NEET 2018 · Chemistry

NEET 2018 Chemistry Questions with Solutions

The NEET 2018 paper had 45 Chemistry questions from 22 chapters.

Coordination Compounds had the most questions (5), followed by Organic Chemistry: Some Basic Principles and Techniques with 4.

18 questions below have the answer and explanation free; the other 27 are in Premium.

Practise NEET 2018 Chemistry free

Chemistry questions: 45
Chapters covered: 22
Solved free here: 18 of 45
Easy / Medium / Hard: 13 / 23 / 9

Difficulty is NEET MIND's own tag for each question.

Chapter-wise: NEET 2018 Chemistry

How many questions each chapter had in NEET 2018. Open a chapter for its questions from every year.

All 45 NEET 2018 Chemistry questions

In paper order. Try each one, then open the answer where it is shown.

Question 1 (NEET 2018, Q136)
Classification of Elements and Periodicity in PropertiesEasy
The correct order of N-compounds in its decreasing order of oxidation states is
1. Option A: HNO₃, NO, N₂, NH₄Cl
2. Option B: HNO₃, NO, NH₄Cl, N₂
3. Option C: NH₄Cl, N₂, NO, HNO₃
4. Option D: HNO₃, NH₄Cl, NO, N₂
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Correct answer: (A) HNO₃, NO, N₂, NH₄Cl
Explanation
Oxidation states of nitrogen are: - In HNO₃ : +5 - In NO : +2 - In N₂ : 0 - In NH₄Cl : -3 Therefore, the decreasing order is: $\mathrm{HNO_3 > NO > N_2 > NH_4Cl}$ Hence, option (A) is correct.
Question 2 (NEET 2018, Q137)
Classification of Elements and Periodicity in PropertiesMedium
The correct order of atomic radii in group 13 elements is
1. Option A: B < Al < In < Ga < Tl
2. Option B: B < Al < Ga < In < Tl
3. Option C: B < Ga < Al < In < Tl
4. Option D: B < Ga < Al < Tl < In
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Correct answer: (C) B < Ga < Al < In < Tl
Explanation
Due to d-block contraction, gallium has a slightly smaller atomic radius than aluminium. Thus, the correct order is: $\mathrm{B < Ga < Al < In < Tl}$ Hence, option (C) is correct.
Question 3 (NEET 2018, Q138)
General Principles And Processes Of Isolation Of ElementsMedium
Considering Ellingham diagram, which of the following metals can be used to reduce alumina?
1. Option A: Fe
2. Option B: Zn
3. Option C: Cu
4. Option D: Mg
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Correct answer: (D) Mg
Explanation
A metal more reactive than aluminium can reduce alumina. Magnesium is more reactive than aluminium and can reduce Al₂O₃. Hence, option (D) is correct.
Question 4 (NEET 2018, Q139)
The d- and f-Block ElementsMedium
Which one of the following elements is unable to form MF₆³⁻ ion?
1. Option A: Ga
2. Option B: Al
3. Option C: In
4. Option D: B
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Question 5 (NEET 2018, Q140)
The d- and f-Block ElementsMedium
Which of the following statements is not true for halogens?
1. Option A: All form monobasic oxyacids
2. Option B: All are oxidizing agents
3. Option C: Chlorine has the highest electron-gain enthalpy
4. Option D: All but fluorine show positive oxidation states
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Question 6 (NEET 2018, Q141)
Chemical Bonding and Molecular StructureMedium
In the structure of ClF₃, the number of lone pair of electrons on central atom 'Cl' is
1. Option A: One
2. Option B: Two
3. Option C: Three
4. Option D: Four
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Question 7 (NEET 2018, Q142)
BiomoleculesMedium
The difference between amylose and amylopectin is
1. Option A: Amylopectin have 1 → 4 α-linkage and 1 → 6 α-linkage
2. Option B: Amylose have 1 → 4 α-linkage and 1 → 6 β-linkage
3. Option C: Amylose is made up of glucose and galactose
4. Option D: Amylopectin have 1 → 4 α-linkage and 1 → 6 β-linkage
