NEET 2022 · Physics

NEET 2022 Physics Questions with Solutions

The NEET 2022 paper had 51 Physics questions from 26 chapters.

Moving Charges and Magnetism had the most questions (5), followed by Current Electricity with 4.

46 questions below have the answer and explanation free; the other 5 are in Premium.

Physics questions
51
Chapters covered
26
Solved free here
46 of 51
Easy / Medium / Hard
22 / 24 / 5

Difficulty is NEET MIND's own tag for each question.

Chapter-wise: NEET 2022 Physics

How many questions each chapter had in NEET 2022. Open a chapter for its questions from every year.

  1. Moving Charges and Magnetism5 Qs
  2. Current Electricity4 Qs
  3. Electromagnetic Waves3 Qs
  4. Ray Optics and Optical Instruments3 Qs
  5. Semiconductor Electronics3 Qs
  6. System of Particles and Rotational Motion3 Qs
  7. Alternating Current2 Qs
  8. Atoms2 Qs
  9. Dual Nature of Radiation and Matter2 Qs
  10. Electric Charges and Fields2 Qs
  11. Electrostatic Potential and Capacitance2 Qs
  12. Gravitation2 Qs
  13. Mechanical Properties of Fluids2 Qs
  14. Motion in a Straight Line2 Qs
  15. Nuclei2 Qs
  16. Units and Measurements2 Qs
  17. Electromagnetic Induction1 Q
  18. Kinetic Theory1 Q
  19. Laws of Motion1 Q
  20. Mechanical Properties of Solids1 Q
  21. Motion in a Plane1 Q
  22. Oscillations1 Q
  23. Thermodynamics1 Q
  24. Wave Optics1 Q
  25. Waves1 Q
  26. Work, Energy and Power1 Q

All 51 NEET 2022 Physics questions

In paper order. Try each one, then open the answer where it is shown.

  1. Question 1 (NEET 2022, Q1)

    Current ElectricityEasy
    Two resistors of resistance, 100 Ω and 200 Ω are connected in parallel in an electrical circuit. The ratio of the thermal energy developed in 100 Ω to that in 200 Ω in a given time is
    1. Option A: 4 : 1
    2. Option B: 1 : 2
    3. Option C: 2 : 1
    4. Option D: 1 : 4

    The answer and explanation for this question are in NEET MIND Premium.

  2. Question 2 (NEET 2022, Q2)

    Electrostatic Potential and CapacitanceEasy
    Two hollow conducting spheres of radii R1_1 and R2_2 (R1_1 >> R2_2) have equal charges. The potential would be
    1. Option A: Dependent on the material property of the sphere
    2. Option B: More on bigger sphere
    3. Option C: More on smaller sphere
    4. Option D: Equal on both the spheres
    Show answer & explanation

    Correct answer: (C) More on smaller sphere

    Explanation

    Potential of a conducting sphere is given by: V=kQRV = \frac{kQ}{R} For equal charge, potential is inversely proportional to radius. Since R1>R2R_1 > R_2, the smaller sphere has greater potential.

  3. Question 3 (NEET 2022, Q3)

    Dual Nature of Radiation and MatterMedium
    When two monochromatic lights of frequency ν\nu and ν2\frac{\nu}{2} are incident on a photoelectric metal, their stopping potentials become Vs2\frac{V_s}{2} and VsV_s respectively. The threshold frequency for this metal is:
    1. Option A: 32ν\frac{3}{2}\nu
    2. Option B: 2ν2\nu
    3. Option C: 3ν3\nu
    4. Option D: 23ν\frac{2}{3}\nu
    Show answer & explanation

    Correct answer: (A) 32ν\frac{3}{2}\nu

    Explanation

    Using Einstein’s photoelectric equation: eV=h(ν−ν0)eV = h(\nu-\nu_0) For frequency ν\nu: e(Vs2)=h(ν−ν0)e\left(\frac{V_s}{2}\right)=h(\nu-\nu_0) ...(1) For frequency ν2\frac{\nu}{2}: eVs=h(ν2−ν0)eV_s=h\left(\frac{\nu}{2}-\nu_0\right) ...(2) Multiplying (1) by 2: eVs=2h(ν−ν0)eV_s=2h(\nu-\nu_0) Equating with (2): 2(ν−ν0)=ν2−ν02(\nu-\nu_0)=\frac{\nu}{2}-\nu_0 2ν−2ν0=ν2−ν02\nu-2\nu_0=\frac{\nu}{2}-\nu_0 3ν2=ν0\frac{3\nu}{2}=\nu_0 Hence threshold frequency: ν0=32ν\boxed{\nu_0=\frac{3}{2}\nu} Therefore option (A) is correct.

  4. Question 4 (NEET 2022, Q4)

    Current ElectricityEasy
    As the temperature increases, the electrical resistance
    1. Option A: Decreases for conductors but increases for semiconductors
    2. Option B: Increases for both conductors and semiconductors
    3. Option C: Decreases for both conductors and semiconductors
    4. Option D: Increases for conductor but decreases for semiconductors

    The answer and explanation for this question are in NEET MIND Premium.

