AIPMT 2012 · Chemistry

AIPMT 2012 Chemistry Questions with Solutions

The AIPMT 2012 paper had 30 Chemistry questions from 18 chapters.

Electrochemistry and The d- and f-Block Elements had the most questions (4 each), followed by Aldehydes, Ketones and Carboxylic Acids with 3.

4 questions below have the answer and explanation free; the other 26 are in Premium.

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Chemistry questions: 30
Chapters covered: 18
Solved free here: 4 of 30
Easy / Medium / Hard: 6 / 13 / 11

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Chapter-wise: AIPMT 2012 Chemistry

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All 30 AIPMT 2012 Chemistry questions

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Question 1 (AIPMT 2012, Q91)
Coordination CompoundsMedium
Red precipitate is obtained when ethanol solution of dimethylglyoxime is added to ammoniacal Ni(II). Which of the following statements is not true?
1. Option A: Complex has symmetrical H-bonding
2. Option B: Red complex has a tetrahedral geometry
3. Option C: Dimethylglyoxime functions as bidentate ligand
4. Option D: Red complex has a square planar geometry
The answer and explanation for this question are in NEET MIND Premium.
Question 2 (AIPMT 2012, Q92)
Chemical Bonding and Molecular StructureMedium
During change of O₂ to O₂⁻ ion, the electron adds on which one of the following orbitals?
1. Option A: π orbital
2. Option B: σ* orbital
3. Option C: σ orbital
4. Option D: π* orbital
The answer and explanation for this question are in NEET MIND Premium.
Question 3 (AIPMT 2012, Q93)
Aldehydes, Ketones and Carboxylic AcidsMedium
Consider the reaction: RCHO + NH₂NH₂ → RCH = N – NH₂ What sort of reaction is it?
1. Option A: Free radical addition–elimination reaction
2. Option B: Electrophilic substitution elimination reaction
3. Option C: Nucleophilic addition–elimination reaction
4. Option D: Electrophilic addition–elimination reaction
The answer and explanation for this question are in NEET MIND Premium.
Question 4 (AIPMT 2012, Q94)
The d- and f-Block ElementsHard
In which of the following arrangements the given sequence is not strictly according to the property indicated against it?
1. Option A: H₂O < H₂S < H₂Se < H₂Te : increasing pKa values
2. Option B: NH₃ < PH₃ < AsH₃ < SbH₃ : increasing acidic character
3. Option C: CO₂ < SiO₂ < SnO₂ < PbO₂ : increasing oxidizing power
4. Option D: HF < HCl < HBr < HI : increasing acidic strength
The answer and explanation for this question are in NEET MIND Premium.
Question 5 (AIPMT 2012, Q95)
ElectrochemistryHard
The Gibbs energy for the decomposition of Al₂O₃ at 500°C is as follows: $\frac{2}{3}Al_2O_3 \rightarrow \frac{4}{3}Al + O_2$ $\Delta_r G = +960\,kJ\,mol^{-1}$ The potential difference needed for the electrolytic reduction of aluminium oxide (Al₂O₃) at 500°C is at least:
1. Option A: 3.0 V
2. Option B: 2.5 V
3. Option C: 5.0 V
4. Option D: 4.5 V
The answer and explanation for this question are in NEET MIND Premium.
Question 6 (AIPMT 2012, Q96)
EquilibriumMedium
Given that the equilibrium constant for the reaction $2SO_2(g) + O_2(g) \rightleftharpoons 2SO_3(g)$ has a value of 278 at a particular temperature. What is the value of the equilibrium constant for the following reaction at the same temperature? $SO_3(g) \rightleftharpoons SO_2(g) + \frac{1}{2}O_2(g)$
1. Option A: 3.6 × 10⁻³
2. Option B: 6.0 × 10⁻²
3. Option C: 1.3 × 10⁻⁵
4. Option D: 1.8 × 10⁻³
