AIPMT 2012 · Physics

AIPMT 2012 Physics Questions with Solutions

The AIPMT 2012 paper had 30 Physics questions from 21 chapters.

System of Particles and Rotational Motion had the most questions (3), followed by Current Electricity, Dual Nature of Radiation and Matter and 5 other chapters with 2 each.

2 questions below have the answer and explanation free; the other 28 are in Premium.

Physics questions
30
Chapters covered
21
Solved free here
2 of 30
Easy / Medium / Hard
9 / 16 / 5

Difficulty is NEET MIND's own tag for each question.

Chapter-wise: AIPMT 2012 Physics

How many questions each chapter had in AIPMT 2012. Open a chapter for its questions from every year.

  1. System of Particles and Rotational Motion3 Qs
  2. Current Electricity2 Qs
  3. Dual Nature of Radiation and Matter2 Qs
  4. Gravitation2 Qs
  5. Laws of Motion2 Qs
  6. Ray Optics and Optical Instruments2 Qs
  7. Semiconductor Electronics2 Qs
  8. Waves2 Qs
  9. Alternating Current1 Q
  10. Atoms1 Q
  11. Electric Charges and Fields1 Q
  12. Electromagnetic Induction1 Q
  13. Electromagnetic Waves1 Q
  14. Electrostatic Potential and Capacitance1 Q
  15. Magnetism and Matter1 Q
  16. Moving Charges and Magnetism1 Q
  17. Nuclei1 Q
  18. Thermal Properties of Matter1 Q
  19. Thermodynamics1 Q
  20. Units and Measurements1 Q
  21. Work, Energy and Power1 Q

All 30 AIPMT 2012 Physics questions

In paper order. Try each one, then open the answer where it is shown.

  1. Question 1 (AIPMT 2012, Q1)

    Alternating CurrentMedium
    The instantaneous values of alternating current and voltage in a circuit are given as i=12sin⁡(100πt) Ai=\frac{1}{\sqrt{2}}\sin(100\pi t)\,\text{A} and e=12sin⁡(100πt+π3) Ve=\frac{1}{\sqrt{2}}\sin\left(100\pi t+\frac{\pi}{3}\right)\,\text{V}. The average power consumed in the circuit is:
    1. Option A: 34\frac{\sqrt{3}}{4}
    2. Option B: 12\frac{1}{2}
    3. Option C: 18\frac{1}{8}
    4. Option D: 14\frac{1}{4}

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  2. Question 2 (AIPMT 2012, Q2)

    Current ElectricityEasy
    The power dissipated in the circuit shown in the figure is 30 watts. The value of resistance R is:
    1. Option A: 15 Ω
    2. Option B: 10 Ω
    3. Option C: 30 Ω
    4. Option D: 20 Ω

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  3. Question 3 (AIPMT 2012, Q3)

    Units and MeasurementsMedium
    The dimensions of (μ0ε0)−1/2\left(\mu_0\varepsilon_0\right)^{-1/2} are:
    1. Option A: [L−1T][L^{-1}T]
    2. Option B: [LT−1][LT^{-1}]
    3. Option C: [L1/2T1/2][L^{1/2}T^{1/2}]
    4. Option D: [L1/2T−1/2][L^{1/2}T^{-1/2}]

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  4. Question 4 (AIPMT 2012, Q4)

    ThermodynamicsMedium
    An ideal gas goes from state A to state B via three different processes as indicated in the P-V diagram. If Q1,Q2,Q3Q_1, Q_2, Q_3 indicate the heat absorbed by the gas along the three processes and ΔU1,ΔU2,ΔU3\Delta U_1, \Delta U_2, \Delta U_3 indicate the change in internal energy along the three processes respectively, then:
    1. Option A: Q3>Q2>Q1Q_3 > Q_2 > Q_1 and ΔU1=ΔU2=ΔU3\Delta U_1 = \Delta U_2 = \Delta U_3
    2. Option B: Q1=Q2=Q3Q_1 = Q_2 = Q_3 and ΔU1>ΔU2>ΔU3\Delta U_1 > \Delta U_2 > \Delta U_3
    3. Option C: Q3>Q2>Q1Q_3 > Q_2 > Q_1 and ΔU1>ΔU2>ΔU3\Delta U_1 > \Delta U_2 > \Delta U_3
    4. Option D: Q1>Q2>Q3Q_1 > Q_2 > Q_3 and ΔU1=ΔU2=ΔU3\Delta U_1 = \Delta U_2 = \Delta U_3

