Optics Flashcards for NEET — 20 cards

First 8 of 20 Optics flashcards

Read the question, answer it in your head, then open the answer to check yourself.

1. Card 1 of 20

   State the spherical mirror formula and the expression for linear magnification ($m$).

   Hint: Remember the negative sign in the magnification formula for mirrors!

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   Answer

   Formula: $\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$. Magnification: $m = -\frac{v}{u} = \frac{h_i}{h_o}$.

2. Card 2 of 20

   Write the formula relating object distance ($u$), image distance ($v$), and radius of curvature ($R$).

   Hint: $n_1$ is the medium where the object is placed, $n_2$ is the other medium.

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   Answer

   $\frac{n_2}{v} - \frac{n_1}{u} = \frac{n_2 - n_1}{R}$

3. Card 3 of 20

   Write the Lens Maker's Formula.

   Hint: Used by opticians to design lenses of a desired focal length.

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   Answer

   Where $n_{21} = \frac{n_2}{n_1}$ is the refractive index of the lens relative to the surrounding medium.

4. Card 4 of 20

   State the Thin Lens Formula and its magnification ($m$).

   Hint: Notice the sign difference compared to the mirror formula.

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   Answer

   Formula: $\frac{1}{v} - \frac{1}{u} = \frac{1}{f}$. Magnification: $m = \frac{v}{u}$.

5. Card 5 of 20

   How do you calculate Equivalent Power ($P$), Focal Length ($F$), and Magnification ($m$) for thin lenses in contact?

   Hint: Powers add up, magnifications multiply.

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   Answer

   $P_{eq} = P_1 + P_2 + ...$ \n$\frac{1}{F_{eq}} = \frac{1}{f_1} + \frac{1}{f_2} + ...$ \n$m_{eq} = m_1 \times m_2 \times ...$

6. Card 6 of 20

   What is the formula for the refractive index ($\mu$) of a prism at the angle of minimum deviation ($\delta_m$)?

   Hint: At minimum deviation, angle of incidence ($i$) = angle of emergence ($e$), and the refracted ray is parallel to the base.

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   Answer

   Where $A$ is the angle of the prism.

7. Card 7 of 20

   What is the formula for the magnifying power of a Compound Microscope in normal adjustment (image at infinity)?

   Hint: Product of objective and eyepiece magnifications.

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   Answer

   $L$ = tube length, $D$ = least distance of distinct vision (25 cm), $f_o$ = focal length of objective, $f_e$ = focal length of eyepiece.

8. Card 8 of 20

   Write the magnifying power and tube length formula for an Astronomical Telescope in normal adjustment.

   Hint: Objective lens is much larger than the eyepiece here.

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   Answer

   Magnification: $m = \frac{f_o}{f_e}$ \nTube Length: $L = f_o + f_e$