NEET 2016 · Chemistry

NEET 2016 Chemistry Questions with Solutions

The NEET 2016 paper had 43 Chemistry questions from 22 chapters.

Chemical Bonding and Molecular Structure had the most questions (7), followed by Hydrocarbons with 4.

10 questions below have the answer and explanation free; the other 33 are in Premium.

Practise NEET 2016 Chemistry free

Chemistry questions: 43
Chapters covered: 22
Solved free here: 10 of 43
Easy / Medium / Hard: 10 / 25 / 8

Difficulty is NEET MIND's own tag for each question.

Chapter-wise: NEET 2016 Chemistry

How many questions each chapter had in NEET 2016. Open a chapter for its questions from every year.

All 43 NEET 2016 Chemistry questions

In paper order. Try each one, then open the answer where it is shown.

Question 1 (NEET 2016, Q46)
Alcohols, Phenols and EthersEasy
Which one of the following compounds shows the presence of intramolecular hydrogen bond?
1. Option A: H₂O₂
2. Option B: HCN
3. Option C: Cellulose
4. Option D: Concentrated acetic acid
The answer and explanation for this question are in NEET MIND Premium.
Question 2 (NEET 2016, Q47)
ElectrochemistryMedium
The molar conductivity of a $0.5\ \text{mol dm}^{-3}$ solution of AgNO₃ with electrolytic conductivity of $5.76 \times 10^{-3}\ \text{S cm}^{-1}$ at $298\ \text{K}$ is:
1. Option A: 2.88 S cm² mol⁻¹
2. Option B: 11.52 S cm² mol⁻¹
3. Option C: 0.086 S cm² mol⁻¹
4. Option D: 28.8 S cm² mol⁻¹
The answer and explanation for this question are in NEET MIND Premium.
Question 3 (NEET 2016, Q48)
Chemical KineticsMedium
The decomposition of phosphine $(PH_3)$ on tungsten at low pressure is a first-order reaction. It is because:
1. Option A: Rate is proportional to the surface coverage
2. Option B: Rate is inversely proportional to the surface coverage
3. Option C: Rate is independent of the surface coverage
4. Option D: Rate of decomposition is very slow
The answer and explanation for this question are in NEET MIND Premium.
Question 4 (NEET 2016, Q49)
SolutionsMedium
The coagulation values in millimoles per litre of the electrolytes used for the coagulation of $As_2S_3$ are given below: I. $(NaCl)=52$ II. $(BaCl_2)=0.69$ III. $(MgSO_4)=0.22$ The correct order of their coagulating power is:
1. Option A: I > II > III
2. Option B: II > I > III
3. Option C: III > II > I
4. Option D: III > I > II
The answer and explanation for this question are in NEET MIND Premium.
Question 5 (NEET 2016, Q50)
ElectrochemistryMedium
During the electrolysis of molten sodium chloride, the time required to produce $0.10$ mol of chlorine gas using a current of $3$ amperes is:
1. Option A: 55 minutes
2. Option B: 110 minutes
3. Option C: 220 minutes
4. Option D: 330 minutes
The answer and explanation for this question are in NEET MIND Premium.
Question 6 (NEET 2016, Q51)
Structure of AtomEasy
How many electrons can fit in the orbital for which $n = 3$ and $l = 1$ ?
1. Option A: 2
2. Option B: 6
3. Option C: 10
4. Option D: 14
Show answer & explanationHide answer & explanation
Correct answer: (A) 2
Explanation
For $n = 3$ and $l = 1$ , the orbital belongs to the $3p$ subshell. A single orbital can accommodate a maximum of two electrons with opposite spins. Hence option (A) is correct.
Question 7 (NEET 2016, Q52)
ThermodynamicsMedium
For a sample of perfect gas when its pressure is changed isothermally from $P_i$ to $P_f$ , the entropy change is given by:
1. Option A: $\Delta S = nR\ln\left(\dfrac{P_f}{P_i}\right)$
2. Option B: $\Delta S = nR\ln\left(\dfrac{P_i}{P_f}\right)$
3. Option C: $\Delta S = nRT\ln\left(\dfrac{P_f}{P_i}\right)$
4. Option D: $\Delta S = RT\ln\left(\dfrac{P_i}{P_f}\right)$
The answer and explanation for this question are in NEET MIND Premium.
Question 8 (NEET 2016, Q53)
SolutionsEasy
The van't Hoff factor $(i)$ for a dilute aqueous solution of the strong electrolyte barium hydroxide is:
