AIPMT 2005 · Chemistry

AIPMT 2005 Chemistry Questions with Solutions

The AIPMT 2005 paper had 50 Chemistry questions from 25 chapters.

Chemical Bonding and Molecular Structure had the most questions (6), followed by Organic Chemistry: Some Basic Principles and Techniques with 5.

6 questions below have the answer and explanation free; the other 44 are in Premium.

Chemistry questions
50
Chapters covered
25
Solved free here
6 of 50
Easy / Medium / Hard
13 / 29 / 8

Difficulty is NEET MIND's own tag for each question.

Chapter-wise: AIPMT 2005 Chemistry

How many questions each chapter had in AIPMT 2005. Open a chapter for its questions from every year.

  1. Chemical Bonding and Molecular Structure6 Qs
  2. Organic Chemistry: Some Basic Principles and Techniques5 Qs
  3. Solutions4 Qs
  4. Classification of Elements and Periodicity in Properties3 Qs
  5. Thermodynamics3 Qs
  6. Aldehydes, Ketones and Carboxylic Acids2 Qs
  7. Amines2 Qs
  8. Chemical Kinetics2 Qs
  9. Coordination Compounds2 Qs
  10. Equilibrium2 Qs
  11. Hydrocarbons2 Qs
  12. Hydrogen2 Qs
  13. Solid State2 Qs
  14. The d- and f-Block Elements2 Qs
  15. Alcohols, Phenols and Ethers1 Q
  16. Biomolecules1 Q
  17. Electrochemistry1 Q
  18. General Principles And Processes Of Isolation Of Elements1 Q
  19. Haloalkanes and Haloarenes1 Q
  20. Polymers1 Q
  21. Principles Of Qualitative Analysis1 Q
  22. Redox Reactions1 Q
  23. Some Basic Concepts of Chemistry1 Q
  24. Structure of Atom1 Q
  25. Surface Chemistry1 Q

All 50 AIPMT 2005 Chemistry questions

In paper order. Try each one, then open the answer where it is shown.

  1. Question 1 (AIPMT 2005, Q47)

    Solid StateMedium
    Copper has face-centered cubic (fcc) lattice with interatomic spacing equal to 2.54 A˚2.54\,\text{\AA}. The value of lattice constant for this lattice is:
    1. Option A: 2.29 A˚2.29\,\text{\AA}
    2. Option B: 3.29 A˚3.29\,\text{\AA}
    3. Option C: 2.59 A˚2.59\,\text{\AA}
    4. Option D: 3.59 A˚3.59\,\text{\AA}

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  2. Question 2 (AIPMT 2005, Q51)

    Organic Chemistry: Some Basic Principles and TechniquesEasy
    Which amongst the following is the most stable carbocation?
    1. Option A: Option 1
    2. Option B: Option 2
    3. Option C: Option 3
    4. Option D: Option 4

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  3. Question 3 (AIPMT 2005, Q52)

    HydrocarbonsMedium
    Products of the following reaction:
    1. Option A: Option 1
    2. Option B: Option 2
    3. Option C: Option 3
    4. Option D: Option 4

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  4. Question 4 (AIPMT 2005, Q53)

    EquilibriumMedium
    At 25∘C25^\circ C, the dissociation constant of a base, BOHBOH, is 1.0×10−121.0 \times 10^{-12}. The concentration of hydroxyl ions in 0.01 M0.01\,M aqueous solution of the base would be:
    1. Option A: 1.0×10−6 mol L−11.0 \times 10^{-6}\,mol\,L^{-1}
    2. Option B: 1.0×10−5 mol L−11.0 \times 10^{-5}\,mol\,L^{-1}
    3. Option C: 1.0×10−8 mol L−11.0 \times 10^{-8}\,mol\,L^{-1}
    4. Option D: 1.0×10−7 mol L−11.0 \times 10^{-7}\,mol\,L^{-1}

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  5. Question 5 (AIPMT 2005, Q54)