  5. Question 5 (NEET 2022, Q5)

    WavesEasy
    If the tension on a stretched string is doubled, then the ratio of the initial and final speeds of a transverse wave along the string is
    1. Option A: 1 : 2
    2. Option B: 1 : 1
    3. Option C: √2 : 1
    4. Option D: 1 : √2
    Show answer & explanation

    Correct answer: (D) 1 : √2

    Explanation

    Speed of transverse wave on a stretched string: v=Tμv = \sqrt{\frac{T}{\mu}} If tension becomes double: v′=2Tμ=2vv' = \sqrt{\frac{2T}{\mu}} = \sqrt{2}v Therefore, v:v′=1:2v : v' = 1 : \sqrt{2}

  6. Question 6 (NEET 2022, Q6)

    Electromagnetic WavesMedium
    Match List-I with List-II. Choose the correct answer from the options given below
    1. Option A: (a)-(ii), (b)-(iii), (c)-(iv), (d)-(i)
    2. Option B: (a)-(iv), (b)-(iii), (c)-(ii), (d)-(i)
    3. Option C: (a)-(iii), (b)-(ii), (c)-(i), (d)-(iv)
    4. Option D: (a)-(iii), (b)-(iv), (c)-(ii), (d)-(i)
    Show answer & explanation

    Correct answer: (A) (a)-(ii), (b)-(iii), (c)-(iv), (d)-(i)

    Explanation

    Typical wavelength ranges: - AM radio waves → 102 m10^2\,m - Microwaves → 10−2 m10^{-2}\,m - Infrared radiations → 10−4 m10^{-4}\,m - X-rays → 10−10 m10^{-10}\,m Hence the correct matching is: (a)−(ii),(b)−(iii),(c)−(iv),(d)−(i)(a)-(ii), (b)-(iii), (c)-(iv), (d)-(i)

  7. Question 7 (NEET 2022, Q7)

    System of Particles and Rotational MotionMedium
    The ratio of the radius of gyration of a thin uniform disc about an axis passing through its centre and normal to its plane to the radius of gyration of the disc about its diameter is
    1. Option A: 1 : √2
    2. Option B: 2 : 1
    3. Option C: √2 : 1
    4. Option D: 4 : 1
    Show answer & explanation

    Correct answer: (C) √2 : 1

    Explanation

    For a disc: I(normal)=MR²/2 ⇒ k₁=R/√2; I(diameter)=MR²/4 ⇒ k₂=R/2. Hence ratio = (R/√2):(R/2)=√2:1.

  8. Question 8 (NEET 2022, Q8)

    Ray Optics and Optical InstrumentsEasy
    A biconvex lens has radii of curvature, 20 cm each. If the refractive index of the material of the lens is 1.5, the power of the lens is
    1. Option A: Infinity
    2. Option B: +2 D
    3. Option C: +20 D
    4. Option D: +5 D
    Show answer & explanation

    Correct answer: (D) +5 D

    Explanation

    Using lens maker formula: 1/f=(μ−1)(1/R₁−1/R₂)=(0.5)(1/20−(−1/20))=1/20 cm⁻¹. Thus f=20 cm=0.2 m and P=1/f=+5 D.

  9. Question 9 (NEET 2022, Q9)

    Dual Nature of Radiation and MatterEasy
    The graph which shows the variation of the de Broglie wavelength (λ) of a particle and its associated momentum (p) is
    1. Option A: Option (1)
    2. Option B: Option (2)
    3. Option C: Option (3)
    4. Option D: Option (4)
    Show answer & explanation

    Correct answer: (A) Option (1)

    Explanation

    According to de Broglie relation, λ = h/p. Hence wavelength is inversely proportional to momentum, giving a decreasing hyperbolic curve. Therefore option (A) is correct.

  10. Question 10 (NEET 2022, Q10)

    Electromagnetic WavesEasy
    When light propagates through a material medium of relative permittivity εr\varepsilon_r and relative permeability μr\mu_r, the velocity of light, vv, is given by (cc = velocity of light in vacuum)
    1. Option 1: v=cεrμrv=\dfrac{c}{\sqrt{\varepsilon_r\mu_r}}
    2. Option 2: v=cv=c
    3. Option 3: v=μrεrv=\sqrt{\dfrac{\mu_r}{\varepsilon_r}}
    4. Option 4: v=εrμrv=\sqrt{\dfrac{\varepsilon_r}{\mu_r}}
    Show answer & explanation