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Correct answer: (A) Amylopectin have 1 → 4 α-linkage and 1 → 6 α-linkage
Explanation
Amylose is a linear polymer of α-D-glucose linked through α(1→4) glycosidic bonds. Amylopectin is branched and contains both α(1→4) and α(1→6) glycosidic linkages. Hence, option (A) is correct.
Question 8 (NEET 2018, Q143)
PolymersMedium
Regarding cross-linked or network polymers, which of the following statements is incorrect?
1. Option A: They contain covalent bonds between various linear polymer chains.
2. Option B: They are formed from bi- and tri-functional monomers.
3. Option C: They contain strong covalent bonds in their polymer chains.
4. Option D: Examples are bakelite and melamine.
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Correct answer: (C) They contain strong covalent bonds in their polymer chains.
Explanation
Cross-linked or network polymers are formed from bi-functional and tri-functional monomers. They contain covalent bonds between different polymer chains, producing a three-dimensional network structure. Examples include bakelite and melamine. Statement (3) is not specific to cross-linking because all polymers contain covalent bonds within their chains. Hence, option (C) is incorrect.
Question 9 (NEET 2018, Q144)
Organic Chemistry: Some Basic Principles and TechniquesHard
A mixture of 2.3 g formic acid and 4.5 g oxalic acid is treated with conc. H₂SO₄. The evolved gaseous mixture is passed through KOH pellets. Weight (in g) of the remaining product at STP will be
1. Option A: 1.4
2. Option B: 3.0
3. Option C: 4.4
4. Option D: 2.8
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Question 10 (NEET 2018, Q145)
The d- and f-Block ElementsEasy
Which of the following oxides is most acidic in nature?
1. Option A: MgO
2. Option B: BeO
3. Option C: CaO
4. Option D: BaO
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Question 11 (NEET 2018, Q146)
AminesHard
Nitration of aniline in strong acidic medium also gives m-nitroaniline because
1. Option A: Inspite of substituents nitro group always goes to only m-position.
2. Option B: In electrophilic substitution reactions amino group is meta directive.
3. Option C: In acidic (strong) medium aniline is present as anilinium ion.
4. Option D: In absence of substituents nitro group always goes to m-position.
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Correct answer: (C) In acidic (strong) medium aniline is present as anilinium ion.
Explanation
In strongly acidic medium, aniline gets protonated to form anilinium ion (–NH₃⁺). The anilinium ion is meta-directing, leading to significant formation of m-nitroaniline during nitration. Hence, option (C) is correct.
Question 12 (NEET 2018, Q147)
Alcohols, Phenols and EthersMedium
The compound A on treatment with Na gives B, and with PCl₅ gives C. B and C react together to give diethyl ether. A, B and C are in the order
1. Option A: C₂H₅OH, C₂H₆, C₂H₅Cl
2. Option B: C₂H₅OH, C₂H₅Cl, C₂H₅ONa
3. Option C: C₂H₅OH, C₂H₅ONa, C₂H₅Cl
4. Option D: C₂H₅Cl, C₂H₆, C₂H₅OH
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Question 13 (NEET 2018, Q148)
HydrocarbonsMedium
Hydrocarbon (A) reacts with bromine by substitution to form an alkyl bromide which by Wurtz reaction is converted to gaseous hydrocarbon containing less than four carbon atoms. (A) is
1. Option A: CH ≡ CH
2. Option B: CH₂ = CH₂
3. Option C: CH₄
4. Option D: CH₃–CH₃
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Question 14 (NEET 2018, Q149)
HydrocarbonsHard
The compound C₇H₈ undergoes the following reactions: The product 'C' is
1. Option A: m-bromotoluene
2. Option B: o-bromotoluene
3. Option C: p-bromotoluene
4. Option D: 3-bromo-2,4,6-trichlorotoluene