    Organic Chemistry: Some Basic Principles and TechniquesEasy
    Which one of the following pairs represents stereoisomerism?
    1. Option A: Chain isomerism and rotational isomerism
    2. Option B: Structural isomerism and geometric isomerism
    3. Option C: Linkage isomerism and geometric isomerism
    4. Option D: Optical isomerism and geometric isomerism

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  6. Question 6 (AIPMT 2005, Q55)

    AminesMedium
    Aniline in a set of reactions yielded a product D. The structure of the product D would be:
    1. Option A: C6H5CH2NH2C_6H_5CH_2NH_2
    2. Option B: C6H5NHCH2CH3C_6H_5NHCH_2CH_3
    3. Option C: C6H5NHOHC_6H_5NHOH
    4. Option D: C6H5CH2OHC_6H_5CH_2OH

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  7. Question 7 (AIPMT 2005, Q56)

    Chemical Bonding and Molecular StructureMedium
    The correct order in which the O–O bond length increases in the following is:
    1. Option A: H2O2<O2<O3H_2O_2 < O_2 < O_3
    2. Option B: O3<H2O2<O2O_3 < H_2O_2 < O_2
    3. Option C: O2<O3<H2O2O_2 < O_3 < H_2O_2
    4. Option D: O2<H2O2<O3O_2 < H_2O_2 < O_3

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  8. Question 8 (AIPMT 2005, Q57)

    General Principles And Processes Of Isolation Of ElementsMedium
    The mass of carbon anode consumed (giving only carbon dioxide) in the production of 270 kg270\,kg of aluminium metal from bauxite by the Hall process is: (Atomic mass of Al = 27)
    1. Option A: 180 kg180\,kg
    2. Option B: 120 kg120\,kg
    3. Option C: 360 kg360\,kg
    4. Option D: 90 kg90\,kg
    Show answer & explanation

    Correct answer: (D) 90 kg90\,kg

    Explanation

    In Hall–Héroult process: Cathode reaction: Al3++3e−→AlAl^{3+} + 3e^- \rightarrow Al Anode reaction: C+O2→CO2C + O_2 \rightarrow CO_2 Overall: 2Al2O3+3C→4Al+3CO22Al_2O_3 + 3C \rightarrow 4Al + 3CO_2 Thus, 4 mol Al→3 mol C4\text{ mol Al} \rightarrow 3\text{ mol C} Mass relation: 4×27=108 g Al4 \times 27 = 108\,g\,Al requires 3×12=36 g C3 \times 12 = 36\,g\,C For $270\,kgAl:Al:Carbon required=36108×270\text{Carbon required} = \frac{36}{108} \times 270=90 kg= 90\,kg$ Hence **Option D** is correct.

  9. Question 9 (AIPMT 2005, Q58)

    Aldehydes, Ketones and Carboxylic AcidsHard
    In a set of reactions, acetic acid yielded a product D. The structure of D would be:
    1. Option A: Option 1
    2. Option B: Option 2
    3. Option C: Option 3
    4. Option D: Option 4

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  10. Question 10 (AIPMT 2005, Q60)

    Aldehydes, Ketones and Carboxylic AcidsHard
    The major organic product formed from the following reaction is:
    1. Option A: Option 1
    2. Option B: Option 2
    3. Option C: Option 3
    4. Option D: Option 4

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  11. Question 11 (AIPMT 2005, Q61)

    Redox ReactionsMedium
    The number of moles of KMnO4KMnO_4 reduced by one mole of KIKI in alkaline medium is:
    1. Option A: one fifth
    2. Option B: five
    3. Option C: one
    4. Option D: two
    Show answer & explanation

    Correct answer: (D) two

    Explanation

    In alkaline medium: MnO4−+2H2O+3e−→MnO2+4OH−MnO_4^- + 2H_2O + 3e^- \rightarrow MnO_2 + 4OH^- and iodide is oxidized as: 2I−→I2+2e−2I^- \rightarrow I_2 + 2e^- Balancing electrons gives: 2MnO4−+6I−+4H2O→2MnO2+3I2+8OH−2MnO_4^- + 6I^- + 4H_2O \rightarrow 2MnO_2 + 3I_2 + 8OH^- Thus, 2 mol KMnO4 react with 6 mol KI2\text{ mol } KMnO_4 \text{ react with } 6\text{ mol } KI Therefore, 1 mol KI=26=13 mol KMnO41\text{ mol } KI = \frac{2}{6} = \frac{1}{3}\text{ mol } KMnO_4 But based on the given answer key, the accepted answer is **Option A (one fifth)**.

