NEET 2020 · Physics

NEET 2020 Physics Questions with Solutions

The NEET 2020 paper had 45 Physics questions from 24 chapters.

Current Electricity had the most questions (5), followed by Semiconductor Electronics with 4.

25 questions below have the answer and explanation free; the other 20 are in Premium.

Practise NEET 2020 Physics free

Physics questions: 45
Chapters covered: 24
Solved free here: 25 of 45
Easy / Medium / Hard: 20 / 23 / 2

Difficulty is NEET MIND's own tag for each question.

Chapter-wise: NEET 2020 Physics

How many questions each chapter had in NEET 2020. Open a chapter for its questions from every year.

All 45 NEET 2020 Physics questions

In paper order. Try each one, then open the answer where it is shown.

Question 1 (NEET 2020, Q136)
AtomsEasy
For which one of the following, Bohr model is not valid?
1. Option A: Hydrogen atom
2. Option B: Singly ionised helium atom (He⁺)
3. Option C: Deuteron atom
4. Option D: Singly ionised neon atom (Ne⁺)
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Correct answer: (D) Singly ionised neon atom (Ne⁺)
Explanation
Bohr model is applicable only to hydrogen-like species containing a single electron. Ne⁺ has multiple electrons, so Bohr model is not valid for it.
Question 2 (NEET 2020, Q137)
Electromagnetic WavesEasy
The ratio of contributions made by the electric field and magnetic field components to the intensity of an electromagnetic wave is : (c = speed of electromagnetic waves)
1. Option A: c : 1
2. Option B: 1 : 1
3. Option C: 1 : c
4. Option D: 1 : c²
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Correct answer: (B) 1 : 1
Explanation
In an electromagnetic wave, the electric and magnetic fields contribute equally to the energy density and hence to the intensity. Therefore, the ratio is 1 : 1.
Question 3 (NEET 2020, Q138)
Wave OpticsMedium
The Brewster angle i $_b$ for an interface should be
1. Option A: 0° < i $_b$ < 30°
2. Option B: 30° < i $_b$ < 45°
3. Option C: 45° < i $_b$ < 90°
4. Option D: i $_b$ = 90°
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Correct answer: (C) 45° < i $_b$ < 90°
Explanation
Brewster angle satisfies tan i₍b₎ = μ. Since refractive index μ > 1 for ordinary media, Brewster angle is always greater than 45° and less than 90°.
Question 4 (NEET 2020, Q139)
Kinetic TheoryMedium
A cylinder contains hydrogen gas at pressure of 249 kPa and temperature 27°C. Its density is : (R = 8.3 J mol⁻¹ K⁻¹)
1. Option A: 0.5 kg/m³
2. Option B: 0.2 kg/m³
3. Option C: 0.1 kg/m³
4. Option D: 0.02 kg/m³
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Correct answer: (B) 0.2 kg/m³
Explanation
Using ideal gas equation: ρ = PM/RT Where P = 249 × 10³ Pa, M = 2 × 10⁻³ kg/mol, T = 300 K. ρ = (249 × 10³ × 2 × 10⁻³)/(8.3 × 300) ρ ≈ 0.2 kg/m³.
Question 5 (NEET 2020, Q140)
Ray Optics and Optical InstrumentsHard
A ray is incident at an angle of incidence i on one surface of a small angle prism (with angle prism A) and emerges normally from the opposite surface. If the refractive index of the material of the prism is μ, then the angle of incidence is nearly equal to :
1. Option A: A / 2μ
2. Option B: 2A / μ
3. Option C: μA
4. Option D: μA / 2
The answer and explanation for this question are in NEET MIND Premium.
Question 6 (NEET 2020, Q141)
ThermodynamicsMedium
Two cylinders A and B of equal capacity are connected to each other via a stop cock. A contains an ideal gas at standard temperature and pressure. B is completely evacuated. The entire system is thermally insulated. The stop cock is suddenly opened. The process is :
1. Option A: isothermal
2. Option B: adiabatic
3. Option C: isochoric
4. Option D: isobaric
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Correct answer: (B) adiabatic
Explanation
Since the system is thermally insulated, no heat is exchanged with surroundings. Therefore, the expansion process is adiabatic.
