AIPMT 2009 · Chemistry

AIPMT 2009 Chemistry Questions with Solutions

The AIPMT 2009 paper had 49 Chemistry questions from 21 chapters.

Chemical Bonding and Molecular Structure and Hydrocarbons had the most questions (5 each), followed by Chemical Kinetics with 4.

5 questions below have the answer and explanation free; the other 44 are in Premium.

Chemistry questions
49
Chapters covered
21
Solved free here
5 of 49
Easy / Medium / Hard
10 / 24 / 15

Difficulty is NEET MIND's own tag for each question.

Chapter-wise: AIPMT 2009 Chemistry

How many questions each chapter had in AIPMT 2009. Open a chapter for its questions from every year.

  1. Chemical Bonding and Molecular Structure5 Qs
  2. Hydrocarbons5 Qs
  3. Chemical Kinetics4 Qs
  4. Coordination Compounds3 Qs
  5. Electrochemistry3 Qs
  6. Solid State3 Qs
  7. Thermodynamics3 Qs
  8. Alcohols, Phenols and Ethers2 Qs
  9. Biomolecules2 Qs
  10. Equilibrium2 Qs
  11. Haloalkanes and Haloarenes2 Qs
  12. Organic Chemistry: Some Basic Principles and Techniques2 Qs
  13. Redox Reactions2 Qs
  14. Some Basic Concepts of Chemistry2 Qs
  15. Structure of Atom2 Qs
  16. The d- and f-Block Elements2 Qs
  17. Aldehydes, Ketones and Carboxylic Acids1 Q
  18. Amines1 Q
  19. Classification of Elements and Periodicity in Properties1 Q
  20. Polymers1 Q
  21. Solutions1 Q

All 49 AIPMT 2009 Chemistry questions

In paper order. Try each one, then open the answer where it is shown.

  1. Question 1 (AIPMT 2009, Q47)

    Solid StateMedium
    Sodium has body centred packing. Distance between two nearest atoms is 3.7 A˚3.7\,\AA. The lattice parameter is:
    1. Option A: 8.6 A˚8.6\,\AA
    2. Option B: 6.8 A˚6.8\,\AA
    3. Option C: 4.3 A˚4.3\,\AA
    4. Option D: 3.0 A˚3.0\,\AA

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  2. Question 2 (AIPMT 2009, Q51)

    Some Basic Concepts of ChemistryEasy
    10 g of hydrogen and 64 g of oxygen were filled in a steel vessel and exploded. Amount of water produced in this reaction will be:
    1. Option A: 1 mol
    2. Option B: 2 mol
    3. Option C: 3 mol
    4. Option D: 4 mol

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  3. Question 3 (AIPMT 2009, Q52)

    Redox ReactionsEasy
    Oxidation number of P in PO43−PO_4^{3-}, of S in SO42−SO_4^{2-} and that of Cr in Cr2O72−Cr_2O_7^{2-} are respectively:
    1. Option A: +3+3, +6+6 and +6+6
    2. Option B: +5+5, +6+6 and +6+6
    3. Option C: +3+3, +6+6 and +5+5
    4. Option D: +5+5, +3+3 and +6+6
    Show answer & explanation

    Correct answer: (B) +5+5, +6+6 and +6+6

    Explanation

    Using oxidation number rules: For PO43−PO_4^{3-} → P=+5P = +5 For SO42−SO_4^{2-} → S=+6S = +6 For Cr2O72−Cr_2O_7^{2-} → Cr=+6Cr = +6

  4. Question 4 (AIPMT 2009, Q53)

    Structure of AtomMedium
    Maximum number of electrons in a subshell of an atom is determined by the following:
    1. Option A: 2n22n^2
    2. Option B: 4l+24l+2
    3. Option C: 2l+22l+2
    4. Option D: 4l−24l-2

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  5. Question 5 (AIPMT 2009, Q54)

    Structure of AtomMedium
    Which of the following is not permissible arrangement of electrons in an atom?
    1. Option A: n=3,  l=2,  m=−3,  s=−12n=3,\; l=2,\; m=-3,\; s=-\frac{1}{2}
    2. Option B: n=4,  l=0,  m=0,  s=−12n=4,\; l=0,\; m=0,\; s=-\frac{1}{2}
    3. Option C: n=5,  l=3,  m=0,  s=+12n=5,\; l=3,\; m=0,\; s=+\frac{1}{2}
    4. Option D: n=3,  l=2,  m=−3,  s=−12n=3,\; l=2,\; m=-3,\; s=-\frac{1}{2}