  12. Question 12 (AIPMT 2005, Q62)

    Chemical Bonding and Molecular StructureEasy
    Which of the following molecules has trigonal planar geometry?
    1. Option A: IF3IF_3
    2. Option B: PCl3PCl_3
    3. Option C: NH3NH_3
    4. Option D: BF3BF_3

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  13. Question 13 (AIPMT 2005, Q63)

    The d- and f-Block ElementsMedium
    The aqueous solution containing which one of the following ions will be colourless? (Atomic no.: Sc=21Sc = 21, Fe=26Fe = 26, Ti=22Ti = 22, Mn=25Mn = 25)
    1. Option A: Sc3+Sc^{3+}
    2. Option B: Fe2+Fe^{2+}
    3. Option C: Ti3+Ti^{3+}
    4. Option D: Mn2+Mn^{2+}

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  14. Question 14 (AIPMT 2005, Q64)

    Classification of Elements and Periodicity in PropertiesHard
    Four successive members of the first row transition elements are listed below with their atomic numbers. Which one of them is expected to have the highest third ionization enthalpy?
    1. Option A: Vanadium (Z=23)(Z = 23)
    2. Option B: Chromium (Z=24)(Z = 24)
    3. Option C: Iron (Z=26)(Z = 26)
    4. Option D: Manganese (Z=25)(Z = 25)

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  15. Question 15 (AIPMT 2005, Q65)

    Alcohols, Phenols and EthersMedium
    Which one of the following compounds is most acidic?
    1. Option A: Option 1
    2. Option B: Option 2
    3. Option C: Option 3
    4. Option D: Option 4

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  16. Question 16 (AIPMT 2005, Q66)

    ThermodynamicsMedium
    A reaction occurs spontaneously if:
    1. Option A: TΔS<ΔHT\Delta S < \Delta H and both ΔH\Delta H and ΔS\Delta S are positive
    2. Option B: TΔS>ΔHT\Delta S > \Delta H and both ΔH\Delta H and ΔS\Delta S are positive
    3. Option C: TΔS=ΔHT\Delta S = \Delta H and both ΔH\Delta H and ΔS\Delta S are positive
    4. Option D: TΔS>ΔHT\Delta S > \Delta H and ΔH\Delta H is positive while ΔS\Delta S is negative

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  17. Question 17 (AIPMT 2005, Q67)

    PolymersMedium
    The monomer of the given polymer is:
    1. Option A: Option 1
    2. Option B: Option 2
    3. Option C: Option 3
    4. Option D: Option 4

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  18. Question 18 (AIPMT 2005, Q68)

    Chemical Bonding and Molecular StructureMedium
    The correct sequence of increasing covalent character is represented by:
    1. Option A: LiCl<NaCl<BeCl2LiCl < NaCl < BeCl_2
    2. Option B: BeCl2<NaCl<LiClBeCl_2 < NaCl < LiCl
    3. Option C: NaCl<LiCl<BeCl2NaCl < LiCl < BeCl_2
    4. Option D: BeCl2<LiCl<NaClBeCl_2 < LiCl < NaCl

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  19. Question 19 (AIPMT 2005, Q69)

    HydrogenHard
    What is the correct relationship between the pH values of isomolar solutions of sodium oxide (pH1pH_1), sodium sulphide (pH2pH_2), sodium selenide (pH3pH_3) and sodium telluride (pH4pH_4)?
    1. Option A: pH1>pH2≈pH3>pH4pH_1 > pH_2 \approx pH_3 > pH_4
    2. Option B: pH1<pH2<pH3<pH4pH_1 < pH_2 < pH_3 < pH_4
    3. Option C: pH1<pH2<pH3≈pH4pH_1 < pH_2 < pH_3 \approx pH_4
    4. Option D: pH1>pH2>pH3>pH4pH_1 > pH_2 > pH_3 > pH_4
    Show answer & explanation

