PhysicsNCERT Class 12
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Nuclei Notes

Study Notes

5 Topics23 Formulas2 PYQs32 Key Points

Topics

5
1

Chapter Overview

Overview

The chapter Nuclei explains the structure, size, mass and stability of atomic nuclei. A nucleus contains protons and neutrons, collectively called nucleons, and is characterized by atomic number Z and mass number A. The chapter connects nuclear size with A through R = R0A^(1/3), showing nearly constant nuclear density. It then explains why nuclear mass is less than the sum of separate nucleon masses through mass defect and binding energy. Nuclear force is introduced as a strong, short-range, charge-independent and saturating force. Radioactivity describes spontaneous alpha, beta and gamma emissions governed by exponential decay law. Finally, nuclear fission and fusion explain large energy release due to changes in binding energy per nucleon.

Key Points5
  • 1Nuclear physics is mainly about composition, size, stability, force and energy transformations of nuclei.
  • 2The binding energy curve explains why both fission and fusion release energy.
  • 3Radioactive decay is statistical; we cannot predict which nucleus decays next, only the average rate.
  • 4Alpha decay changes A and Z, beta decay changes Z but not A, gamma decay changes only energy state.
  • 5NEET questions commonly test direct formulas, graph interpretation and decay equations.
Memory Tricks2

Chapter Flow Trick

Remember the order as C-B-F-R-E: Composition, Binding energy, Forces, Radioactivity, Energy.

Energy Clue

If products have higher binding energy per nucleon than reactants, energy is released.

Examples2

Why Iron Is Stable

Iron has one of the highest binding energies per nucleon, so its nucleons are tightly bound and it is highly stable.

Energy in the Sun

The Sun shines because light nuclei fuse to form heavier nuclei and release energy.

Reference Tables1
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Common Mistakes2

Confusing Atomic Mass and Mass Number

Mass number A is a count of nucleons, while atomic mass is measured in u or kg and includes actual mass defect effects.

Linear Nuclear Radius

Do not assume R is proportional to A. Radius is proportional to A^(1/3), while volume is proportional to A.

Formula Cards4
Mass Number

Mass number is the total number of nucleons present in the nucleus.

Variables

A=

Mass number

Z=

Atomic number or number of protons

N=

Number of neutrons

Nuclear Radius

Radius of a nucleus increases with cube root of mass number.

Variables

R=

Nuclear radius

R0=

Nuclear radius constant, about 1.2 × 10^-15 m

A=

Mass number

Diagrams3
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2

Nuclear Composition

Overview

Nuclear composition describes what is inside the nucleus and how nuclei are identified. The nucleus contains protons and neutrons, collectively called nucleons. The atomic number Z is the number of protons and determines the element. The mass number A is the total number of protons and neutrons, so neutron number N = A - Z. Nuclides are written as AZX, where X is the chemical symbol. Isotopes have the same Z but different A, isobars have the same A but different Z, and isotones have the same N. Nuclear radius follows R = R0A^(1/3), which means nuclear volume is proportional to A. This leads to almost constant nuclear density for all nuclei.

Key Points5
  • 1The chemical identity of an atom is fixed by Z, not by A.
  • 2Different isotopes of the same element have similar chemical properties but different nuclear masses.
  • 3Nuclear radius is extremely small; 1 fm = 10^-15 m.
  • 4Since volume is proportional to R^3 and R^3 is proportional to A, mass per unit volume remains nearly constant.
  • 5Nuclear density is enormously larger than ordinary matter density.
Memory Tricks2

Iso Words Trick

Isotope: same proton number. Isobar: same mass bar A. Isotone: same neutron tone N.

A-Z-N Triangle

Write A on top, Z and N below. Cover any one to get the missing relation: A = Z + N, N = A - Z.

Examples2

Finding Neutrons

For 238U with Z = 92, neutron number N = 238 - 92 = 146.

Hydrogen Isotopes

Protium, deuterium and tritium all have Z = 1 but have different neutron numbers.

