NEET Physics · Flashcards

System of Particles - Rotational Motion Flashcards for NEET — 22 cards

This deck has 22 flashcards on System of Particles - Rotational Motion for NEET Physics, from NCERT Class 11. It follows the NCERT chapter System of Particles and Rotational Motion.

A comprehensive NEET flashcard deck detailing Center of Mass, Vector Cross Products, Inertial Theorems, and pure Rolling Mechanics with essential shortcut formulas and visual aids.

The first 8 cards are below with their answers. Sign up free to study all 22 cards with spaced repetition.

First 8 of 22 System of Particles - Rotational Motion flashcards

Read the question, answer it in your head, then open the answer to check yourself.

  1. Card 1 of 22

    What is the formula for the Center of Mass (RcmR_{cm}) of a discrete multi-particle system?

    Hint: The position of the CoM is independent of the coordinate system chosen, but its coordinates depend on the origin.

    Show answer

    Answer

    Rcm=m1r1+m2r2+...+mnrnm1+m2+...+mn=∑miri∑miR_{cm} = \frac{m_1 r_1 + m_2 r_2 + ... + m_n r_n}{m_1 + m_2 + ... + m_n} = \frac{\sum m_i r_i}{\sum m_i}

  2. Card 2 of 22

    How do you calculate the Center of Mass of a body with a portion removed (Cavity Problems)?

    Hint: Treat the removed portion as a 'negative mass'.

    Show answer

    Answer

    xcm=A1x1−A2x2A1−A2x_{cm} = \frac{A_1 x_1 - A_2 x_2}{A_1 - A_2} Where A1A_1 is the area/volume of the complete body and A2A_2 is the area/volume of the removed part.

  3. Card 3 of 22

    What happens to the trajectory of the Center of Mass of a projectile (like a firecracker) if it explodes in mid-air?

    Hint: Only external forces (FextF_{ext}) can change the acceleration of the CoM.

    Show answer

    Answer

    The Center of Mass continues to move along the original parabolic trajectory. Internal forces of explosion do not affect the motion of the CoM.

  4. Card 4 of 22

    What is the vector relation between linear velocity (vv) and angular velocity (ω\omega)?

    Hint: Order matters! It is NOT r⃗×ω⃗\vec{r} \times \vec{\omega}.

    Show answer

    Answer

    v⃗=ω⃗×r⃗\vec{v} = \vec{\omega} \times \vec{r}

  5. Card 5 of 22

    Define Torque (τ\tau) and state its vector formula.

    Hint: Maximum torque occurs when the force is applied perpendicular to the position vector (θ=90∘\theta = 90^\circ).

    Show answer

    Answer

    τ⃗=r⃗×F⃗\vec{\tau} = \vec{r} \times \vec{F}

  6. Card 6 of 22

    Define Angular Momentum (LL) for a particle and its relation to linear momentum (pp).

    Hint: For a rigid body rotating about a fixed axis, L=IωL = I\omega.

    Show answer

    Answer

    Angular momentum is the moment of linear momentum. L⃗=r⃗×p⃗\vec{L} = \vec{r} \times \vec{p} Magnitude: L=mvrsin⁡(θ)L = mvr \sin(\theta)

  7. Card 7 of 22

    State the relationship between Torque and Angular Momentum (Newton's Second Law for Rotation).

    Hint: Analogous to F⃗=dp⃗dt\vec{F} = \frac{d\vec{p}}{dt}.

    Show answer

    Answer

    The net external torque acting on a system is equal to the rate of change of its angular momentum. τ⃗ext=dL⃗dt\vec{\tau}_{ext} = \frac{d\vec{L}}{dt}

  8. Card 8 of 22

    State the Law of Conservation of Angular Momentum.

    Hint: Example: An ice skater spinning faster when pulling their arms in (decreasing II increases ω\omega).

    Show answer

    Answer

    If the net external torque on a system is zero (τext=0\tau_{ext} = 0), the total angular momentum remains constant. L⃗initial=L⃗final\vec{L}_{initial} = \vec{L}_{final} or I1ω1=I2ω2I_1\omega_1 = I_2\omega_2.

14 more cards in this deck

Sign up free to study all 22 cards with spaced repetition.

Sign up free

More Physics flashcard decks

All 20 Physics decks