NEET 2019 · Chemistry

NEET 2019 Chemistry Questions with Solutions

The NEET 2019 paper had 43 Chemistry questions from 20 chapters.

The d- and f-Block Elements had the most questions (7), followed by Solutions with 5.

15 questions below have the answer and explanation free; the other 28 are in Premium.

Practise NEET 2019 Chemistry free

Chemistry questions: 43
Chapters covered: 20
Solved free here: 15 of 43
Easy / Medium / Hard: 22 / 21 / 0

Difficulty is NEET MIND's own tag for each question.

Chapter-wise: NEET 2019 Chemistry

How many questions each chapter had in NEET 2019. Open a chapter for its questions from every year.

All 43 NEET 2019 Chemistry questions

In paper order. Try each one, then open the answer where it is shown.

Question 1 (NEET 2019, Q1)
ElectrochemistryMedium
Following limiting molar conductivities are given as:
1. Option A: $\frac{(x-y)}{2} + z$
2. Option B: $x - y + 2z$
3. Option C: $x + y + z$
4. Option D: $x - y + z$
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Correct answer: (A) $\frac{(x-y)}{2} + z$
Explanation
According to Kohlrausch’s law: $\Lambda_m^\circ(AB) = \Lambda_m^\circ(A^+) + \Lambda_m^\circ(B^-)$ For acetic acid: $\Lambda_m^\circ(\mathrm{CH_3COOH}) = \Lambda_m^\circ(\mathrm{CH_3COO^-}) + \Lambda_m^\circ(\mathrm{H^+})$ Using the given conductivities: $\Lambda_m^\circ(\mathrm{CH_3COOK}) = \Lambda_m^\circ(\mathrm{CH_3COO^-}) + \Lambda_m^\circ(\mathrm{K^+})$ $\Lambda_m^\circ(\mathrm{H_2SO_4}) = 2\Lambda_m^\circ(\mathrm{H^+}) + \Lambda_m^\circ(\mathrm{SO_4^{2-}})$ $\Lambda_m^\circ(\mathrm{K_2SO_4}) = 2\Lambda_m^\circ(\mathrm{K^+}) + \Lambda_m^\circ(\mathrm{SO_4^{2-}})$ Subtracting: $\Lambda_m^\circ(\mathrm{H_2SO_4}) - \Lambda_m^\circ(\mathrm{K_2SO_4}) = 2\left[\Lambda_m^\circ(\mathrm{H^+}) - \Lambda_m^\circ(\mathrm{K^+})\right]$ Therefore: $\Lambda_m^\circ(\mathrm{H^+}) - \Lambda_m^\circ(\mathrm{K^+}) = \frac{x-y}{2}$ Hence: $\Lambda_m^\circ(\mathrm{CH_3COOH}) = z + \frac{x-y}{2}$ So, option (A) is correct.
Question 2 (NEET 2019, Q2)
Chemical KineticsEasy
A first order reaction has a rate constant of $2.303 \times 10^{-3}\ \text{s}^{-1}$ . The time required for $40\ \text{g}$ of this reactant to reduce to $10\ \text{g}$ will be [Given that $\log_{10} 2 = 0.3010$ ]
1. Option A: 602 s
2. Option B: 230.3 s
3. Option C: 301 s
4. Option D: 2000 s
The answer and explanation for this question are in NEET MIND Premium.
Question 3 (NEET 2019, Q3)
Chemical KineticsEasy
For a reaction, activation energy $E_a = 0$ and the rate constant at $200\ \text{K}$ is $1.6 \times 10^6\ \text{s}^{-1}$ . The rate constant at $400\ \text{K}$ will be given that gas constant, $R = 8.314\ \text{J K}^{-1}\text{mol}^{-1}$ .
1. Option A: $3.2 \times 10^6\ \text{s}^{-1}$
2. Option B: $3.2 \times 10^4\ \text{s}^{-1}$
3. Option C: $1.6 \times 10^6\ \text{s}^{-1}$
4. Option D: $1.6 \times 10^3\ \text{s}^{-1}$
The answer and explanation for this question are in NEET MIND Premium.
Question 4 (NEET 2019, Q4)
SolutionsMedium
The correct option representing a Freundlich adsorption isotherm is:
1. Option A: $\dfrac{x}{m} = kp^{-1}$
2. Option B: $\dfrac{x}{m} = kp^{0.3}$
3. Option C: $\dfrac{x}{m} = kp^{2.5}$
4. Option D: $\dfrac{x}{m} = kp^{-0.5}$
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Correct answer: (B) $\dfrac{x}{m} = kp^{0.3}$
Explanation
