AIPMT 2014 · Chemistry

AIPMT 2014 Chemistry Questions with Solutions

The AIPMT 2014 paper had 40 Chemistry questions from 21 chapters.

Chemical Bonding and Molecular Structure, Electrochemistry and The d- and f-Block Elements had the most questions (4 each).

10 questions below have the answer and explanation free; the other 30 are in Premium.

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Chemistry questions: 40
Chapters covered: 21
Solved free here: 10 of 40
Easy / Medium / Hard: 17 / 21 / 2

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Chapter-wise: AIPMT 2014 Chemistry

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All 40 AIPMT 2014 Chemistry questions

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Question 1 (AIPMT 2014, Q50)
Surface ChemistryEasy
Which property of colloids is not dependent on the charge on colloidal particles?
1. Option A: Coagulation
2. Option B: Electrophoresis
3. Option C: Electro-osmosis
4. Option D: Tyndall effect
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Correct answer: (D) Tyndall effect
Explanation
Tyndall effect is the scattering of light by colloidal particles and is an optical property. It does not depend on the charge present on colloidal particles, whereas coagulation, electrophoresis and electro-osmosis are charge-dependent phenomena.
Question 2 (AIPMT 2014, Q51)
EquilibriumEasy
Which of the following salts will give highest pH in water?
1. Option A: KCl
2. Option B: NaCl
3. Option C: Na₂CO₃
4. Option D: CuSO₄
The answer and explanation for this question are in NEET MIND Premium.
Question 3 (AIPMT 2014, Q52)
SolutionsMedium
Of the following 0.10 M aqueous solutions, which one will exhibit the largest freezing point depression?
1. Option A: KCl
2. Option B: C₆H₁₂O₆
3. Option C: Al₂(SO₄)₃
4. Option D: K₂SO₄
The answer and explanation for this question are in NEET MIND Premium.
Question 4 (AIPMT 2014, Q53)
Some Basic Concepts of ChemistryEasy
When 22.4 litres of H₂(g) is mixed with 11.2 litres of Cl₂(g) each at S.T.P., the moles of HCl(g) formed is equal to:
1. Option A: 1 mol of HCl (g)
2. Option B: 2 mol of HCl (g)
3. Option C: 0.5 mol of HCl (g)
4. Option D: 1.5 mol of HCl (g)
The answer and explanation for this question are in NEET MIND Premium.
Question 5 (AIPMT 2014, Q54)
ElectrochemistryEasy
When 0.1 mol MnO₄²⁻ is oxidised, the quantity of electricity required to completely oxidise MnO₄²⁻ to MnO₄⁻ is:
1. Option A: 96500 C
2. Option B: 2 × 96500 C
3. Option C: 9650 C
4. Option D: 96.50 C
The answer and explanation for this question are in NEET MIND Premium.
Question 6 (AIPMT 2014, Q55)
EquilibriumMedium
Using the Gibbs energy change, ΔG° = +63.3 kJ, for the following reaction, $Ag₂CO₃ ⇌ 2Ag + (aq) + CO₃²⁻(aq)$ the Kₛₚ of Ag₂CO₃(s) in water at 25°C is: (R = 8.314 J K⁻¹ mol⁻¹)
1. Option A: 3.2 × 10⁻²⁶
2. Option B: 8.0 × 10⁻¹²
3. Option C: 2.9 × 10⁻³⁰
4. Option D: 7.9 × 10⁻²⁰
The answer and explanation for this question are in NEET MIND Premium.
Question 7 (AIPMT 2014, Q56)
ElectrochemistryMedium
The weight of silver (at. wt. = 108) displaced by a quantity of electricity which displaces 5600 mL of O₂ at STP will be:
1. Option A: 5.4 g
2. Option B: 10.8 g
3. Option C: 54.9 g
4. Option D: 108.0 g
The answer and explanation for this question are in NEET MIND Premium.
Question 8 (AIPMT 2014, Q57)
ThermodynamicsMedium
Which of the following statements is correct for the spontaneous adsorption of a gas?
1. Option A: ΔS is negative and therefore, ΔH should be highly positive
2. Option B: ΔS is negative and therefore, ΔH should be highly negative
3. Option C: ΔS is positive and therefore, ΔH should be negative
4. Option D: ΔS is positive and therefore, ΔH should also be highly positive
The answer and explanation for this question are in NEET MIND Premium.
Question 9 (AIPMT 2014, Q58)
ThermodynamicsMedium
For the reaction: $X₂O₄(l) → 2XO₂(g)$ ΔU = 2.1 k cal, and ΔS = 20 cal K⁻¹ at 300 K. Hence ΔG is:
1. Option A: 2.7 k cal
2. Option B: −2.7 k cal
3. Option C: 9.3 k cal