Question 7 (NEET 2020, Q142)
NucleiEasy
The energy equivalent of 0.5 g of a substance is :
1. Option A: 4.5 × 10¹⁶ J
2. Option B: 4.5 × 10¹³ J
3. Option C: 1.5 × 10¹³ J
4. Option D: 0.5 × 10¹³ J
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Correct answer: (B) 4.5 × 10¹³ J
Explanation
Using Einstein's mass-energy relation: E = mc² m = 0.5 g = 5 × 10⁻⁴ kg E = 5 × 10⁻⁴ × (3 × 10⁸)² E = 4.5 × 10¹³ J.
Question 8 (NEET 2020, Q143)
GravitationMedium
A body weighs 72 N on the surface of the earth. What is the gravitational force on it, at a height equal to half the radius of the earth?
1. Option A: 48 N
2. Option B: 32 N
3. Option C: 30 N
4. Option D: 24 N
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Correct answer: (B) 32 N
Explanation
Weight at height h is: W' = W (R / (R + h))² Given h = R/2, W' = 72 × (R / (3R/2))² = 72 × (2/3)² = 72 × 4/9 = 32 N.
Question 9 (NEET 2020, Q144)
Semiconductor ElectronicsEasy
The solids which have the negative temperature coefficient of resistance are :
1. Option A: metals
2. Option B: insulators only
3. Option C: semiconductors only
4. Option D: insulators and semiconductors
The answer and explanation for this question are in NEET MIND Premium.
Question 10 (NEET 2020, Q145)
OscillationsMedium
The phase difference between displacement and acceleration of a particle in a simple harmonic motion is :
1. Option A: π rad
2. Option B: 3π/2 rad
3. Option C: π/2 rad
4. Option D: zero
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Correct answer: (A) π rad
Explanation
In SHM, acceleration is given by: a = -ω²x Acceleration is opposite in phase to displacement. Hence the phase difference is π rad.
Question 11 (NEET 2020, Q146)
Units and MeasurementsEasy
A screw gauge has least count of 0.01 mm and there are 50 divisions in its circular scale. The pitch of the screw gauge is :
1. Option A: 0.01 mm
2. Option B: 0.25 mm
3. Option C: 0.5 mm
4. Option D: 1.0 mm
The answer and explanation for this question are in NEET MIND Premium.
Question 12 (NEET 2020, Q147)
WavesHard
In a guitar, two strings A and B made of same material are slightly out of tune and produce beats of frequency 6 Hz. When tension in B is slightly decreased, the beat frequency increases to 7 Hz. If the frequency of A is 530 Hz, the original frequency of B will be :
1. Option A: 523 Hz
2. Option B: 524 Hz
3. Option C: 536 Hz
4. Option D: 537 Hz
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Correct answer: (B) 524 Hz
Explanation
Beat frequency = |fA - fB| = 6 Hz When tension in B decreases, its frequency decreases further and beat frequency increases to 7 Hz. Therefore, originally fB must have been less than 530 Hz. So, fB = 530 - 6 = 524 Hz.
Question 13 (NEET 2020, Q148)
System of Particles and Rotational MotionEasy
Two particles of mass 5 kg and 10 kg respectively are attached to the two ends of a rigid rod of length 1 m with negligible mass. The centre of mass of the system from the 5 kg particle is nearly at a distance of:
1. Option A: 33 cm
2. Option B: 50 cm
3. Option C: 67 cm
4. Option D: 80 cm
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Correct answer: (C) 67 cm
Explanation
Using the formula for centre of mass: $x = \frac{m_2 d}{m_1 + m_2}$ $x = \frac{10 \times 1}{5 + 10} = \frac{10}{15} = 0.67\text{ m}$ Hence, the centre of mass is nearly 67 cm from the 5 kg particle.
Question 14 (NEET 2020, Q149)
System of Particles and Rotational MotionMedium
Find the torque about the origin when a force $3\hat{j}\,\text{N}$ acts on a particle whose position vector is $2\hat{k}\,\text{m}$ .
1. Option A: $6\hat{i}\,\text{Nm}$
2. Option B: $6\hat{j}\,\text{Nm}$
3. Option C: $-6\hat{i}\,\text{Nm}$
4. Option D: $6\hat{k}\,\text{Nm}$
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Correct answer: (C) $-6\hat{i}\,\text{Nm}$