    Correct answer: A

    Explanation

    ["The speed of electromagnetic waves in a medium is:","v=frac1sqrtmuvarepsilonv=\\frac{1}{\\sqrt{\\mu\\varepsilon}}","For a material medium:","mu=murmu0,qquadvarepsilon=varepsilonrvarepsilon0\\mu=\\mu_r\\mu_0, \\qquad \\varepsilon=\\varepsilon_r\\varepsilon_0","Substituting:","v=frac1sqrtmurmu0varepsilonrvarepsilon0v=\\frac{1}{\\sqrt{\\mu_r\\mu_0\\varepsilon_r\\varepsilon_0}}","Using:","c=frac1sqrtmu0varepsilon0c=\\frac{1}{\\sqrt{\\mu_0\\varepsilon_0}}","Hence:","v=fraccsqrtvarepsilonrmurv=\\frac{c}{\\sqrt{\\varepsilon_r\\mu_r}}","Therefore, the correct answer is:","boxedv=fraccsqrtvarepsilonrmur\\boxed{v=\\frac{c}{\\sqrt{\\varepsilon_r\\mu_r}}}"]

  11. Question 11 (NEET 2022, Q11)

    NucleiMedium
    In the given nuclear reaction, the element X is: ²²₁₁Na → X + e⁺ + ν
    1. Option A: ²²₁₂Mg
    2. Option B: ²³₁₁Na
    3. Option C: ²⁰₁₀Ne
    4. Option D: ²²₁₀Ne
    Show answer & explanation

    Correct answer: (D) ²²₁₀Ne

    Explanation

    In β⁺ decay, atomic number decreases by 1 while mass number remains unchanged. Hence ²²₁₁Na → ²²₁₀Ne + e⁺ + ν.

  12. Question 12 (NEET 2022, Q12)

    ThermodynamicsMedium
    An ideal gas undergoes four different processes from the same initial state as shown in the figure below. Those processes are adiabatic, isothermal, isobaric and isochoric. The curve which represents the adiabatic process among 1, 2, 3 and 4 is:
    1. Option A: 4
    2. Option B: 1
    3. Option C: 2
    4. Option D: 3
    Show answer & explanation

    Correct answer: (C) 2

    Explanation

    For an ideal gas on a P–V diagram, the adiabatic curve is steeper than the isothermal curve because pressure decreases more rapidly during adiabatic expansion. Hence, among the given curves, process 2 represents the adiabatic process. Therefore, option (C) is correct.

  13. Question 13 (NEET 2022, Q13)

    Motion in a Straight LineEasy
    The ratio of the distances travelled by a freely falling body in the 1ˢᵗ, 2ⁿᵈ, 3ʳᵈ and 4ᵗʰ seconds is:
    1. Option A: 1 : 1 : 1 : 1
    2. Option B: 1 : 2 : 3 : 4
    3. Option C: 1 : 4 : 9 : 16
    4. Option D: 1 : 3 : 5 : 7
    Show answer & explanation

    Correct answer: (D) 1 : 3 : 5 : 7

    Explanation

    For a freely falling body under constant acceleration, distance covered in the nth second is: sₙ = u + a/2 (2n − 1) For free fall, u = 0 and a = g: sₙ ∝ (2n − 1) Thus, distances in successive seconds are: 1st : 2nd : 3rd : 4th = 1 : 3 : 5 : 7 Hence, option (D) is correct.

  14. Question 14 (NEET 2022, Q14)

    System of Particles and Rotational MotionEasy
    Two objects of mass 10 kg and 20 kg respectively are connected to the two ends of a rigid rod of length 10 m with negligible mass. The distance of the centre of mass of the system from the 10 kg mass is:
    1. Option A: 5 m
    2. Option B: 10/3 m
    3. Option C: 20/3 m
    4. Option D: 10 m
    Show answer & explanation

    Correct answer: (C) 20/3 m

    Explanation

    Position of centre of mass: x = (m₂L)/(m₁ + m₂) = (20 × 10)/(10 + 20) = 200/30 = 20/3 m Hence, option (C) is correct.

  15. Question 15 (NEET 2022, Q15)

    Electromagnetic WavesEasy
    The energy that will be ideally radiated by a 100 kW transmitter in 1 hour is:
    1. Option A: 1 × 10⁵ J
    2. Option B: 36 × 10⁷ J
    3. Option C: 36 × 10⁴ J
    4. Option D: 36 × 10⁵ J
    Show answer & explanation

    Correct answer: (B) 36 × 10⁷ J

    Explanation

    Energy radiated: E = Pt P = 100 kW = 10⁵ W t = 1 hour = 3600 s E = 10⁵ × 3600 = 36 × 10⁷ J Hence, option (B) is correct.

  16. Question 16 (NEET 2022, Q16)

    Work, Energy and PowerMedium
    An electric lift with a maximum load of 2000 kg (lift + passengers) is moving up with a constant speed of 1.5 ms⁻¹. The frictional force opposing the motion is 3000 N. The minimum power delivered by the motor to the lift in watts is: (g = 10 ms⁻²)
    1. Option A: 23500
    2. Option B: 23000
    3. Option C: 20000
    4. Option D: 34500
    Show answer & explanation

    Correct answer: (D) 34500

    Explanation

    Total opposing force: F = mg + friction = (2000 × 10) + 3000 = 23000 N Power: P = Fv = 23000 × 1.5 = 34500 W Hence, option (D) is correct.