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  5. Question 5 (AIPMT 2012, Q5)

    Semiconductor ElectronicsEasy
    To get an output Y = 1 in the given circuit which of the following is correct:
    1. Option A: A = 1, B = 0, C = 1
    2. Option B: A = 1, B = 1, C = 0
    3. Option C: A = 0, B = 1, C = 0
    4. Option D: A = 1, B = 0, C = 0

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  6. Question 6 (AIPMT 2012, Q6)

    Electric Charges and FieldsMedium
    Two metallic spheres of radii 1 cm and 3cm are given charges −1×10−2 C-1\times10^{-2}\,\text{C} and 5×10−2 C5\times10^{-2}\,\text{C} respectively. If these are connected by a conducting wire, the final charge on the bigger sphere is:
    1. Option A: 3×10−2 C3\times10^{-2}\,\text{C}
    2. Option B: 4×10−2 C4\times10^{-2}\,\text{C}
    3. Option C: 1×10−2 C1\times10^{-2}\,\text{C}
    4. Option D: 2×10−2 C2\times10^{-2}\,\text{C}

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  7. Question 7 (AIPMT 2012, Q7)

    Dual Nature of Radiation and MatterEasy
    Two radiations of photon energies 1 eV and 2.5 eV, successively illuminate a photosensitive metallic surface of work function 0.5 eV. The ratio of the maximum speeds of the emitted electrons is:
    1. Option A: 1 : 2
    2. Option B: 1 : 1
    3. Option C: 1 : 5
    4. Option D: 1 : 4

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  8. Question 8 (AIPMT 2012, Q8)

    System of Particles and Rotational MotionMedium
    The moment of inertia of a uniform circular disc is maximum about an axis perpendicular to the disc and passing through:
    1. Option A: C
    2. Option B: D
    3. Option C: A
    4. Option D: B

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  9. Question 9 (AIPMT 2012, Q9)

    WavesHard
    A train moving at a speed of 220 ms−1{m s}^{-1} towards a stationary object emits a sound of frequency 1000 Hz1000\,\text{Hz}. Some of the sound reaching the object gets reflected back to the train as echo. The frequency of the echo as detected by the driver of the train is: (Speed of sound in air is 330 ms−1{m s}^{-1})
    1. Option A: 4000 Hz
    2. Option B: 5000 Hz
    3. Option C: 3000 Hz
    4. Option D: 3500 Hz

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  10. Question 10 (AIPMT 2012, Q10)

    NucleiMedium
    The half life of a radioactive nucleus is 50 days. The time interval (t2−t1)(t_2-t_1) between the time t2t_2 when 23\dfrac{2}{3} of it has decayed and the time t1t_1 when 13\dfrac{1}{3} of it has decayed is:
    1. Option A: 50 days
    2. Option B: 60 days
    3. Option C: 15 days
    4. Option D: 30 days

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  11. Question 11 (AIPMT 2012, Q11)

    Laws of MotionEasy
    A car of mass m is moving on a level circular track of radius R. If μs\mu_s represents the static friction between the road and tyres of the car, the maximum speed of the car in circular motion is given by:
    1. Option A: Rgμs\sqrt{\dfrac{Rg}{\mu_s}}
    2. Option B: mRgμs\sqrt{\dfrac{mRg}{\mu_s}}
    3. Option C: μsRg\sqrt{\mu_s R g}
    4. Option D: μsmRg\sqrt{\mu_s m R g}

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  12. Question 12 (AIPMT 2012, Q12)

    System of Particles and Rotational MotionHard
    A circular platform is mounted on a frictionless vertical axle. Its radius is R = 2 m and its moment of inertia about the axle is 200 kgm2{kg m}^2. A man of mass 50 kg stands on the edge of the platform and begins to walk along the edge at the speed of 1 ms−1{m s}^{-1} relative to the ground. Time taken by the man to complete one revolution is:
    1. Option A: 3π2 s\dfrac{3\pi}{2}\,\text{s}
    2. Option B: 2π s2\pi\,\text{s}
    3. Option C: π2 s\dfrac{\pi}{2}\,\text{s}
    4. Option D: π s\pi\,\text{s}

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  13. Question 13 (AIPMT 2012, Q13)

    Dual Nature of Radiation and MatterMedium
    If the momentum of an electron is changed by P, then the de Broglie wavelength associated with it changes by 0.5%. The initial momentum of electrons will be:
    1. Option A: 400P
    2. Option B: P200\dfrac{P}{200}
    3. Option C: 100P
    4. Option D: 200P