The answer and explanation for this question are in NEET MIND Premium.
Question 7 (AIPMT 2012, Q97)
Alcohols, Phenols and EthersEasy
Which of the following compounds can be used as antifreeze in automobile radiators?
1. Option A: Glycol
2. Option B: Nitrophenol
3. Option C: Ethyl alcohol
4. Option D: Methyl alcohol
The answer and explanation for this question are in NEET MIND Premium.
Question 8 (AIPMT 2012, Q98)
ElectrochemistryHard
Molar conductivities (Λₘ°) at infinite dilution of NaCl, HCl and CH₃COONa are 126.4, 425.9 and 91.0 S cm² mol⁻¹ respectively. Λₘ° for CH₃COOH will be :
1. Option A: 180.5 S cm² mol⁻¹
2. Option B: 290.8 S cm² mol⁻¹
3. Option C: 390.5 S cm² mol⁻¹
4. Option D: 425.5 S cm² mol⁻¹
The answer and explanation for this question are in NEET MIND Premium.
Question 9 (AIPMT 2012, Q99)
SolutionsHard
Vapour pressure of chloroform (CHCl₃) and dichloromethane (CH₂Cl₂) at 25°C are 200 mmHg and 41.5 mmHg respectively. Vapour pressure of the solution obtained by mixing 25.5 g of CHCl₃ and 40 g of CH₂Cl₂ at the same temperature will be:
1. Option A: 615.0 mmHg
2. Option B: 347.9 mmHg
3. Option C: 285.5 mmHg
4. Option D: 173.9 mmHg
The answer and explanation for this question are in NEET MIND Premium.
Question 10 (AIPMT 2012, Q100)
Some Basic Concepts of ChemistryEasy
A certain gas takes three times as long to effuse out as helium. Its molecular mass will be:
1. Option A: 36 u
2. Option B: 64 u
3. Option C: 9 u
4. Option D: 27 u
The answer and explanation for this question are in NEET MIND Premium.
Question 11 (AIPMT 2012, Q101)
PolymersHard
Which one of the following sets forms the biodegradable polymer?
1. Option A: Option (1)
2. Option B: Option (2)
3. Option C: Option (3)
4. Option D: Option (4)
Show answer & explanationHide answer & explanation
Correct answer: (A) Option (1)
Explanation
The polymer formed from amino acids such as glycine and aminocaproic acid is biodegradable due to peptide-like linkages. The other polymers are synthetic non-biodegradable polymers. Therefore, option (A) is correct.
Question 12 (AIPMT 2012, Q102)
The d- and f-Block ElementsEasy
The catalytic activity of transition metals and their compounds is ascribed mainly to:
1. Option A: Their unfilled d-orbitals
2. Option B: Their ability to adopt variable oxidation states
3. Option C: Their chemical reactivity
4. Option D: Their magnetic behavior
The answer and explanation for this question are in NEET MIND Premium.
Question 13 (AIPMT 2012, Q103)
EquilibriumMedium
Given the reaction between two gases represented by A₂ and B₂ to give the compound AB: $A_2(g) + B_2(g) \rightleftharpoons 2AB(g)$ At equilibrium, the concentration: $[A_2] = 3.0 \times 10^{-3} M$ $[B_2] = 4.2 \times 10^{-3} M$ $[AB] = 2.8 \times 10^{-3} M$ If the reaction takes place in a sealed vessel at 527°C, then the value of (KC) will be:
1. Option A: 1.9
2. Option B: 0.62
3. Option C: 4.5
4. Option D: 2.0
The answer and explanation for this question are in NEET MIND Premium.
Question 14 (AIPMT 2012, Q104)
ElectrochemistryMedium
Standard reduction potentials of the half reactions are given below: $F_2(g) + 2e^- \rightarrow 2F^-_{(aq)} ; E^0 = +2.85V$ $Cl_2(g) + 2e^- \rightarrow 2Cl^-_{(aq)} ; E^0 = +1.36V$ $Br_2(l) + 2e^- \rightarrow 2Br^-_{(aq)} ; E^0 = +1.06V$ $I_2(s) + 2e^- \rightarrow 2I^-_{(aq)} ; E^0 = +0.53V$ The strongest oxidizing and reducing agents respectively are:
1. Option A: Br₂ and Cl⁻
2. Option B: Cl₂ and Br⁻
3. Option C: Cl₂ and I₂
4. Option D: F₂ and I⁻