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  6. Question 6 (AIPMT 2009, Q55)

    ThermodynamicsMedium
    From the following bond energies: H–H bond energy = 431.37  kJ mol−1431.37\;\text{kJ mol}^{-1} C=C bond energy = 606.10  kJ mol−1606.10\;\text{kJ mol}^{-1} C–C bond energy = 336.49  kJ mol−1336.49\;\text{kJ mol}^{-1} C–H bond energy = 410.50  kJ mol−1410.50\;\text{kJ mol}^{-1} Enthalpy for the reaction:
    1. Option A: 553.0  kJ mol−1553.0\;\text{kJ mol}^{-1}
    2. Option B: 1523.6  kJ mol−11523.6\;\text{kJ mol}^{-1}
    3. Option C: −243.6  kJ mol−1-243.6\;\text{kJ mol}^{-1}
    4. Option D: −120.0  kJ mol−1-120.0\;\text{kJ mol}^{-1}

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  7. Question 7 (AIPMT 2009, Q56)

    EquilibriumMedium
    The ionization constant of ammonium hydroxide is 1.77×10−51.77 \times 10^{-5} at 298 K298\,K. Hydrolysis constant of ammonium chloride is:
    1. Option A: 5.65×10−125.65 \times 10^{-12}
    2. Option B: 5.65×10−105.65 \times 10^{-10}
    3. Option C: 6.50×10−126.50 \times 10^{-12}
    4. Option D: 5.65×10−135.65 \times 10^{-13}

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  8. Question 8 (AIPMT 2009, Q57)

    ElectrochemistryHard
    Given: (i) Cu2++2e−→Cu,  E∘=0.337 V\mathrm{Cu^{2+} + 2e^- \rightarrow Cu},\; E^\circ = 0.337\,V (ii) Cu2++e−→Cu+,  E∘=0.153 V\mathrm{Cu^{2+} + e^- \rightarrow Cu^+},\; E^\circ = 0.153\,V The electrode potential E∘E^\circ for the reaction: Cu++e−→Cu\mathrm{Cu^+ + e^- \rightarrow Cu} will be:
    1. Option A: 0.38 V0.38\,V
    2. Option B: 0.52 V0.52\,V
    3. Option C: 0.90 V0.90\,V
    4. Option D: 0.30 V0.30\,V

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  9. Question 9 (AIPMT 2009, Q58)

    Some Basic Concepts of ChemistryMedium
    What is the [OH−][OH^-] in the final solution prepared by mixing 20.0 mL20.0\,mL of 0.050 M0.050\,M HCl with 30.0 mL30.0\,mL of 0.10 M0.10\,M Ba(OH)2Ba(OH)_2?
    1. Option A: 0.12 M0.12\,M
    2. Option B: 0.10 M0.10\,M
    3. Option C: 0.40 M0.40\,M
    4. Option D: 0.0050 M0.0050\,M

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  10. Question 10 (AIPMT 2009, Q59)

    ThermodynamicsMedium
    The energy absorbed by each molecule (A2)(A_2) of a substance is 4.4×10−19 J4.4 \times 10^{-19}\,J and bond energy per molecule is 4.0×10−19 J4.0 \times 10^{-19}\,J. The kinetic energy of the molecule per atom will be:
    1. Option A: 4.0×10−20 J4.0 \times 10^{-20}\,J
    2. Option B: 2.0×10−20 J2.0 \times 10^{-20}\,J
    3. Option C: 2.2×10−19 J2.2 \times 10^{-19}\,J
    4. Option D: 4.0×10−19 J4.0 \times 10^{-19}\,J

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  11. Question 11 (AIPMT 2009, Q60)