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Question 15 (NEET 2018, Q150)
Environmental ChemistryEasy
Which oxide of nitrogen is not a common pollutant introduced into the atmosphere both due to natural and human activity?
1. Option A: N₂O₅
2. Option B: NO₂
3. Option C: NO
4. Option D: N₂O
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Correct answer: (A) N₂O₅
Explanation
Common atmospheric nitrogen oxide pollutants include NO, NO₂ and N₂O produced from combustion processes and natural activities. N₂O₅ is comparatively unstable and is not considered a common atmospheric pollutant. Hence, option (A) is correct.
Question 16 (NEET 2018, Q151)
Organic Chemistry: Some Basic Principles and TechniquesMedium
Which of the following molecules represents the order of hybridisation sp², sp², sp, sp from left to right atoms?
1. Option A: HC ≡ C – C ≡ CH
2. Option B: CH₂ = CH – C ≡ CH
3. Option C: CH₃ – CH = CH – CH₃
4. Option D: CH₂ = CH – CH = CH₂
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Question 17 (NEET 2018, Q152)
Organic Chemistry: Some Basic Principles and TechniquesHard
Which of the following carbocations is expected to be most stable?
1. Option A: Option (1)
2. Option B: Option (2)
3. Option C: Option (3)
4. Option D: Option (4)
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Question 18 (NEET 2018, Q153)
Organic Chemistry: Some Basic Principles and TechniquesMedium
Which of the following is correct with respect to –I effect of the substituents? (R = alkyl)
1. Option A: –NH₂ < –OR < –F
2. Option B: –NR₂ < –OR < –F
3. Option C: –NR₂ > –OR > –F
4. Option D: –NH₂ > –OR > –F
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Question 19 (NEET 2018, Q154)
Alcohols, Phenols and EthersMedium
In the reaction
1. Option A: Option (1)
2. Option B: Option (2)
3. Option C: Option (3)
4. Option D: Option (4)
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Question 20 (NEET 2018, Q155)
Aldehydes, Ketones and Carboxylic AcidsEasy
Carboxylic acids have higher boiling points than aldehydes, ketones and even alcohols of comparable molecular mass. It is due to their
1. Option A: Formation of intramolecular H-bonding
2. Option B: Formation of carboxylate ion
3. Option C: Formation of intermolecular H-bonding
4. Option D: More extensive association of carboxylic acid via van der Waals force of attraction
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Correct answer: (C) Formation of intermolecular H-bonding
Explanation
Carboxylic acids form strong intermolecular hydrogen bonds and exist as associated dimers. This increases intermolecular attraction and raises the boiling point. Hence, option (C) is correct.
Question 21 (NEET 2018, Q156)
Aldehydes, Ketones and Carboxylic AcidsMedium
Compound A, C₈H₁₀O, is found to react with NaOI (produced by reacting Y with NaOH) and yields a yellow precipitate with characteristic smell. A and Y are respectively
1. Option A: Option (1)
2. Option B: Option (2)
3. Option C: Option (3)
4. Option D: Option (4)
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Correct answer: (D) Option (4)
Explanation
The iodoform test is given by compounds containing the group: $\mathrm{CH_3-CH(OH)-}$ or compounds oxidisable to methyl ketones. 1-Phenylethanol (C₆H₅CH(OH)CH₃) is a secondary alcohol that gets oxidised to acetophenone, which gives the iodoform test. Hence, option (D) is correct.
Question 22 (NEET 2018, Q157)
HydrocarbonsHard
Identify the major products P, Q and R in the following sequence of reactions:
1. Option A: Option (1)
2. Option B: Option (2)
3. Option C: Option (3)
4. Option D: Option (4)
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Question 23 (NEET 2018, Q158)
AminesEasy
Which of the following compounds can form a zwitterion?
