AIPMT 2015 · Chemistry

AIPMT 2015 Chemistry Questions with Solutions

The AIPMT 2015 paper had 45 Chemistry questions from 21 chapters.

Chemical Bonding and Molecular Structure and Some Basic Concepts of Chemistry had the most questions (5 each), followed by Alcohols, Phenols and Ethers and Coordination Compounds with 4 each.

7 questions below have the answer and explanation free; the other 38 are in Premium.

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Chemistry questions: 45
Chapters covered: 21
Solved free here: 7 of 45
Easy / Medium / Hard: 21 / 22 / 2

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All 45 AIPMT 2015 Chemistry questions

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Question 1 (AIPMT 2015, Q1)
HydrocarbonsMedium
2,3-Dimethyl-2-butene can be prepared by heating which of the following compounds with a strong acid?
1. Option A: Compound (1)
2. Option B: Compound (2)
3. Option C: Compound (3)
4. Option D: Compound (4)
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Question 2 (AIPMT 2015, Q2)
The d- and f-Block ElementsEasy
Gadolinium belongs to 4f series. Its atomic number is 64. Which of the following is the correct electronic configuration of gadolinium?
1. Option A: [Xe] 4f⁷ 5d¹ 6s²
2. Option B: [Xe] 4f⁶ 5d² 6s²
3. Option C: [Xe] 4f⁸ 6d²
4. Option D: [Xe] 4f⁹ 5s¹
The answer and explanation for this question are in NEET MIND Premium.
Question 3 (AIPMT 2015, Q3)
ThermodynamicsMedium
The formation of the oxide ion, $\mathrm{O^{2-}(g)}$ , from an oxygen atom requires first an exothermic and then an endothermic step as shown below: $\mathrm{O(g) + e^- \rightarrow O^-(g)}; \qquad \Delta_f H^\circ = -141\;kJ\;mol^{-1}$ $\mathrm{O^-(g) + e^- \rightarrow O^{2-}(g)}; \qquad \Delta_f H^\circ = +780\;kJ\;mol^{-1}$ Thus, the process of formation of O²⁻ in the gas phase is unfavourable even though O²⁻ is isoelectronic with neon. It is due to the fact that:
1. Option A: Oxygen is more electronegative.
2. Option B: Addition of electron in oxygen results in larger size of the ion.
3. Option C: Electron repulsion outweighs the stability gained by achieving noble gas configuration.
4. Option D: O⁻ ion has comparatively smaller size than oxygen atom.
The answer and explanation for this question are in NEET MIND Premium.
Question 4 (AIPMT 2015, Q4)
AminesEasy
The number of structural isomers possible for the molecular formula $\mathrm{C_3H_9N}$ is:
1. Option A: 2
2. Option B: 3
3. Option C: 4
4. Option D: 5
The answer and explanation for this question are in NEET MIND Premium.
Question 5 (AIPMT 2015, Q5)
EquilibriumEasy
If the equilibrium constant for $\mathrm{N_2(g) + O_2(g) \rightleftharpoons 2NO(g)}$ is K, the equilibrium constant for $\mathrm{\frac{1}{2}N_2(g) + \frac{1}{2}O_2(g) \rightleftharpoons NO(g)}$ will be:
1. Option A: $K$
2. Option B: $K^2$
3. Option C: $K^{1/2}$
4. Option D: 1/2 K
The answer and explanation for this question are in NEET MIND Premium.
Question 6 (AIPMT 2015, Q6)
EquilibriumEasy
Which one of the following pairs of solution is not an acidic buffer?
1. Option A: $\mathrm{H_2CO_3}$ and $\mathrm{Na_2CO_3}$
2. Option B: $\mathrm{H_3PO_4}$ and $\mathrm{Na_3PO_4}$
3. Option C: $\mathrm{HClO_4}$ and $\mathrm{NaClO_4}$
4. Option D: $\mathrm{CH_3COOH}$ and $\mathrm{CH_3COONa}$
The answer and explanation for this question are in NEET MIND Premium.
Question 7 (AIPMT 2015, Q7)
ElectrochemistryEasy
Aqueous solution of which of the following compounds is the best conductor of electric current?
1. Option A: Ammonia, $\mathrm{NH_3}$
2. Option B: Fructose, $\mathrm{C_6H_{12}O_6}$
3. Option C: Acetic acid, $\mathrm{C_2H_4O_2}$
4. Option D: Hydrochloric acid, $\mathrm{HCl}$
The answer and explanation for this question are in NEET MIND Premium.
