Magnetism and Matter NEET PYQs (2005–2026) with Solutions

10 solved Magnetism and Matter PYQs

Real NEET and AIPMT questions from this chapter, newest first. Try each one, then open the answer and the step-by-step explanation.

1. Question 1 (NEET 2024)

   NEET 2024MediumMagnetic Properties of Materials

   Match List-I with List-II. Choose the correct answer from the options given below:

   1. AOption A: A-III, B-II, C-I, D-IV
   2. BOption B: A-IV, B-III, C-II, D-I
   3. COption C: A-II, B-III, C-IV, D-I
   4. DOption D: A-II, B-I, C-III, D-IV

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   Correct answer: (C) A-II, B-III, C-IV, D-I

   Explanation

   Diamagnetic substances have small negative susceptibility: $$0 > \chi > -1$$ Ferromagnetic substances have very large positive susceptibility: $$\chi \gg 1$$ Paramagnetic substances have small positive susceptibility: $$0 < \chi < \varepsilon$$ Non-magnetic substances have: $$\chi = 0$$ Thus: A-II, B-III, C-IV, D-I Hence, option (C) is correct.

2. Question 2 (NEET 2024)

   NEET 2024MediumMagnetic Properties of Materials

   A sheet is placed on a horizontal surface in front of a strong magnetic pole. A force is needed to: A. hold the sheet there if it is magnetic. B. hold the sheet there if it is non-magnetic. C. move the sheet away from the pole with uniform velocity if it is conducting. D. move the sheet away from the pole with uniform velocity if it is both, non-conducting and non-polar. Choose the correct statement(s) from the options given below:

   1. AOption A: A, C and D only
   2. BOption B: C only
   3. COption C: B and D only
   4. DOption D: A and C only

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   Correct answer: (D) A and C only

   Explanation

   If the sheet is magnetic, it is attracted by the magnetic pole, so force is needed to hold it in place. Thus statement A is correct. If the sheet is conducting and moved away, eddy currents are induced, opposing the motion. Hence force is needed for uniform velocity. Thus statement C is correct. A non-magnetic sheet does not require force to hold near the pole, and a non-conducting non-polar sheet experiences no magnetic interaction. Therefore, statements A and C are correct. Hence, option (D) is correct.

3. Question 3 (NEET 2019)

   NEET 2019EasyMagnetic Field & Gauss's Law

   The relations amongst the three elements of earth’s magnetic field, namely horizontal component H, vertical component V and dip δ are, ($B_E$ = total magnetic field)

   1. AOption A: Option 1
   2. BOption B: Option 2
   3. COption C: Option 3
   4. DOption D: Option 4

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   Correct answer: (C) Option 3

   Explanation

   If $$B_E$$ is the total magnetic field of the earth and $$\delta$$ is the angle of dip, then: For the horizontal component: $$H = B_E \cos\delta$$ For the vertical component: $$V = B_E \sin\delta$$ Hence, option (C) is correct.

4. Question 4 (NEET 2013)

   NEET 2013HardBar Magnet

   A bar magnet of length $l$ and magnetic dipole moment $M$ is bent in the form of an arc as shown in figure. The new magnetic dipole moment will be

   1. AOption A: Option 1
   2. BOption B: Option 2
   3. COption C: Option 3
   4. DOption D: Option 4

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   Correct answer: (B) Option 2

   Explanation

   For the bent magnet: $$M = m l$$ Arc length: $$l = r\theta = r\cdot\frac{\pi}{3}$$ Hence: $$r = \frac{3l}{\pi}$$ New dipole moment: $$M' = mr = m\cdot\frac{3l}{\pi} = \frac{3M}{\pi}$$

5. Question 5 (AIPMT 2012)

   AIPMT 2012MediumBar Magnet

   A magnetic needle suspended parallel to a magnetic field requires √3 J of work to turn it through 60°. The torque needed to maintain the needle in this position will be:

   1. AOption A: 3 J
   2. BOption B: √3 J
   3. COption C: 3/2 J
   4. AOption A: 2√3 J

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   Correct answer: (A) 3 J, (A) 2√3 J

   Explanation

   Work done in rotating magnetic dipole: $$W = MB(1 - \cos\theta)$$ Given: $$W = \sqrt{3}\,J, \quad \theta = 60^\circ$$ $$\sqrt{3} = MB\left(1 - \frac{1}{2}\right)$$ $$MB = 2\sqrt{3}$$ Torque required: $$\tau = MB\sin\theta$$ $$\tau = 2\sqrt{3} \times \frac{\sqrt{3}}{2} = 3\,J$$ Hence option (A) is correct.