  17. Question 17 (NEET 2022, Q17)

    Current ElectricityMedium
    A copper wire of length 10 m10\,m and radius (10−2π) m\left(\frac{10^{-2}}{\sqrt{\pi}}\right)\,m has electrical resistance of 10 Ω10\,\Omega. The current density in the wire for an electric field strength of 10 (V/m)10\,(V/m) is
    1. Option A: 105  A/m210^5\;A/m^2
    2. Option B: 104  A/m210^4\;A/m^2
    3. Option C: 106  A/m210^6\;A/m^2
    4. Option D: 10−5  A/m210^{-5}\;A/m^2

    The answer and explanation for this question are in NEET MIND Premium.

  18. Question 18 (NEET 2022, Q18)

    Mechanical Properties of FluidsEasy
    If a soap bubble expands, the pressure inside the bubble:
    1. Option A: Is equal to the atmospheric pressure
    2. Option B: Decreases
    3. Option C: Increases
    4. Option D: Remains the same
    Show answer & explanation

    Correct answer: (B) Decreases

    Explanation

    Excess pressure inside a soap bubble is: ΔP = 4T/r As the radius increases during expansion, excess pressure decreases. Hence pressure inside the bubble decreases. Therefore option (B) is correct.

  19. Question 19 (NEET 2022, Q19)

    Moving Charges and MagnetismMedium
    Given below are two statements: Statement I: Biot-Savart's law gives us the expression for the magnetic field strength of an infinitesimal current element I(dl) of a current carrying conductor only. Statement II: Biot-Savart's law is analogous to Coulomb's inverse square law of charge q, with the former being related to the field produced by a scalar source, I(dl), while the latter being produced by a vector source, q. In light of above statements choose the most appropriate answer from the options given below.
    1. Option A: Statement I is incorrect and Statement II is correct
    2. Option B: Both Statement I and Statement II are correct
    3. Option C: Both Statement I and Statement II are incorrect
    4. Option D: Statement I is correct and Statement II is incorrect
    Show answer & explanation

    Correct answer: (D) Statement I is correct and Statement II is incorrect

    Explanation

    Statement I is correct because Biot–Savart law gives the contribution of an infinitesimal current element to magnetic field. Statement II is incorrect because charge is scalar while current element Idl is vector; the statement reverses these properties. Hence option (D) is correct.

  20. Question 20 (NEET 2022, Q20)

    Laws of MotionHard
    A shell of mass m is at rest initially. It explodes into three fragments having mass in the ratio 2 : 2 : 1. If the fragments having equal mass fly off along mutually perpendicular directions with speed v, the speed of the third (lighter) fragment is:
    1. Option A: 3√2v
    2. Option B: v
    3. Option C: √2v
    4. Option D: 2√2v
    Show answer & explanation

    Correct answer: (D) 2√2v

    Explanation

    Initial momentum = 0. Masses are: 2m/5, 2m/5 and m/5. Momentum of two equal fragments: p₁ = (2m/5)v, p₂ = (2m/5)v Resultant momentum: p = √[(2m/5)v]² + [(2m/5)v]² = 2√2 mv/5 For third fragment: (m/5)V = 2√2 mv/5 V = 2√2v Hence option (D) is correct.

  21. Question 21 (NEET 2022, Q21)

    Mechanical Properties of FluidsMedium
    A spherical ball is dropped in a long column of highly viscous liquid. The curve in the graph shown, which represents the speed of the ball (v) as a function of time (t), is:
    1. Option A: D
    2. Option B: A
    3. Option C: B
    4. Option D: C
    Show answer & explanation

    Correct answer: (C) B

    Explanation

    A ball falling through viscous liquid attains terminal velocity. Velocity increases rapidly initially and gradually approaches a constant value. Curve B represents this behaviour. Hence option (C) is correct.

  22. Question 22 (NEET 2022, Q22)

    System of Particles and Rotational MotionMedium
    The angular speed of a fly wheel moving with uniform angular acceleration changes from 1200 rpm to 3120 rpm in 16 seconds. The angular acceleration in rad/s² is:
    1. Option A: 104π
    2. Option B: 2π
    3. Option C: 4π
    4. Option D: 12π
    Show answer & explanation

    Correct answer: (C) 4π

    Explanation

    Initial angular speed: ω₁ = 1200 × 2π/60 = 40π rad/s Final angular speed: ω₂ = 3120 × 2π/60 = 104π rad/s Angular acceleration: α = (ω₂ − ω₁)/t = (104π − 40π)/16 = 4π rad/s² Hence option (C) is correct.

  23. Question 23 (NEET 2022, Q23)

    Alternating CurrentEasy
    The peak voltage of the AC source is equal to:
    1. Option A: 1/√2 times the rms value of the AC source
    2. Option B: The value of voltage supplied to the circuit
    3. Option C: The rms value of the AC source
    4. Option D: √2 times the rms value of the AC source
    Show answer & explanation

    Correct answer: (D) √2 times the rms value of the AC source

    Explanation

    For alternating voltage: Vᵣₘₛ = V₀/√2 Therefore: V₀ = √2 Vᵣₘₛ Hence option (D) is correct.

