NEET Physics · Flashcards
This deck has 15 flashcards on Gravitation for NEET Physics, from NCERT Class 11.
A comprehensive, high-yield flashcard deck featuring core concepts, formulas, and visual diagrams to master Class 11 Gravitation for NEET.
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Card 1 of 15
State Newton's Universal Law of Gravitation.
Hint: G = 6.67 × 10⁻¹¹ N m² / kg²
Answer
Every particle attracts every other particle with a force directly proportional to the product of their masses and inversely proportional to the square of the distance between them: F = G(m₁ × m₂) / r².
Card 2 of 15
State Kepler's First Law (Law of Orbits).
Hint: Not a perfect circle!
Answer
All planets move in elliptical orbits with the Sun situated at one of the foci of the ellipse.
Card 3 of 15
State Kepler's Second Law (Law of Areas) and its underlying conservation principle.
Hint: Planets move faster when closest to the sun (perihelion).
Answer
The line joining the planet to the sun sweeps out equal areas in equal time intervals. (Constant areal velocity). Principle: Conservation of Angular Momentum.
Card 4 of 15
State Kepler's Third Law (Law of Periods).
Hint: Formula: T² = (4π² / GM) * a³
Answer
The square of the time period (T) of a planet's revolution is directly proportional to the cube of the semi-major axis (a) of its elliptical orbit: T² ∝ a³.
Card 5 of 15
What is the formula for acceleration due to gravity (g) on the surface of the Earth?
Hint: Independent of the falling object's mass (m).
Answer
g = GM / R², where M is Earth's mass and R is Earth's radius.
Card 6 of 15
How does acceleration due to gravity (g) vary with altitude (h)?
Hint: g decreases as you go higher.
Answer
Exact formula: g' = g / (1 + h/R)². Approximation (for h << R): g' ≈ g(1 - 2h/R).
Card 7 of 15
How does acceleration due to gravity (g) vary with depth (d)?
Hint: g decreases linearly with depth. At the center of the Earth (d = R), g' = 0.
Answer
g' = g(1 - d/R).
Card 8 of 15
Draw the graph showing the variation of 'g' with distance 'r' from the center of the Earth.
Hint: Linear increase from center, then an exponential curve downward from the surface.
Answer
Inside (r < R): g ∝ r Outside (r > R): g ∝ 1/r²
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