4. Option D: −9.3 k cal
The answer and explanation for this question are in NEET MIND Premium.
Question 10 (AIPMT 2014, Q59)
ThermodynamicsMedium
For a given exothermic reaction, Kₚ and K′ₚ are the equilibrium constants at temperatures T₁ and T₂, respectively. Assuming that the heat of reaction is constant in the temperature range between T₁ and T₂, it is readily observed that:
1. Option A: Kₚ > K′ₚ
2. Option B: Kₚ < K′ₚ
3. Option C: Kₚ = K′ₚ
4. Option D: Kₚ = 1/K′ₚ
The answer and explanation for this question are in NEET MIND Premium.
Question 11 (AIPMT 2014, Q60)
Classification of Elements and Periodicity in PropertiesEasy
Which of the following orders of ionic radii is correctly represented?
1. Option A: H⁻ > H⁺ > H
2. Option B: Na⁺ > F⁻ > O²⁻
3. Option C: F⁻ > O²⁻ > Na⁺
4. Option D: Al³⁺ > Mg²⁺ > N³⁻
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Correct answer: (A) H⁻ > H⁺ > H
Explanation
H⁻ has two electrons and is larger than neutral hydrogen due to increased electron-electron repulsion. H⁺ is essentially a proton and has the smallest size. Therefore the correct order is H⁻ > H > H⁺. Among the given options, the answer key marks option (A).
Question 12 (AIPMT 2014, Q61)
Some Basic Concepts of ChemistryMedium
1.0 g of magnesium is burnt with 0.56 g O₂ in a closed vessel. Which reactant is left in excess and how much? (At. wt. Mg = 24 ; O = 16)
1. Option A: Mg, 0.16 g
2. Option B: O₂, 0.16 g
3. Option C: Mg, 0.44 g
4. Option D: O₂, 0.28 g
The answer and explanation for this question are in NEET MIND Premium.
Question 13 (AIPMT 2014, Q62)
Redox ReactionsMedium
The pair of compounds that can exist together is:
1. Option A: Mg, 0.16 g
2. Option B: O₂, 0.16 g
3. Option C: Mg, 0.44 g
4. Option D: O₂, 0.28 g
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Correct answer: (A) Mg, 0.16 g
Explanation
Fe²⁺ in FeCl₂ and Sn²⁺ in SnCl₂ are both reducing species and do not oxidize one another. In contrast, FeCl₃ oxidizes SnCl₂ and I⁻, while HgCl₂ is reduced by SnCl₂. Therefore FeCl₂ and SnCl₂ can coexist.
Question 14 (AIPMT 2014, Q63)
Chemical Bonding and Molecular StructureEasy
The pair of compounds that can exist together is:
1. Option A: FeCl₃ and SnCl₂
2. Option B: HgCl₂ and SnCl₂
3. Option C: FeCl₂ and SnCl₂
4. Option D: FeCl₃ and KI
The answer and explanation for this question are in NEET MIND Premium.
Question 15 (AIPMT 2014, Q64)
Structure of AtomEasy
Be²⁺ is isoelectronic with which of the following ions?
1. Option A: H⁺
2. Option B: Li⁺
3. Option C: Na⁺
4. Option D: Mg²⁺
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Correct answer: (B) Li⁺
Explanation
Beryllium has atomic number 4. Be²⁺ therefore contains 2 electrons. Li⁺ also contains 2 electrons (3 − 1 = 2). Hence Be²⁺ and Li⁺ are isoelectronic.
Question 16 (AIPMT 2014, Q65)
Chemical Bonding and Molecular StructureMedium
Which of the following molecules has the maximum dipole moment?
1. Option A: CO₂
2. Option B: CH₄
3. Option C: NH₃
4. Option D: NF₃
The answer and explanation for this question are in NEET MIND Premium.
Question 17 (AIPMT 2014, Q66)
Chemical Bonding and Molecular StructureEasy
Which one of the following species has plane triangular shape?
1. Option A: N₃⁻
2. Option B: NO₃⁻
3. Option C: NO₂⁻
4. Option D: CO₂
The answer and explanation for this question are in NEET MIND Premium.
Question 18 (AIPMT 2014, Q67)
Chemical Bonding and Molecular StructureEasy
Acidity of diprotic acids in aqueous solutions increases in the order:
1. Option A: H₂S < H₂Se < H₂Te
2. Option B: H₂Se < H₂S < H₂Te
3. Option C: H₂Te < H₂S < H₂Se
4. Option D: H₂Se < H₂Te < H₂S
The answer and explanation for this question are in NEET MIND Premium.
Question 19 (AIPMT 2014, Q68)
ElectrochemistryMedium
$(a) H₂O₂ + O₃ → H₂O + 2O₂$ $(b) H₂O₂ + Ag₂O → 2Ag + H₂O + O₂$ Role of hydrogen peroxide in the above reactions is respectively
1. Option A: Oxidizing in (a) and reducing in (b)
2. Option B: Reducing in (a) and oxidizing in (b)
3. Option C: Reducing in (a) and reducing in (b)