    Chemical KineticsMedium
    For the reaction: N2+3H2→2NH3\mathrm{N_2 + 3H_2 \rightarrow 2NH_3} If d[NH3]dt=2×10−4  mol  L−1  s−1\frac{d[NH_3]}{dt} = 2 \times 10^{-4}\;mol\;L^{-1}\;s^{-1} The value of −d[H2]dt-\frac{d[H_2]}{dt} will be:
    1. Option A: 1×10−4  mol  L−1  s−11 \times 10^{-4}\;mol\;L^{-1}\;s^{-1}
    2. Option B: 3×10−4  mol  L−1  s−13 \times 10^{-4}\;mol\;L^{-1}\;s^{-1}
    3. Option C: 4×10−4  mol  L−1  s−14 \times 10^{-4}\;mol\;L^{-1}\;s^{-1}
    4. Option D: 6×10−4  mol  L−1  s−16 \times 10^{-4}\;mol\;L^{-1}\;s^{-1}

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  12. Question 12 (AIPMT 2009, Q61)

    Chemical KineticsHard
    For the reaction A+B→A + B \rightarrow products, it is observed that: (1) On doubling the initial concentration of AA only, the rate of reaction is also doubled. (2) On doubling the initial concentration of both AA and BB, there is a change by a factor of 88 in the rate of the reaction. The rate law of this reaction is:
    1. Option A: rate=k[A][B]rate = k[A][B]
    2. Option B: rate=k[A]2[B]rate = k[A]^2[B]
    3. Option C: rate=k[A][B]2rate = k[A][B]^2
    4. Option D: rate=k[A]2[B]2rate = k[A]^2[B]^2

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  13. Question 13 (AIPMT 2009, Q62)

    ElectrochemistryHard
    The equivalent conductance of M32\dfrac{M}{32} solution of a weak monobasic acid is 8.0  mho  cm28.0\;mho\;cm^2 and at infinite dilution is 400  mho  cm2400\;mho\;cm^2. The dissociation constant of this acid is:
    1. Option A: 1.25×10−41.25 \times 10^{-4}
    2. Option B: 1.25×10−51.25 \times 10^{-5}
    3. Option C: 1.25×10−61.25 \times 10^{-6}
    4. Option D: 6.25×10−46.25 \times 10^{-4}

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  14. Question 14 (AIPMT 2009, Q63)

    SolutionsHard
    A 0.0020 M0.0020\,M aqueous solution of an ionic compound Co(NH3)5(NO2)ClCo(NH_3)_5(NO_2)Cl freezes at −0.00732∘C-0.00732^\circ C. Number of moles of ions which 11 mole of ionic compound produces on being dissolved in water will be: (kfk_f = 1.86 °C/m)
    1. Option A: 1
    2. Option B: 2
    3. Option C: 3
    4. Option D: 4

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  15. Question 15 (AIPMT 2009, Q64)

    Chemical KineticsMedium
    In the reaction: BrO3−(aq)+5Br−(aq)+6H+→3Br2(l)+3H2O(l)\mathrm{BrO_3^- (aq) + 5Br^- (aq) + 6H^+ \rightarrow 3Br_2(l) + 3H_2O(l)} The rate of appearance of bromine Br₂ is related to rate of disappearance of bromide ions as follows:
    1. Option A: d(Br2)dt=35d(Br−)dt\dfrac{d(Br_2)}{dt}=\dfrac{3}{5}\dfrac{d(Br^-)}{dt}
    2. Option B: d(Br2)dt=−35d(Br−)dt\dfrac{d(Br_2)}{dt}=-\dfrac{3}{5}\dfrac{d(Br^-)}{dt}
    3. Option C: d(Br2)dt=−53d(Br−)dt\dfrac{d(Br_2)}{dt}=-\dfrac{5}{3}\dfrac{d(Br^-)}{dt}
    4. Option D: d(Br2)dt=53d(Br−)dt\dfrac{d(Br_2)}{dt}=\dfrac{5}{3}\dfrac{d(Br^-)}{dt}

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  16. Question 16 (AIPMT 2009, Q65)

    Solid StateMedium
    Lithium metal crystallizes in a body centred cubic crystal. If the length of the side of the unit cell of lithium is 351 pm351\,pm, the atomic radius of lithium will be:
    1. Option A: 300.5 pm300.5\,pm
    2. Option B: 240.8 pm240.8\,pm
    3. Option C: 151.8 pm151.8\,pm
    4. Option D: 75.5 pm75.5\,pm