    Correct answer: (D) pH1>pH2>pH3>pH4pH_1 > pH_2 > pH_3 > pH_4

    Explanation

    Basicity depends on hydrolysis of the anions. Down the group acidity of hydrides increases: H2O<H2S<H2Se<H2TeH_2O < H_2S < H_2Se < H_2Te Hence conjugate base strength decreases: O2−>S2−>Se2−>Te2−O^{2-} > S^{2-} > Se^{2-} > Te^{2-} Therefore pH order is: pH1>pH2>pH3>pH4pH_1 > pH_2 > pH_3 > pH_4 Hence **Option D** is correct.

  20. Question 20 (AIPMT 2005, Q70)

    ThermodynamicsEasy
    Which of the following pairs of a chemical reaction is certain to result in a spontaneous reaction?
    1. Option A: Exothermic and decreasing disorder
    2. Option B: Endothermic and increasing disorder
    3. Option C: Exothermic and increasing disorder
    4. Option D: Endothermic and decreasing disorder

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  21. Question 21 (AIPMT 2005, Q71)

    SolutionsMedium
    The vapour pressure of two liquids P and Q are 8080 torr and 6060 torr respectively. The total vapour pressure of solution obtained by mixing 33 moles of P and 22 moles of Q would be:
    1. Option A: 144 torr144\,torr
    2. Option B: 288 torr288\,torr
    3. Option C: 14 torr14\,torr
    4. Option D: 72 torr72\,torr

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  22. Question 22 (AIPMT 2005, Q72)

    HydrocarbonsMedium
    Which one of the following alkenes will react fastest with H2H_2 under catalytic hydrogenation conditions? (R = Alkyl substituent)
    1. Option A: Option 1
    2. Option B: Option 2
    3. Option C: Option 3
    4. Option D: Option 4

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  23. Question 23 (AIPMT 2005, Q73)

    Chemical KineticsMedium
    For a first order reaction A→BA \rightarrow B, the reaction rate at reactant concentration of 0.01 M0.01\,M is found to be 2.0×10−5 mol L−1 s−12.0 \times 10^{-5}\,mol\,L^{-1}\,s^{-1}. The half-life period of the reaction is:
    1. Option A: 227 s227\ s
    2. Option B: 327 s327\ s
    3. Option C: 527 s527\ s
    4. Option D: 347 s347\ s

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  24. Question 24 (AIPMT 2005, Q74)

    Chemical Bonding and Molecular StructureEasy
    Which of the following is the electron deficient molecule?
    1. Option A: B2H6B_2H_6
    2. Option B: C2H6C_2H_6
    3. Option C: PH3PH_3
    4. Option D: SiH4SiH_4

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  25. Question 25 (AIPMT 2005, Q75)

    Classification of Elements and Periodicity in PropertiesMedium
    A nuclide of an alkaline earth metal undergoes radioactive decay by emission of three α\alpha-particles in succession. The group of the periodic table to which the resulting daughter element would belong is:
    1. Option A: Group 14
    2. Option B: Group 16
    3. Option C: Group 4
    4. Option D: Group 6

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  26. Question 26 (AIPMT 2005, Q76)

    Some Basic Concepts of ChemistryEasy
    The surface tension of which of the following liquid is maximum?
    1. Option A: H2OH_2O
    2. Option B: C6H6C_6H_6
    3. Option C: CH3OHCH_3OH
    4. Option D: C2H5OHC_2H_5OH

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  27. Question 27 (AIPMT 2005, Q77)

    ThermodynamicsMedium
    The absolute enthalpy of neutralisation of the reaction: MgO(s)+2HCl(aq)→MgCl2(aq)+H2O(l)MgO(s) + 2HCl(aq) \rightarrow MgCl_2(aq) + H_2O(l) will be:
    1. Option A: less than −57.33 kJ mol−1-57.33\ kJ\ mol^{-1}
    2. Option B: −57.33 kJ mol−1-57.33\ kJ\ mol^{-1}
    3. Option C: greater than −57.33 kJ mol−1-57.33\ kJ\ mol^{-1}
    4. Option D: 57.33 kJ mol−157.33\ kJ\ mol^{-1}

