NEET Physics · Flashcards

Atoms & Nuclei Flashcards for NEET — 20 cards

This deck has 20 flashcards on Atoms & Nuclei for NEET Physics, from NCERT Class 12. It covers the NCERT chapters Atoms and Nuclei.

Journey into the subatomic world: Master Rutherford's scattering, the Bohr model, energy transitions, mass defect, binding energy, and nuclear reactions with high-yield formulas and concepts.

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First 8 of 20 Atoms & Nuclei flashcards

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  1. Card 1 of 20

    What was the main conclusion of the Rutherford Alpha-particle scattering experiment?

    Hint: Why did most alpha particles pass straight through?

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    Answer

  2. Card 2 of 20

    What is the Impact Parameter (bb)?

    Hint: If b=0b=0, the scattering angle is 180 degrees (head-on collision).

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    Answer

    The perpendicular distance of the initial velocity vector of the alpha particle from the central axis of the nucleus.

  3. Card 3 of 20

    State Bohr's Quantization Condition for angular momentum.

    Hint: Angular momentum is an integral multiple of h/2πh/2\pi.

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    Answer

    Where n=1,2,3...n = 1, 2, 3... (principal quantum number).

  4. Card 4 of 20

    How does the radius of the nthn^{th} Bohr orbit (rnr_n) depend on the principal quantum number (nn) and atomic number (ZZ)?

    Hint: For hydrogen (Z=1,n=1Z=1, n=1), r1=0.529 A˚r_1 = 0.529 \text{ \AA} (Bohr radius).

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    Answer

    rn∝n2Zr_n \propto \frac{n^2}{Z}

  5. Card 5 of 20

    Write the formula for the total energy of an electron in the nthn^{th} orbit of a hydrogen-like atom.

    Hint: The negative sign indicates the electron is bound to the nucleus.

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    Answer

    En=−13.6Z2n2 eVE_n = -13.6 \frac{Z^2}{n^2} \text{ eV}

  6. Card 6 of 20

    What is the relationship between Kinetic Energy (KK), Potential Energy (UU), and Total Energy (EE) of an electron in an orbit?

    Hint: Total energy is negative. Kinetic is always positive. Potential is twice the total.

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    Answer

    K=−EK = -E and U=2EU = 2E

  7. Card 7 of 20

    Match the Hydrogen Spectrum series to their electromagnetic regions (Lyman, Balmer, Paschen).

    Hint: Transitions down to n=1,n=2,n=3n=1, n=2, n=3 respectively.

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  8. Card 8 of 20

    State the Rydberg formula for the wavelength of emitted light during an electron transition.

    Hint: RR is the Rydberg constant (≈1.097×107 m−1\approx 1.097 \times 10^7 \text{ m}^{-1}).

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    Answer

    1λ=RZ2(1n12−1n22)\frac{1}{\lambda} = R Z^2 \left(\frac{1}{n_1^2} - \frac{1}{n_2^2}\right)

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