According to Freundlich adsorption isotherm: $\frac{x}{m} = kp^{1/n}$ where: $0 < \frac{1}{n} < 1$ Among the given options, only $0.3 $satisfies this condition. Hence,$ $\frac{x}{m} = kp^{0.3}$ $ is the correct representation.
Question 5 (NEET 2019, Q5)
Chemical Bonding and Molecular StructureMedium
Which of the following is paramagnetic?
1. Option A: $O_2$
2. Option B: $N_2$
3. Option C: $H_2$
4. Option D: $Li_2$
The answer and explanation for this question are in NEET MIND Premium.
Question 6 (NEET 2019, Q6)
Chemical Bonding and Molecular StructureEasy
Which of the following is the correct order of dipole moment?
1. Option A: $\mathrm{H_2O < NF_3 < NH_3 < BF_3}$
2. Option B: $\mathrm{NH_3 < BF_3 < NF_3 < H_2O}$
3. Option C: $\mathrm{BF_3 < NF_3 < NH_3 < H_2O}$
4. Option D: $\mathrm{BF_3 < NH_3 < NF_3 < H_2O}$
The answer and explanation for this question are in NEET MIND Premium.
Question 7 (NEET 2019, Q7)
The d- and f-Block ElementsEasy
Crude sodium chloride obtained by crystallisation of brine solution does not contain:
1. Option A: $\mathrm{CaSO_4}$
2. Option B: $\mathrm{MgSO_4}$
3. Option C: $\mathrm{Na_2SO_4}$
4. Option D: $\mathrm{MgCl_2}$
The answer and explanation for this question are in NEET MIND Premium.
Question 8 (NEET 2019, Q8)
S-Block ElementsEasy
Which of the alkali metal chloride $(\mathrm{MCl})$ forms its dihydrate salt $(\mathrm{MCl \cdot 2H_2O})$ easily?
1. Option A: $\mathrm{KCl}$
2. Option B: $\mathrm{LiCl}$
3. Option C: $\mathrm{CsCl}$
4. Option D: $\mathrm{RbCl}$
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Correct answer: (B) $\mathrm{LiCl}$
Explanation
Among alkali metal chlorides, only lithium chloride readily forms hydrated salts due to the small size and high polarising power of the $\mathrm{Li^+}$ ion. Therefore, lithium chloride forms the dihydrate: $\mathrm{LiCl \cdot 2H_2O}$ Other alkali metal chlorides generally do not form hydrates easily. Hence, the correct option is (2).
Question 9 (NEET 2019, Q9)
Alcohols, Phenols and EthersMedium
The reaction that does not give benzoic acid as the major product is
1. Option A: Option 1
2. Option B: Option 2
3. Option C: Option 3
4. Option D: Option 4
The answer and explanation for this question are in NEET MIND Premium.
Question 10 (NEET 2019, Q10)
AminesMedium
The amine that reacts with Hinsberg’s reagent to give an alkali insoluble product is
1. Option A: Option 1
2. Option B: Option 2
3. Option C: Option 3
4. Option D: Option 4
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Correct answer: (B) Option 2
Explanation
Secondary amines react with Hinsberg reagent to form sulphonamides that are insoluble in alkali because they do not contain an acidic hydrogen atom.
Question 11 (NEET 2019, Q11)
BiomoleculesEasy
Which structure(s) of proteins remain(s) intact during denaturation process?
1. Option A: Tertiary structure only
2. Option B: Both secondary and tertiary structures
3. Option C: Primary structure only
4. Option D: Secondary structure only
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Correct answer: (C) Primary structure only
Explanation
During denaturation, the secondary, tertiary and quaternary structures of proteins are destroyed, while the primary structure remains intact because peptide bonds are not broken.
Question 12 (NEET 2019, Q12)
HydrocarbonsEasy
The polymer that is used as a substitute for wool in making commercial fibres is
1. Option A: Buna-N
2. Option B: Melamine