The answer and explanation for this question are in NEET MIND Premium.
Question 15 (AIPMT 2012, Q105)
Chemical Bonding and Molecular StructureHard
For diatomic species listed below, identify the correct order in which the bond order is increasing in them:
1. Option A: O₂⁻ < NO < C₂²⁻ < He₂⁺
2. Option B: C₂²⁻ < He₂⁺ < O₂⁻ < NO
3. Option C: He₂⁺ < O₂⁻ < NO < C₂²⁻
4. Option D: NO < O₂⁻ < C₂²⁻ < He₂⁺
The answer and explanation for this question are in NEET MIND Premium.
Question 16 (AIPMT 2012, Q106)
Coordination CompoundsHard
Low spin complex of (d $^6$ ) cation in an octahedral field will have the following energy: Δ₀ = crystal field splitting energy in octahedral field, (P) = electron pairing energy)
1. Option A: -12/5 Δ₀ + 3P
2. Option B: -2/5 Δ₀ + 2P
3. Option C: -2/5 Δ₀ + P
4. Option D: -12/5 Δ₀ + P
The answer and explanation for this question are in NEET MIND Premium.
Question 17 (AIPMT 2012, Q107)
Aldehydes, Ketones and Carboxylic AcidsEasy
Which of the following compounds will give yellow precipitate with iodine and alkali?
1. Option A: Methyl acetate
2. Option B: Acetamide
3. Option C: 2-Hydroxypropane
4. Option D: Acetophenone
The answer and explanation for this question are in NEET MIND Premium.
Question 18 (AIPMT 2012, Q108)
Structure of AtomMedium
The orbital angular momentum of a p-electron is given as:
1. Option A: Option (1)
2. Option B: Option (2)
3. Option C: Option (3)
4. Option D: Option (4)
The answer and explanation for this question are in NEET MIND Premium.
Question 19 (AIPMT 2012, Q109)
The d- and f-Block ElementsHard
Which one of the following does not correctly represent the order of the property indicated against it?
1. Option A: Ti³⁺ < V³⁺ < Cr³⁺ < Mn³⁺ : increasing magnetic moment
2. Option B: Ti < V < Cr < Mn : increasing melting points
3. Option C: Ti < V < Mn < Cr : increasing 2nd ionization enthalpy
4. Option D: Ti < V < Cr < Mn : increasing number of oxidation states
The answer and explanation for this question are in NEET MIND Premium.
Question 20 (AIPMT 2012, Q110)
Chemistry In Everyday LifeEasy
Chloroamphenicol is an:
1. Option A: Antihistaminic
2. Option B: Antiseptic and disinfectant
3. Option C: Antibiotic – broad spectrum
4. Option D: Antifertility drug
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Correct answer: (C) Antibiotic – broad spectrum
Explanation
Chloramphenicol is a broad-spectrum antibiotic effective against many bacteria. Therefore, option (C) is correct.
Question 21 (AIPMT 2012, Q111)
Aldehydes, Ketones and Carboxylic AcidsMedium
Consider the following reaction: The product 'A' is:
1. Option A: C₆H₅OH
2. Option B: C₆H₅COOH $_3$
3. Option C: C₆H₅Cl
4. Option D: C₆H₅CHO
The answer and explanation for this question are in NEET MIND Premium.
Question 22 (AIPMT 2012, Q112)
HydrocarbonsEasy
Which one of the following reagents will be able to distinguish between 1-butyne and 2-butyne?
1. Option A: HCl
2. Option B: O₂
3. Option C: Br₂
4. Option D: NaNH₂
The answer and explanation for this question are in NEET MIND Premium.
Question 23 (AIPMT 2012, Q113)
Some Basic Concepts of ChemistryHard
For real gases van der Waals equation is written as $\left(p + \frac{an^2}{V^2}\right)(V-nb)=nRT$ where 'a' and 'b' are van der Waals constants. Two sets of gases are: (I) O₂, CO₂, H₂ and He (II) CH₄, O₂ and H₂ The gases given in set-I in increasing order of 'b' and gases given in set-II in decreasing order of 'a' are arranged below. Select the correct order from the following:
1. Option A: (I) O₂ < He < H₂ < CO₂ ; (II) H₂ > O₂ > CH₄
2. Option B: (I) H₂ < He < O₂ < CO₂ ; (II) CH₄ > O₂ > H₂
3. Option C: (I) H₂ < O₂ < He < CO₂ ; (II) O₂ > CH₄ > H₂
4. Option D: (I) He < H₂ < CO < O₂ ; (II) CH₄ > H₂ > O₂
The answer and explanation for this question are in NEET MIND Premium.
Question 24 (AIPMT 2012, Q114)
Chemical KineticsMedium
Activation energy (Eₐ) and rate constants (k₁ and k₂) of a chemical reaction at two different temperatures (T₁ and T₂) related by :
1. Option A: Option (1)
2. Option B: Option (2)
3. Option C: Option (3)
4. Option D: Option (4)
The answer and explanation for this question are in NEET MIND Premium.
Question 25 (AIPMT 2012, Q115)
The d- and f-Block ElementsMedium
Which of the following exhibits only +3 oxidation state?
1. Option A: Th
2. Option B: Ac
3. Option C: Pa
4. Option D: U
The answer and explanation for this question are in NEET MIND Premium.
Question 26 (AIPMT 2012, Q116)
ThermodynamicsMedium
Equal volumes of two monoatomic gases A and B at same temperature and pressure are mixed. The ratio of specific heats (C $_p$ /C $_v$ ) of the mixture will be:
1. Option A: 1.50
2. Option B: 3.3
3. Option C: 1.67
4. Option D: 0.83
The answer and explanation for this question are in NEET MIND Premium.
Question 27 (AIPMT 2012, Q117)
Solid StateHard
Structure of a mixed oxide is cubic close-packed (c.c.p). The cubic unit cell of mixed oxide is composed of oxide ions. One fourth of the tetrahedral voids are occupied by divalent metal A and the octahedral voids are occupied by a monovalent metal B. The formula of the oxide is:
1. Option A: A₂BO₂
2. Option B: A₂B₃O₄
3. Option C: AB₂O₂
4. Option D: ABO₂
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Correct answer: (C) AB₂O₂
Explanation
In ccp arrangement of oxide ions: If oxide ions = 4, Tetrahedral voids = 8 → one fourth occupied = 2 A²⁺ ions Octahedral voids = 4 → fully occupied = 4 B⁺ ions Thus ratio: $A:B:O = 2:4:4 = 1:2:2$ Balancing charge: $2(+2) + 4(+1) = 8$ For oxide ions: $4(-2) = -8$ Hence empirical formula becomes: $A_2B_3O_4$ Therefore, option (B) is correct.
Question 28 (AIPMT 2012, Q118)
ElectrochemistryMedium
Four successive members of the first series of the transition metals are listed below. For which one of the standard potential (E°M²⁺⁄M) value has a positive sign?
1. Option A: Ni (Z = 28)
2. Option B: Cu (Z = 29)
3. Option C: Fe (Z = 26)
4. Option D: Co (Z = 27)
The answer and explanation for this question are in NEET MIND Premium.
Question 29 (AIPMT 2012, Q119)
S-Block ElementsMedium
In the replacement reaction $Cl + MF \rightarrow CF + MI$ The reaction will be most favourable if M happens to be:
1. Option A: K
2. Option B: Rb
3. Option C: Li
4. Option D: Na
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Correct answer: (B) Rb
Explanation
Lithium forms the most stable fluoride due to high lattice enthalpy of LiF. Hence the reaction becomes most favorable when M is lithium. Therefore, option (C) is correct.
Question 30 (AIPMT 2012, Q120)
AminesHard
An organic compound (C₃H₉N) (A), when treated with nitrous acid, gave an alcohol and N₂ gas was evolved. (A) on warming with CHCl₃ and caustic potash gave (C) which on reduction gave isopropylmethylamine. Predict the structure of (A).
1. Option A: Option (1)
2. Option B: Option (2)
3. Option C: Option (3)
4. Option D: Option (4)
The answer and explanation for this question are in NEET MIND Premium.

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