6. Question 6 (AIPMT 2009)

   AIPMT 2009EasyMagnetic Properties of Materials

   If a diamagnetic substance is brought near the north or the south pole of a bar magnet, it is:

   1. AOption A: Attracted by both the poles
   2. BOption B: Repelled by both the poles
   3. COption C: Repelled by the north pole and attracted by the south pole
   4. DOption D: Attracted by the north pole and repelled by the south pole

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   Correct answer: (B) Repelled by both the poles

   Explanation

   Diamagnetic substances are weakly repelled by magnetic fields irrespective of pole.

7. Question 7 (AIPMT 2008)

   AIPMT 2008EasyMagnetic Properties of Materials

   Curie temperature is the temperature above which

   1. AOption A: Ferromagnetic material becomes diamagnetic material
   2. BOption B: Ferromagnetic material becomes paramagnetic material
   3. COption C: Paramagnetic material becomes diamagnetic material
   4. DOption D: Paramagnetic material becomes ferromagnetic material

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   Correct answer: (B) Ferromagnetic material becomes paramagnetic material

   Explanation

   Above the Curie temperature, thermal agitation destroys the alignment of magnetic domains in a ferromagnetic substance. As a result, the ferromagnetic material loses its spontaneous magnetization and behaves as a paramagnetic material. Hence, the correct answer is ferromagnetic material becomes paramagnetic material.

8. Question 8 (AIPMT 2007)

   AIPMT 2007MediumMagnetic Properties of Materials

   If the temperature and magnetic field applied across a paramagnetic substance are both tripled, by how many times will the intensity of magnetization change?

   1. AOption A: 1/3 times
   2. BOption B: 1 time (unchanged)
   3. COption C: 3 times
   4. DOption D: 9 times

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   Correct answer: (B) 1 time (unchanged)

   Explanation

   For a paramagnetic substance, Curie's law gives M ∝ H/T. If both magnetic field H and temperature T are tripled, then M' ∝ (3H)/(3T) = H/T. Therefore the intensity of magnetization remains unchanged.

9. Question 9 (AIPMT 2006)

   AIPMT 2006EasyMagnetic Properties of Materials

   Above Curie temperature:

   1. AOption A: A ferromagnetic substance becomes paramagnetic
   2. BOption B: A paramagnetic substance becomes diamagnetic
   3. COption C: A diamagnetic substance becomes paramagnetic
   4. DOption D: A paramagnetic substance becomes ferromagnetic

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   Correct answer: (A) A ferromagnetic substance becomes paramagnetic

   Explanation

   Above the Curie temperature, thermal agitation destroys the spontaneous alignment of magnetic domains in a ferromagnetic material. As a result, the material behaves as a paramagnetic substance. Hence option (A) is correct.

10. Question 10 (AIPMT 2005)

    AIPMT 2005EasyMagnetic Properties of Materials

    If the magnetic dipole moment of an atom of diamagnetic material, paramagnetic material and ferromagnetic material is denoted by $\mu_d$, $\mu_p$ and $\mu_f$ respectively, then

    1. AOption A: $\mu_d \ne 0$ and $\mu_f \ne 0$
    2. BOption B: $\mu_p = 0$ and $\mu_f \ne 0$
    3. COption C: $\mu_d = 0$ and $\mu_p \ne 0$
    4. DOption D: $\mu_d \ne 0$ and $\mu_p = 0$

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    Correct answer: (C) $\mu_d = 0$ and $\mu_p \ne 0$

    Explanation

    Diamagnetic substances have zero resultant magnetic dipole moment per atom because all electron magnetic moments are paired and cancel each other. Therefore $\mu_d = 0$. Paramagnetic substances have atoms with unpaired electrons, so each atom possesses a non-zero magnetic dipole moment. Therefore $\mu_p \ne 0$. Hence option A is correct.