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  17. Question 17 (AIPMT 2009, Q66)

    EquilibriumHard
    The dissociation constants of acetic acid and HCN at 25∘C25^\circ C are 1.5×10−51.5 \times 10^{-5} and 4.5×10−104.5 \times 10^{-10} respectively. The equilibrium constant for: CN−+CH3COOH⇌HCN+CH3COO−\mathrm{CN^- + CH_3COOH \rightleftharpoons HCN + CH_3COO^-} would be:
    1. Option A: 3.0×1043.0 \times 10^{4}
    2. Option B: 3.0×1053.0 \times 10^{5}
    3. Option C: 3.0×10−53.0 \times 10^{-5}
    4. Option D: 3.0×10−43.0 \times 10^{-4}

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  18. Question 18 (AIPMT 2009, Q67)

    ThermodynamicsMedium
    The values of ΔH\Delta H and ΔS\Delta S for the reaction: C(graphite)+CO2(g)→2CO(g)\mathrm{C(graphite) + CO_2(g) \rightarrow 2CO(g)} are 170 kJ and 170 J K⁻¹ respectively. This reaction will be spontaneous at:
    1. Option A: 510 K510\,K
    2. Option B: 710 K710\,K
    3. Option C: 910 K910\,K
    4. Option D: 1110 K1110\,K

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  19. Question 19 (AIPMT 2009, Q68)

    Chemical KineticsMedium
    Half-life period of a first-order reaction is 1386 s1386\,s. The specific rate constant of the reaction is:
    1. Option A: 5.0×10−2 s−15.0 \times 10^{-2}\,s^{-1}
    2. Option B: 5.0×10−3 s−15.0 \times 10^{-3}\,s^{-1}
    3. Option C: 0.5×10−2 s−10.5 \times 10^{-2}\,s^{-1}
    4. Option D: 0.5×10−3 s−10.5 \times 10^{-3}\,s^{-1}

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  20. Question 20 (AIPMT 2009, Q69)

    Chemical Bonding and Molecular StructureMedium
    In which of the following molecules / ions BF3BF_3, NO2−NO_2^-, NH2−NH_2^- and H2OH_2O, the central atom is sp2sp^2 hybridized?
    1. Option A: BF3BF_3 and NO2−NO_2^-
    2. Option B: NO2−NO_2^- and NH2NH_2
    3. Option C: NH2−NH_2^- and H2OH_2O
    4. Option D: NO2−NO_2^- and H2OH_2O

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  21. Question 21 (AIPMT 2009, Q70)

    Redox ReactionsEasy
    Among the following which is the strongest oxidizing agent?
    1. Option A: Cl2Cl_2
    2. Option B: F2F_2
    3. Option C: Br2Br_2
    4. Option D: I2I_2
    Show answer & explanation

    Correct answer: (B) F2F_2

    Explanation

    Fluorine has the highest standard reduction potential among halogens and therefore is the strongest oxidizing agent. Hence option (B) is correct.

  22. Question 22 (AIPMT 2009, Q71)

    Chemical Bonding and Molecular StructureHard
    According to MO theory which of the following lists ranks the nitrogen species in terms of increasing bond order?
    1. Option A: N2−<N22−<N2N_2^- < N_2^{2-} < N_2
    2. Option B: N2−<N2<N22−N_2^- < N_2 < N_2^{2-}
    3. Option C: N22−<N2−<N2N_2^{2-} < N_2^- < N_2
    4. Option D: N2<N22−<N2−N_2 < N_2^{2-} < N_2^-

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  23. Question 23 (AIPMT 2009, Q72)

    Chemical Bonding and Molecular StructureMedium
    In the case of alkali metals, the covalent character decreases in order:
    1. Option A: MI>MBr>MCl>MFMI > MBr > MCl > MF
    2. Option B: MCl>MI>MBr>MFMCl > MI > MBr > MF
    3. Option C: MF>MCl>MBr>MIMF > MCl > MBr > MI
    4. Option D: MF>MCl>MI>MBrMF > MCl > MI > MBr

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  24. Question 24 (AIPMT 2009, Q73)