4. Option D: Oxidizing in (a) and oxidizing in (b)
The answer and explanation for this question are in NEET MIND Premium.
Question 20 (AIPMT 2014, Q69)
BiomoleculesEasy
Artificial sweetener which is stable under cold conditions only is:
1. Option A: Saccharine
2. Option B: Sucralose
3. Option C: Aspartame
4. Option D: Alitame
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Correct answer: (C) Aspartame
Explanation
Aspartame is unstable at high temperatures and loses its sweetness upon heating. Therefore it is generally used only in cold foods and beverages.
Question 21 (AIPMT 2014, Q70)
The d- and f-Block ElementsMedium
In acidic medium, H₂O₂ changes Cr₂O₇²⁻ to CrO₅, which has two (−O−O−) bonds. Oxidation state of Cr in CrO₅ is:
1. Option A: +5
2. Option B: +3
3. Option C: +6
4. Option D: −10
The answer and explanation for this question are in NEET MIND Premium.
Question 22 (AIPMT 2014, Q71)
ElectrochemistryEasy
The reaction of aqueous KMnO₄ with H₂O₂ in acidic conditions gives:
1. Option A: Mn⁴⁺ and O₂
2. Option B: Mn²⁺ and O₂
3. Option C: Mn²⁺ and O₃
4. Option D: Mn⁴⁺ and MnO₂
The answer and explanation for this question are in NEET MIND Premium.
Question 23 (AIPMT 2014, Q72)
The d- and f-Block ElementsHard
Among the following complexes, the one which shows zero crystal field stabilization energy (CFSE) is:
1. Option A: [Mn(H₂O)₆]³⁺
2. Option B: [Fe(H₂O)₆]³⁺
3. Option C: [Co(H₂O)₆]²⁺
4. Option D: [Co(H₂O)₆]³⁺
The answer and explanation for this question are in NEET MIND Premium.
Question 24 (AIPMT 2014, Q73)
The d- and f-Block ElementsMedium
Magnetic moment 2.83 BM is given by which of the following ions? (Atomic numbers: Ti = 22, Cr = 24, Mn = 25, Ni = 28)
1. Option A: Ti³⁺
2. Option B: Ni²⁺
3. Option C: Cr³⁺
4. Option D: Mn²⁺
The answer and explanation for this question are in NEET MIND Premium.
Question 25 (AIPMT 2014, Q74)
Coordination CompoundsMedium
Which of the following complexes is:
1. Option A: mer-[Co(NH₃)₃Cl₃]
2. Option B: cis-[PtCl₂(NH₃)₂]
3. Option C: cis-K₂[PtCl₂Br₂]
4. Option D: Na₂CoCl₄
The answer and explanation for this question are in NEET MIND Premium.
Question 26 (AIPMT 2014, Q75)
The d- and f-Block ElementsEasy
Reason of lanthanoid contraction is:
1. Option A: Negligible screening effect of 'f' orbitals
2. Option B: Increasing nuclear charge
3. Option C: Decreasing nuclear charge
4. Option D: Decreasing screening effect
The answer and explanation for this question are in NEET MIND Premium.
Question 27 (AIPMT 2014, Q76)
AminesMedium
In the following reaction, the product (A)
1. Option A: Option (1)
2. Option B: Option (2)
3. Option C: Option (3)
4. Option D: Option (4)
The answer and explanation for this question are in NEET MIND Premium.
Question 28 (AIPMT 2014, Q77)
AminesEasy
Which of the following will be the most stable diazonium salt RN₂⁺X⁻?
1. Option A: CH₃N₂⁺X⁻
2. Option B: C₆H₅N₂⁺X⁻
3. Option C: CH₃CH₂N₂⁺X⁻
4. Option D: C₆H₅CH₂N₂⁺X⁻
The answer and explanation for this question are in NEET MIND Premium.
Question 29 (AIPMT 2014, Q78)
BiomoleculesMedium
D(+) glucose reacts with hydroxylamine and yields an oxime. The structure of the oxime would be:
1. Option A: Structure (1)
2. Option B: Structure (2)
3. Option C: Structure (3)
4. Option D: Structure (4)
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Correct answer: (D) Structure (4)
Explanation
Hydroxylamine reacts with the aldehyde group of open-chain D(+)-glucose to form an oxime (–CH=NOH). The stereochemistry at C₂, C₃, C₄ and C₅ remains unchanged. Therefore the correct oxime structure is option (D).
Question 30 (AIPMT 2014, Q80)
PolymersEasy
Which one of the following is an example of a thermosetting polymer?
1. Option A: Option (1)
2. Option B: Option (2)
3. Option C: Option (3)
4. Option D: Option (4)
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Correct answer: (D) Option (4)
Explanation
Thermosetting polymers are heavily cross-linked polymers that become hard and infusible upon heating. Bakelite, a phenol-formaldehyde resin, is a classic example of a thermosetting polymer.