Question 8 (AIPMT 2015, Q8)
PolymersEasy
Caprolactam is used for the manufacture of:
1. Option A: Terylene
2. Option B: Nylon-6, 6
3. Option C: Nylon-6
4. Option D: Teflon
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Correct answer: (C) Nylon-6
Explanation
Caprolactam undergoes ring-opening polymerization to form Nylon-6. The repeating unit of Nylon-6 is: $\mathrm{[-NH-(CH_2)_5-CO-]_n}$ Therefore, caprolactam is used in the manufacture of Nylon-6. Hence, option (C) is correct.
Question 9 (AIPMT 2015, Q9)
S-Block ElementsEasy
On heating which of the following releases $\mathrm{CO_2}$ most easily?
1. Option A: $\mathrm{MgCO_3}$
2. Option B: $\mathrm{CaCO_3}$
3. Option C: $\mathrm{K_2CO_3}$
4. Option D: $\mathrm{Na_2CO_3}$
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Correct answer: (A) $\mathrm{MgCO_3}$
Explanation
The ease of decomposition of carbonates depends on their thermal stability. The thermal stability order is: $\mathrm{K_2CO_3 > Na_2CO_3 > CaCO_3 > MgCO_3}$ Since $\mathrm{MgCO_3} $is the least thermally stable among the given carbonates, it decomposes most readily on heating:$ $\mathrm{MgCO_3 \xrightarrow{\Delta} MgO + CO_2}$ $ Hence, option (A) is correct.
Question 10 (AIPMT 2015, Q10)
The d- and f-Block ElementsEasy
Strong reducing behaviour of $\mathrm{H_3PO_2}$ is due to:
1. Option A: High oxidation state of phosphorus
2. Option B: Presence of two $\mathrm{-OH}$ groups and one $\mathrm{P-H}$ bond
3. Option C: Presence of one $\mathrm{-OH}$ group and two $\mathrm{P-H}$ bonds
4. Option D: High electron gain enthalpy of phosphorus
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Question 11 (AIPMT 2015, Q11)
Chemical Bonding and Molecular StructureMedium
Decreasing order of stability of $\mathrm{O_2}$ , $\mathrm{O_2^-}$ , $\mathrm{O_2^+}$ and $\mathrm{O_2^{2-}}$ is:
1. Option A: O₂ > O₂⁺ > O₂²⁻ > O₂⁻
2. Option B: O₂⁻ > O₂²⁻ > O₂⁺ > O₂
3. Option C: O₂⁺ > O₂ > O₂⁻ > O₂²⁻
4. Option D: O₂²⁻ > O₂⁻ > O₂ > O₂⁺
The answer and explanation for this question are in NEET MIND Premium.
Question 12 (AIPMT 2015, Q12)
Some Basic Concepts of ChemistryEasy
The number of water molecules is maximum in:
1. Option A: 18 gram of water
2. Option B: 18 moles of water
3. Option C: 18 molecules of water
4. Option D: 1.8 gram of water
The answer and explanation for this question are in NEET MIND Premium.
Question 13 (AIPMT 2015, Q13)
Chemical Bonding and Molecular StructureMedium
In which of the following pairs, both the species are not isostructural?
1. Option A: NH₃, PH₃
2. Option B: XeF₄, XeO₄
3. Option C: SiCl₄, PCl₄⁺
4. Option D: Diamond, silicon carbide
The answer and explanation for this question are in NEET MIND Premium.
Question 14 (AIPMT 2015, Q14)
HydrocarbonsMedium
In the reaction with HCl, an alkene reacts in accordance with the Markovnikov's rule, to give a product 1-chloro-1-methylcyclohexane. The possible alkene is:
1. Option A: Option (1)
2. Option B: Option (2)
3. Option C: Option (3)
4. Option D: Option (4)
The answer and explanation for this question are in NEET MIND Premium.
Question 15 (AIPMT 2015, Q15)
Redox ReactionsMedium
Assuming complete ionization, same moles of which of the following compounds will require the least amount of acidified KMnO₄ for complete oxidation?