    Chemical Bonding and Molecular StructureEasy
    Which of the following oxides is not expected to react with sodium hydroxide?
    1. Option A: BeOBeO
    2. Option B: B2O3B_2O_3
    3. Option C: CaOCaO
    4. Option D: SiO2SiO_2

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  25. Question 25 (AIPMT 2009, Q74)

    ElectrochemistryHard
    Al2O3Al_2O_3 is reduced by electrolysis at low potentials and high currents. If 4.0×1044.0 \times 10^4 amperes of current is passed through molten Al2O3Al_2O_3 for 66 hours, what mass of aluminium is produced? (Assume 100%100\% current efficiency, atomic mass of Al=27 g mol−1Al = 27\,g\,mol^{-1})
    1. Option A: 1.3×104 g1.3 \times 10^4\,g
    2. Option B: 9.0×103 g9.0 \times 10^3\,g
    3. Option C: 8.1×104 g8.1 \times 10^4\,g
    4. Option D: 2.4×105 g2.4 \times 10^5\,g

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  26. Question 26 (AIPMT 2009, Q75)

    The d- and f-Block ElementsMedium
    The stability of +1+1 oxidation state increases in the sequence:
    1. Option A: Ga<In<Al<TlGa < In < Al < Tl
    2. Option B: Al<Ga<In<TlAl < Ga < In < Tl
    3. Option C: Tl<In<Ga<AlTl < In < Ga < Al
    4. Option D: In<Tl<Ga<AlIn < Tl < Ga < Al

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  27. Question 27 (AIPMT 2009, Q76)

    Solid StateMedium
    Copper crystallizes in a face-centred cubic lattice with a unit cell length of 361 pm361\,pm. What is the radius of copper atom in pm?
    1. Option A: 108108
    2. Option B: 128128
    3. Option C: 157157
    4. Option D: 181181

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  28. Question 28 (AIPMT 2009, Q77)

    Alcohols, Phenols and EthersEasy
    What is the dominant intermolecular force or bond that must be overcome in converting liquid CH3OHCH_3OH to a gas?
    1. Option A: London dispersion force
    2. Option B: Hydrogen bonding
    3. Option C: Dipole-dipole interaction
    4. Option D: Covalent bonds

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  29. Question 29 (AIPMT 2009, Q78)

    Coordination CompoundsHard
    Which of the following complex ions is expected to absorb visible light? (At no. Zn = 30, Sc = 21, Ti = 22, Cr = 24)
    1. Option A: [Zn(NH3)6]2+[Zn(NH_3)_6]^{2+}
    2. Option B: [Sc(H2O)3(NH3)3]3+[Sc(H_2O)_3(NH_3)_3]^{3+}
    3. Option C: [Ti(en)2(NH3)2]4+[Ti(en)_2(NH_3)_2]^{4+}
    4. Option D: [Cr(NH3)6]3+[Cr(NH_3)_6]^{3+}

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  30. Question 30 (AIPMT 2009, Q79)

    Coordination CompoundsHard
    Out of TiF62−TiF_6^{2-} and CoF63−CoF_6^{3-}, Cu2Cl2Cu_2Cl_2 and NiCl42−NiCl_4^{2-} (Z(Z of Ti=22Ti=22, Co=27Co=27, Cu=29Cu=29, Ni=28)Ni=28) the colourless species are:
    1. Option A: CoF63−CoF_6^{3-} and NiCl42−NiCl_4^{2-}
    2. Option B: TiF62−TiF_6^{2-} and CoF63−CoF_6^{3-}
    3. Option C: Cu2Cl2Cu_2Cl_2 and NiCl42−NiCl_4^{2-}
    4. Option D: TiF62−TiF_6^{2-} and Cu2Cl2Cu_2Cl_2

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  31. Question 31 (AIPMT 2009, Q80)

    Coordination CompoundsHard
    Which of the following does not show optical isomerism? (en=(en = ethylenediamine))
    1. Option A: [Co(en)3]3+[Co(en)_3]^{3+}
    2. Option B: [Co(en)2Cl2]+[Co(en)_2Cl_2]^+
    3. Option C: [Co(NH3)3Cl3]0[Co(NH_3)_3Cl_3]^0
    4. Option D: [Co(en)Cl2(NH3)2]+[Co(en)Cl_2(NH_3)_2]^+

