path
λ=1/(√2πd2nv)λ = 1/(√2πd²n_v)

Average distance between successive molecular collisions.

λ
Mean free path
d
Molecular diameter
n_v
Number of molecules per unit volume
Mean Free Path in Terms of Pressure
λ=kBT/(√2πd2P)λ = k_BT/(√2πd²P)

Useful when pressure and temperature are given instead of number density.

k_B
Boltzmann constant
T
Absolute temperature
d
Molecular diameter
P
Pressure
Collision Frequency
z=vavg/λz = v_{avg}/λ

Number of collisions per second made by a molecule.

z
Collision frequency
v_avg
Average molecular speed
λ
Mean free path
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Diagrams6

Videos for Kinetic Theory

  • CBSE Class 11 Physics - 13 | Kinetic Theory | Full ChapterShiksha House Official · English
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NEET PYQs from Kinetic Theory

The latest 3 of 21 previous-year questions from this chapter.

  1. NEET 2026Set 50MediumQ1

    An ideal gas is made of polyatomic molecules. Each of the molecules has three translational, three rotational and $f$ number of vibrational modes. If the ratio of heat capacities $C_P/C_V$ of the gas is $8/7$, then the value of $f$ is:

    • A$4$
    • B$3$
    • C$2$
    • D$1$
  2. NEET 2026Set 50MediumQ2

    The mean free path of molecules in an ideal gas $A$ is half that of another ideal gas $B$. The diameter of the spherical molecules of gas $A$ is twice the diameter of the molecules of $B$. If number densities of the gases $A$ and $B$ are $n_A$ and $n_B$, respectively, the correct option is:

    • A$n_A = n_B$
    • B$n_A = 2n_B$
    • C$n_A = \frac{1}{4}n_B$
    • D$n_A = \frac{1}{2}n_B$
  3. NEET 2026Set 11EasyQ3

    A flask contains argon and chlorine in the ratio of $2:1$ by mass. The temperature of the mixture is $27^\circ C$. The ratio of root mean square speed of the molecules of the two gases $\left(\dfrac{v_{\mathrm{rms}}^{\mathrm{Ar}}}{v_{\mathrm{rms}}^{\mathrm{Cl}}}\right)$ is: (Atomic mass of argon $=40.0\,u$ and molecular mass of chlorine $=70.0\,u$)

    • A$\dfrac{\sqrt{7}}{2}$
    • B$\dfrac{7}{4}$
    • C$\dfrac{7}{2}$
    • D$\dfrac{2}{\sqrt{7}}$

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