  24. Question 24 (NEET 2022, Q24)

    Moving Charges and MagnetismMedium
    The dimensions [MLT⁻²A⁻²] belong to the:
    1. Option A: Electric permittivity
    2. Option B: Magnetic flux
    3. Option C: Self inductance
    4. Option D: Magnetic permeability
    Show answer & explanation

    Correct answer: (D) Magnetic permeability

    Explanation

    Magnetic permeability μ has dimensions: [μ] = [MLT⁻²A⁻²] Hence option (D), magnetic permeability, is correct.

  25. Question 25 (NEET 2022, Q25)

    Motion in a Straight LineEasy
    The displacement-time graphs of two moving particles make angles of 30° and 45° with the x-axis as shown in the figure. The ratio of their respective velocities is:
    1. Option A: 1 : √3
    2. Option B: √3 : 1
    3. Option C: 1 : 1
    4. Option D: 1 : 2
    Show answer & explanation

    Correct answer: (A) 1 : √3

    Explanation

    Velocity equals slope of displacement-time graph. v₁/v₂ = tan30°/tan45° = (1/√3)/1 = 1 : √3 Hence option (A) is correct.

  26. Question 26 (NEET 2022, Q26)

    Semiconductor ElectronicsMedium
    In the given circuits (a), (b) and (c), the potential drop across the two p-n junctions are equal in:
    1. Option A: Both circuits (a) and (c)
    2. Option B: Circuit (a) only
    3. Option C: Circuit (b) only
    4. Option D: Circuit (c) only
    Show answer & explanation

    Correct answer: (A) Both circuits (a) and (c)

    Explanation

    In circuits (a) and (c), the two identical p-n junctions experience equal potential drops due to symmetric biasing conditions. Hence the correct answer is option (A).

  27. Question 27 (NEET 2022, Q27)

    Electric Charges and FieldsEasy
    The angle between the electric lines of force and the equipotential surface is:
    1. Option A: 180°
    2. Option B: 0°
    3. Option C: 45°
    4. Option D: 90°
    Show answer & explanation

    Correct answer: (D) 90°

    Explanation

    Electric field lines are always perpendicular to equipotential surfaces because no work is done in moving along an equipotential surface. Hence, the angle between them is 90°. Therefore option (D) is correct.

  28. Question 28 (NEET 2022, Q28)

    Units and MeasurementsEasy
    Plane angle and solid angle have:
    1. Option A: Both units and dimensions
    2. Option B: Units but no dimensions
    3. Option C: Dimensions but no units
    4. Option D: No units and no dimensions
    Show answer & explanation

    Correct answer: (B) Units but no dimensions

    Explanation

    Plane angle and solid angle are dimensionless quantities but have SI units: radian and steradian respectively. Therefore, they have units but no dimensions. Hence option (B) is correct.

  29. Question 29 (NEET 2022, Q29)

    Wave OpticsMedium
    In a Young's double slit experiment, a student observes 8 fringes in a certain segment of screen when a monochromatic light of 600 nm wavelength is used. If the wavelength of light is changed to 400 nm, then the number of fringes he would observe in the same region of the screen is:
    1. Option A: 12
    2. Option B: 6
    3. Option C: 8
    4. Option D: 9
    Show answer & explanation

    Correct answer: (A) 12

    Explanation

    Fringe width in YDSE: β ∝ λ Number of fringes in a fixed screen length: N ∝ 1/λ Thus, N₂/N₁ = λ₁/λ₂ N₂/8 = 600/400 N₂ = 12 Hence option (A) is correct.

  30. Question 30 (NEET 2022, Q30)

    Ray Optics and Optical InstrumentsMedium
    A light ray falls on a glass surface of refractive index √3, at an angle 60°. The angle between the refracted and reflected rays would be:
    1. Option A: 120°
    2. Option B: 30°
    3. Option C: 60°
    4. Option D: 90°
    Show answer & explanation

    Correct answer: (D) 90°

    Explanation

    Using Snell's law: sin i / sin r = μ sin 60° / sin r = √3 (√3/2)/sin r = √3 sin r = 1/2 r = 30° Reflected angle = 60° Angle between reflected and refracted rays: = 180° − (60° + 30°) = 90° Hence option (D) is correct.

  31. Question 31 (NEET 2022, Q31)

    Semiconductor ElectronicsEasy
    In half wave rectification, if the input frequency is 60 Hz, then the output frequency would be:
    1. Option A: 120 Hz
    2. Option B: Zero
    3. Option C: 30 Hz
    4. Option D: 60 Hz
    Show answer & explanation

    Correct answer: (D) 60 Hz

    Explanation

    For half-wave rectification, output frequency equals input frequency: f_output = f_input Thus: f_output = 60 Hz Hence option (D) is correct.

  32. Question 32 (NEET 2022, Q32)

    GravitationEasy
    A body of mass 60 g experiences a gravitational force of 3.0 N, when placed at a particular point. The magnitude of gravitational field intensity at that point is:
    1. Option A: 180 N/kg
    2. Option B: 0.05 N/kg
    3. Option C: 50 N/kg
    4. Option D: 20 N/kg
    Show answer & explanation

    Correct answer: (C) 50 N/kg

    Explanation

    Gravitational field intensity: g = F/m = 3/(0.06) = 50 N/kg Hence option (C) is correct.