Question 31 (AIPMT 2014, Q81)
PolymersEasy
Which of the following organic compounds polymerizes to form the polyester Dacron?
1. Option A: Propylene and para HO-(C₆H₄)-OH
2. Option B: Benzoic acid and ethanol
3. Option C: Terephthalic acid and ethylene glycol
4. Option D: Benzoic acid and para HO-(C₆H₄)-OH
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Correct answer: (C) Terephthalic acid and ethylene glycol
Explanation
Dacron (Terylene) is a polyester obtained by condensation polymerization of ethylene glycol (ethane-1,2-diol) and terephthalic acid (benzene-1,4-dicarboxylic acid).
Question 32 (AIPMT 2014, Q82)
Environmental ChemistryEasy
Which of the following is not a common component of photochemical smog?
1. Option A: Ozone
2. Option B: Acrolein
3. Option C: Peroxyacetyl nitrate
4. Option D: Chlorofluorocarbons
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Correct answer: (D) Chlorofluorocarbons
Explanation
Photochemical smog commonly contains ozone (O₃), aldehydes such as acrolein, and peroxyacetyl nitrate (PAN). Chlorofluorocarbons (CFCs) are not common constituents of photochemical smog.
Question 33 (AIPMT 2014, Q83)
Principles Related To Practical ChemistryMedium
In the Kjeldahl's method for estimation of nitrogen present in a soil sample, ammonia evolved from 0.75 g of sample neutralized 10 mL of 1 M H₂SO₄. The percentage of nitrogen in the soil is:
1. Option A: 37.33
2. Option B: 45.33
3. Option C: 35.33
4. Option D: 43.33
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Correct answer: (A) 37.33
Explanation
10 mL of 1 M H₂SO₄ contains 0.01 mol H₂SO₄. From H₂SO₄ + 2NH₃ → (NH₄)₂SO₄, moles of NH₃ = 2 × 0.01 = 0.02 mol. Nitrogen present = 0.02 × 14 = 0.28 g. Therefore, percentage nitrogen = (0.28/0.75) × 100 = 37.33%.
Question 34 (AIPMT 2014, Q84)
HydrocarbonsHard
What products are formed when the following compounds is treated with Br₂ in the presence of FeBr₃?
1. Option A: Compound (1)
2. Option B: Compound (2)
3. Option C: Compound (3)
4. Option D: Compound (4)
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Question 35 (AIPMT 2014, Q85)
Haloalkanes and HaloarenesMedium
Which of the following compounds will undergo racemisation when solution of KOH hydrolyses?
1. Option A: (i) and (ii)
2. Option B: (ii) and (iv)
3. Option C: (iii) and (iv)
4. Option D: (i) and (iv)
The answer and explanation for this question are in NEET MIND Premium.
Question 36 (AIPMT 2014, Q86)
Alcohols, Phenols and EthersMedium
Among the following sets of reactants which one produces anisole?
1. Option A: CH₃CHO ; RMgX
2. Option B: C₆H₅OH ; NaOH ; CH₃I
3. Option C: C₆H₅OH ; neutral FeCl₃
4. Option D: C₆H₅CH₃ ; CH₃COCl ; AlCl₃
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Question 37 (AIPMT 2014, Q87)
Aldehydes, Ketones and Carboxylic AcidsMedium
Which of the following will not be soluble in sodium hydrogen carbonate?
1. Option A: 2,4,6-Trinitrophenol
2. Option B: Benzoic acid
3. Option C: o-Nitrophenol
4. Option D: Benzenesulphonic acid
The answer and explanation for this question are in NEET MIND Premium.
Question 38 (AIPMT 2014, Q88)
Aldehydes, Ketones and Carboxylic AcidsMedium
Which one is most reactive towards nucleophilic addition reaction?
1. Option A: Option (1)
2. Option B: Option (2)
3. Option C: Option (3)
4. Option D: Option (4)
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Question 39 (AIPMT 2014, Q89)
Haloalkanes and HaloarenesMedium
Identify Z in the sequence of reactions:
1. Option A: CH₃ – (CH₂)₃ – O – CH₂CH₃
2. Option B: (CH₃)₂CH₂ – O – CH₂CH₃
3. Option C: CH₃(CH₂)₄ – O – CH₃
4. Option D: CH₃CH₂ – CH(CH₃) – O – CH₂CH₃
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Question 40 (AIPMT 2014, Q90)
HydrocarbonsEasy
Which of the following organic compounds has the same hybridization as its combustion product (CO₂)?
1. Option A: Ethane
2. Option B: Ethyne
3. Option C: Ethene
4. Option D: Ethanol
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