Hydrogen NEET PYQs (2005–2026) with Solutions

10 solved Hydrogen PYQs

Real NEET and AIPMT questions from this chapter, newest first. Try each one, then open the answer and the step-by-step explanation.

1. Question 1 (NEET 2026)

   NEET 2026EasyIndustrial preparation of hydrogen (steam reforming)

   Methane reacts with steam at 1273 K in the presence of nickel catalyst to form:

   1. AOption A: CO and H₂O
   2. BOption B: CO₂ and H₂
   3. COption C: CO and H₂
   4. DOption D: CO₂ and H₂O

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   Correct answer: (C) CO and H₂

   Explanation

   Steam reforming reaction: CH₄ + H₂O → CO + 3H₂ (Ni catalyst, 1273 K). Hence option (C) is correct.

2. Question 2 (NEET 2024)

   NEET 2024EasyMohr's Salt

   During the preparation of Mohr’s salt solution (Ferrous ammonium sulphate), which of the following is added to prevent hydrolysis of Fe²⁺ ion?

   1. AOption A: dilute nitric acid
   2. BOption B: dilute sulphuric acid
   3. COption C: dilute hydrochloric acid
   4. DOption D: concentrated sulphuric acid

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   Correct answer: (B) dilute sulphuric acid

   Explanation

   Mohr’s salt solution is prepared in the presence of dilute sulphuric acid to prevent hydrolysis and oxidation of Fe²⁺ ions. Hence, option (B) is correct.

3. Question 3 (NEET 2023)

   NEET 2023MediumLiquid Ammonia

   Given below are two statements : one is labelled as Assertion A and the other is labelled as Reason R : Assertion A : Metallic sodium dissolves in liquid ammonia giving a deep blue solution, which is paramagnetic. Reason R : The deep blue solution is due to the formation of amide. In the light of above statements, choose the correct answer from the options given below:

   1. AOption A: Both A and R are true and R is the correct explanation of A.
   2. BOption B: Both A and R are true but R is NOT the correct explanation of A.
   3. COption C: A is true but R is false.
   4. DOption D: A is false but R is true.

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   Correct answer: (C) A is true but R is false.

   Explanation

   Metallic sodium dissolves in liquid ammonia to produce solvated electrons, giving a deep blue paramagnetic solution. The colour and paramagnetism are due to these solvated electrons, not because of amide formation. Therefore, Assertion A is true but Reason R is false.

4. Question 4 (NEET 2023)

   NEET 2023MediumUses of Hydrogen

   Which of the following statements are NOT correct? A. Hydrogen is used to reduce heavy metal oxides to metals. B. Heavy water is used to study reaction mechanism. C. Hydrogen is used to make saturated fats from oils. D. The H-H bond dissociation enthalpy is lowest as compared to a single bond between two atoms of any element. E. Hydrogen reduces oxides of metals that are more active than iron. Choose the most appropriate answer from the options given below :

   1. AOption A: B, C, D, E only
   2. BOption B: B, D only
   3. COption C: D, E only
   4. DOption D: A, B, C only

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   Correct answer: (C) D, E only

   Explanation

   Evaluate each statement: A. Correct — Hydrogen reduces some metal oxides. B. Correct — Heavy water is used in studying reaction mechanisms. C. Correct — Hydrogenation converts oils into saturated fats. D. Incorrect — H-H bond dissociation enthalpy is not the lowest. E. Incorrect — Hydrogen reduces oxides of metals less active than iron. Thus, D and E are NOT correct. Therefore, option (C) is correct.

5. Question 5 (NEET 2022)

   NEET 2022MediumStructure and Bonding in Diborane

   Which of the following statement is not correct about diborane?

   1. AOption A: Both the Boron atoms are sp² hybridised
   2. BOption B: There are two 3-centre-2-electron bonds
   3. COption C: The four terminal B-H bonds are two centre two electron bonds
   4. DOption D: The four terminal Hydrogen atoms and the two Boron atoms lie in one plane

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   Correct answer: (A) Both the Boron atoms are sp² hybridised

   Explanation

   In diborane (B₂H₆), boron atoms are approximately sp³ hybridised, not sp². Diborane contains two 3-centre-2-electron bridge bonds and four normal B-H bonds. Hence option (A) is incorrect and is the correct answer.