1. Option A: Aniline
2. Option B: Acetanilide
3. Option C: Glycine
4. Option D: Benzoic acid
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Correct answer: (C) Glycine
Explanation
A zwitterion contains both positive and negative charges in the same molecule. Glycine contains both amino (–NH₂) and carboxylic acid (–COOH) groups and exists as: $\mathrm{H_3N^+{-}CH_2{-}COO^-}$ Hence, glycine forms a zwitterion. Therefore, option (C) is correct.
Question 24 (NEET 2018, Q159)
Redox ReactionsMedium
For the redox reaction: $\mathrm{MnO_4^- + C_2O_4^{2-} + H^+ \rightarrow Mn^{2+} + CO_2 + H_2O}$ The correct coefficients of the reactants for the balanced equation are
1. Option A: Option (1)
2. Option B: Option (2)
3. Option C: Option (3)
4. Option D: Option (4)
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Correct answer: (B) Option (2)
Explanation
The balanced redox reaction in acidic medium is: $\mathrm{2MnO_4^- + 5C_2O_4^{2-} + 16H^+ \rightarrow 2Mn^{2+} + 10CO_2 + 8H_2O}$ Thus, the coefficients of: - MnO₄⁻ = 2 - C₂O₄²⁻ = 5 - H⁺ = 16 Hence, option (B) is correct.
Question 25 (NEET 2018, Q160)
EquilibriumEasy
Which one of the following conditions will favour maximum formation of the product in the reaction,
1. Option A: Low temperature and high pressure
2. Option B: Low temperature and low pressure
3. Option C: High temperature and low pressure
4. Option D: High temperature and high pressure
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Question 26 (NEET 2018, Q161)
Chemical KineticsEasy
When initial concentration of the reactant is doubled, the half-life period of a zero order reaction
1. Option A: Is halved
2. Option B: Is doubled
3. Option C: Remains unchanged
4. Option D: Is tripled
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Question 27 (NEET 2018, Q162)
Some Basic Concepts of ChemistryEasy
The correction factor 'a' to the ideal gas equation corresponds to
1. Option A: Density of the gas molecules
2. Option B: Volume of the gas molecules
3. Option C: Forces of attraction between the gas molecules
4. Option D: Electric field present between the gas molecules
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Question 28 (NEET 2018, Q163)
ThermodynamicsHard
The bond dissociation energies of X₂, Y₂ and XY are in the ratio of 1 : 0.5 : 1. ΔH for the formation of XY is −200 kJ mol⁻¹. The bond dissociation energy of X₂ will be
1. Option A: 200 kJ mol⁻¹
2. Option B: 100 kJ mol⁻¹
3. Option C: 400 kJ mol⁻¹
4. Option D: 800 kJ mol⁻¹
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Correct answer: (D) 800 kJ mol⁻¹
Explanation
For the reaction: $\frac{1}{2}X_2 + \frac{1}{2}Y_2 \rightarrow XY$ Using bond energies: $\Delta H = \left(\frac{x}{2}+\frac{x/2}{2}\right)-x$ $-200 = \left(\frac{x}{2}+\frac{x}{4}\right)-x$ $-200 = -\frac{x}{4}$ $x = 800\text{ kJ mol}^{-1}$ Hence, option (D) is correct.
Question 29 (NEET 2018, Q164)
Classification of Elements and Periodicity in PropertiesEasy
Magnesium reacts with an element (X) to form an ionic compound. If the ground state electronic configuration of X is 1s² 2s² 2p³, the simplest formula for this compound is
1. Option A: Mg₂X₃
2. Option B: MgX₂
3. Option C: Mg₃X₂
4. Option D: Mg₂X
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Correct answer: (C) Mg₃X₂
Explanation
The electronic configuration: $1s^2\ 2s^2\ 2p^3$ belongs to nitrogen. Nitrogen has valency 3 and magnesium has valency 2. Thus, the ionic compound formed is: $\mathrm{Mg_3X_2}$ Hence, option (C) is correct.
Question 30 (NEET 2018, Q165)
Solid StateHard
Iron exhibits bcc structure at room temperature. Above 900°C, it transforms to fcc structure. The ratio of density of iron at room temperature to that at 900°C (assuming molar mass and atomic radius of iron remains constant with temperature) is