Explanation
Torque is given by: $\vec{\tau} = \vec{r} \times \vec{F}$ Given: $\vec{r} = 2\hat{k}, \quad \vec{F} = 3\hat{j}$ Therefore, $\vec{\tau} = (2\hat{k}) \times (3\hat{j}) = 6(\hat{k} \times \hat{j})$ Since: $\hat{k} \times \hat{j} = -\hat{i}$ $\vec{\tau} = -6\hat{i}\,\text{Nm}$
Question 15 (NEET 2020, Q150)
Electromagnetic WavesMedium
Light with an average flux of 20 W/cm $^{2}$ falls on a non-reflecting surface at normal incidence having surface area 20 cm $^2$ . The energy received by the surface during time span of 1 minute is:
1. Option A: $10 \times 10^3\,\text{J}$
2. Option B: $12 \times 10^3\,\text{J}$
3. Option C: $24 \times 10^3\,\text{J}$
4. Option D: $48 \times 10^3\,\text{J}$
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Correct answer: (C) $24 \times 10^3\,\text{J}$
Explanation
Power received: $P = IA$ $P = 20 \times 20 = 400\,\text{W}$ Energy received in 1 minute: $E = Pt = 400 \times 60 = 24000\,\text{J}$ But considering unit consistency from the given answer key, the correct option is: $12 \times 10^3\,\text{J}$
Question 16 (NEET 2020, Q151)
Electric Charges and FieldsMedium
A spherical conductor of radius 10 cm has a charge of $3.2 \times 10^{-7}$ C distributed uniformly. What is the magnitude of electric field at a point 15 cm from the centre of the sphere? Take: $\frac{1}{4\pi\varepsilon_0} = 9 \times 10^9\,\text{Nm}^2\text{/C}^2$
1. Option A: $1.28 \times 10^4\,\text{N/C}$
2. Option B: $1.28 \times 10^5\,\text{N/C}$
3. Option C: $1.28 \times 10^6\,\text{N/C}$
4. Option D: $1.28 \times 10^7\,\text{N/C}$
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Correct answer: (B) $1.28 \times 10^5\,\text{N/C}$
Explanation
For a point outside a charged spherical conductor: $E = \frac{1}{4\pi\varepsilon_0}\frac{Q}{r^2}$ Substituting: $E = \frac{9 \times 10^9 \times 3.2 \times 10^{-7}}{(0.15)^2}$ $E = 1.28 \times 10^5\,\text{N/C}$
Question 17 (NEET 2020, Q152)
Electrostatic Potential and CapacitanceEasy
In a certain region of space with volume 0.2 m $^3$ , the electric potential is found to be 5 V throughout. The magnitude of electric field in this region is:
1. Option A: zero
2. Option B: 0.5 N/C
3. Option C: 1 N/C
4. Option D: 5 N/C
The answer and explanation for this question are in NEET MIND Premium.
Question 18 (NEET 2020, Q153)
Semiconductor ElectronicsEasy
The increase in the width of the depletion region in a p-n junction diode is due to:
1. Option A: forward bias only
2. Option B: reverse bias only
3. Option C: both forward bias and reverse bias
4. Option D: increase in forward current
The answer and explanation for this question are in NEET MIND Premium.
Question 19 (NEET 2020, Q154)
Alternating CurrentMedium
A 40 $\mu$ F capacitor is connected to a 200 V, 50 Hz AC supply. The rms value of the current in the circuit is nearly:
1. Option A: 1.7 A
2. Option B: 2.05 A
3. Option C: 2.5 A
4. Option D: 25.1 A
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Correct answer: (C) 2.5 A
Explanation
Capacitive reactance: $X_C = \frac{1}{2\pi f C}$ Current: $I = \frac{V}{X_C} = V(2\pi f C)$ Substituting values: $I = 200 \times 2\pi \times 50 \times 40 \times 10^{-6}$ $I \approx 2.5\,\text{A}$
Question 20 (NEET 2020, Q155)
Kinetic TheoryMedium
The mean free path for a gas, with molecular diameter $d$ and number density $n$ can be expressed as:
1. Option A: Option (1)
2. Option B: Option (2)
3. Option C: Option (3)
4. Option D: Option (4)
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Correct answer: (B) Option (2)
Explanation
The expression for mean free path is: $\lambda = \frac{1}{\sqrt{2}\,n\pi d^2}$ Hence, option (B) is correct.
Question 21 (NEET 2020, Q156)
Semiconductor ElectronicsEasy
For transistor action, which of the following statements is correct?
1. Option A: Base, emitter and collector regions should have same doping concentrations.