3. Option C: Nylon-6,6
4. Option D: Polyacrylonitrile
The answer and explanation for this question are in NEET MIND Premium.
Question 13 (NEET 2019, Q13)
BiomoleculesEasy
The artificial sweetener stable at cooking temperature and does not provide calories is
1. Option A: Alitame
2. Option B: Saccharin
3. Option C: Aspartame
4. Option D: Sucralose
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Correct answer: (D) Sucralose
Explanation
Sucralose is a trichloro derivative of sucrose. It is stable at cooking temperature and does not provide calories.
Question 14 (NEET 2019, Q14)
SolutionsMedium
The density of 2 M aqueous solution of NaOH is 1.28 g/cm³. The molality of the solution is [Given that molecular mass of NaOH = 40 g mol⁻¹]
1. Option A: $1.32\,\mathrm{m}$
2. Option B: $1.20\,\mathrm{m}$
3. Option C: $1.56\,\mathrm{m}$
4. Option D: $1.67\,\mathrm{m}$
The answer and explanation for this question are in NEET MIND Premium.
Question 15 (NEET 2019, Q15)
Structure of AtomEasy
Orbital having 3 angular nodes and 3 total nodes is
1. Option A: 6d
2. Option B: 5p
3. Option C: 3d
4. Option D: 4f
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Correct answer: (D) 4f
Explanation
Total number of nodes is given by: $n-1=3$ Therefore, $n=4$ Angular nodes are equal to azimuthal quantum number: $l=3$ The orbital corresponding to $n=4$ and $l=3$ is $4f$ orbital.
Question 16 (NEET 2019, Q16)
Structure of AtomMedium
In hydrogen atom, the de Broglie wavelength of an electron in the second Bohr orbit is given that Bohr radius $a_0 = 52.9\,\text{pm}$ .
1. Option A: 105.8 pm
2. Option B: 211.6 pm
3. Option C: $211.6\pi\,\text{pm}$
4. Option D: $52.9\pi\,\text{pm}$
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Correct answer: (C) $211.6\pi\,\text{pm}$
Explanation
Radius of second Bohr orbit: $r_n=a_0n^2$ $r_2=52.9\times(2)^2=211.6\,\text{pm}$ Using Bohr quantization condition: $n\lambda=2\pi r$ For $n=2$ : $\lambda=\frac{2\pi r}{2}=\pi r$ $\lambda=211.6\pi\,\text{pm}$
Question 17 (NEET 2019, Q17)
ThermodynamicsEasy
The volume occupied by $1.8\,\text{g}$ of water vapour at $374^{\circ}C$ and $1\,\text{bar}$ pressure will be given that $R = 0.083\,\text{bar L K}^{-1}\text{mol}^{-1}$ .
1. Option A: 5.37 L
2. Option B: 96.66 L
3. Option C: 55.87 L
4. Option D: 3.10 L
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Correct answer: (A) 5.37 L
Explanation
Using ideal gas equation: $PV=nRT$ Number of moles: $n=\frac{1.8}{18}=0.1$ Temperature: $T=374+273=647\,K$ Therefore, $V=\frac{nRT}{P}$ $V=\frac{0.1\times0.083\times647}{1}$ $V=5.37\,L$
Question 18 (NEET 2019, Q20)
Classification of Elements and Periodicity in PropertiesEasy
Match the oxide given in Column A with its property given in Column B. $\begin{array}{|c|c|}\hline \text{Column A} & \text{Column B} \\ \hline (i)\; Na_2O & (a)\; \text{Neutral} \\ (ii)\; Al_2O_3 & (b)\; \text{Basic} \\ (iii)\; N_2O & (c)\; \text{Acidic} \\ (iv)\; Cl_2O_7 & (d)\; \text{Amphoteric} \\ \hline \end{array}$ Which of the following options has all correct pairs?
1. Option A: (i)-(b), (ii)-(d), (iii)-(a), (iv)-(c)
2. Option B: (i)-(b), (ii)-(a), (iii)-(d), (iv)-(c)
3. Option C: (i)-(c), (ii)-(b), (iii)-(a), (iv)-(d)
4. Option D: (i)-(a), (ii)-(d), (iii)-(b), (iv)-(c)
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Correct answer: (A) (i)-(b), (ii)-(d), (iii)-(a), (iv)-(c)
Explanation