1. Option A: √3 / √2
2. Option B: 4√3 / 3√2
3. Option C: 1 / 2
4. Option D: 3√3 / 4√2
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Correct answer: (D) 3√3 / 4√2
Explanation
Density: $\rho = \frac{ZM}{N_A a^3}$ For BCC: $Z=2,\quad a=\frac{4r}{\sqrt3}$ For FCC: $Z=4,\quad a=2\sqrt2 r$ Therefore, $\frac{\rho_{bcc}}{\rho_{fcc}} = \frac{2/(4r/\sqrt3)^3}{4/(2\sqrt2 r)^3}$ $= \frac{3\sqrt3}{4\sqrt2}$ Hence, option (D) is correct.
Question 31 (NEET 2018, Q166)
Chemical Bonding and Molecular StructureMedium
Consider the following species: $CN⁺, CN⁻, NO and CN$ Which one of these will have the highest bond order?
1. Option A: NO
2. Option B: CN⁻
3. Option C: CN
4. Option D: CN⁺
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Question 32 (NEET 2018, Q167)
Structure of AtomMedium
Which one is a wrong statement?
1. Option A: Total orbital angular momentum of electron in s orbital is equal to zero
2. Option B: An orbital is designated by three quantum numbers while an electron in an atom is designated by four quantum numbers
3. Option C: The value of magnetic quantum number for d $_z$ 2 is zero
4. Option D: The given electronic configuration of nitrogen atom
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Correct answer: (D) The given electronic configuration of nitrogen atom
Explanation
According to Hund's rule of maximum multiplicity, electrons in degenerate p-orbitals first occupy each orbital singly with parallel spins before pairing occurs. Therefore, the correct electronic configuration of nitrogen is: 1s² 2s² 2p³ with all three p-electrons having parallel spins. The given diagram violates Hund's rule because one electron has opposite spin.
Question 33 (NEET 2018, Q168)
Chemical KineticsMedium
The correct difference between first and second order reactions is that
1. Option A: The rate of a first-order reaction does not depend on reactant concentrations; the rate of a second-order reaction does depend on reactant concentrations
2. Option B: The half-life of a first-order reaction does not depend on [A]₀; the half-life of a second-order reaction does depend on [A]₀
3. Option C: The rate of a first-order reaction does depend on reactant concentrations; the rate of a second-order reaction does not depend on reactant concentrations
4. Option D: A first-order reaction can be catalyzed; a second-order reaction cannot be catalyzed
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Question 34 (NEET 2018, Q169)
Some Basic Concepts of ChemistryEasy
In which case is number of molecules of water maximum?
1. Option A: 18 mL of water
2. Option B: 0.18 g of water
3. Option C: 10⁻³ mol of water
4. Option D: 0.00224 L of water vapours at 1 atm and 273 K
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Question 35 (NEET 2018, Q170)
HydrogenMedium
Among CaH₂, BeH₂, BaH₂, the order of ionic character is
1. Option A: BeH₂ < CaH₂ < BaH₂
2. Option B: CaH₂ < BeH₂ < BaH₂
3. Option C: BaH₂ < BeH₂ < CaH₂
4. Option D: BeH₂ < BaH₂ < CaH₂
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Correct answer: (A) BeH₂ < CaH₂ < BaH₂
Explanation
In group 2 hydrides, ionic character increases down the group because metallic character increases down the group. BeH₂ is predominantly covalent, while BaH₂ is the most ionic. Therefore, the order of ionic character is: $\mathrm{BeH_2 < CaH_2 < BaH_2}$
Question 36 (NEET 2018, Q171)
Redox ReactionsHard
Consider the change in oxidation state of Bromine corresponding to different E° values as shown in the diagram below. Then the species undergoing disproportionation is
1. Option A: BrO₃⁻
2. Option B: BrO₄⁻
3. Option C: HBrO
4. Option D: Br₂
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Correct answer: (C) HBrO
