NEET Chemistry · Flashcards

Chemical Thermodynamics Flashcards for NEET — 20 cards

This deck has 20 flashcards on Chemical Thermodynamics for NEET Chemistry, from NCERT Class 11. It follows the NCERT chapter Thermodynamics.

Energy dynamics of chemical reactions with this essentials, covering the Laws of Thermodynamics, enthalpy calculations, entropy, and the ultimate criteria for spontaneity.

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First 8 of 20 Chemical Thermodynamics flashcards

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  1. Card 1 of 20

    How do you calculate the Enthalpy of a Reaction (ΔrH\Delta_r H) using Enthalpies of Formation vs using Bond Enthalpies?

    Hint: Watch the order! Bond energy calculation is Reactants - Products (Energy absorbed to break bonds - Energy released forming bonds).

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    Answer

    Using Formation: ΔrH=∑ΔfH∘(Products)−∑ΔfH∘(Reactants)\Delta_r H = \sum \Delta_f H^\circ(\text{Products}) - \sum \Delta_f H^\circ(\text{Reactants}) Using Bond Energy: ΔrH=∑BE(Reactants)−∑BE(Products)\Delta_r H = \sum BE(\text{Reactants}) - \sum BE(\text{Products})

  2. Card 2 of 20

    What kind of property results from the ratio of two extensive properties?

    Hint: Extensive ÷ Extensive = Intensive

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    Answer

    An intensive property. Example: Mass (extensive) / Volume (extensive) = Density (intensive).

  3. Card 3 of 20

    Identify which of the following are path functions and which are state functions: Internal Energy (UU), Heat (qq), Work (ww), Enthalpy (HH), Entropy (SS).

    Hint: State functions only care about initial and final states, not how you got there.

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    Answer

    Path functions: Heat (qq) and Work (ww). State functions: Internal Energy (UU), Enthalpy (HH), Entropy (SS). (Also P,V,T,GP, V, T, G)

  4. Card 4 of 20

    Write the mathematical expression for the First Law of Thermodynamics and define its terms.

    Hint: Law of conservation of energy.

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    Answer

    ΔU=q+w\Delta U = q + w Where ΔU\Delta U is the change in internal energy, qq is heat, and ww is work.

  5. Card 5 of 20

    According to the IUPAC sign convention, what are the signs for heat absorbed by the system and work done BY the system (expansion)?

    Hint: Energy entering the system is positive (+). Energy leaving is negative (-).

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    Answer

  6. Card 6 of 20

    What is the work done (ww) during the free expansion of an ideal gas in a vacuum?

    Hint: No opposing force = no work done.

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    Answer

    w=0w = 0. Since the external pressure (PextP_{ext}) is zero in a vacuum, work w=−PextΔV=0w = -P_{ext}\Delta V = 0.

  7. Card 7 of 20

    State the formula for the maximum work done during the reversible isothermal expansion of an ideal gas.

    Hint: Reversible work is always the maximum magnitude of work.

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    Answer

    wrev=−2.303nRTlog⁡(V2V1)w_{rev} = -2.303 nRT \log \left(\frac{V_2}{V_1}\right) OR wrev=−2.303nRTlog⁡(P1P2)w_{rev} = -2.303 nRT \log \left(\frac{P_1}{P_2}\right)

  8. Card 8 of 20

    How is the change in Enthalpy (ΔH\Delta H) related to the change in Internal Energy (ΔU\Delta U) for a reaction involving gases?

    Hint: Only count the species in the (g) state!

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    Answer

    ΔH=ΔU+ΔngRT\Delta H = \Delta U + \Delta n_g RT Where Δng=(moles of gaseous products)−(moles of gaseous reactants)\Delta n_g = (\text{moles of gaseous products}) - (\text{moles of gaseous reactants}).

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