1. Option A: FeC₂O₄
2. Option B: Fe(NO₂)₂
3. Option C: FeSO₄
4. Option D: FeSO₃
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Correct answer: (C) FeSO₄
Explanation
On complete ionization: FeC2O4 gives Fe2+ and C2O4^2−, both of which are oxidized by KMnO4. Fe(NO2)2 gives Fe2+ and NO2−, both oxidizable. FeSO3 gives Fe2+ and SO3^2−, both oxidizable. FeSO4 gives only Fe2+, while SO4^2− is already in its highest oxidation state and cannot be further oxidized. Therefore FeSO4 requires the least amount of acidified KMnO4.
Question 16 (AIPMT 2015, Q16)
Alcohols, Phenols and EthersEasy
Reaction of phenol with chloroform in presence of dilute sodium hydroxide finally introduces which one of the following functional groups?
1. Option A: -CHCl₂
2. Option B: -CHO
3. Option C: -CH₂Cl
4. Option D: -COOH
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Question 17 (AIPMT 2015, Q17)
Chemical Bonding and Molecular StructureEasy
The vacant space in bcc lattice unit cell is:
1. Option A: 23%
2. Option B: 32%
3. Option C: 26%
4. Option D: 48%
The answer and explanation for this question are in NEET MIND Premium.
Question 18 (AIPMT 2015, Q18)
Chemical Bonding and Molecular StructureMedium
Which of the statements given below is incorrect?
1. Option A: ONF is isoelectronic with O₂N⁻
2. Option B: OF₂ is an oxide of fluorine
3. Option C: Cl₂O₇ is an anhydride of perchloric acid
4. Option D: O₃ molecule is bent
The answer and explanation for this question are in NEET MIND Premium.
Question 19 (AIPMT 2015, Q19)
Coordination CompoundsEasy
The name of complex ion, $[\mathrm{Fe(CN)_6}]^{3-}$ is:
1. Option A: Tricyanoferrate (III) ion
2. Option B: Hexacyanidoferrate (III) ion
3. Option C: Hexacyanoiron (III) ion
4. Option D: Hexacyanitoferrate (III) ion
The answer and explanation for this question are in NEET MIND Premium.
Question 20 (AIPMT 2015, Q20)
Some Basic Concepts of ChemistryMedium
If Avogadro number $N_A$ is changed from $6.022 \times 10^{23}\ \mathrm{mol^{-1}}$ to $6.022 \times 10^{20}\ \mathrm{mol^{-1}}$ , this would change:
1. Option A: the ratio of chemical species to each other in a balanced equation
2. Option B: the ratio of elements to each other in a compound
3. Option C: the definition of mass in units of grams
4. Option D: the mass of one mole of carbon
The answer and explanation for this question are in NEET MIND Premium.
Question 21 (AIPMT 2015, Q21)
Organic Chemistry: Some Basic Principles and TechniquesEasy
Which of the following statements is not correct for a nucleophile?
1. Option A: Nucleophiles attack low e⁻ density sites
2. Option B: Nucleophiles are not electron seeking
3. Option C: Nucleophile is a Lewis acid
4. Option D: Ammonia is a nucleophile
The answer and explanation for this question are in NEET MIND Premium.
Question 22 (AIPMT 2015, Q22)
Some Basic Concepts of ChemistryEasy
A gas such as carbon monoxide would be most likely to obey the ideal gas law at:
1. Option A: high temperatures and high pressures
2. Option B: low temperatures and low pressures
3. Option C: high temperatures and low pressures
4. Option D: low temperatures and high pressures
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Question 23 (AIPMT 2015, Q23)
Coordination CompoundsMedium
The hybridization involved in complex $[\mathrm{Ni(CN)_4}]^{2-}$ is (Atomic number of Ni = 28):
1. Option A: d²sp²
2. Option B: d²sp³
3. Option C: dsp²
4. Option D: sp³
The answer and explanation for this question are in NEET MIND Premium.
Question 24 (AIPMT 2015, Q24)
ThermodynamicsEasy
The heat of combustion of carbon to CO₂ is $-393.5\ \mathrm{kJ\ mol^{-1}}$ . The heat released upon formation of 35.2 g of CO₂ from carbon and oxygen gas is:
1. Option A: -630 kJ
2. Option B: -3.15 kJ
3. Option C: -315 kJ
4. Option D: +315 kJ
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Question 25 (AIPMT 2015, Q25)
Some Basic Concepts of ChemistryMedium
20.0 g of a magnesium carbonate sample decomposes on heating to give carbon dioxide and 8.0 g magnesium oxide. What will be the percentage purity of magnesium carbonate in the sample? (Atomic weight: Mg = 24)
1. Option A: 60
2. Option B: 84
3. Option C: 75
4. Option D: 96
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Question 26 (AIPMT 2015, Q26)
SolutionsEasy
What is the mole fraction of the solute in a 1.00 m aqueous solution?