1. Option A: 0
2. Option B: 1
3. Option C: 2
4. Option D: 3
The answer and explanation for this question are in NEET MIND Premium.
Question 9 (NEET 2016, Q54)
EquilibriumHard
The percentage of pyridine $(C_5H_5N)$ that forms pyridinium ion $(C_5H_5N^+H)$ in a $0.10\ \text{M}$ aqueous pyridine solution $(K_b\text{ for }C_5H_5N = 1.7 \times 10^{-9})$ is:
1. Option A: 0.0060%
2. Option B: 0.013%
3. Option C: 0.77%
4. Option D: 1.6%
The answer and explanation for this question are in NEET MIND Premium.
Question 10 (NEET 2016, Q55)
Solid StateMedium
In calcium fluoride, having the fluorite structure, the coordination numbers for calcium ion $(Ca^{2+})$ and fluoride ion $(F^-)$ are:
1. Option A: 4 and 2
2. Option B: 6 and 6
3. Option C: 8 and 4
4. Option D: 4 and 8
Show answer & explanationHide answer & explanation
Correct answer: (C) 8 and 4
Explanation
In fluorite structure of $CaF_2$ : - $Ca^{2+}$ ions form FCC arrangement. - $F^-$ ions occupy all tetrahedral voids. Thus: - Coordination number of $Ca^{2+}$ is $8$ . - Coordination number of $F^-$ is $4$ . Hence option (C) is correct.
Question 11 (NEET 2016, Q56)
ThermodynamicsMedium
If the $E^\circ_{cell}$ for a given reaction has a negative value, which of the following gives the correct relationships for the values of $\Delta G^\circ$ and $K_{eq}$ ?
1. Option A: $\Delta G^\circ > 0;\ K_{eq} < 1$
2. Option B: $\Delta G^\circ > 0;\ K_{eq} > 1$
3. Option C: $\Delta G^\circ < 0;\ K_{eq} > 1$
4. Option D: $\Delta G^\circ < 0;\ K_{eq} < 1$
The answer and explanation for this question are in NEET MIND Premium.
Question 12 (NEET 2016, Q57)
SolutionsEasy
Which one of the following is incorrect for ideal solution?
1. Option A: $\Delta H_{mix} = 0$
2. Option B: $\Delta U_{mix} = 0$
3. Option C: $\Delta P = P_{obs} - P_{calculated\ by\ Raoult's\ law} = 0$
4. Option D: $\Delta G_{mix} = 0$
The answer and explanation for this question are in NEET MIND Premium.
Question 13 (NEET 2016, Q58)
EquilibriumMedium
The solubility of $AgCl(s)$ with solubility product $1.6 \times 10^{-10}$ in $0.1\ \text{M}\ NaCl$ solution would be:
1. Option A: $1.26 \times 10^{-5}\ \text{M}$
2. Option B: $1.6 \times 10^{-9}\ \text{M}$
3. Option C: $1.6 \times 10^{-11}\ \text{M}$
4. Option D: Zero
The answer and explanation for this question are in NEET MIND Premium.
Question 14 (NEET 2016, Q59)
Some Basic Concepts of ChemistryHard
Suppose the elements $X$ and $Y$ combine to form two compounds $XY_2$ and $X_3Y_2$ . When $0.1$ mole of $XY_2$ weighs $10\ \text{g}$ and $0.05$ mole of $X_3Y_2$ weighs $9\ \text{g}$ , the atomic weights of $X$ and $Y$ are:
1. Option A: 40, 30
2. Option B: 60, 40
3. Option C: 20, 30
4. Option D: 30, 20
The answer and explanation for this question are in NEET MIND Premium.
Question 15 (NEET 2016, Q60)
ElectrochemistryEasy
The number of electrons delivered at the cathode during electrolysis by a current of $1$ ampere in $60$ seconds is (charge on electron $=1.60\times10^{-19}\ \text{C}$ ):
1. Option A: $6\times10^{23}$
2. Option B: $6\times10^{20}$
3. Option C: $3.75\times10^{20}$
4. Option D: $7.48\times10^{23}$
The answer and explanation for this question are in NEET MIND Premium.
Question 16 (NEET 2016, Q61)
HydrogenMedium
Boric acid is an acid because its molecule:
1. Option A: Contains replaceable $H^+$ ion
2. Option B: Gives up a proton
3. Option C: Accepts OH⁻ from water releasing proton
4. Option D: Combines with proton from water molecule
Show answer & explanationHide answer & explanation
Correct answer: (C) Accepts OH⁻ from water releasing proton
Explanation
Boric acid acts as a Lewis acid. It accepts $OH^-$ ions from water: $B(OH)_3 + H_2O \rightarrow [B(OH)_4]^- + H^+$ Thus it releases proton indirectly. Hence option (C) is correct.
Question 17 (NEET 2016, Q62)