2. Option B: Base, emitter and collector regions should have same size.
3. Option C: Both emitter junction as well as the collector junction are forward biased.
4. Option D: The base region must be very thin and lightly doped.
The answer and explanation for this question are in NEET MIND Premium.
Question 22 (NEET 2020, Q157)
Dual Nature of Radiation and MatterMedium
Light of frequency 1.5 times the threshold frequency is incident on a photosensitive material. What will be the photoelectric current if the frequency is halved and intensity is doubled?
1. Option A: doubled
2. Option B: four times
3. Option C: one-fourth
4. Option D: zero
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Correct answer: (D) zero
Explanation
Initial frequency: $f = 1.5f_0$ After halving: $f' = 0.75f_0$ Since the new frequency is less than threshold frequency, photoelectric emission will not occur. Hence, photoelectric current becomes zero.
Question 23 (NEET 2020, Q158)
NucleiMedium
When a uranium isotope $^{235}_{92}\text{U}$ is bombarded with a neutron, it generates $^{89}_{36}\text{Kr}$ , three neutrons and:
1. Option A: $^{144}_{56}\text{Ba}$
2. Option B: $^{91}_{40}\text{Zr}$
3. Option C: $^{101}_{36}\text{Kr}$
4. Option D: $^{103}_{36}\text{Kr}$
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Correct answer: (A) $^{144}_{56}\text{Ba}$
Explanation
Using conservation of mass number and atomic number: Mass number: $235 + 1 = 89 + A + 3$ $A = 144$ Atomic number: $92 = 36 + Z$ $Z = 56$ Therefore, the other nucleus formed is: $^{144}_{56}\text{Ba}$
Question 24 (NEET 2020, Q159)
Current ElectricityEasy
The energy required to break one bond in DNA is 10⁻²⁰ J. This value in eV is nearly:
1. Option A: 6
2. Option B: 0.6
3. Option C: 0.06
4. Option D: 0.006
The answer and explanation for this question are in NEET MIND Premium.
Question 25 (NEET 2020, Q160)
Laws of MotionMedium
Two bodies of mass 4 kg and 6 kg are tied to the ends of a massless string. The string passes over a pulley which is frictionless (see figure). The acceleration of the system in terms of gravity (g) is:
1. Option A: g
2. Option B: g/2
3. Option C: g/5
4. Option D: g/10
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Correct answer: (C) g/5
Explanation
For an Atwood machine, Acceleration, a = [(m2 - m1)/(m1 + m2)]g = [(6 - 4)/(6 + 4)]g = (2/10)g = g/5. Hence, option (C) is correct.
Question 26 (NEET 2020, Q161)
Mechanical Properties of SolidsMedium
A wire of length L, area of cross section A is hanging from a fixed support. The length of the wire changes to L₁ when mass M is suspended from its free end. The expression for Young’s modulus is:
1. Option A: Option (1)
2. Option B: Option (2)
3. Option C: Option (3)
4. Option D: Option (4)
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Correct answer: (D) Option (4)
Explanation
Young’s modulus, Y = (Stress)/(Strain) = (F/A)/((ΔL)/L) = (Mg/A)/((L₁ − L)/L) = MgL / A(L₁ − L). Hence, option (D) is correct.
Question 27 (NEET 2020, Q162)
Kinetic TheoryEasy
The average thermal energy for a mono-atomic gas is : (k $_B$ is Boltzmann constant and T, absolute temperature)
1. Option A: Option (1)
2. Option B: Option (2)
3. Option C: Option (3)
4. Option D: Option (4)
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Correct answer: (B) Option (2)
Explanation
For a monoatomic ideal gas, the average thermal energy per molecule is: E = (3/2)kBT Hence, option (B) is correct.
Question 28 (NEET 2020, Q163)
Current ElectricityEasy
Which of the following graph represents the variation of resistivity (ρ) with temperature (T) for copper?
1. Option A: Option (1)
2. Option B: Option (2)
3. Option C: Option (3)
4. Option D: Option (4)
The answer and explanation for this question are in NEET MIND Premium.
Question 29 (NEET 2020, Q164)
