NEET Physics · Flashcards
This deck has 22 flashcards on Properties of Solids & Fluids for NEET Physics, from NCERT Class 11. It covers the NCERT chapters Mechanical Properties of Solids, Mechanical Properties of Fluids and Thermal Properties of Matter.
A high-yield NEET flashcard deck covering the mechanical properties of solids, fluid statics and dynamics, surface tension, and thermal physics, complete with core formulas and visual aids.
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Card 1 of 22
What is the formula for the excess pressure inside a Liquid Drop vs. a Soap Bubble?
Hint: Pressure is always higher on the concave side of the liquid surface.
Answer
Liquid Drop (1 surface): ΔP = 2S / R Soap Bubble (2 surfaces): ΔP = 4S / R
Card 2 of 22
How does the Angle of Contact (θ) determine the shape of the meniscus and capillary action?
Hint: Depends on cohesive vs. adhesive forces.
Answer
θ < 90° (Rises/Concave) vs θ > 90° (Falls/Convex)
Card 3 of 22
Write Jurin's Law for the height (h) of capillary rise.
Hint: If the tube is insufficiently long, the liquid will not overflow; instead, its radius of curvature changes.
Answer
h = (2S cosθ) / (r ρ g) Where S=surface tension, θ=angle of contact, r=radius of tube, ρ=density.
Card 4 of 22
What is the relationship between the coefficients of linear (α), areal (β), and volume (γ) thermal expansion?
Hint: Applicable for isotropic solid materials.
Answer
α : β : γ = 1 : 2 : 3 Meaning: β = 2α, and γ = 3α.
Card 5 of 22
Differentiate between Specific Heat Capacity (c) and Latent Heat (L).
Hint: During melting or boiling, temperature remains constant.
Answer
Specific Heat (c): Heat required to raise the temp of 1 kg of substance by 1°C. Q = mcΔT (Temp changes, State constant). Latent Heat (L): Heat required to change the state of 1 kg of substance. Q = mL (State changes, Temp constant).
Card 6 of 22
State the Principle of Calorimetry.
Hint: Based on the Law of Conservation of Energy.
Answer
In an isolated system, Heat Lost by hot bodies = Heat Gained by cold bodies.
Card 7 of 22
What is the formula for the rate of heat flow (dQ/dt) through a solid rod via conduction?
Hint: Analogous to Ohm's Law (I = V / R). Thermal resistance R_th = L / (KA).
Answer
Rate of heat flow is analogous to electric current.
Card 8 of 22
State the Stefan-Boltzmann Law.
Hint: For a non-blackbody, Power P = e σ A T⁴ (where e is emissivity).
Answer
The total energy radiated per unit surface area per unit time by a blackbody is directly proportional to the fourth power of its absolute temperature. E = σ T⁴
14 more cards in this deck
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