Coordination CompoundsMedium
AlF₃ is soluble in HF only in presence of KF. It is due to the formation of:
1. Option A: $K_3[AlF_3H_3]$
2. Option B: $K_3[AlF_6]$
3. Option C: $AlH_3$
4. Option D: $K[AlF_3H]$
The answer and explanation for this question are in NEET MIND Premium.
Question 18 (NEET 2016, Q63)
General Principles And Processes Of Isolation Of ElementsEasy
Zinc can be coated on iron to produce galvanized iron but the reverse is not possible. It is because:
1. Option A: Zinc is lighter than iron
2. Option B: Zinc has lower melting point than iron
3. Option C: Zinc has lower negative electrode potential than iron
4. Option D: Zinc has higher negative electrode potential than iron
Show answer & explanationHide answer & explanation
Correct answer: (D) Zinc has higher negative electrode potential than iron
Explanation
Standard reduction potentials: $E^\circ_{Zn^{2+}/Zn} = -0.76\ \text{V}$ $E^\circ_{Fe^{2+}/Fe} = -0.44\ \text{V}$ Zinc has more negative electrode potential and oxidizes more easily. Thus zinc protects iron sacrificially. Hence option (D) is correct.
Question 19 (NEET 2016, Q64)
S-Block ElementsEasy
The suspension of slaked lime in water is known as:
1. Option A: Limewater
2. Option B: Quicklime
3. Option C: Milk of lime
4. Option D: Aqueous solution of slaked lime
Show answer & explanationHide answer & explanation
Correct answer: (C) Milk of lime
Explanation
A suspension of slaked lime $Ca(OH)_2$ in water is called milk of lime. Hence option (C) is correct.
Question 20 (NEET 2016, Q65)
Chemical Bonding and Molecular StructureMedium
The hybridizations of atomic orbitals of nitrogen in $NO_2^+$ , $NO_3^-$ and $NH_4^+$ respectively are:
1. Option A: $sp,\ sp^3\ \text{and}\ sp^2$
2. Option B: $sp^2,\ sp^3\ \text{and}\ sp$
3. Option C: $sp,\ sp^2\ \text{and}\ sp^3$
4. Option D: $sp^2,\ sp\ \text{and}\ sp^3$
The answer and explanation for this question are in NEET MIND Premium.
Question 21 (NEET 2016, Q66)
Chemical Bonding and Molecular StructureEasy
Which one of the following fluoro-compounds is most likely to behave as a Lewis base?
1. Option A: $BF_3$
2. Option B: $PF_3$
3. Option C: $CF_4$
4. Option D: $SiF_4$
The answer and explanation for this question are in NEET MIND Premium.
Question 22 (NEET 2016, Q67)
Chemical Bonding and Molecular StructureHard
Which of the following pairs of ions is isoelectronic and isostructural?
1. Option A: $CO_3^{2-},\ NO_3^-$
2. Option B: $ClO_3^-,\ CO_3^{2-}$
3. Option C: $SO_3^{2-},\ NO_3^-$
4. Option D: $ClO_3^-,\ SO_3^{2-}$
The answer and explanation for this question are in NEET MIND Premium.
Question 23 (NEET 2016, Q68)
S-Block ElementsMedium
In context with beryllium, which one of the following statements is incorrect?
1. Option A: It is rendered passive by nitric acid
2. Option B: It forms $Be_2C$
3. Option C: Its salts rarely hydrolyze
4. Option D: Its hydride is electron-deficient and polymeric
Show answer & explanationHide answer & explanation
Correct answer: (C) Its salts rarely hydrolyze
Explanation
Beryllium salts hydrolyze readily because of the small size and high polarizing power of $Be^{2+}$ ion. Therefore the statement 'Its salts rarely hydrolyze' is incorrect. Hence option (C) is correct.
Question 24 (NEET 2016, Q69)
Redox ReactionsMedium
Hot concentrated sulphuric acid is a moderately strong oxidizing agent. Which of the following reactions does not show oxidizing behaviour?
1. Option A: $Cu + 2H_2SO_4 \rightarrow CuSO_4 + SO_2 + 2H_2O$
2. Option B: $3S + 2H_2SO_4 \rightarrow 3SO_2 + 2H_2O$
3. Option C: $C + 2H_2SO_4 \rightarrow CO_2 + 2SO_2 + 2H_2O$
4. Option D: $CaF_2 + H_2SO_4 \rightarrow CaSO_4 + 2HF$
Show answer & explanationHide answer & explanation
Correct answer: (D) $CaF_2 + H_2SO_4 \rightarrow CaSO_4 + 2HF$
Explanation