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  14. Question 14 (AIPMT 2012, Q14)

    GravitationEasy
    If vev_e is the escape velocity and vov_o is the orbital velocity of a satellite of orbit close to the Earth's surface, then these are related by:
    1. Option A: vo=vev_o=v_e
    2. Option B: ve=2vov_e=\sqrt{2}v_o
    3. Option C: ve=2 vov_e=\sqrt{2}\,v_o
    4. Option D: vo=2vev_o=\sqrt{2}v_e

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  15. Question 15 (AIPMT 2012, Q15)

    WavesHard
    The equation of simple harmonic wave is given by: y=3sin⁡[π2(50t−x)]y=3\sin\left[\frac{\pi}{2}(50t-x)\right] where x and y are in metres and t is in seconds. The ratio of maximum particle velocity to the wave velocity is:
    1. Option A: 32π\dfrac{3}{2}\pi
    2. Option B: 3π3\pi
    3. Option C: 23π\dfrac{2}{3}\pi
    4. Option D: 2π2\pi

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  16. Question 16 (AIPMT 2012, Q16)

    Moving Charges and MagnetismHard
    A proton carrying 1 MeV kinetic energy is moving in a circular path of radius R in a uniform magnetic field. What should be the energy of an α\alpha-particle to describe a circle of same radius in the same field?
    1. Option A: 1 MeV
    2. Option B: 0.5 MeV
    3. Option C: 4 MeV
    4. Option D: 2 MeV

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  17. Question 17 (AIPMT 2012, Q17)

    System of Particles and Rotational MotionEasy
    Three masses are placed on the x-axis: 300 g at origin, 500 g at x = 40 cm and 400 g at x = 70 cm. The distance of the centre of mass from the origin is:
    1. Option A: 45 cm
    2. Option B: 50 cm
    3. Option C: 30 cm
    4. Option D: 40 cm

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  18. Question 18 (AIPMT 2012, Q18)

    Electromagnetic InductionMedium
    In a coil of resistance 10 Ω, the induced current developed by changing magnetic flux through it is shown in figure as a function of time. The magnitude of change in flux through the coil in Weber is:
    1. Option A: 2
    2. Option B: 6
    3. Option C: 4
    4. Option D: 8

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  19. Question 19 (AIPMT 2012, Q19)

    Electrostatic Potential and CapacitanceMedium
    A parallel plate capacitor has a uniform electric field E in the space between the plates. If the distance between the plates is d and area of each plate is A, the energy stored in the capacitor is:
    1. Option A: E²Ad/ε₀
    2. Option B: (1/2) ε₀E²Ad
    3. Option C: ε₀EAdt/√m
    4. Option D: (1/2) ε₀E²

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  20. Question 20 (AIPMT 2012, Q20)

    Work, Energy and PowerHard
    A car of mass m starts from rest and accelerates so that the instantaneous power delivered to the car has a constant magnitude P₀. The instantaneous velocity of this car is proportional to:
    1. Option A: t¹ᐟ²
    2. Option B: t⁻¹ᐟ²
    3. Option C: t/√m
    4. Option D: t²P₀

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  21. Question 21 (AIPMT 2012, Q21)

    GravitationMedium
    Which one of the following plots represents the variation of gravitational field on a particle with distance r due to a thin spherical shell of radius R? (r is measured from the centre of the spherical shell)
    1. Option A: Option (1)
    2. Option B: Option (2)
    3. Option C: Option (3)
    4. Option D: Option (4)

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  22. Question 22 (AIPMT 2012, Q22)

    Semiconductor ElectronicsMedium
    The input resistance of a silicon transistor is 100 Ω. Base current is changed by 40 μA which results in a change in collector current by 2 mA. This transistor is used as a common emitter amplifier with a load resistance of 4 kΩ. The voltage gain of the amplifier is:
    1. Option A: 3000
    2. Option B: 4000
    3. Option C: 1000
    4. Option D: 2000

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  23. Question 23 (AIPMT 2012, Q23)

    Ray Optics and Optical InstrumentsMedium
    For the angle of minimum deviation of a prism to be equal to its refracting angle, the prism must be made of a material whose refractive index:
    1. Option A: Lies between 2 and √2
    2. Option B: Is less than 1
    3. Option C: Is greater than 2
    4. Option D: Lies between √2 and 1

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  24. Question 24 (AIPMT 2012, Q24)