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  32. Question 32 (AIPMT 2009, Q81)

    The d- and f-Block ElementsMedium
    Which one of the elements with the following outer orbital configurations may exhibit the largest number of oxidation states?
    1. Option A: 3d24s23d^2 4s^2
    2. Option B: 3d34s23d^3 4s^2
    3. Option C: 3d54s13d^5 4s^1
    4. Option D: 3d54s23d^5 4s^2

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  33. Question 33 (AIPMT 2009, Q82)

    Chemical Bonding and Molecular StructureEasy
    Which of the following molecules acts as a Lewis acid?
    1. Option A: (CH3)3N(CH_3)_3N
    2. Option B: (CH3)3B(CH_3)_3B
    3. Option C: (CH3)2O(CH_3)_2O
    4. Option D: (CH3)3P(CH_3)_3P

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  34. Question 34 (AIPMT 2009, Q83)

    Classification of Elements and Periodicity in PropertiesMedium
    Amongst the elements with the following electronic configurations, which one of them may have the highest ionization energy?
    1. Option A: [Ne]3s23p1[Ne]3s^2 3p^1
    2. Option B: [Ne]3s23p3[Ne]3s^2 3p^3
    3. Option C: [Ne]3s23p2[Ne]3s^2 3p^2
    4. Option D: [Ar]3d104s24p3[Ar]3d^{10}4s^2 4p^3

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  35. Question 35 (AIPMT 2009, Q84)

    PolymersMedium
    The straight chain polymer is formed by:
    1. Option A: hydrolysis of (CH3)2SiCl2(CH_3)_2SiCl_2 followed by condensation polymerization
    2. Option B: hydrolysis of (CH3)3SiCl(CH_3)_3SiCl followed by condensation polymerization
    3. Option C: hydrolysis of CH3SiCl3CH_3SiCl_3 followed by condensation polymerization
    4. Option D: hydrolysis of (CH3)4Si(CH_3)_4Si followed by addition polymerization
    Show answer & explanation

    Correct answer: (A) hydrolysis of (CH3)2SiCl2(CH_3)_2SiCl_2 followed by condensation polymerization

    Explanation

    Hydrolysis of dimethyldichlorosilane forms silanediol, which on condensation polymerization gives linear silicone polymers: [−Si(CH3)2−O−]n[-Si(CH_3)_2-O-]_n Hence option (A) is correct.

  36. Question 36 (AIPMT 2009, Q85)

    Organic Chemistry: Some Basic Principles and TechniquesMedium
    The IUPAC name of the compound having the formula CH≡C−CH=CH2CH \equiv C-CH=CH_2 is:
    1. Option A: 1-butene-3-yne
    2. Option B: 3-buten-1-yne
    3. Option C: 1-butyn-3-ene
    4. Option D: but-1-yn-3-ene

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  37. Question 37 (AIPMT 2009, Q86)

    HydrocarbonsEasy
    Which of the following compounds will exhibit cis-trans (geometrical) isomerism?
    1. Option A: 1-Butanol
    2. Option B: 2-Butene
    3. Option C: 2-Butanol
    4. Option D: 2-Butyne

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  38. Question 38 (AIPMT 2009, Q87)

    Alcohols, Phenols and EthersHard
    H₂COH.CH₂OH on heating with periodic acid gives:
    1. Option A: Option 1
    2. Option B: Option 2
    3. Option C: Option 3
    4. Option D: Option 4

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  39. Question 39 (AIPMT 2009, Q88)

    Haloalkanes and HaloarenesMedium
    Consider the following reaction: The product Z is :
    1. Option A: CH3CH2OHCH_3CH_2OH
    2. Option B: CH2=CH2CH_2 = CH_2
    3. Option C: CH3CH2−O−CH2CH3CH_3CH_2-O-CH_2CH_3
    4. Option D: CH3CH2−O−SO3HCH_3CH_2-O-SO_3H

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  40. Question 40 (AIPMT 2009, Q89)

    HydrocarbonsEasy
    Benzene reacts with CH3ClCH_3Cl in the presence of anhydrous AlCl3AlCl_3 to form:
    1. Option A: Xylene
    2. Option B: Toluene
    3. Option C: Chlorobenzene
    4. Option D: Benzyl chloride