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  28. Question 28 (AIPMT 2005, Q78)

    Surface ChemistryEasy
    Which one of the following forms micelles in aqueous solution above a certain concentration?
    1. Option A: Urea
    2. Option B: Dodecyl trimethyl ammonium chloride
    3. Option C: Pyridinium chloride
    4. Option D: Glucose
    Show answer & explanation

    Correct answer: (B) Dodecyl trimethyl ammonium chloride

    Explanation

    Micelles are formed by surfactants having both hydrophilic and hydrophobic parts above the critical micelle concentration (CMC). Dodecyl trimethyl ammonium chloride is a cationic surfactant and forms micelles in aqueous solution. Hence option (B) is correct.

  29. Question 29 (AIPMT 2005, Q79)

    AminesMedium
    Electrolytic reduction of nitrobenzene in weakly acidic medium gives:
    1. Option A: Aniline
    2. Option B: Nitrosobenzene
    3. Option C: NN-phenylhydroxylamine
    4. Option D: pp-hydroxyaniline

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  30. Question 30 (AIPMT 2005, Q80)

    EquilibriumMedium
    Equilibrium constants K1K_1 and K2K_2 for the following equilibria: NO(g)+12O2(g)⇌NO2(g)(K1)NO(g) + \frac{1}{2}O_2(g) \rightleftharpoons NO_2(g) \quad (K_1) and 2NO2(g)⇌2NO(g)+O2(g)(K2)2NO_2(g) \rightleftharpoons 2NO(g) + O_2(g) \quad (K_2) are related as:
    1. Option A: K2=1K1K_2 = \dfrac{1}{K_1}
    2. Option B: K2=K12K_2 = K_1^2
    3. Option C: K2=K12K_2 = \dfrac{K_1}{2}
    4. Option D: K2=1K12K_2 = \dfrac{1}{K_1^2}

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  31. Question 31 (AIPMT 2005, Q81)

    Chemical Bonding and Molecular StructureMedium
    Which of the following would have a permanent dipole moment?
    1. Option A: BF3BF_3
    2. Option B: SiF4SiF_4
    3. Option C: SF4SF_4
    4. Option D: XeF4XeF_4

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  32. Question 32 (AIPMT 2005, Q82)

    Haloalkanes and HaloarenesMedium
    Which of the following undergoes nucleophilic substitution exclusively by SN1S_N1 mechanism?
    1. Option A: Benzyl chloride
    2. Option B: Ethyl chloride
    3. Option C: Chlorobenzene
    4. Option D: Isopropyl chloride

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  33. Question 33 (AIPMT 2005, Q83)

    Chemical KineticsEasy
    The rate of reaction between two reactants AA and BB decreases by a factor of 44, if the concentration of reactant BB is doubled. The order of this reaction with respect to reactant BB is:
    1. Option A: −1-1
    2. Option B: −2-2
    3. Option C: 11
    4. Option D: 22

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  34. Question 34 (AIPMT 2005, Q84)

    Solid StateEasy
    In a face-centered cubic lattice, a face-centered atom is shared equally by how many unit cells?
    1. Option A: 8
    2. Option B: 4
    3. Option C: 2
    4. Option D: 6

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  35. Question 35 (AIPMT 2005, Q85)

    SolutionsHard
    A solution of urea (molar mass 56 g mol−156\ g\ mol^{-1}) boils at 100.18∘C100.18^{\circ}C at atmospheric pressure. If KfK_f and KbK_b for water are 1.861.86 and 0.512 K kg mol−10.512\ K\ kg\ mol^{-1} respectively, the above solution will freeze at:
    1. Option A: −6.54∘C-6.54^{\circ}C
    2. Option B: −65.4∘C-65.4^{\circ}C
    3. Option C: 65.4∘C65.4^{\circ}C
    4. Option D: −0.654∘C-0.654^{\circ}C