$Na_2O$ is a basic oxide, $Al_2O_3$ is amphoteric in nature, $N_2O$ is a neutral oxide, and $Cl_2O_7$ is an acidic oxide. Therefore, the correct matching is (i)-(b), (ii)-(d), (iii)-(a), (iv)-(c).
Question 19 (NEET 2019, Q21)
HydrocarbonsMedium
Match the catalyst with the process. Which of the following is the correct option?
1. Option A: (i)-(c), (ii)-(a), (iii)-(d), (iv)-(b)
2. Option B: (i)-(c), (ii)-(d), (iii)-(a), (iv)-(b)
3. Option C: (i)-(a), (ii)-(b), (iii)-(c), (iv)-(d)
4. Option D: (i)-(a), (ii)-(c), (iii)-(b), (iv)-(d)
The answer and explanation for this question are in NEET MIND Premium.
Question 20 (NEET 2019, Q22)
Organic Chemistry: Some Basic Principles and TechniquesMedium
The most stable carbocation among the following is
1. Option A: Option 1
2. Option B: Option 2
3. Option C: Option 3
4. Option D: Option 4
The answer and explanation for this question are in NEET MIND Premium.
Question 21 (NEET 2019, Q23)
HydrocarbonsEasy
The alkane that gives only one mono-chloro product on chlorination with $Cl_2$ in presence of diffused sunlight is
1. Option A: Isopentane
2. Option B: 2,2-dimethylbutane
3. Option C: Neopentane
4. Option D: n-pentane
The answer and explanation for this question are in NEET MIND Premium.
Question 22 (NEET 2019, Q24)
HydrocarbonsMedium
In the following reaction, The number of sigma $(\sigma)$ bonds present in the product $A$ is:
1. Option A: 18
2. Option B: 21
3. Option C: 9
4. Option D: 24
The answer and explanation for this question are in NEET MIND Premium.
Question 23 (NEET 2019, Q25)
Coordination CompoundsMedium
Aluminium chloride in acidified aqueous solution forms a complex 'A'. In which hybridisation state of Al is 'B'. What are 'A' and 'B', respectively?
1. Option A: $[Al(H_2O)_6]^{3+},\ d^2sp^3$
2. Option B: $[Al(H_2O)_6]^{3+},\ sp^3d^2$
3. Option C: $[Al(H_2O)_4]^{3+},\ sp^3$
4. Option D: $[Al(H_2O)_4]^{3+},\ dsp^2$
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Question 24 (NEET 2019, Q26)
PolymersEasy
Which of the following compounds is used in cosmetic surgery?
1. Option A: Zeolites
2. Option B: Silica
3. Option C: Silicates
4. Option D: Silicones
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Correct answer: (D) Silicones
Explanation
Silicones are widely used in cosmetic surgery because of their chemical stability and biocompatibility.
Question 25 (NEET 2019, Q27)
General Principles And Processes Of Isolation Of ElementsEasy
Identify the incorrect statement.
1. Option A: Gangue is an ore contaminated with undesired materials
2. Option B: The scientific and technological process used for isolation of the metal from its ore is known as metallurgy
3. Option C: Minerals are naturally occurring chemical substances in the earth's crust
4. Option D: Ores are minerals that may contain a metal
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Correct answer: (A) Gangue is an ore contaminated with undesired materials
Explanation
Gangue refers to the earthy and unwanted impurities associated with an ore, not the ore itself.
Question 26 (NEET 2019, Q28)
The d- and f-Block ElementsMedium
A compound 'X' upon reaction with $H_2O$ produces a colourless gas 'Y' with rotten fish smell. Gas 'Y' is absorbed in a solution of $CuSO_4$ to give $Cu_3P_2$ as one of the products. Predict the compound 'X'.
1. Option A: $Ca_3(PO_4)_2$
2. Option B: $Ca_3P_2$
3. Option C: NH₄Cl
4. Option D: $As_2O_3$