  33. Question 33 (NEET 2022, Q33)

    Moving Charges and MagnetismEasy
    A square loop of side 1 m and resistance 1 Ω is placed in a magnetic field of 0.5 T. If the plane of loop is perpendicular to the direction of magnetic field, the magnetic flux through the loop is:
    1. Option A: Zero weber
    2. Option B: 2 weber
    3. Option C: 0.5 weber
    4. Option D: 1 weber
    Show answer & explanation

    Correct answer: (C) 0.5 weber

    Explanation

    Magnetic flux: Φ = BA cosθ Area = 1 × 1 = 1 m² Since plane is perpendicular to field, θ = 0° Φ = 0.5 × 1 × 1 = 0.5 Wb Hence option (C) is correct.

  34. Question 34 (NEET 2022, Q34)

    AtomsMedium
    Let T₁ and T₂ be the energy of an electron in the first and second excited states of hydrogen atoms, respectively. According to Bohr's model of an atom, the ratio T₁ : T₂ is:
    1. Option A: 9 : 4
    2. Option B: 1 : 4
    3. Option C: 4 : 1
    4. Option D: 4 : 9
    Show answer & explanation

    Correct answer: (A) 9 : 4

    Explanation

    For hydrogen atom: Eₙ ∝ -1/n² First excited state: n = 2 Second excited state: n = 3 T₁:T₂ = (1/2²):(1/3²) = 1/4 : 1/9 = 9 : 4 Hence option (A) is correct.

  35. Question 35 (NEET 2022, Q35)

    Moving Charges and MagnetismMedium
    A long solenoid of radius 1 mm has 100 turns per mm. If 1 A current flows in the solenoid, the magnetic field strength at the centre of the solenoid is:
    1. Option A: 6.28 × 10⁻⁴ T
    2. Option B: 6.28 × 10⁻² T
    3. Option C: 12.56 × 10⁻² T
    4. Option D: 12.56 × 10⁻⁴ T
    Show answer & explanation

    Correct answer: (C) 12.56 × 10⁻² T

    Explanation

    Magnetic field inside long solenoid: B = μ₀nI n = 100 turns/mm = 10⁵ turns/m μ₀ = 4π × 10⁻⁷ Tm/A I = 1 A B = 4π × 10⁻⁷ × 10⁵ × 1 = 4π × 10⁻² ≈ 12.56 × 10⁻² T Hence option (C) is correct.

  36. Question 36 (NEET 2022, Q36)

    OscillationsMedium
    Two pendulums of length 121 cm and 100 cm start vibrating in phase. At some instant, the two are at their mean position in the same phase. The minimum number of vibrations of the shorter pendulum after which the two are again in phase at the mean position is:
    1. Option A: 8
    2. Option B: 11
    3. Option C: 9
    4. Option D: 10
    Show answer & explanation

    Correct answer: (B) 11

    Explanation

    Time period of a pendulum: T ∝ √L Therefore: T₁/T₂ = √121/√100 = 11/10 For the pendulums to return to the mean position in the same phase: n₁T₁ = n₂T₂ Minimum integers satisfying: n₁/n₂ = 10/11 Thus, the shorter pendulum completes 11 vibrations. Hence option (B) is correct.

  37. Question 37 (NEET 2022, Q37)

    Kinetic TheoryHard
    The volume occupied by the molecules contained in 4.5 kg water at STP, if the intermolecular forces vanish away is:
    1. Option A: 5.6 m³
    2. Option B: 5.6 × 10⁶ m³
    3. Option C: 5.6 × 10³ m³
    4. Option D: 5.6 × 10⁻³ m³
    Show answer & explanation

    Correct answer: (A) 5.6 m³

    Explanation

    Mass of water: m = 4.5 kg = 4500 g Number of moles: n = 4500/18 = 250 mol At STP, 1 mol ideal gas occupies 22.4 × 10⁻³ m³. Thus: V = 250 × 22.4 × 10⁻³ = 5.6 m³ Hence option (A) is correct.

  38. Question 38 (NEET 2022, Q38)

    Ray Optics and Optical InstrumentsMedium
    Two transparent media A and B are separated by a plane boundary. The speed of light in those media are 1.5 × 10⁸ m/s and 2.0 × 10⁸ m/s, respectively. The critical angle for a ray of light for these two media is:
    1. Option A: tan⁻¹(0.750)
    2. Option B: sin⁻¹(0.500)
    3. Option C: sin⁻¹(0.750)
    4. Option D: tan⁻¹(0.500)
    Show answer & explanation

    Correct answer: (C) sin⁻¹(0.750)

    Explanation

    Refractive index is inversely proportional to speed: n₁/n₂ = v₂/v₁ Critical angle: sin C = n₂/n₁ = v₁/v₂ = (1.5 × 10⁸)/(2.0 × 10⁸) = 0.75 Thus: C = sin⁻¹(0.750) Hence option (C) is correct.