6. Question 6 (NEET 2022)

   NEET 2022MediumClassification and Nature of Hydrides

   Match List-I with List-II: Choose the correct answer from the options given below

   1. AOption A: (a)-(ii), (b)-(iii), (c)-(iv), (d)-(i)
   2. BOption B: (a)-(iv), (b)-(i), (c)-(ii), (d)-(iii)
   3. COption C: (a)-(iii), (b)-(i), (c)-(ii), (d)-(iv)
   4. DOption D: (a)-(i), (b)-(ii), (c)-(iv), (d)-(iii)

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   Correct answer: (B) (a)-(iv), (b)-(i), (c)-(ii), (d)-(iii)

   Explanation

   Matching: MgH₂ → Ionic (iv) GeH₄ → Electron precise (i) B₂H₆ → Electron deficient (ii) HF → Electron rich (iii) Hence: (a)-(iv), (b)-(i), (c)-(ii), (d)-(iii) Therefore option (B) is correct.

7. Question 7 (NEET 2022)

   NEET 2022MediumHydrides of Group 16 Elements

   Given below are two statements: Statement I: The boiling points of the following hydrides of group 16 elements increase in the order: H₂O < H₂S < H₂Se < H₂Te Statement II: The boiling points of these hydrides increase with increase in molar mass. Choose the most appropriate answer.

   1. AOption A: Statement I is incorrect but Statement II is correct
   2. BOption B: Both Statement I and Statement II are correct
   3. COption C: Both Statement I and Statement II are incorrect
   4. DOption D: Statement I is correct but Statement II is incorrect

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   Correct answer: (C) Both Statement I and Statement II are incorrect

   Explanation

   Actual boiling point order is: H₂S < H₂Se < H₂Te < H₂O because H₂O shows strong hydrogen bonding. Hence Statement I is incorrect. Statement II is generally correct for H₂S, H₂Se and H₂Te due to increasing molar mass. Therefore option (A) is correct.

8. Question 8 (NEET 2021)

   NEET 2021EasyIsotopes of Hydrogen

   Tritium, a radioactive isotope of hydrogen, emits which of the following particles?

   1. AOption A: Neutron (n)
   2. BOption B: $Beta (β^−)$
   3. COption C: Alpha (α)
   4. DOption D: Gamma (γ)

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   Correct answer: (B) $Beta (β^−)$

   Explanation

   Tritium (³H) undergoes beta decay and emits β⁻ particles.

9. Question 9 (NEET 2020)

   NEET 2020EasyHydrogen Peroxide, Boranes and Water Hardness

   Match the following and identify the correct option.

   1. AOption A: (a) (iii) (b) (i) (c) (ii) (d) (iv)
   2. BOption B: (a) (iii) (b) (ii) (c) (i) (d) (iv)
   3. COption C: (a) (iii) (b) (iv) (c) (ii) (d) (i)
   4. DOption D: (a) (i) (b) (iii) (c) (ii) (d) (iv)

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   Correct answer: (A) (a) (iii) (b) (i) (c) (ii) (d) (iv)

   Explanation

   CO + H₂ is called synthesis gas. Temporary hardness of water is caused by bicarbonates of calcium and magnesium. Diborane (B₂H₆) is an electron deficient hydride. Hydrogen peroxide has a non-planar structure. Hence the correct matching is (iii), (i), (ii), (iv).

10. Question 10 (NEET 2018)

    NEET 2018MediumIonic and Covalent Hydrides

    Among CaH₂, BeH₂, BaH₂, the order of ionic character is

    1. AOption A: BeH₂ < CaH₂ < BaH₂
    2. BOption B: CaH₂ < BeH₂ < BaH₂
    3. COption C: BaH₂ < BeH₂ < CaH₂
    4. DOption D: BeH₂ < BaH₂ < CaH₂

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    Correct answer: (A) BeH₂ < CaH₂ < BaH₂

    Explanation

    In group 2 hydrides, ionic character increases down the group because metallic character increases down the group. BeH₂ is predominantly covalent, while BaH₂ is the most ionic. Therefore, the order of ionic character is: $$\mathrm{BeH_2 < CaH_2 < BaH_2}$$