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Question 27 (NEET 2019, Q29)
The d- and f-Block ElementsMedium
Which of the following oxoacids of phosphorus has strongest reducing property?
1. Option A: $H_3PO_4$
2. Option B: $H_4P_2O_7$
3. Option C: $H_3PO_3$
4. Option D: $H_3PO_2$
The answer and explanation for this question are in NEET MIND Premium.
Question 28 (NEET 2019, Q30)
The d- and f-Block ElementsEasy
Identify the correct formula of oleum from the following.
1. Option A: $H_2S_2O_8$
2. Option B: $H_2S_2O_7$
3. Option C: $H_2SO_3$
4. Option D: $H_2SO_4$
The answer and explanation for this question are in NEET MIND Premium.
Question 29 (NEET 2019, Q31)
The d- and f-Block ElementsMedium
When neutral or faintly alkaline $KMnO_4$ is treated with potassium iodide, iodide ion is converted into ‘X’. ‘X’ is
1. Option A: $IO^{-}$
2. Option B: $I_2$
3. Option C: $IO_4^{-}$
4. Option D: $IO_3^{-}$
The answer and explanation for this question are in NEET MIND Premium.
Question 30 (NEET 2019, Q32)
Coordination CompoundsMedium
The Crystal Field Stabilization Energy (CFSE) for $[CoCl_6]^{3-}$ is $18000\ \text{cm}^{-1}$ . The CFSE for $[CoCl_4]^{2-}$ will be
1. Option A: $8000\ \text{cm}^{-1}$
2. Option B: $6000\ \text{cm}^{-1}$
3. Option C: $16000\ \text{cm}^{-1}$
4. Option D: $18000\ \text{cm}^{-1}$
The answer and explanation for this question are in NEET MIND Premium.
Question 31 (NEET 2019, Q33)
Principles Related To Practical ChemistryEasy
The liquified gas that is used in dry cleaning along with a suitable detergent is
1. Option A: $CO_2$
2. Option B: Water gas
3. Option C: Petroleum gas
4. Option D: $NO_2$
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Correct answer: (A) $CO_2$
Explanation
Liquified carbon dioxide ( $CO_2$ ) is used in dry cleaning with a suitable detergent because it acts as an environmentally safer cleaning solvent.
Question 32 (NEET 2019, Q34)
Haloalkanes and HaloarenesMedium
The hydrolysis reaction that takes place at the slowest rate, among the following is
1. Option A: Option 1
2. Option B: Option 2
3. Option C: Option 3
4. Option D: Option 4
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Correct answer: (B) Option 2
Explanation
Aryl halides such as chlorobenzene undergo nucleophilic substitution very slowly because the C–Cl bond acquires partial double bond character due to resonance. This makes bond cleavage difficult and hydrolysis occurs at the slowest rate.
Question 33 (NEET 2019, Q35)
Alcohols, Phenols and EthersEasy
When vapours of a secondary alcohol is passed over heated copper at 573 K, the product formed is
1. Option A: an alkene
2. Option B: a carboxylic acid
3. Option C: an aldehyde
4. Option D: a ketone
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Question 34 (NEET 2019, Q36)
Alcohols, Phenols and EthersMedium
The major products C and D formed in the following reaction is:
1. Option A: Option 1
2. Option B: Option 2
3. Option C: Option 3
4. Option D: Option 4
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Question 35 (NEET 2019, Q37)
EquilibriumEasy
The pH of $0.01\ M$ NaOH (aq) solution will be
1. Option A: 9
2. Option B: 7.01
3. Option C: 2
4. Option D: 12
The answer and explanation for this question are in NEET MIND Premium.
Question 36 (NEET 2019, Q38)
EquilibriumEasy
Which of the following cannot act both as Bronsted acid and as Bronsted base?