  39. Question 39 (NEET 2022, Q39)

    GravitationMedium
    Match List-I with List-II:
    1. Option A: (a)-(iv), (b)-(ii), (c)-(i), (d)-(iii)
    2. Option B: (a)-(ii), (b)-(i), (c)-(iv), (d)-(iii)
    3. Option C: (a)-(ii), (b)-(iv), (c)-(i), (d)-(iii)
    4. Option D: (a)-(ii), (b)-(iv), (c)-(iii), (d)-(i)
    Show answer & explanation

    Correct answer: (C) (a)-(ii), (b)-(iv), (c)-(i), (d)-(iii)

    Explanation

    Dimensions: G → [M⁻¹L³T⁻²] Potential energy → [ML²T⁻²] Potential → [L²T⁻²] Intensity → [LT⁻²] Thus matching: (a)-(ii), (b)-(iv), (c)-(i), (d)-(iii) Hence option (C) is correct.

  40. Question 40 (NEET 2022, Q40)

    Alternating CurrentHard
    A series LCR circuit with inductance 10 H, capacitance 10 μF, resistance 50 Ω is connected to an AC source of voltage V = 200 sin(100t) volt. If the resonance frequency of the LCR circuit is ν₀ and the frequency of AC source is ν, then:
    1. Option A: ν = 100 Hz; ν₀ = 100/π Hz
    2. Option B: ν₀ = ν = 50 Hz
    3. Option C: ν₀ = ν = 50/π Hz
    4. Option D: ν₀ = 50/π Hz; ν = 50 Hz
    Show answer & explanation

    Correct answer: (C) ν₀ = ν = 50/π Hz

    Explanation

    Angular frequency of source: ω = 100 rad/s ν = ω/2π = 100/2π = 50/π Hz Resonance frequency: ν₀ = 1/(2π√LC) = 1/[2π√(10×10⁻⁵)] = 50/π Hz Hence: ν₀ = ν = 50/π Hz Therefore option (C) is correct.

  41. Question 41 (NEET 2022, Q41)

    Motion in a PlaneEasy
    A ball is projected with a velocity 10 ms⁻¹, at an angle of 60° with the vertical direction. Its speed at the highest point of its trajectory will be:
    1. Option A: 10 ms⁻¹
    2. Option B: Zero
    3. Option C: 5√3 ms⁻¹
    4. Option D: 5 ms⁻¹
    Show answer & explanation

    Correct answer: (C) 5√3 ms⁻¹

    Explanation

    Angle with horizontal: θ = 30° At highest point, vertical velocity = 0. Remaining horizontal velocity: v = u cos30° = 10 × √3/2 = 5√3 ms⁻¹ Hence option (C) is correct.

  42. Question 42 (NEET 2022, Q42)

    Moving Charges and MagnetismMedium
    From Ampere's circuital law for a long straight wire of circular cross-section carrying a steady current, the variation of magnetic field inside and outside region of the wire is:
    1. Option A: A linearly decreasing function of distance up to the boundary of the wire and then a linearly increasing one for the outside region
    2. Option B: Uniform and remains constant for both the regions
    3. Option C: A linearly increasing function of distance up to the boundary of the wire and then linearly decreasing for the outside region
    4. Option D: A linearly increasing function of distance r up to the boundary of the wire and then decreasing with 1/r dependence for the outside region

    The answer and explanation for this question are in NEET MIND Premium.

  43. Question 43 (NEET 2022, Q43)

    Mechanical Properties of SolidsMedium
    Given below are two statements: One is labelled as Assertion (A) and the other is labelled as Reason (R). Assertion (A): The stretching of a spring is determined by the shear modulus of the material of the spring. Reason (R): A coil spring of copper has more tensile strength than a steel spring of same dimensions. In the light of the above statements, choose the most appropriate answer from the options given below.
    1. Option A: (A) is false but (R) is true
    2. Option B: Both (A) and (R) are true and (R) is the correct explanation of (A)
    3. Option C: Both (A) and (R) are true and (R) is not the correct explanation of (A)
    4. Option D: (A) is true but (R) is false
    Show answer & explanation

    Correct answer: (D) (A) is true but (R) is false

    Explanation

    Extension in a coil spring depends on the shear modulus (modulus of rigidity) of the material, so Assertion (A) is true. Copper has lower tensile strength than steel, hence Reason (R) is false. Therefore option (D) is correct.

  44. Question 44 (NEET 2022, Q44)

    Semiconductor ElectronicsMedium
    The truth table for the given logic circuit is:
    1. Option A: Option 1
    2. Option B: Option 2
    3. Option C: Option 3
    4. Option D: Option 4
    Show answer & explanation

    Correct answer: (D) Option 4

    Explanation

    Evaluating the logic gates in sequence gives output values: A B → C 00 → 1 01 → 0 10 → 1 11 → 0 Hence option (D) is correct.