1. Option A: 0.0354
2. Option B: 0.0177
3. Option C: 0.177
4. Option D: 1.770
The answer and explanation for this question are in NEET MIND Premium.
Question 27 (AIPMT 2015, Q27)
Solid StateMedium
The correct statement regarding defects in crystalline solids is:
1. Option A: Frenkel defect is a dislocation defect
2. Option B: Frenkel defect is found in halides of alkaline metals
3. Option C: Schottky defects have no effect on the density of crystalline solids
4. Option D: Frenkel defects decrease the density of crystalline solids
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Correct answer: (A) Frenkel defect is a dislocation defect
Explanation
In a Frenkel defect, an ion leaves its normal lattice site and occupies an interstitial site. It is classified as a dislocation defect. Frenkel defects do not change the density of the crystal, whereas Schottky defects decrease the density.
Question 28 (AIPMT 2015, Q28)
The d- and f-Block ElementsMedium
The stability of +1 oxidation state among Al, Ga, In and Tl increases in the sequence:
1. Option A: Tl < In < Ga < Al
2. Option B: In < Tl < Ga < Al
3. Option C: Ga < In < Al < Tl
4. Option D: Al < Ga < In < Tl
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Question 29 (AIPMT 2015, Q29)
Organic Chemistry: Some Basic Principles and TechniquesEasy
Two possible stereo-structures of $\mathrm{CH_3CHOHCOOH}$ , which are optically active, are called:
1. Option A: Enantiomers
2. Option B: Mesomers
3. Option C: Diastereomers
4. Option D: Atropisomers
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Question 30 (AIPMT 2015, Q30)
Alcohols, Phenols and EthersMedium
The following reaction is known by the name:
1. Option A: Acetylation reaction
2. Option B: Schotten-Baumann reaction
3. Option C: Friedel-Crafts reaction
4. Option D: Perkin's reaction
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Question 31 (AIPMT 2015, Q31)
Coordination CompoundsMedium
The sum of coordination number and oxidation number of the metal M in the complex $[\mathrm{M(en)_2(C_2O_4)}]Cl$ (where en is ethylenediamine) is:
1. Option A: 7
2. Option B: 8
3. Option C: 9
4. Option D: 6
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Question 32 (AIPMT 2015, Q32)
Aldehydes, Ketones and Carboxylic AcidsMedium
Reaction of carbonyl compound with one of the following reagents involves nucleophilic addition followed by elimination of water. The reagent is:
1. Option A: Hydrocyanic acid
2. Option B: Sodium hydrogen sulphite
3. Option C: A Grignard reagent
4. Option D: Hydrazine in presence of feebly acidic solution
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Question 33 (AIPMT 2015, Q33)
Alcohols, Phenols and EthersMedium
Which one of the following esters gets hydrolysed most easily under alkaline conditions?
1. Option A: Option (1)
2. Option B: Option (2)
3. Option C: Option (3)
4. Option D: Option (4)
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Question 34 (AIPMT 2015, Q34)
Organic Chemistry: Some Basic Principles and TechniquesMedium
In an S $_N$ 1 reaction on chiral centres, there is:
1. Option A: 100% retention
2. Option B: 100% inversion
3. Option C: 100% racemization
4. Option D: Inversion more than retention leading to partial racemization
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Question 35 (AIPMT 2015, Q35)
Chemical KineticsEasy
The rate constant of the reaction $A \rightarrow B$ is 0.6 × 10⁻³ mole per second. If the concentration of A is 5 M, then concentration of B after 20 minutes is:
1. Option A: 0.36 M
2. Option B: 0.72 M
3. Option C: 1.08 M
4. Option D: 3.60 M
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Question 36 (AIPMT 2015, Q36)
EquilibriumMedium
What is the pH of the resulting solution when equal volumes of 0.1 M NaOH and 0.01 M HCl are mixed?
1. Option A: 7.0
2. Option B: 1.04
3. Option C: 12.65
4. Option D: 2.0
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Question 37 (AIPMT 2015, Q37)
Coordination CompoundsHard
Number of possible isomers for the complex $[\mathrm{Co(en)_2Cl_2}]Cl$ will be (where en = ethylenediamine):
1. Option A: 3
2. Option B: 4
3. Option C: 2
4. Option D: 1
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Question 38 (AIPMT 2015, Q38)
Chemical Bonding and Molecular StructureEasy
The variation of the boiling points of the hydrogen halides is in the order HF > HI > HBr > HCl. What explains the higher boiling point of hydrogen fluoride?