1. Option A: $\mathrm{HSO_4^-}$
2. Option B: $\mathrm{HCO_3^-}$
3. Option C: $\mathrm{NH_3}$
4. Option D: $\mathrm{HCl}$
The answer and explanation for this question are in NEET MIND Premium.
Question 37 (NEET 2019, Q39)
SolutionsMedium
The molar solubility of $CaF_2\,(K_{sp}=5.3\times10^{-11})$ in $0.1\,M$ solution of NaF is:
1. Option A: $5.3\times10^{-10}\;\text{mol L}^{-1}$
2. Option B: $5.3\times10^{-11}\;\text{mol L}^{-1}$
3. Option C: $5.3\times10^{-8}\;\text{mol L}^{-1}$
4. Option D: $5.3\times10^{-9}\;\text{mol L}^{-1}$
The answer and explanation for this question are in NEET MIND Premium.
Question 38 (NEET 2019, Q40)
The d- and f-Block ElementsEasy
The oxidation state of Cr in $CrO_6$ is:
1. Option A: $+4$
2. Option B: $-6$
3. Option C: $+12$
4. Option D: $+6$
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Question 39 (NEET 2019, Q41)
Coordination CompoundsMedium
The number of hydrogen bonded water molecule(s) associated with $CuSO_4\cdot5H_2O$ is:
1. Option A: 5
2. Option B: 3
3. Option C: 1
4. Option D: 2
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Question 40 (NEET 2019, Q42)
The d- and f-Block ElementsMedium
Formula of nickel oxide with metal deficiency defect in crystal is $Ni_{0.98}O$ . The crystal contains $Ni^{2+}$ and $Ni^{3+}$ ions. The fraction of nickel existing as $Ni^{2+}$ ions in the crystal is:
1. Option A: 0.31
2. Option B: 0.96
3. Option C: 0.04
4. Option D: 0.50
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Question 41 (NEET 2019, Q43)
SolutionsMedium
Which of the following statements is correct regarding a solution of two components A and B exhibiting positive deviation from ideal behaviour?
1. Option A: Intermolecular attractive forces between A-A and B-B are equal to those between A-B.
2. Option B: Intermolecular attractive forces between A-A and B-B are stronger than those between A-B.
3. Option C: $\Delta_{mix}H = 0$ at constant temperature and pressure.
4. Option D: $\Delta_{mix}V = 0$ at constant temperature and pressure.
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Question 42 (NEET 2019, Q44)
SolutionsEasy
In water saturated air, the mole fraction of water vapour is 0.02. If the total pressure of the saturated air is 1.2 atm, the partial pressure of dry air is:
1. Option A: 0.98 atm
2. Option B: 1.18 atm
3. Option C: 1.76 atm
4. Option D: 1.176 atm
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Question 43 (NEET 2019, Q45)
ElectrochemistryEasy
The standard electrode potential ( $E^⊖$ ) values of $\mathrm{Al^{3+}/Al}$ , $\mathrm{Ag^+/Ag}$ , $\mathrm{K^+/K}$ and $\mathrm{Cr^{3+}/Cr}$ are $-1.66\,V$ , $0.80\,V$ , $-2.93\,V$ and $-0.74\,V$ , respectively. The correct decreasing order of reducing power of the metal is
1. Option A: Al > K > Ag > Cr
2. Option B: Ag > Cr > Al > K
3. Option C: K > Al > Cr > Ag
4. Option D: K > Al > Ag > Cr
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Correct answer: (C) K > Al > Cr > Ag
Explanation
Reducing power of a metal increases as the standard reduction potential becomes more negative. Given: $E^\circ(\mathrm{K^+/K}) = -2.93\,V$ $E^\circ(\mathrm{Al^{3+}/Al}) = -1.66\,V$ $E^\circ(\mathrm{Cr^{3+}/Cr}) = -0.74\,V$ $E^\circ(\mathrm{Ag^+/Ag}) = +0.80\,V$ Hence, decreasing order of reducing power is: $\mathrm{K > Al > Cr > Ag}$ Therefore, option (C) is correct.

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