  45. Question 45 (NEET 2022, Q45)

    NucleiEasy
    A nucleus of mass number 189 splits into two nuclei having mass numbers 125 and 64. The ratio of radius of two daughter nuclei respectively is:
    1. Option A: 25 : 16
    2. Option B: 1 : 1
    3. Option C: 4 : 5
    4. Option D: 5 : 4
    Show answer & explanation

    Correct answer: (D) 5 : 4

    Explanation

    Nuclear radius: R ∝ A^(1/3) Thus: R₁/R₂ = (125/64)^(1/3) = 5/4 Hence the ratio is 5 : 4. Therefore option (D) is correct.

  46. Question 46 (NEET 2022, Q46)

    Current ElectricityMedium
    A Wheatstone bridge is used to determine the value of unknown resistance X by adjusting the variable resistance Y as shown in the figure. For the most precise measurement of X, the resistances P and Q:
    1. Option A: Do not play any significant role
    2. Option B: Should be approximately equal to 2X
    3. Option C: Should be approximately equal and are small
    4. Option D: Should be very large and unequal

    The answer and explanation for this question are in NEET MIND Premium.

  47. Question 47 (NEET 2022, Q47)

    Units and MeasurementsEasy
    The area of a rectangular field (in m²) of length 55.3 m and breadth 25 m after rounding off the value for correct significant digits is:
    1. Option A: 14 × 10²
    2. Option B: 138 × 10¹
    3. Option C: 1382
    4. Option D: 1382.5
    Show answer & explanation

    Correct answer: (A) 14 × 10²

    Explanation

    Area = length × breadth = 55.3 × 25 = 1382.5 m² The least number of significant figures is 2 (from 25). Thus rounded value: = 1.4 × 10³ m² = 14 × 10² m² Hence option (A) is correct.

  48. Question 48 (NEET 2022, Q48)

    Electromagnetic InductionHard
    A big circular coil of 1000 turns and average radius 10 m is rotating about its horizontal diameter at 2 rad s⁻¹. If the vertical component of earth's magnetic field at that place is 2 × 10⁻⁵ T and electrical resistance of the coil is 12.56 Ω, then the maximum induced current in the coil will be:
    1. Option A: 2 A
    2. Option B: 0.25 A
    3. Option C: 1.5 A
    4. Option D: 1 A
    Show answer & explanation

    Correct answer: (D) 1 A

    Explanation

    Maximum induced emf: Eₘ = NBAω N = 1000, B = 2 × 10⁻⁵ T, A = π(10)² = 100π m², ω = 2 rad/s Eₘ = 1000 × 2×10⁻⁵ × 100π × 2 = 4π V Maximum current: Iₘ = Eₘ/R = 4π/12.56 ≈ 1 A Hence option (D) is correct.

  49. Question 49 (NEET 2022, Q49)

    Electric Charges and FieldsMedium
    Two point charges −q and +q are placed at a distance L, as shown in the figure. The magnitude of electric field intensity at a distance R (R >> L) varies as:
    1. Option A: 1/R⁶
    2. Option B: 1/R²
    3. Option C: 1/R³
    4. Option D: 1/R⁴
    Show answer & explanation

    Correct answer: (C) 1/R³

    Explanation

    The arrangement forms an electric dipole. The electric field due to a dipole at a distant point varies as: E ∝ 1/R³ Hence option (C) is correct.

  50. Question 50 (NEET 2022, Q50)

    Electrostatic Potential and CapacitanceHard
    A capacitor of capacitance C = 900 pF is charged fully by a 100 V battery B as shown in figure (a). Then it is disconnected from the battery and connected to another uncharged capacitor of capacitance C = 900 pF as shown in figure (b). The electrostatic energy stored by the system (b) is:
    1. Option A: 1.5 × 10⁻⁶ J
    2. Option B: 4.5 × 10⁻⁶ J
    3. Option C: 3.25 × 10⁻⁶ J
    4. Option D: 2.25 × 10⁻⁶ J
    Show answer & explanation

    Correct answer: (D) 2.25 × 10⁻⁶ J

    Explanation

    Initial energy: U = ½CV² = ½ × 900×10⁻¹² × (100)² = 4.5 × 10⁻⁶ J After connecting to identical uncharged capacitor, charge redistributes equally and energy becomes half: U' = U/2 = 2.25 × 10⁻⁶ J Hence option (D) is correct.

  51. Question 51 (NEET 2022, Q98)

    AtomsEasy
    If radius of second Bohr orbit of the He+ ion is 105.8 pm, what is the radius of third Bohr orbit of of third Bohr orbit of Li²⁺ ion?
    1. Option A: 158.7 Å
    2. Option B: 158.7 pm
    3. Option C: 15.87 pm
    4. Option D: 1.587 pm
    Show answer & explanation

    Correct answer: (B) 158.7 pm

    Explanation

    For hydrogen-like species: rₙ ∝ n²/Z Given: For He+ (Z = 2), n = 2: r₂ = 105.8 pm For Li2+ (Z = 3), n = 3: r = 105.8 × (3²/3)/(2²/2) = 105.8 × (3/2) = 158.7 pm Hence option (B) is correct.

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