Reference Tables2
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Common Mistakes2

Wrong Nuclide Symbol Reading

In AZX notation, A is written upper left and Z lower left. Students often swap A and Z in NEET questions.

Assuming Nuclear Density Depends on A

Because radius increases as A^(1/3), volume is proportional to A; hence density is approximately constant.

Formula Cards4
Mass Number Relation

Total number of nucleons equals number of protons plus number of neutrons.

Variables

A=

Mass number

Z=

Number of protons

N=

Number of neutrons

Neutron Number

Used to identify isotones and neutron content of a nucleus.

Variables

N=

Number of neutrons

A=

Mass number

Z=

Atomic number

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3

Mass Defect & Binding Energy

Overview

The mass of a stable nucleus is always less than the sum of the masses of its separate protons and neutrons. This missing mass is called mass defect and is converted into binding energy according to Einstein's mass-energy relation. Binding energy is the energy required to completely separate a nucleus into its nucleons, or equivalently the energy released when the nucleus is formed from free nucleons. Binding energy per nucleon is more useful for comparing nuclear stability. The binding energy curve rises sharply for light nuclei, reaches a maximum near iron and nickel, then slowly decreases for heavy nuclei. Therefore, fusion of light nuclei and fission of heavy nuclei can release energy by moving toward higher binding energy per nucleon.

Key Points5
  • 1Mass defect is not an error; it is the mass equivalent of nuclear binding energy.
  • 2Packing fraction indicates whether isotopic mass is higher or lower relative to mass number.
  • 3Binding energy per nucleon is a better stability indicator than total binding energy.
  • 4The binding energy curve explains both stellar fusion and nuclear reactor fission.
  • 5Energy release is calculated from mass difference between reactants and products.
Memory Tricks2

BEND Rule

Binding Energy Needs Defect: if there is mass defect, there is binding energy.

Fe Peak Rule

Everything wants to move toward iron-like stability: light nuclei fuse upward; heavy nuclei split downward.

Examples2

Simple Energy Calculation

If mass defect is 0.01 u, binding energy = 0.01 × 931.5 MeV = 9.315 MeV.

Graph-Based NEET Idea

A heavy nucleus such as uranium releases energy by fission because its fragments have greater binding energy per nucleon.

Reference Tables2
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Common Mistakes2

Using Total Binding Energy for Stability

For comparing stability of different nuclei, use binding energy per nucleon, not total binding energy.

Forgetting 931.5 MeV

If mass defect is in atomic mass unit, multiply by 931.5 MeV, not by 3 × 10^8 directly.

Formula Cards4
Mass Defect

Difference between the total mass of free nucleons and the actual mass of the nucleus.

Variables

Δm=

Mass defect

Z=

Number of protons

mp=

Mass of one proton

mn=

Mass of one neutron

M=

Actual nuclear mass

Binding Energy

Energy equivalent of the mass defect.

Variables

B.E.=

Binding energy

Δm=

Mass defect in kg or atomic mass unit

c=

Speed of light

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4

Nuclear Forces

Overview

Nuclear force is the attractive force that holds protons and neutrons together inside the nucleus. This is necessary because protons repel one another electrostatically, yet nuclei remain stable. Nuclear force is much stronger than electrostatic and gravitational forces at nuclear distances, but it acts only over a very short range of about 1 to 2 femtometres. It is nearly charge independent, meaning proton-proton, proton-neutron and neutron-neutron nuclear interactions are approximately similar after ignoring electrostatic repulsion. It also has saturation property: each nucleon interacts strongly only with its nearest neighbours, not with all nucleons in the nucleus. This explains why binding energy per nucleon remains roughly constant for medium and heavy nuclei.

Key Points5
  • 1Nuclear force is not gravitational; gravity is negligible inside the nucleus.
  • 2It is not simply electrostatic because it acts between neutrons also.
  • 3Short-range nature explains why electrons are not held inside the nucleus by nuclear force.
  • 4Saturation property explains nearly constant nuclear density and binding energy per nucleon.
  • 5The repulsive core prevents all nucleons from merging into a point.
Memory Tricks2

SCSRS Trick

Nuclear force is Strong, Charge-independent, Short-range, Repulsive-core, Saturating.