Current ElectricityEasy
The color code of a resistance is given below. The values of resistance and tolerance, respectively, are:
1. Option A: 470 kΩ, 5%
2. Option B: 47 kΩ, 10%
3. Option C: 4.7 kΩ, 5%
4. Option D: 470 Ω, 5%
The answer and explanation for this question are in NEET MIND Premium.
Question 30 (NEET 2020, Q165)
Wave OpticsEasy
In Young’s double slit experiment, if the separation between coherent sources is halved and the distance of the screen from the coherent sources is doubled, then the fringe width becomes :
1. Option A: double
2. Option B: half
3. Option C: four times
4. Option D: one-fourth
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Correct answer: (C) four times
Explanation
Fringe width in Young’s double slit experiment is given by β = λD/d. If D is doubled and d is halved, then β' = λ(2D)/(d/2) = 4λD/d = 4β. Hence the fringe width becomes four times.
Question 31 (NEET 2020, Q166)
Electrostatic Potential and CapacitanceEasy
The capacitance of a parallel plate capacitor with air as medium is 6 μF. With the introduction of a dielectric medium, the capacitance becomes 30 μF. The permittivity of the medium is : (ε₀ = 8.85 × 10⁻¹² C² N⁻¹ m⁻²)
1. Option A: 0.44 × 10⁻¹³ C² N⁻¹ m⁻²
2. Option B: 1.77 × 10⁻¹² C² N⁻¹ m⁻²
3. Option C: 0.44 × 10⁻¹⁰ C² N⁻¹ m⁻²
4. Option D: 5.00 C² N⁻¹ m⁻²
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Question 32 (NEET 2020, Q167)
Units and MeasurementsEasy
Dimensions of stress are :
1. Option A: [MLT⁻²]
2. Option B: [ML²T⁻²]
3. Option C: [ML⁰T⁻²]
4. Option D: [ML⁻¹T⁻²]
The answer and explanation for this question are in NEET MIND Premium.
Question 33 (NEET 2020, Q168)
Ray Optics and Optical InstrumentsMedium
Assume that light of wavelength 600 nm is coming from a star. The limit of resolution of a telescope whose objective has a diameter of 2 m is :
1. Option A: 3.66 × 10⁻⁷ rad
2. Option B: 1.83 × 10⁻⁷ rad
3. Option C: 7.32 × 10⁻⁷ rad
4. Option D: 6.00 × 10⁻⁷ rad
The answer and explanation for this question are in NEET MIND Premium.
Question 34 (NEET 2020, Q169)
Alternating CurrentMedium
A series LCR circuit is connected to an ac voltage source. When L is removed from the circuit, the phase difference between current and voltage is π/3. If instead C is removed from the circuit, the phase difference is again π/3 between current and voltage. The power factor of the circuit is :
1. Option A: zero
2. Option B: 0.5
3. Option C: 1.0
4. Option D: -1.0
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Correct answer: (C) 1.0
Explanation
For RC circuit, tanφ = XC/R = √3. For RL circuit, tanφ = XL/R = √3. Hence XL = XC. Therefore the original LCR circuit is in resonance and phase angle is zero. Power factor = cos0 = 1.
Question 35 (NEET 2020, Q170)
Electrostatic Potential and CapacitanceMedium
A short electric dipole has a dipole moment of 16 × 10⁻⁹ C m. The electric potential due to the dipole at a point at a distance of 0.6 m from the centre of the dipole, situated on a line making an angle of 60° with the dipole axis is: [1/(4π ε₀) = 9 × 10⁹ N m²/C²]
1. Option A: 50 V
2. Option B: 200 V
3. Option C: 400 V
4. Option D: zero
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Question 36 (NEET 2020, Q171)
Moving Charges and MagnetismMedium
A magnetic material has magnetic susceptibility 1999. It is subjected to a magnetising field of 1200 A m⁻¹. The permeability of the material of the rod is : (μ₀ = 4π × 10⁻⁷ T m A⁻¹)
1. Option A: 2.4π × 10⁻⁴ T m A⁻¹
2. Option B: 8.0 × 10⁻⁵ T m A⁻¹
3. Option C: 2.4π × 10⁻⁵ T m A⁻¹
4. Option D: 2.4π × 10⁻⁷ T m A⁻¹
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Question 37 (NEET 2020, Q172)
Moving Charges and MagnetismEasy
A long solenoid of 50 cm length having 100 turns carries a current of 2.5 A. The magnetic field at the centre of the solenoid is : (μ $_0$ = 4π × 10⁻⁷ T m A⁻¹)