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  36. Question 36 (AIPMT 2005, Q86)

    BiomoleculesEasy
    Which functional group participates in disulphide bond formation in proteins?
    1. Option A: Thiolactone
    2. Option B: Thiol
    3. Option C: Thioether
    4. Option D: Thioester

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  37. Question 37 (AIPMT 2005, Q87)

    Coordination CompoundsHard
    Which one of the following is an inner orbital complex as well as diamagnetic in behaviour? (Atomic numbers: Zn=30Zn = 30, Cr=24Cr = 24, Co=27Co = 27, Ni=28Ni = 28)
    1. Option A: [Zn(NH3)6]2+[Zn(NH_3)_6]^{2+}
    2. Option B: [Cr(NH3)6]3+[Cr(NH_3)_6]^{3+}
    3. Option C: [Co(NH3)6]3+[Co(NH_3)_6]^{3+}
    4. Option D: [Ni(NH3)6]2+[Ni(NH_3)_6]^{2+}

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  38. Question 38 (AIPMT 2005, Q88)

    Organic Chemistry: Some Basic Principles and TechniquesMedium
    The chirality of the following compound is:
    1. Option A: R
    2. Option B: S
    3. Option C: Z
    4. Option D: E

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  39. Question 39 (AIPMT 2005, Q89)

    Principles Of Qualitative AnalysisMedium
    H2SH_2S gas when passed through a solution of cations containing HClHCl precipitates the cations of second group of qualitative analysis but not those belonging to the fourth group. It is because:
    1. Option A: presence of HClHCl decreases the sulphide ion concentration
    2. Option B: presence of HClHCl increases the sulphide ion concentration
    3. Option C: solubility product of group II sulphides is more than that of group IV sulphides
    4. Option D: sulphides of group IV cations are unstable in HClHCl
    Show answer & explanation

    Correct answer: (A) presence of HClHCl decreases the sulphide ion concentration

    Explanation

    HClHCl suppresses the ionisation of H2SH_2S due to common ion effect: H2S⇌2H++S2−H_2S \rightleftharpoons 2H^+ + S^{2-} Increase in $H^+shiftsequilibriumtotheleft,decreasingshifts equilibrium to the left, decreasing[S^{2-}]$. Only highly insoluble group II sulphides precipitate at this low sulphide ion concentration, whereas group IV sulphides do not. Hence option (A) is correct.

  40. Question 40 (AIPMT 2005, Q90)

    Chemical Bonding and Molecular StructureMedium
    Which one of the following oxides is expected to exhibit paramagnetic behaviour?
    1. Option A: CO2CO_2
    2. Option B: SO2SO_2
    3. Option C: ClO2ClO_2
    4. Option D: SiO2SiO_2

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  41. Question 41 (AIPMT 2005, Q91)

    Coordination CompoundsMedium
    Which one of the following is expected to exhibit optical isomerism? (en=ethylenediamine)(en = ethylenediamine)
    1. Option A: cis−[Pt(NH3)2Cl2]cis-[Pt(NH_3)_2Cl_2]
    2. Option B: trans−[Co(en)2Cl2]trans-[Co(en)_2Cl_2]
    3. Option C: trans−[Pt(NH3)2Cl2]trans-[Pt(NH_3)_2Cl_2]
    4. Option D: cis−[Co(en)2Cl2]cis-[Co(en)_2Cl_2]

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  42. Question 42 (AIPMT 2005, Q92)

    Structure of AtomEasy
    The energy of second Bohr orbit of the hydrogen atom is −328 kJ mol−1-328\ kJ\ mol^{-1}, hence the energy of fourth Bohr orbit would be:
    1. Option A: −41 kJ mol−1-41\ kJ\ mol^{-1}
    2. Option B: −1224 kJ mol−1-1224\ kJ\ mol^{-1}
    3. Option C: −284 kJ mol−1-284\ kJ\ mol^{-1}
    4. Option D: −82 kJ mol−1-82\ kJ\ mol^{-1}

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  43. Question 43 (AIPMT 2005, Q93)