Nearest Neighbour Trick

Think of nuclear force like holding hands only with nearby students, not with everyone in the school.

Examples2

Why Protons Stay Together

In a helium nucleus, two protons repel each other electrically, but strong nuclear force binds them with neutrons.

Why Large Nuclei Need More Neutrons

Neutrons add attractive nuclear force without adding proton-proton electrostatic repulsion, improving stability.

Reference Tables2
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Common Mistakes2

Thinking Nuclear Force Is Long Range

Nuclear force is extremely strong but not long range. Beyond a few femtometres it becomes negligible.

Ignoring Repulsive Core

Nuclear force is not always attractive; at extremely small separation it becomes strongly repulsive.

Formula Cards2
Electrostatic Repulsion Between Protons

Protons repel each other due to Coulomb force, but nuclear force dominates at very small distances.

Variables

F=

Electrostatic force

k=

Coulomb constant

e=

Charge of proton

r=

Separation between protons

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5

Radioactivity

Overview

Radioactivity is the spontaneous disintegration of unstable nuclei with emission of alpha particles, beta particles or gamma rays. It is a nuclear phenomenon and is almost unaffected by temperature, pressure, chemical state or external physical conditions. In alpha decay, the nucleus emits a helium nucleus, so A decreases by 4 and Z decreases by 2. In beta-minus decay, a neutron converts into a proton, so Z increases by 1 while A remains unchanged. In beta-plus decay, a proton converts into a neutron, so Z decreases by 1. Gamma decay emits high-energy photons from an excited nucleus without changing A or Z. The number of undecayed nuclei follows exponential decay, leading to half-life, mean life and activity concepts.

Key Points6
  • 1Radioactive decay is probabilistic; λ represents probability of decay per unit time.
  • 2Half-life is independent of initial number of nuclei.
  • 3After n half-lives, remaining nuclei = N0/2^n.
  • 4Activity decreases exponentially just like the number of undecayed nuclei.
  • 5Gamma emission usually follows alpha or beta decay when the daughter nucleus is excited.
  • 6Conservation of charge and mass number helps complete nuclear decay equations.
Memory Tricks3

Alpha Subtracts 4 and 2

Alpha is a helium nucleus: 4He2, so subtract 4 from A and 2 from Z.

Beta Minus Adds Z

In beta-minus decay, neutron becomes proton; proton count increases, so Z increases by 1.

Gamma Gives No Change

Gamma is only energy, not a nucleon, so A and Z remain unchanged.

Examples3

Half-Life Numerical

If half-life is 10 days, after 30 days n = 3 half-lives, so remaining sample = N0/2^3 = N0/8.

Alpha Decay Equation

238U92 emits alpha particle to form 234Th90 because A becomes 238 - 4 = 234 and Z becomes 92 - 2 = 90.

NEET PYQ Pattern

A common question gives initial activity and asks activity after several half-lives; use R = R0/2^n.

Reference Tables2
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Common Mistakes3

Changing A in Beta Decay

Beta decay changes a neutron into proton or proton into neutron, so total nucleon number A remains unchanged.

Treating Half-Life as Linear Decay

After two half-lives, remaining amount is one-fourth, not zero.

Confusing Mean Life and Half-Life

Mean life τ = 1/λ, while half-life T1/2 = 0.693/λ. Mean life is greater than half-life.

Formula Cards5
Radioactive Decay Law

Number of undecayed nuclei decreases exponentially with time.

Variables

N=

Nuclei remaining after time t

N0=

Initial number of nuclei

λ=

Decay constant

t=

Time

Activity

Activity is the rate of disintegration of radioactive nuclei.

Variables

R=

Activity or decay rate

N=

Number of undecayed nuclei

λ=

Decay constant

Half-Life

Time in which half of the radioactive nuclei decay.