In the reaction: $CaF_2 + H_2SO_4 \rightarrow CaSO_4 + 2HF$ there is no change in oxidation state of any element. Thus concentrated sulphuric acid does not act as an oxidizing agent in this reaction. Hence option (D) is correct.
Question 25 (NEET 2016, Q70)
Chemical Bonding and Molecular StructureMedium
Which of the following pairs of d-orbitals will have electron density along the axes?
1. Option A: $d_{z^2},\ d_{xz}$
2. Option B: $d_{xz},\ d_{yz}$
3. Option C: $d_{z^2},\ d_{x^2-y^2}$
4. Option D: $d_{xy},\ d_{x^2-y^2}$
The answer and explanation for this question are in NEET MIND Premium.
Question 26 (NEET 2016, Q71)
Chemical Bonding and Molecular StructureEasy
The correct geometry and hybridization for $XeF_4$ are:
1. Option A: Octahedral, $sp^3d^2$
2. Option B: Trigonal bipyramidal, $sp^3d$
3. Option C: Planar triangular, $sp^3d^3$
4. Option D: Square planar, $sp^3d^2$
The answer and explanation for this question are in NEET MIND Premium.
Question 27 (NEET 2016, Q72)
Chemical Bonding and Molecular StructureMedium
Among the following, which one is a wrong statement?
1. Option A: $PH_5$ and $BiCl_5$ do not exist
2. Option B: $p\pi-d\pi$ bonds are present in $SO_2$
3. Option C: $SeF_4$ and $CH_4$ have same shape
4. Option D: $I_3^+$ has bent geometry
The answer and explanation for this question are in NEET MIND Premium.
Question 28 (NEET 2016, Q73)
Coordination CompoundsHard
The correct increasing order of trans-effect of the following species is:
1. Option A: NH₃ > CN⁻ > Br⁻ > C₆H₅⁻
2. Option B: CN⁻ > C₆H₅⁻ > Br⁻ > NH₃
3. Option C: Br⁻ > CN⁻ > NH₃ > C₆H₅⁻
4. Option D: CN⁻ > Br⁻ > C₆H₅⁻ > NH₃
The answer and explanation for this question are in NEET MIND Premium.
Question 29 (NEET 2016, Q74)
The d- and f-Block ElementsMedium
Which one of the following statements related to lanthanoids is incorrect?
1. Option A: Europium shows +2 oxidation state
2. Option B: The basicity decreases as the ionic radius decreases from Pr to Lu
3. Option C: All the lanthanoids are much more reactive than aluminium
4. Option D: Ce(+4)solutions are widely used as oxidizing agent in volumetric analysis
The answer and explanation for this question are in NEET MIND Premium.
Question 30 (NEET 2016, Q75)
Coordination CompoundsHard
Jahn-Teller effect is not observed in high spin complexes of:
1. Option A: $d^7$
2. Option B: $d^8$
3. Option C: $d^4$
4. Option D: $d^9$
The answer and explanation for this question are in NEET MIND Premium.
Question 31 (NEET 2016, Q76)
Haloalkanes and HaloarenesMedium
Which of the following can be used as the halide component for Friedel-Crafts reaction?
1. Option A: Chlorobenzene
2. Option B: Bromobenzene
3. Option C: Chloroethene
4. Option D: Isopropyl chloride
Show answer & explanationHide answer & explanation
Correct answer: (D) Isopropyl chloride
Explanation
Friedel-Crafts alkylation requires formation of a stable carbocation. Isopropyl chloride forms relatively stable secondary carbocation. Aryl and vinyl halides do not undergo Friedel-Crafts reactions easily. Hence option (D) is correct.
Question 32 (NEET 2016, Q77)
Chemical Bonding and Molecular StructureMedium
In which of the following molecules, all atoms are coplanar?
1. Option A: Option 1
2. Option B: Option 2
3. Option C: Option 3
4. Option D: Option 4
The answer and explanation for this question are in NEET MIND Premium.
Question 33 (NEET 2016, Q78)
PolymersMedium
Which one of the following structures represents nylon 6,6 polymer?
1. Option A: Option 1
2. Option B: Option 2
3. Option C: Option 3
4. Option D: Option 4
Show answer & explanationHide answer & explanation
Correct answer: (D) Option 4
Explanation
Nylon-6,6 is formed by condensation polymerization of adipic acid and hexamethylene diamine. Its repeating unit is: $[-NH-(CH_2)_6-NH-CO-(CH_2)_4-CO-]_n$ Hence option (D) is correct.
Question 34 (NEET 2016, Q79)
Organic Chemistry: Some Basic Principles and TechniquesMedium