1. Option A: The bond energy of HF molecules is greater than in other hydrogen halides
2. Option B: The effect of nuclear shielding is much reduced in fluorine which polarises the HF molecule
3. Option C: The electronegativity of fluorine is much higher than for other elements in the group
4. Option D: There is strong hydrogen bonding between HF molecules
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Question 39 (AIPMT 2015, Q39)
Some Basic Concepts of ChemistryMedium
What is the mass of the precipitate formed when 50 mL of 16.9% solution of AgNO₃ is mixed with 50 mL of 5.8% NaCl solution? (Ag = 107.8, N = 14, O = 16, Na = 23, Cl = 35.5)
1. Option A: 7 g
2. Option B: 14 g
3. Option C: 28 g
4. Option D: 3.5 g
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Question 40 (AIPMT 2015, Q40)
HydrocarbonsMedium
The oxidation of benzene by $\mathrm{V_2O_5}$ in the presence of air produces:
1. Option A: Benzoic acid
2. Option B: Benzaldehyde
3. Option C: Benzoic anhydride
4. Option D: Maleic anhydride
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Question 41 (AIPMT 2015, Q41)
Alcohols, Phenols and EthersHard
Which of the following is not the product of dehydration of the given alcohol?
1. Option A: Option (1)
2. Option B: Option (2)
3. Option C: Option (3)
4. Option D: Option (4)
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Question 42 (AIPMT 2015, Q42)
AminesMedium
Method by which aniline cannot be prepared is:
1. Option A: Reduction of nitrobenzene with $\mathrm{H_2/Pd}$ in ethanol
2. Option B: Potassium salt of phthalimide treated with chlorobenzene followed by hydrolysis with aqueous NaOH solution
3. Option C: Hydrolysis of phenylisocyanide with acidic solution
4. Option D: Degradation of benzamide with bromine in alkaline solution
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Question 43 (AIPMT 2015, Q43)
Haloalkanes and HaloarenesMedium
Which of the following reaction(s) can be used for the preparation of alkyl halides?
1. Option A: (IV) only
2. Option B: (III) and (IV) only
3. Option C: (I), (III) and (IV) only
4. Option D: (I) and (II) only
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Correct answer: (C) (I), (III) and (IV) only
Explanation
Primary alcohols react with HCl efficiently only in the presence of anhydrous ZnCl₂ (Lucas reagent). Tertiary alcohols react readily with HCl due to the formation of a stable carbocation. Secondary alcohols also require ZnCl₂ for effective conversion. Therefore reactions (I), (III) and (IV) can be used for the preparation of alkyl halides.
Question 44 (AIPMT 2015, Q44)
Structure of AtomEasy
Which is the correct order of increasing energy of the listed orbitals in the atom of titanium? (Atomic number $Z = 22$ )
1. Option A: 3s 3p 3d 4s
2. Option B: 3s 3p 4s 3d
3. Option C: 3s 4s 3p 3d
4. Option D: 4s 3s 3p 3d
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Correct answer: (B) 3s 3p 4s 3d
Explanation
Titanium ( $Z=22$ ) has the electronic configuration: $\mathrm{1s^2\,2s^2\,2p^6\,3s^2\,3p^6\,4s^2\,3d^2}$ According to the $(n+l) $rule, the increasing order of orbital energies is:$ $\mathrm{3s < 3p < 4s < 3d}$ $ Hence option (B) is correct.
Question 45 (AIPMT 2015, Q45)
General Principles And Processes Of Isolation Of ElementsEasy
In the extraction of copper from its sulphide ore, the metal is finally obtained by the reduction of cuprous oxide with:
1. Option A: Copper(I) sulphide
2. Option B: Sulphur dioxide
3. Option C: Iron(II) sulphide
4. Option D: Carbon monoxide
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Correct answer: (A) Copper(I) sulphide
Explanation
During the extraction of copper from sulphide ores, cuprous oxide undergoes self-reduction with copper(I) sulphide: $\mathrm{Cu_2S + 2Cu_2O \rightarrow 6Cu + SO_2\uparrow}$ Thus copper(I) sulphide acts as the reducing agent and copper metal is obtained.

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