Explanation
For disproportionation of HBrO: Reduction half reaction: $\mathrm{HBrO \rightarrow Br_2} \qquad E^\circ = 1.595\ V$ Oxidation half reaction: $\mathrm{HBrO \rightarrow BrO_3^-} \qquad E^\circ = 1.5\ V$ Therefore, $E^\circ_{cell} = 1.595 - 1.5 = 0.095\ V$ Since the value is positive, HBrO undergoes disproportionation.
Question 37 (NEET 2018, Q172)
EquilibriumMedium
The solubility of BaSO₄ in water is 2.42 × 10⁻³ g L⁻¹ at 298 K. The value of its solubility product (Ksp) will be (Given molar mass of BaSO₄ = 233 g mol⁻¹)
1. Option A: 1.08 × 10⁻¹⁰ mol² L⁻²
2. Option B: 1.08 × 10⁻¹² mol² L⁻²
3. Option C: 1.08 × 10⁻⁸ mol² L⁻²
4. Option D: 1.08 × 10⁻¹⁴ mol² L⁻²
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Question 38 (NEET 2018, Q173)
EquilibriumMedium
Following solutions were prepared by mixing different volumes of NaOH and HCl of different concentrations: pH of which one of them will be equal to 1?
1. Option A: b
2. Option B: a
3. Option C: c
4. Option D: d
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Question 39 (NEET 2018, Q174)
Surface ChemistryEasy
On which of the following properties does the coagulating power of an ion depend?
1. Option A: The magnitude of the charge on the ion alone
2. Option B: Size of the ion alone
3. Option C: The sign of charge on the ion alone
4. Option D: Both magnitude and sign of the charge on the ion
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Correct answer: (D) Both magnitude and sign of the charge on the ion
Explanation
Coagulation of colloidal solutions by electrolytes depends on the charge present on colloidal particles as well as on the effective ion of the electrolyte. According to the Hardy-Schulze rule, the coagulating power mainly depends on the magnitude of charge of the oppositely charged ion. Hence both magnitude and sign of charge are important.
Question 40 (NEET 2018, Q175)
Some Basic Concepts of ChemistryEasy
Given van der Waals constants for NH₃, H₂, O₂ and CO₂ are respectively 4.17, 0.244, 1.36 and 3.59, which gas is most easily liquefied?
1. Option A: NH₃
2. Option B: H₂
3. Option C: CO₂
4. Option D: O₂
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Question 41 (NEET 2018, Q176)
Coordination CompoundsEasy
Iron carbonyl, Fe(CO)₅ is
1. Option A: Tetranuclear
2. Option B: Mononuclear
3. Option C: Dinuclear
4. Option D: Trinuclear
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Question 42 (NEET 2018, Q177)
Coordination CompoundsMedium
The type of isomerism shown by the complex [CoCl₂(en)₂] is
1. Option A: Geometrical isomerism
2. Option B: Coordination isomerism
3. Option C: Linkage isomerism
4. Option D: Ionization isomerism
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Question 43 (NEET 2018, Q178)
Coordination CompoundsMedium
Which one of the following ions exhibits d-d transition and paramagnetism as well?
1. Option A: CrO₄²⁻
2. Option B: Cr₂O₇²⁻
3. Option C: MnO₄²⁻
4. Option D: MnO₄⁻
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Question 44 (NEET 2018, Q179)
Coordination CompoundsHard
The geometry and magnetic behaviour of the complex [Ni(CO)₄] are
1. Option A: Square planar geometry and diamagnetic
2. Option B: Tetrahedral geometry and diamagnetic
3. Option C: Tetrahedral geometry and paramagnetic
4. Option D: Square planar geometry and paramagnetic
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Question 45 (NEET 2018, Q180)
Coordination CompoundsMedium
Match the metal ions given in Column I with the spin magnetic moments of the ions given in Column II and assign the correct code :
1. Option A: Option (1)
2. Option B: Option (2)
3. Option C: Option (3)
4. Option D: Option (4)
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