    AtomsEasy
    The transition from the state n = 3 to n = 1 in a hydrogen like atom results in ultraviolet radiation. Infrared radiation will be obtained in the transition from:
    1. Option A: 3 → 2
    2. Option B: 4 → 2
    3. Option C: 4 → 3
    4. Option D: 2 → 1

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  25. Question 25 (AIPMT 2012, Q25)

    Ray Optics and Optical InstrumentsMedium
    A rod of length 10 cm lies along the principal axis of a concave mirror of focal length 10 cm in such a way that its end closer to the pole is 20 cm away from the mirror. The length of the image is:
    1. Option A: 15 cm
    2. Option B: 2.5 cm
    3. Option C: 5 cm
    4. Option D: 10 cm

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  26. Question 26 (AIPMT 2012, Q26)

    Thermal Properties of MatterMedium
    A slab of stone of area 0.36 m² and thickness 0.1 m is exposed on the lower surface to steam at 100°C. A block of ice at 0°C rests on the upper surface of the slab. In one hour 4.8 kg of ice is melted. (Given latent heat of fusion of ice = 3.36 × 105^5 J kg⁻¹) The thermal conductivity of slab is:
    1. Option A: 1.29 J/m/s/°C
    2. Option B: 2.05 J/m/s/°C
    3. Option C: 1.02 J/m/s/°C
    4. Option D: 1.24 J/m/s/°C
    Show answer & explanation

    Correct answer: (D) 1.24 J/m/s/°C

    Explanation

    Heat conducted in one hour melts ice: Q=mL=4.8×3.36×105Q = mL = 4.8 \times 3.36 \times 10^5 Q=1.6128×106 JQ = 1.6128 \times 10^6\,J Using conduction formula: Q=kAΔT tdQ = \frac{kA\Delta T\, t}{d} Where: - A=0.36 m2A = 0.36\,m^2 - ΔT=100∘C\Delta T = 100^\circ C - t=3600 st = 3600\,s - d=0.1 md = 0.1\,m Therefore: k=QdAΔTtk = \frac{Qd}{A\Delta T t} k=1.6128×106×0.10.36×100×3600k = \frac{1.6128 \times 10^6 \times 0.1}{0.36 \times 100 \times 3600} k≈1.24 J m−1 s−1 ∘C−1k \approx 1.24\,J\,m^{-1}\,s^{-1}\,^\circ C^{-1} Hence option (D) is correct.

  27. Question 27 (AIPMT 2012, Q27)

    Laws of MotionEasy
    A stone is dropped from a height h. It hits the ground with a certain momentum P. If the same stone is dropped from a height 100% more than previous height, the momentum when it hits the ground will change by:
    1. Option A: 41%
    2. Option B: 200%
    3. Option C: 100%
    4. Option D: 68%

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  28. Question 28 (AIPMT 2012, Q28)

    Current ElectricityMedium
    A cell having an emf ε and internal resistance r is connected across a variable external resistance R. As the resistance R is increased, the plot of potential difference V across R is given by:
    1. Option A: Graph (1)
    2. Option B: Graph (2)
    3. Option C: Graph (3)
    4. Option D: Graph (4)

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  29. Question 29 (AIPMT 2012, Q29)

    Magnetism and MatterMedium
    A magnetic needle suspended parallel to a magnetic field requires √3 J of work to turn it through 60°. The torque needed to maintain the needle in this position will be:
    1. Option A: 3 J
    2. Option B: √3 J
    3. Option C: 3/2 J
    4. Option A: 2√3 J
    Show answer & explanation

    Correct answer: (A) 3 J, (A) 2√3 J

    Explanation

    Work done in rotating magnetic dipole: W=MB(1−cos⁡θ)W = MB(1 - \cos\theta) Given: W=3 J,θ=60∘W = \sqrt{3}\,J, \quad \theta = 60^\circ 3=MB(1−12)\sqrt{3} = MB\left(1 - \frac{1}{2}\right) MB=23MB = 2\sqrt{3} Torque required: τ=MBsin⁡θ\tau = MB\sin\theta τ=23×32=3 J\tau = 2\sqrt{3} \times \frac{\sqrt{3}}{2} = 3\,J Hence option (A) is correct.

  30. Question 30 (AIPMT 2012, Q30)

    Electromagnetic WavesEasy
    The ratio of amplitude of magnetic field to the amplitude of electric field for an electromagnetic wave propagating in vacuum is equal to:
    1. Option A: Reciprocal of speed of light in vacuum
    2. Option B: The ratio of magnetic permeability to the electric susceptibility of vacuum
    3. Option C: Unity
    4. Option D: The speed of light in vacuum

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