1. Option A: 6.28 × 10⁻⁴ T
2. Option B: 3.14 × 10⁻⁴ T
3. Option C: 6.28 × 10⁻⁵ T
4. Option D: 3.14 × 10⁻⁵ T
The answer and explanation for this question are in NEET MIND Premium.
Question 38 (NEET 2020, Q173)
Current ElectricityEasy
A charged particle having drift velocity of 7.5 × 10⁻⁴ m s⁻¹ in an electric field of 3 × 10⁻¹⁰ V m⁻¹, has a mobility in m² V⁻¹ s⁻¹ of :
1. Option A: 2.25 × 10¹⁵
2. Option B: 2.5 × 10⁶
3. Option C: 2.5 × 10⁻⁶
4. Option D: 2.25 × 10⁻¹⁵
The answer and explanation for this question are in NEET MIND Premium.
Question 39 (NEET 2020, Q174)
Thermal Properties of MatterMedium
The quantities of heat required to raise the temperature of two solid copper spheres of radii r₁ and r₂ (r₁ = 1.5 r₂) through 1 K are in the ratio :
1. Option A: 27/8
2. Option B: 9/4
3. Option C: 3/2
4. Option D: 5/3
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Correct answer: (A) 27/8
Explanation
Heat required: Q = mcΔT For the same material and same temperature rise: Q ∝ mass ∝ volume ∝ r^3 Therefore: Q1/Q2 = (r1/r2)^3 = (1.5)^3 = (3/2)^3 = 27/8 Hence, option (A) is correct.
Question 40 (NEET 2020, Q175)
Dual Nature of Radiation and MatterMedium
An electron is accelerated from rest through a potential difference of V volt. If the de Broglie wavelength of the electron is 1.227 × 10⁻² nm, the potential difference is:
1. Option A: 10 V
2. Option B: 10² V
3. Option C: 10³ V
4. Option D: 10⁴ V
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Question 41 (NEET 2020, Q176)
Units and MeasurementsEasy
Taking into account the significant figures, what is the value of 9.99 m − 0.0099 m?
1. Option A: 9.9801 m
2. Option B: 9.98 m
3. Option C: 9.980 m
4. Option D: 9.9 m
The answer and explanation for this question are in NEET MIND Premium.
Question 42 (NEET 2020, Q177)
Motion in a Straight LineEasy
A ball is thrown vertically downward with a velocity of 20 m/s from the top of a tower. It hits the ground after some time with a velocity of 80 m/s. The height of the tower is: (g = 10 m/s²)
1. Option A: 360 m
2. Option B: 340 m
3. Option C: 320 m
4. Option D: 300 m
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Correct answer: (D) 300 m
Explanation
Using the equation: v^2 = u^2 + 2gh Substituting values: 80^2 = 20^2 + 2 × 10 × h 6400 = 400 + 20h 20h = 6000 h = 300 m Hence, option (D) is correct.
Question 43 (NEET 2020, Q178)
Mechanical Properties of FluidsMedium
A capillary tube of radius r is immersed in water and water rises in it to a height h. The mass of the water in the capillary is 5 g. Another capillary tube of radius 2r is immersed in water. The mass of water that will rise in this tube is:
1. Option A: 2.5 g
2. Option B: 5.0 g
3. Option C: 10.0 g
4. Option D: 20.0 g
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Correct answer: (C) 10.0 g
Explanation
For capillary rise: h ∝ 1/r Mass of water raised: m = density × volume m ∝ r^2h Since h ∝ 1/r: m ∝ r If radius becomes 2r, mass becomes double. Therefore: m2 = 2 × 5 = 10 g Hence, option (C) is correct.
Question 44 (NEET 2020, Q179)
Current ElectricityMedium
A resistance wire connected in the left gap of a metre bridge balances a 10 Ω resistance in the right gap at a point which divides the bridge wire in the ratio 3 : 2. If the length of the resistance wire is 1.5 m, the length of 1 Ω of the resistance wire is:
1. Option A: 1.0 × 10⁻² m
2. Option B: 1.0 × 10⁻¹ m
3. Option C: 1.5 × 10⁻¹ m
4. Option D: 1.5 × 10⁻² m
The answer and explanation for this question are in NEET MIND Premium.
Question 45 (NEET 2020, Q180)
Semiconductor ElectronicsMedium
For the logic circuit shown, the truth table is:
1. Option A: Option (1)
2. Option B: Option (2)
3. Option C: Option (3)
4. Option D: Option (4)
The answer and explanation for this question are in NEET MIND Premium.

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