Variables

T1/2=

Half-life

λ=

Decay constant

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6

Nuclear Energy

Overview

Nuclear energy is released when nuclear reactions produce products with higher binding energy per nucleon than the reactants. In nuclear fission, a heavy nucleus such as uranium-235 absorbs a neutron and splits into two medium-mass nuclei along with more neutrons and a large amount of energy. These neutrons can trigger further fissions, producing a chain reaction. A nuclear reactor controls this chain reaction using moderator, control rods, coolant and shielding. In nuclear fusion, two light nuclei combine to form a heavier nucleus and release energy; this powers the Sun and stars. Fusion requires extremely high temperature because positively charged nuclei must overcome electrostatic repulsion before nuclear force can bind them.

Key Points6
  • 1Fission is used in nuclear reactors and atomic bombs, but reactors use controlled chain reactions.
  • 2Fusion releases enormous energy and produces stellar energy, but controlled fusion is technically difficult.
  • 3Criticality depends on neutron multiplication: one neutron from each fission should cause another fission in a steady reactor.
  • 4The energy released per fission of U-235 is about 200 MeV.
  • 5Nuclear reactors convert nuclear energy into heat, then steam, then mechanical and electrical energy.
  • 6Shielding and control systems are essential for radiation safety.
Memory Tricks3

Fission Splits, Fusion Joins

Fission sounds like division; fusion sounds like joining. Heavy splits, light joins.

Reactor MCCS

Moderator slows, Control rods capture, Coolant carries heat, Shielding saves.

Critical k Trick

k = 1 keeps it calm; k less than 1 loses reaction; k greater than 1 grows reaction.

Examples3

Energy from U-235 Fission

One fission of U-235 releases about 200 MeV, mainly as kinetic energy of fragments and energy of emitted radiation.

Solar Fusion

In the Sun, hydrogen nuclei ultimately form helium and release energy that reaches Earth as sunlight.

Reactor Application

Nuclear power plants use heat from controlled fission to produce steam that rotates turbines and generates electricity.

Reference Tables3
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Common Mistakes3

Thinking Fusion Happens Easily

Fusion needs extremely high temperature because nuclei must overcome electrostatic repulsion.

Confusing Moderator and Control Rods

Moderator slows neutrons; control rods absorb neutrons. They are not the same.

Assuming All Chain Reactions Are Explosive

A reactor uses a controlled chain reaction with k approximately equal to 1.

Formula Cards4
Energy Released in Nuclear Reaction

Positive Q means energy is released in the nuclear reaction.

Variables

Q=

Energy released

c=

Speed of light

Energy from Atomic Mass Units

Shortcut for calculating nuclear energy when mass difference is in atomic mass unit.

Variables

Q=

Energy released in MeV

Δm=

Mass difference in u

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Formula Sheet

10
Mass Number

Mass number is the total number of nucleons present in the nucleus.

Variables

A=

Mass number

Z=

Atomic number or number of protons

N=

Number of neutrons

Nuclear Radius

Radius of a nucleus increases with cube root of mass number.

Variables

R=

Nuclear radius

R0=

Nuclear radius constant, about 1.2 × 10^-15 m

A=

Mass number

Binding Energy

Mass defect is converted into nuclear binding energy.

Variables

B.E.=

Binding energy

Δm=

Mass defect

c=

Speed of light in vacuum

Radioactive Decay Law

Number of undecayed radioactive nuclei decreases exponentially with time.

Variables

N=

Number of nuclei left after time t

N0=

Initial number of nuclei

λ=

Decay constant

t=

Time

Mass Number Relation

Total number of nucleons equals number of protons plus number of neutrons.

Variables

A=

Mass number

Z=

Number of protons

N=

Number of neutrons

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NEET PYQs — Nuclei

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NEET 2013Set WMediumQ1

The half life of a radioactive isotope $X$ is $20$ years. It decays to another element $Y$ which is stable. The two elements $X$ and $Y$ were found to be in the ratio $1:7$ in a sample of a given rock. The age of the rock is estimated to be

NEET 2013Set WMediumQ2

A certain mass of Hydrogen is changed to Helium by the process of fusion. The mass defect in fusion reaction is $0.02866\,u$. The energy liberated per $u$ is (given $1\,u = 931\,\text{MeV}$)

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