In pyrrole, the electron density is maximum on:
1. Option A: 2 and 3
2. Option B: 3 and 4
3. Option C: 2 and 4
4. Option D: 2 and 5
The answer and explanation for this question are in NEET MIND Premium.
Question 35 (NEET 2016, Q80)
HydrocarbonsMedium
Which of the following compounds shall not produce propene by reaction with HBr followed by elimination reaction?
1. Option A: Option 1
2. Option B: Option 2
3. Option C: Option 3
4. Option D: Option 4
The answer and explanation for this question are in NEET MIND Premium.
Question 36 (NEET 2016, Q81)
AminesHard
Which one of the following nitro-compounds does not react with nitrous acid?
1. Option A: Option 1
2. Option B: Option 2
3. Option C: Option 3
4. Option D: Option 4
The answer and explanation for this question are in NEET MIND Premium.
Question 37 (NEET 2016, Q84)
HydrocarbonsHard
In the given reaction, the product $P$ is:
1. Option A: Option 1
2. Option B: Option 2
3. Option C: Option 3
4. Option D: Option 4
The answer and explanation for this question are in NEET MIND Premium.
Question 38 (NEET 2016, Q85)
AminesMedium
A given nitrogen-containing aromatic compound A reacts with $Sn/HCl$ , followed by $HNO_2$ to give an unstable compound B, on treatment with phenol, forms a beautiful coloured compound C with the molecular formula $C_{12}H_{10}N_2O$ . The structure of compound A is:
1. Option A: Option 1
2. Option B: Option 2
3. Option C: Option 3
4. Option D: Option 4
The answer and explanation for this question are in NEET MIND Premium.
Question 39 (NEET 2016, Q86)
Haloalkanes and HaloarenesMedium
Consider the reaction: $CH_3CH_2CH_2Br + NaCN \rightarrow CH_3CH_2CH_2CN + NaBr$ This reaction will be the fastest in:
1. Option A: Ethanol
2. Option B: Methanol
3. Option C: N,N-dimethylformamide (DMF)
4. Option D: Water
Show answer & explanationHide answer & explanation
Correct answer: (C) N,N-dimethylformamide (DMF)
Explanation
The reaction proceeds through an $S_N2$ mechanism. $S_N2$ reactions are fastest in polar aprotic solvents because such solvents do not strongly solvate nucleophiles. DMF is a polar aprotic solvent and therefore enhances the nucleophilicity of $CN^-$ ion. Hence option (C) is correct.
Question 40 (NEET 2016, Q87)
HydrocarbonsMedium
The correct structure of the product A formed in the reaction is:
1. Option A: Option 1
2. Option B: Option 2
3. Option C: Option 3
4. Option D: Option 4
The answer and explanation for this question are in NEET MIND Premium.
Question 41 (NEET 2016, Q88)
Organic Chemistry: Some Basic Principles and TechniquesHard
Which among the given molecules can exhibit tautomerism?
1. Option A: III only
2. Option B: Both I and III
3. Option C: Both I and II
4. Option D: Both II and III
The answer and explanation for this question are in NEET MIND Premium.
Question 42 (NEET 2016, Q89)
Aldehydes, Ketones and Carboxylic AcidsMedium
The correct order of strengths of the carboxylic acids shown below is:
1. Option A: I > II > III
2. Option B: II > III > I
3. Option C: III > II > I
4. Option D: II > I > III
The answer and explanation for this question are in NEET MIND Premium.
Question 43 (NEET 2016, Q90)
HydrocarbonsEasy
The compound that will react most readily with gaseous bromine has the formula:
1. Option A: $C_3H_6$
2. Option B: $C_2H_2$
3. Option C: $C_4H_{10}$
4. Option D: $C_2H_4$
The answer and explanation for this question are in NEET MIND Premium.

Practise NEET 2016 Chemistry with your progress saved

A free account gives you 15 PYQs in every chapter with explanations, and keeps every mistake for revision.

Start practising free

NEET 2016 Chemistry Questions with Solutions

Chapter-wise: NEET 2016 Chemistry

All 43 NEET 2016 Chemistry questions

NEET Chemistry questions in other years

Practise NEET 2016 Chemistry with your progress saved