NEET Physics · Flashcards

Electromagnetic Waves Flashcards for NEET — 20 cards

This deck has 20 flashcards on Electromagnetic Waves for NEET Physics, from NCERT Class 12.

Electromagnetic Waves & Capacitance for NEET: High-yield flashcards covering the spectrum, dielectric effects, capacitor networks, and energy storage formulas

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First 8 of 20 Electromagnetic Waves flashcards

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  1. Card 1 of 20

    What is the formula for the speed of an EM wave in a vacuum and in a material medium?

    Hint: Depends on permeability (μ\mu) and permittivity (ϵ\epsilon).

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    Answer

    Vacuum: c=1μ0ϵ0c = \frac{1}{\sqrt{\mu_0 \epsilon_0}} \nMedium: v=1μϵv = \frac{1}{\sqrt{\mu \epsilon}}

  2. Card 2 of 20

    What is the relationship between the amplitudes of the Electric (E0E_0) and Magnetic (B0B_0) fields in an EM wave?

    Hint: The ratio of their magnitudes equals the speed of light.

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    Answer

    Because c=3×108c = 3 \times 10^8 m/s, the electric field amplitude is much larger than the magnetic field amplitude.

  3. Card 3 of 20

    Define the concept and write the formula for Displacement Current.

    Hint: Maxwell's missing puzzle piece for Ampere's Law.

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    Answer

    Id=ϵ0dΦEdtI_d = \epsilon_0 \frac{d\Phi_E}{dt}

    Where ΦE\Phi_E is the electric flux.

  4. Card 4 of 20

    State the Ampere-Maxwell Law.

    Hint: Generalization of Ampere's circuital law.

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    Answer

    ∮B⃗⋅dl⃗=μ0(Ic+Id)=μ0(Ic+ϵ0dΦEdt)\oint \vec{B} \cdot d\vec{l} = \mu_0 (I_c + I_d) = \mu_0 (I_c + \epsilon_0 \frac{d\Phi_E}{dt})

  5. Card 5 of 20

    What is the primary source of Electromagnetic Waves?

    Hint: Charges at rest produce E-fields; steady currents produce B-fields. What produces both?

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    Answer

    An accelerating (or oscillating) electric charge.

  6. Card 6 of 20

    How do you determine the direction of propagation of an EM wave?

    Hint: Poynting vector direction.

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    Answer

  7. Card 7 of 20

    How is the total average energy density of an EM wave shared between the electric and magnetic fields?

    Hint: Symmetry in energy.

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    Answer

    Utotal=UE+UB=12ϵ0Erms2+12Brms2μ0U_{total} = U_E + U_B = \frac{1}{2}\epsilon_0 E_{rms}^2 + \frac{1}{2}\frac{B_{rms}^2}{\mu_0}

  8. Card 8 of 20

    What is the momentum (pp) transferred by an EM wave of energy UU to a perfectly absorbing surface?

    Hint: For a perfectly reflecting surface, it would be 2U/c2U/c.

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    Answer

    p=Ucp = \frac{U}{c}

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