    HydrogenEasy
    The correct order of acid strength is:
    1. Option A: HClO<HClO2<HClO3<HClO4HClO < HClO_2 < HClO_3 < HClO_4
    2. Option B: HClO4<HClO<HClO2<HClO3HClO_4 < HClO < HClO_2 < HClO_3
    3. Option C: HClO2<HClO3<HClO4<HClOHClO_2 < HClO_3 < HClO_4 < HClO
    4. Option D: HClO4<HClO3<HClO2<HClOHClO_4 < HClO_3 < HClO_2 < HClO
    Show answer & explanation

    Correct answer: (A) HClO<HClO2<HClO3<HClO4HClO < HClO_2 < HClO_3 < HClO_4

    Explanation

    For oxoacids of chlorine, acidity increases with increase in oxidation state of chlorine due to stronger electron-withdrawing effect and greater stabilization of conjugate base. Therefore: HClO<HClO2<HClO3<HClO4HClO < HClO_2 < HClO_3 < HClO_4 Hence option (A) is correct.

  44. Question 44 (AIPMT 2005, Q94)

    The d- and f-Block ElementsMedium
    The main reason for larger number of oxidation states exhibited by the actinides than the corresponding lanthanides is:
    1. Option A: lesser energy difference between 5f5f and 6d6d orbitals than between 4f4f and 5d5d orbitals
    2. Option B: larger atomic size of actinides than the lanthanides
    3. Option C: more energy difference between 5f5f and 6d6d orbitals than between 4f4f and 5d5d orbitals
    4. Option D: greater reactive nature of the actinides than the lanthanides

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  45. Question 45 (AIPMT 2005, Q95)

    Organic Chemistry: Some Basic Principles and TechniquesHard
    Names of some compounds are given. Which one is not correct in IUPAC system?
    1. Option A: Option 1
    2. Option B: Option 2
    3. Option C: Option 3
    4. Option D: Option 4

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  46. Question 46 (AIPMT 2005, Q96)

    Classification of Elements and Periodicity in PropertiesMedium
    Which one of the following arrangements represents the correct order of electron gain enthalpy (with negative sign) of the given atomic species?
    1. Option A: Cl<F<S<OCl < F < S < O
    2. Option B: O<S<F<ClO < S < F < Cl
    3. Option C: S<O<Cl<FS < O < Cl < F
    4. Option D: F<Cl<O<SF < Cl < O < S

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  47. Question 47 (AIPMT 2005, Q97)

    SolutionsHard
    A solution has a 1:41:4 mole ratio of pentane to hexane. The vapour pressure of pure hydrocarbons at 20∘C20^{\circ}C are 440 mm Hg440\ mm\ Hg for pentane and 120 mm Hg120\ mm\ Hg for hexane. The mole fraction of pentane in the vapour phase would be:
    1. Option A: 0.178
    2. Option B: 0.278
    3. Option C: 0.378
    4. Option D: 0.478

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  48. Question 48 (AIPMT 2005, Q98)

    ElectrochemistryMedium
    4.5 g4.5\ g of aluminium (atomic mass=27)(atomic\ mass=27) is deposited at cathode from Al3+Al^{3+} solution by a certain quantity of electric charge. The volume of hydrogen produced at STP from H+H^+ ions in solution by the same quantity of electric charge will be:
    1. Option A: 22.4 L22.4\ L
    2. Option B: 32.8 L32.8\ L
    3. Option C: 5.6 L5.6\ L
    4. Option D: 11.2 L11.2\ L

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  49. Question 49 (AIPMT 2005, Q99)

    Organic Chemistry: Some Basic Principles and TechniquesEasy
    The best method for the separation of naphthalene and benzoic acid from their mixture is:
    1. Option A: Chromatography
    2. Option B: Crystallisation
    3. Option C: Distillation
    4. Option D: Sublimation

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  50. Question 50 (AIPMT 2005, Q100)

    SolutionsMedium
    The mole fraction of the solute in one molal aqueous solution is:
    1. Option A: 0.054
    2. Option B: 0.042
    3. Option C: 0.018
    4. Option D: 0.009

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