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  41. Question 41 (AIPMT 2009, Q90)

    HydrocarbonsMedium
    Nitrobenzene can be prepared from benzene by using a mixture of concentrated HNO3HNO_3 and concentrated H2SO4H_2SO_4. In the mixture, nitric acid acts as a/an:
    1. Option A: catalyst
    2. Option B: reducing agent
    3. Option C: acid
    4. Option D: base

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  42. Question 42 (AIPMT 2009, Q91)

    Haloalkanes and HaloarenesEasy
    Which of the following reactions is an example of nucleophilic substitution reaction?
    1. Option A: RX+Mg→RMgXRX + Mg \rightarrow RMgX
    2. Option B: RX+KOH→ROH+KXRX + KOH \rightarrow ROH + KX
    3. Option C: 2RX+2Na→R−R+2NaX2RX + 2Na \rightarrow R-R + 2NaX
    4. Option D: RX+H2→RH+HXRX + H_2 \rightarrow RH + HX

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  43. Question 43 (AIPMT 2009, Q92)

    BiomoleculesEasy
    Which one of the following is employed as a tranquilizer?
    1. Option A: Chlorpheniramine
    2. Option B: Equanil
    3. Option C: Naproxen
    4. Option D: Tetracycline
    Show answer & explanation

    Correct answer: (B) Equanil

    Explanation

    Equanil (meprobamate) is used as a tranquilizer. Chlorpheniramine is an antihistamine, Naproxen is an analgesic, and Tetracycline is an antibiotic. Hence option (B) is correct.

  44. Question 44 (AIPMT 2009, Q93)

    BiomoleculesMedium
    Structures of some common polymers are given. Which one is not correctly presented?
    1. Option A: Option 1
    2. Option B: Option 2
    3. Option C: Option 3
    4. Option D: Option 4
    Show answer & explanation

    Correct answer: (C) Option 3

    Explanation

    Terylene (PET) repeating unit is: [−O−CH2−CH2−O−CO−C6H4−CO−]n[-O-CH_2-CH_2-O-CO-C_6H_4-CO-]_n The structure given in option (D) is not correctly represented. Hence option (D) is correct.

  45. Question 45 (AIPMT 2009, Q94)

    AminesHard
    Predict the product:
    1. Option A: Option 1
    2. Option B: Option 2
    3. Option C: Option 3
    4. Option D: Option 4

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  46. Question 46 (AIPMT 2009, Q95)

    Aldehydes, Ketones and Carboxylic AcidsHard
    Propionic acid with Br2/PBr_2/P yields a dibromo product. Its structure would be:
    1. Option A: Option 1
    2. Option B: Option 2
    3. Option C: Option 3
    4. Option D: Option 4

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  47. Question 47 (AIPMT 2009, Q96)

    HydrocarbonsMedium
    Trichloroacetaldehyde (CCl3CHO)(CCl_3CHO) reacts with chlorobenzene in presence of sulphuric acid and produces:
    1. Option A: Option 1
    2. Option B: Option 2
    3. Option C: Option 3
    4. Option D: Option 4

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  48. Question 48 (AIPMT 2009, Q97)

    HydrocarbonsHard
    Consider the following reaction: The product ZZ is:
    1. Option A: Benzene
    2. Option B: Toluene
    3. Option C: Benzaldehyde
    4. Option D: Benzoic acid

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  49. Question 49 (AIPMT 2009, Q98)

    Organic Chemistry: Some Basic Principles and TechniquesHard
    The state of hybridization of C2C_2, C3C_3, C5C_5 and C6C_6 of the hydrocarbon shown below is:
    1. Option A: sp,  sp2,  sp3,  sp2sp,\; sp^2,\; sp^3,\; sp^2
    2. Option B: sp,  sp3,  sp2,  sp3sp,\; sp^3,\; sp^2,\; sp^3
    3. Option C: sp3,  sp2,  sp2,  spsp^3,\; sp^2,\; sp^2,\; sp
    4. Option D: sp,  sp2,  sp2,  sp3sp,\; sp^2,\; sp^2,\; sp^3

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